README.md

metadata

tags:
  - sentence-transformers
  - sentence-similarity
  - feature-extraction
  - dense
  - generated_from_trainer
  - dataset_size:865218
  - loss:TripletLoss
base_model: Salesforce/SFR-Embedding-Code-400M_R
widget:
  - source_sentence: >
      Swaps in a String

      You are given a string $S$ that contains of the characters $A$, $B$ or $C$
      only.


      In one operation, you can do either of the following:


      - Choose an occurrence of $\text{AB}$ in the string, convert it to
      $\text{BA}$.

      - Choose an occurrence of $\text{BC}$ in the string, convert it to
      $\text{CB}$.


      Note that you are only allowed to operate on adjacent elements.


      Find the maximum number of operations you can do. It can be proven the
      answer is finite.


      Input Format:

      - The first line of input will contain a single integer $T$, denoting the
      number of test cases.

      - Each test case consists of multiple lines of input.
          - The first line of each test case contains $N$ - the length of the string.
          - The second line contains $S$ - the string.

      Output Format:

      For each test case, output on a new line the maximum number of operations
      possible.


      Constraints:

      - $1 \le T \le 10^4$

      - $2 \le N \le 2 \cdot 10^5$

      - $|S| = N$

      - $S_i \in \{A, B, C\}$

      - The sum of $N$ over all test cases does not exceed $2 \cdot 10^5$.


      Sample 1:

      Input:

      3

      4

      ABCC

      5

      BAABB

      2

      BA


      Output:

      2

      4

      0

      Explanation:

      **Test Case 1** : We can convert $\text{ABCC}$ to $\text{ACBC}$ and then
      to $\text{ACCB}$. More than $2$ operations can be proven to be impossible.


