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# by https://github.com/Cosmo-klara | |
from __future__ import print_function | |
import re | |
import inflect | |
import unicodedata | |
# 后缀计量单位替换表 | |
measurement_map = { | |
"m": ["meter", "meters"], | |
"km": ["kilometer", "kilometers"], | |
"km/h": ["kilometer per hour", "kilometers per hour"], | |
"ft": ["feet", "feet"], | |
"L": ["liter", "liters"], | |
"tbsp": ["tablespoon", "tablespoons"], | |
"tsp": ["teaspoon", "teaspoons"], | |
"h": ["hour", "hours"], | |
"min": ["minute", "minutes"], | |
"s": ["second", "seconds"], | |
"°C": ["degree celsius", "degrees celsius"], | |
"°F": ["degree fahrenheit", "degrees fahrenheit"], | |
} | |
# 识别 12,000 类型 | |
_inflect = inflect.engine() | |
# 转化数字序数词 | |
_ordinal_number_re = re.compile(r"\b([0-9]+)\. ") | |
# 我听说好像对于数字正则识别其实用 \d 会好一点 | |
_comma_number_re = re.compile(r"([0-9][0-9\,]+[0-9])") | |
# 时间识别 | |
_time_re = re.compile(r"\b([01]?[0-9]|2[0-3]):([0-5][0-9])\b") | |
# 后缀计量单位识别 | |
_measurement_re = re.compile(r"\b([0-9]+(\.[0-9]+)?(m|km|km/h|ft|L|tbsp|tsp|h|min|s|°C|°F))\b") | |
# 前后 £ 识别 ( 写了识别两边某一边的,但是不知道为什么失败了┭┮﹏┭┮ ) | |
_pounds_re_start = re.compile(r"£([0-9\.\,]*[0-9]+)") | |
_pounds_re_end = re.compile(r"([0-9\.\,]*[0-9]+)£") | |
# 前后 $ 识别 | |
_dollars_re_start = re.compile(r"\$([0-9\.\,]*[0-9]+)") | |
_dollars_re_end = re.compile(r"([(0-9\.\,]*[0-9]+)\$") | |
# 小数的识别 | |
_decimal_number_re = re.compile(r"([0-9]+\.\s*[0-9]+)") | |
# 分数识别 (形式 "3/4" ) | |
_fraction_re = re.compile(r"([0-9]+/[0-9]+)") | |
# 序数词识别 | |
_ordinal_re = re.compile(r"[0-9]+(st|nd|rd|th)") | |
# 数字处理 | |
_number_re = re.compile(r"[0-9]+") | |
def _convert_ordinal(m): | |
""" | |
标准化序数词, 例如: 1. 2. 3. 4. 5. 6. | |
Examples: | |
input: "1. " | |
output: "1st" | |
然后在后面的 _expand_ordinal, 将其转化为 first 这类的 | |
""" | |
ordinal = _inflect.ordinal(m.group(1)) | |
return ordinal + ", " | |
def _remove_commas(m): | |
return m.group(1).replace(",", "") | |
def _expand_time(m): | |
""" | |
将 24 小时制的时间转换为 12 小时制的时间表示方式。 | |
Examples: | |
input: "13:00 / 4:00 / 13:30" | |
output: "one o'clock p.m. / four o'clock am. / one thirty p.m." | |
""" | |
hours, minutes = map(int, m.group(1, 2)) | |
period = "a.m." if hours < 12 else "p.m." | |
if hours > 12: | |
hours -= 12 | |
hour_word = _inflect.number_to_words(hours) | |
minute_word = _inflect.number_to_words(minutes) if minutes != 0 else "" | |
if minutes == 0: | |
return f"{hour_word} o'clock {period}" | |
else: | |
return f"{hour_word} {minute_word} {period}" | |
def _expand_measurement(m): | |
""" | |
处理一些常见的测量单位后缀, 目前支持: m, km, km/h, ft, L, tbsp, tsp, h, min, s, °C, °F | |
如果要拓展的话修改: _measurement_re 和 measurement_map | |
""" | |
sign = m.group(3) | |
ptr = 1 | |
# 想不到怎么方便的取数字,又懒得改正则,诶,1.2 反正也是复数读法,干脆直接去掉 "." | |
num = int(m.group(1).replace(sign, "").replace(".", "")) | |
decimal_part = m.group(2) | |
# 上面判断的漏洞,比如 0.1 的情况,在这里排除了 | |
if decimal_part == None and num == 1: | |
ptr = 0 | |
return m.group(1).replace(sign, " " + measurement_map[sign][ptr]) | |
def _expand_pounds(m): | |
""" | |
没找到特别规范的说明,和美元的处理一样,其实可以把两个合并在一起 | |
""" | |
match = m.group(1) | |
parts = match.split(".") | |
if len(parts) > 2: | |
return match + " pounds" # Unexpected format | |
pounds = int(parts[0]) if parts[0] else 0 | |
pence = int(parts[1].ljust(2, "0")) if len(parts) > 1 and parts[1] else 0 | |
if pounds and pence: | |
pound_unit = "pound" if pounds == 1 else "pounds" | |
penny_unit = "penny" if pence == 1 else "pence" | |
return "%s %s and %s %s" % (pounds, pound_unit, pence, penny_unit) | |
elif pounds: | |
pound_unit = "pound" if pounds == 1 else "pounds" | |
return "%s %s" % (pounds, pound_unit) | |
elif pence: | |
penny_unit = "penny" if pence == 1 else "pence" | |
return "%s %s" % (pence, penny_unit) | |
else: | |
return "zero pounds" | |
def _expand_dollars(m): | |
""" | |
change: 美分是 100 的限值, 应该要做补零的吧 | |
Example: | |
input: "32.3$ / $6.24" | |
output: "thirty-two dollars and thirty cents" / "six dollars and twenty-four cents" | |
""" | |
match = m.group(1) | |
parts = match.split(".") | |
if len(parts) > 2: | |
return match + " dollars" # Unexpected format | |
