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# Answer parsing and normalization code, from
# https://github.com/ruixiangcui/AGIEval/blob/main/src/
# math_equivalence.py and post_process.py
import re
from typing import Dict, List
import numpy as np
def parse_math_answer(raw_string):
def remove_boxed(s):
left = "\\boxed{"
try:
assert s[: len(left)] == left
assert s[-1] == "}"
answer = s[len(left) : -1]
if "=" in answer:
answer = answer.split("=")[-1].lstrip(" ")
return answer
except Exception:
return None
def last_boxed_only_string(string):
idx = string.rfind("\\boxed")
if idx < 0:
idx = string.rfind("\\fbox")
if idx < 0:
return None
i = idx
right_brace_idx = None
num_left_braces_open = 0
while i < len(string):
if string[i] == "{":
num_left_braces_open += 1
if string[i] == "}":
num_left_braces_open -= 1
if num_left_braces_open == 0:
right_brace_idx = i
break
i += 1
if right_brace_idx is None:
retval = None
else:
retval = string[idx : right_brace_idx + 1]
return retval
def get_answer_with_dollar_sign(s):
first_pattern = "\$(.*)\$"
last_match = None
matches = re.findall(first_pattern, s)
if matches:
last_match = matches[-1]
if "=" in last_match:
last_match = last_match.split("=")[-1].lstrip(" ")
return last_match
def get_answer_without_dollar_sign(s):
last_match = None
if "=" in s:
last_match = s.split("=")[-1].lstrip(" ").rstrip(".")
if "\\n" in last_match:
last_match = last_match.split("\\n")[0]
else:
pattern = "(?:\\$)?\d+(?:\.\d+)?(?![\w\d])"
matches = re.findall(pattern, s)
if matches:
last_match = matches[-1]
return last_match
if "\\boxed" in raw_string:
answer = remove_boxed(last_boxed_only_string(raw_string))
else:
answer = get_answer_with_dollar_sign(raw_string)
if not answer:
answer = get_answer_without_dollar_sign(raw_string)
return answer
# code from https://github.com/hendrycks/math/blob/main/modeling/math_equivalence.py
def _fix_fracs(string):
substrs = string.split("\\frac")
new_str = substrs[0]
if len(substrs) > 1:
substrs = substrs[1:]
for substr in substrs:
new_str += "\\frac"
if substr[0] == "{":
new_str += substr
else:
try:
assert len(substr) >= 2
except Exception:
return string
a = substr[0]
b = substr[1]
if b != "{":
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}{" + b + "}" + post_substr
else:
new_str += "{" + a + "}{" + b + "}"
else:
if len(substr) > 2:
post_substr = substr[2:]
new_str += "{" + a + "}" + b + post_substr
else:
new_str += "{" + a + "}" + b
string = new_str
return string
def _fix_a_slash_b(string):
if len(string.split("/")) != 2:
return string
a = string.split("/")[0]
b = string.split("/")[1]
try:
a = int(a)
b = int(b)
assert string == "{}/{}".format(a, b)
new_string = "\\frac{" + str(a) + "}{" + str(b) + "}"
return new_string
except Exception:
return string
def _remove_right_units(string):
# "\\text{ " only ever occurs (at least in the val set) when describing units
if "\\text{ " in string:
splits = string.split("\\text{ ")
assert len(splits) == 2
return splits[0]
else:
return string
def _fix_sqrt(string):
if "\\sqrt" not in string:
return string
splits = string.split("\\sqrt")
new_string = splits[0]
for split in splits[1:]:
if split[0] != "{":
a = split[0]
new_substr = "\\sqrt{" + a + "}" + split[1:]
else:
new_substr = "\\sqrt" + split
new_string += new_substr
return new_string
def _strip_string(string):
# linebreaks
string = string.replace("\n", "")
# print(string)
# remove inverse spaces
string = string.replace("\\!", "")
# print(string)
# replace \\ with \
string = string.replace("\\\\", "\\")
# print(string)
# replace tfrac and dfrac with frac
string = string.replace("tfrac", "frac")
string = string.replace("dfrac", "frac")
# print(string)
# remove \left and \right
string = string.replace("\\left", "")
string = string.replace("\\right", "")
# print(string)
# Remove circ (degrees)
string = string.replace("^{\\circ}", "")
string = string.replace("^\\circ", "")
# remove dollar signs
string = string.replace("\\$", "")
# remove units (on the right)
string = _remove_right_units(string)
# remove percentage
string = string.replace("\\%", "")
string = string.replace("\%", "")
# " 0." equivalent to " ." and "{0." equivalent to "{." Alternatively, add "0" if "." is the start of the string
string = string.replace(" .", " 0.")
string = string.replace("{.", "{0.")
# if empty, return empty string
if len(string) == 0:
return string
if string[0] == ".":
string = "0" + string
# to consider: get rid of e.g. "k = " or "q = " at beginning
if len(string.split("=")) == 2:
if len(string.split("=")[0]) <= 2:
string = string.split("=")[1]
# fix sqrt3 --> sqrt{3}
string = _fix_sqrt(string)
# remove spaces
string = string.replace(" ", "")
# \frac1b or \frac12 --> \frac{1}{b} and \frac{1}{2}, etc. Even works with \frac1{72} (but not \frac{72}1). Also does a/b --> \\frac{a}{b}
string = _fix_fracs(string)
# manually change 0.5 --> \frac{1}{2}
if string == "0.5":
string = "\\frac{1}{2}"
# NOTE: X/Y changed to \frac{X}{Y} in dataset, but in simple cases fix in case the model output is X/Y
string = _fix_a_slash_b(string)
return string
def is_equiv(str1, str2, verbose=False):
if str1 is None and str2 is None:
print("WARNING: Both None")
return True
if str1 is None or str2 is None:
return False
str1, str2 = parse_math_answer(str1), parse_math_answer(str2)
try:
ss1 = _strip_string(str1)
ss2 = _strip_string(str2)
if verbose:
print(ss1, ss2)
return ss1 == ss2
except Exception:
return str1 == str2
def process_results(doc: dict, results: List[str]) -> Dict[str, int]:
candidate = results[0]
gold = doc["answer"]
if not gold:
print(doc, candidate, gold)
if is_equiv(candidate, gold):
retval = 1
else:
retval = 0
results = {
"acc": retval,
}
return results
# use a custom process_results() function, because AGIEval can have multiple valid answers
def process_results_mcqa(doc, results):
results = [result[0] for result in results]
gold = doc["gold"]
acc = 1.0 if int(np.argmax(results)) in gold else 0.0
completion_len = np.array([float(len(i)) for i in doc["choices"]])
acc_norm = 1.0 if int(np.argmax(results / completion_len)) in gold else 0.0
return {
"acc": acc,
"acc_norm": acc_norm,
}
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