      **Test Case 2** : $\text{BAABB} \rightarrow \text{BABAB} \rightarrow
      \text{BBAAB} \rightarrow \text{BBABA} \rightarrow \text{BBBAA}$.
    sentences:
      - "#from collections import Counter\r\n#import math\r\n#import deque\r\nt=int(input())\r\nfor _ in range(t):\r\n    n=int(input())\r\n    a=input()\r\n    C1=[]\r\n    C2=[]\r\n    c1=0\r\n    c2=0\r\n    res=0\r\n    for i in a:\r\n        if i=='A':\r\n            c1+=1\r\n        elif i=='B':\r\n            pass\r\n        else:\r\n            c1=0\r\n        C1.append(c1)\r\n    for i in a[::-1]:\r\n        if i=='A':\r\n            c2=0\r\n        elif i=='B':\r\n            pass\r\n        else:\r\n            c2+=1\r\n        C2.append(c2)\r\n    C2=C2[::-1]\r\n    for i in range(n):\r\n        if a[i]=='B':\r\n            res+=max(C1[i],C2[i])\r\n    print(res)"
      - "#from collections import Counter\r\n#import math\r\n#import deque\r\nt=int(input())\r\nfor _ in range(t):\r\n    n=int(input())\r\n    a=input()\r\n    C1=[]\r\n    C2=[]\r\n    c1=0\r\n    c2=0\r\n    res=0\r\n    for i in a:\r\n        if i=='A':\r\n            c1+=1\r\n        elif i=='C':\r\n            c1=0\r\n        C1.append(c1)\r\n    for i in a[::-1]:\r\n        if i=='A':\r\n            c2=0\r\n        elif i=='C':\r\n            c2+=1\r\n        C2.append(c2)\r\n    C2=C2[::-1]\r\n    for i in range(n):\r\n        if a[i]=='B':\r\n            res+=max(C1[i],C2[i])\r\n    print(res)"
      - "# cook your dish here\r\nimport math\r\nfor _ in range(int(input())):\r\n    n=int(input())\r\n    x=math.ceil(n/2)\r\n    y=math.ceil(n/3)\r\n    print(x,y)\r\n    "
  - source_sentence: "We have N coins numbered 1 to N with two distinguishable sides. A string S represents the current state of the coins. If the i-th character of S is 1, coin i is showing heads; if that character is 0, coin i is showing tails.\n\n  You can repeat the following operation zero or more times.\n\n    * Choose a pair of integers (i,j) such that 1\\leq i < j\\leq N and j-i\\geq \\bm{2}. Flip coin i and coin j.\n\n  Determine whether it is possible to make all the N coins show tails. If it is possible, find the minimum number of operations needed.\n\n  You are given T test cases to solve.\n\n  Constraints\n\n    * 1 \\leq T \\leq 2\\times 10^5\n    * 3 \\leq N \\leq 2\\times 10^5\n    * S is a string of length N consisting of 0 and 1.\n    * All numbers in the input are integers.\n    * For each input file, the sum of N over the test cases is at most 2\\times 10^5.\n\n    Input\n\n    The input is given from Standard Input in the following format:\n\n    T\r\n    \\mathrm{case}_1\r\n    \\vdots\r\n    \\mathrm{case}_T\r\n    \n\n    ​ Each case is in the following format:\n\n    N\r\n    S\r\n    \n\n    Output\n\n    Print T lines. The i-th line (1\\leq i \\leq T) should contain the minimum number of operations needed to make all the coins show tails if it is possible, and -1 otherwise.\n\n  Sample Input 1\n\n  5\r\n  3\r\n  101\r\n  6\r\n  101101\r\n  5\r\n  11111\r\n  6\r\n  000000\r\n  30\r\n  111011100110101100101000000111\r\n  \n\n  Sample Output 1\n\n  1\r\n  2\r\n  -1\r\n  0\r\n  8\r\n  \n\n  For the first test case, you can perform the operation with (i,j)=(1,3) to make all the coins show tails in one operation.\n\n  For the second test case, you can perform the operation with (i,j)=(1,3) and then with (i,j)=(4,6) to make all the coins show tails in two operations.\n\n  For the third test case, you can prove that there is no way to make all the coins show tails, so you should print -1.\n\n  For the fourth test case, the coins already show tails, so no operation is needed."
    sentences:
      - "A, B, X = map(int, input().split())\r\n\r\nans = 0\r\n\r\nfor i in range(1, 12):\r\n    rem = X - i * B\r\n    if rem <= 0:\r\n        continue\r\n    if rem // A < 10**(i - 1):\r\n        continue\r\n\r\n    if 10**(i - 1) <= rem // A < 10**(i):\r\n        ans = max(ans, rem // A)\r\n    elif rem // A >= 10**(i - 1) - 1:\r\n        cand = []\r\n        for i in range(i):\r\n            cand.append('9')\r\n        ans = max(int(''.join(cand)), ans)\r\n    else:\r\n        ans = max(ans, rem // A)\r\n\r\nprint(min(10**9, ans))"