dollars = int(parts[0]) if parts[0] else 0 | |
cents = int(parts[1].ljust(2, "0")) if len(parts) > 1 and parts[1] else 0 | |
if dollars and cents: | |
dollar_unit = "dollar" if dollars == 1 else "dollars" | |
cent_unit = "cent" if cents == 1 else "cents" | |
return "%s %s and %s %s" % (dollars, dollar_unit, cents, cent_unit) | |
elif dollars: | |
dollar_unit = "dollar" if dollars == 1 else "dollars" | |
return "%s %s" % (dollars, dollar_unit) | |
elif cents: | |
cent_unit = "cent" if cents == 1 else "cents" | |
return "%s %s" % (cents, cent_unit) | |
else: | |
return "zero dollars" | |
# 小数的处理 | |
def _expand_decimal_number(m): | |
""" | |
Example: | |
input: "13.234" | |
output: "thirteen point two three four" | |
""" | |
match = m.group(1) | |
parts = match.split(".") | |
words = [] | |
# 遍历字符串中的每个字符 | |
for char in parts[1]: | |
if char == ".": | |
words.append("point") | |
else: | |
words.append(char) | |
return parts[0] + " point " + " ".join(words) | |
# 分数的处理 | |
def _expend_fraction(m): | |
""" | |
规则1: 分子使用基数词读法, 分母用序数词读法. | |
规则2: 如果分子大于 1, 在读分母的时候使用序数词复数读法. | |
规则3: 当分母为2的时候, 分母读做 half, 并且当分子大于 1 的时候, half 也要用复数读法, 读为 halves. | |
Examples: | |
| Written | Said | | |
|:---:|:---:| | |
| 1/3 | one third | | |
| 3/4 | three fourths | | |
| 5/6 | five sixths | | |
| 1/2 | one half | | |
| 3/2 | three halves | | |
""" | |
match = m.group(0) | |
numerator, denominator = map(int, match.split("/")) | |
numerator_part = _inflect.number_to_words(numerator) | |
if denominator == 2: | |
if numerator == 1: | |
denominator_part = "half" | |
else: | |
denominator_part = "halves" | |
elif denominator == 1: | |
return f"{numerator_part}" | |
else: | |
denominator_part = _inflect.ordinal(_inflect.number_to_words(denominator)) | |
if numerator > 1: | |
denominator_part += "s" | |
return f"{numerator_part} {denominator_part}" | |
def _expand_ordinal(m): | |
return _inflect.number_to_words(m.group(0)) | |
def _expand_number(m): | |
num = int(m.group(0)) | |
if num > 1000 and num < 3000: | |
if num == 2000: | |
return "two thousand" | |
elif num > 2000 and num < 2010: | |
return "two thousand " + _inflect.number_to_words(num % 100) | |
elif num % 100 == 0: | |
return _inflect.number_to_words(num // 100) + " hundred" | |
else: | |
return _inflect.number_to_words(num, andword="", zero="oh", group=2).replace(", ", " ") | |
else: | |
return _inflect.number_to_words(num, andword="") | |
def normalize(text): | |
""" | |
!!! 所有的处理都需要正确的输入 !!! | |
可以添加新的处理,只需要添加正则表达式和对应的处理函数即可 | |
""" | |
text = re.sub(_ordinal_number_re, _convert_ordinal, text) | |
text = re.sub(r"(?<!\d)-|-(?!\d)", " minus ", text) | |
text = re.sub(_comma_number_re, _remove_commas, text) | |
text = re.sub(_time_re, _expand_time, text) | |
text = re.sub(_measurement_re, _expand_measurement, text) | |
text = re.sub(_pounds_re_start, _expand_pounds, text) | |
text = re.sub(_pounds_re_end, _expand_pounds, text) | |
text = re.sub(_dollars_re_start, _expand_dollars, text) | |
text = re.sub(_dollars_re_end, _expand_dollars, text) | |
text = re.sub(_decimal_number_re, _expand_decimal_number, text) | |
text = re.sub(_fraction_re, _expend_fraction, text) | |
text = re.sub(_ordinal_re, _expand_ordinal, text) | |
text = re.sub(_number_re, _expand_number, text) | |
text = "".join( | |
char for char in unicodedata.normalize("NFD", text) if unicodedata.category(char) != "Mn" | |
) # Strip accents | |
text = re.sub("%", " percent", text) | |
text = re.sub("[^ A-Za-z'.,?!\-]", "", text) | |
text = re.sub(r"(?i)i\.e\.", "that is", text) | |
text = re.sub(r"(?i)e\.g\.", "for example", text) | |
# 增加纯大写单词拆分 | |
text = re.sub(r"(?<!^)(?<![\s])([A-Z])", r" \1", text) | |
return text | |
if __name__ == "__main__": | |
# 我觉得其实可以把切分结果展示出来(只读,或者修改不影响传给TTS的实际text) | |
# 然后让用户确认后再输入给 TTS,可以让用户检查自己有没有不标准的输入 | |
print(normalize("1. test ordinal number 1st")) | |
print(normalize("32.3$, $6.24, 1.1£, £7.14.")) | |
print(normalize("3/23, 1/2, 3/2, 1/3, 6/1")) | |
print(normalize("1st, 22nd")) | |
print(normalize("a test 20h, 1.2s, 1L, 0.1km")) | |
print(normalize("a test of time 4:00, 13:00, 13:30")) | |
print(normalize("a test of temperature 4°F, 23°C, -19°C")) | |