      - "t=int(input())\r\nimport itertools\r\nimport heapq\r\n\r\nfor i in range(t):\r\n  n=int(input())\r\n  s=list(input())\r\n  #print(s)\r\n  if s==['1','1','0'] or s==['0','1','1']:\r\n    print(-1)\r\n    continue\r\n  if s==['0','1','1','0'] :\r\n    print(3)\r\n    continue\r\n  g=itertools.groupby(s)\r\n  q=[]#heapq.heapify([])\r\n  cnt=0\r\n  cnt2=0\r\n  ans=0\r\n  l2=0\r\n  for k,v in g:\r\n    \r\n    v=list(v)\r\n    #print(v)\r\n    #print(len(v))\r\n    if k=='1':\r\n      l=len(v)\r\n      cnt2+=1\r\n      l2=len(v)\r\n      cnt+=l\r\n      #print(k,list(v),'d')\r\n      #print(l2,len(list(v)),list(v))\r\n      heapq.heappush(q,-l)\r\n  if cnt2==1 and l2==2:\r\n    ans+=1\r\n  #print(cnt2,l2)\r\n  if cnt%2==1:\r\n    print(-1)\r\n    continue\r\n # print(q)\r\n  while q:\r\n    #print(q)\r\n    if len(q)==1:\r\n      l1=heapq.heappop(q)\r\n      ans+=(-l1)//2\r\n    else:\r\n      l1=heapq.heappop(q)\r\n      l2=heapq.heappop(q)\r\n      ans+=-max(l1,l2)\r\n      if l1!=l2:heapq.heappush(q,-abs(l1-l2))\r\n  print(ans)"
      - "t=int(input())\r\nimport itertools\r\nimport heapq\r\n\r\nfor i in range(t):\r\n  n=int(input())\r\n  s=list(input())\r\n  #print(s)\r\n  g=itertools.groupby(s)\r\n  q=[]#heapq.heapify([])\r\n  cnt=0\r\n  cnt2=0\r\n  ans=0\r\n  l2=0\r\n  for k,v in g:\r\n    \r\n    v=list(v)\r\n   # print(v)\r\n    if k=='1':\r\n      l=len(v)\r\n      cnt2+=1\r\n      l2=len(v)\r\n      cnt+=l\r\n      #print(k,list(v),'d')\r\n      #print(l2,len(list(v)),list(v))\r\n      heapq.heappush(q,-l)\r\n  if cnt2==1 and l2==2:\r\n    ans+=1\r\n  #print(cnt2,l2)\r\n  if cnt%2==1:\r\n    print(-1)\r\n    continue\r\n # print(q)\r\n  while q:\r\n    #print(q)\r\n    if len(q)==1:\r\n      l1=heapq.heappop(q)\r\n      ans+=(-l1)//2\r\n    else:\r\n      l1=heapq.heappop(q)\r\n      l2=heapq.heappop(q)\r\n      ans+=-max(l1,l2)\r\n      if l1!=l2:heapq.heappush(q,-abs(l1-l2))\r\n  print(ans)"
  - source_sentence: "Given is an integer S. Find a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:\n\n    * 0 \\leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \\leq 10^9\n    * The area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.\n\n  We can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.\n\n  Constraints\n\n    * 1 \\leq S \\leq 10^{18}\n    * All values in input are integers.\n\n    Input\n\n    Input is given from Standard Input in the following format:\n\n    S\r\n    \n\n    Output\n\n    Print six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between. If multiple solutions exist, any of them will be accepted.\n\n  Sample Input 1\n\n  3\r\n  \n\n  Sample Output 1\n\n  1 0 2 2 0 1\r\n  \n\n  The area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2. Printing 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.\n\n  Sample Input 2\n\n  100\r\n  \n\n  Sample Output 2\n\n  0 0 10 0 0 10\r\n  \n\n  Sample Input 3\n\n  311114770564041497\r\n  \n\n  Sample Output 3\n\n  314159265 358979323 846264338 327950288 419716939 937510582"
    sentences:
      - "import sys\r\ninput = sys.stdin.readline\r\n\r\nx, y = map(int, input().split())\r\nINF = 10**10\r\nif y >= x:\r\n    ans1 = y-x\r\nelse:\r\n    ans1 = INF\r\nif -y >= x:\r\n    ans2 = -y - x + 1\r\nelse:\r\n    ans2 = INF\r\nif y >= -x:\r\n    ans3 = y - (-x) + 1\r\nelse:\r\n    ans3 = INF\r\nif -y >= -x:\r\n    ans4 = -y - (-x) + 2\r\nelse:\r\n    ans4 = INF\r\nans = min(ans1, ans2, ans3, ans4)\r\nprint(ans)\r\n"
      - "s=int(input())\r\nif s+1<=10**9:\r\n  b=str(s+1)\r\n  a=['0','0',b,'1','1','1']\r\nelse:\r\n  a=int(s**(1/2))\r\n  if a**2>=s:\r\n    a_=a\r\n  else:\r\n    if a*(a+1)>=s:\r\n      a_=a+1\r\n    else:\r\n      if a*(a+2)>=s and a+2<=10**9:\r\n        a_=a+2\r\n      else:\r\n        a_=a+1\r\n        a+=1\r\n  x2=str(a)\r\n  y3=str(a_)\r\n  \r\n  y2=str(1)\r\n  x3=str(int(x2)*int(y3)-s)\r\n  x1=str(0)\r\n  y1=str(0)\r\n  a=[x1,y1,x2,y2,x3,y3]\r\nprint((' ').join(a))\r\n"
      - "s=int(input())\r\nif s+1<=10**9:\r\n  b=str(s+1)\r\n  a=['0','0',b,'1','1','1']\r\nelse:\r\n  x2=int(s**(1/2))\r\n  y3=int(s**(1/2))\r\n  while s>x2*y3:\r\n    y3+=1\r\n  x2=str(x2)\r\n  y3=str(y3)\r\n  y2=str(1)\r\n  x3=str(int(x2)*int(y3)-s)\r\n  x1=str(0)\r\n  y1=str(0)\r\n  a=[x1,y1,x2,y2,x3,y3]\r\nprint((' ').join(a)) "
  - source_sentence: "There is a directed graph with N vertices and M edges, where vertices are numbered from 1 to N and edges are numbered from 1 to M. Edge i is a directed edge from vertex A_i to vertex B_i with weight W_i.\n\n  Find the minimum value of the bitwise \\mathrm{XOR} of the weights of edges included in a walk from vertex 1 to vertex N.\n\n  What is a walk from vertex 1 to vertex N?\n\n  Intuitively, it is \"a path from vertex 1 to vertex N that may visit the same vertex or edge multiple times.\" Formally, it is a sequence of edges (e_1,\\ldots,e_k) that satisfies all of the following conditions:\n\n    * e_1 starts at vertex 1.\n    * For all 1 \\leq i < k, the endpoint of e_i and the starting point of e_{i+1} are the same.\n    * e_k ends at vertex N.\n  What is the bitwise \\mathrm{XOR} operation?\n\n  The bitwise \\mathrm{XOR} of non-negative integers A and B, denoted A\\ \\mathrm{XOR}\\ B, is defined as follows:\n\n    * When A\\ \\mathrm{XOR}\\ B is written in binary, the digit at the 2^k place (k \\geq 0) is 1 if exactly one of the digits at the 2^k place of A and B in binary is 1, and 0 otherwise.\n  For example, 3\\ \\mathrm{XOR}\\ 5 = 6 (in binary: 011\\ \\mathrm{XOR}\\ 101 = 110).\n  In general, the bitwise \\mathrm{XOR} of k non-negative integers p_1, p_2, p_3, \\dots, p_k is defined as (\\dots ((p_1\\ \\mathrm{XOR}\\ p_2)\\ \\mathrm{XOR}\\ p_3)\\ \\mathrm{XOR}\\ \\dots\\ \\mathrm{XOR}\\ p_k), and it can be proved that this does not depend on the order of p_1, p_2, p_3, \\dots p_k.\n\n  Constraints\n\n    * 2 \\leq N \\leq 1000\n    * 0 \\leq M \\leq 1000\n    * 1 \\leq A_i,B_i \\leq N\n    * 0 \\leq W_i < 2^{10}\n    * All input values are integers.\n\n    Input\n\n    The input is given from Standard Input in the following format:\n\n    N M\r\n    A_1 B_1 W_1\r\n    A_2 B_2 W_2\r\n    \\vdots\r\n    A_M B_M W_M\r\n    \n\n    Output\n\n    If there is no walk from vertex 1 to vertex N, output -1.\n\n    If there is a walk from vertex 1 to vertex N, output the minimum value of the bitwise \\mathrm{XOR} of the weights of edges included in such a walk.\n\n  Sample Input 1\n\n  3 3\r\n  1 2 4\r\n  2 3 5\r\n  1 3 2\r\n  \n\n  Sample Output 1\n\n  1\r\n  \n\n  The bitwise \\mathrm{XOR} of the weights of edges included in the walk (edge 1, edge 2) is 1.\n\n  Sample Input 2\n\n  4 4\r\n  1 4 7\r\n  4 2 2\r\n  2 3 4\r\n  3 4 1\r\n  \n\n  Sample Output 2\n\n  0\r\n  \n\n  The bitwise \\mathrm{XOR} of the weights of edges included in the walk (edge 1, edge 2, edge 3, edge 4) is 0.\n\n  Note that the walk may include vertex N in the middle.\n\n  Sample Input 3\n\n  999 4\r\n  1 2 9\r\n  2 1 8\r\n  1 2 7\r\n  1 1 6\r\n  \n\n  Sample Output 3\n\n  -1\r\n  \n\n  If there is no walk from vertex 1 to vertex N, output -1."
    sentences:
      - "import sys\r\nimport os\r\nfrom io import StringIO\r\nimport unittest\r\nfrom typing import *\r\n\r\nfrom bisect import *\r\nfrom collections import *\r\nfrom heapq import *\r\nfrom itertools import *\r\nfrom math import *\r\n\r\nMOD = 998244353\r\nINF = 1<<60\r\nLABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\"\r\nSABC = \"abcdefghijklmnopqrstuvwxyz\"\r\n\r\ndef resolve():\r\n    N, M = map(int, input().split())\r\n    graph = [[] for _ in range(N)]\r\n    for _ in range(M):\r\n        a, b, w = map(int, input().split())\r\n        a -= 1\r\n        b -= 1\r\n        graph[a].append((b, w))\r\n    \r\n    dp = [[set() for _ in range(N)] for _ in range(N + 1)]\r\n    for b, w in graph[0]:\r\n        dp[1][b].add(w)\r\n    \r\n    for i in range(1, N):\r\n        for a in range(N):\r\n            for curr_w in dp[i][a]:\r\n                for b, w in graph[a]:\r\n                    if len(dp[i + 1][b]) < 50:\r\n                        dp[i + 1][b].add(curr_w ^ w)\r\n    \r\n    ans = 1 << 60\r\n    for i in range(N + 1):\r\n        for w in dp[i][N - 1]:\r\n            ans = min(ans, w)\r\n    if ans >= 1 << 60:\r\n        ans = -1\r\n    print(ans)\r\n\r\ndef meguru(judge, ok=-1, ng=1<<60):\r\n    while abs(ok - ng) > 1:\r\n        med = (ok + ng) // 2\r\n        if judge(med):\r\n            ok = med\r\n        else:\r\n            ng = med\r\n    return ok\r\n\r\nclass TestClass(unittest.TestCase):\r\n    def test_sample1(self):\r\n        input = \"\"\"3 3\r\n1 2 4\r\n2 3 5\r\n1 3 2\"\"\"\r\n        expected = \"\"\"1\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def test_sample2(self):\r\n        input = \"\"\"4 4\r\n1 4 7\r\n4 2 2\r\n2 3 4\r\n3 4 1\"\"\"\r\n        expected = \"\"\"0\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def test_sample3(self):\r\n        input = \"\"\"999 4\r\n1 2 9\r\n2 1 8\r\n1 2 7\r\n1 1 6\"\"\"\r\n        expected = \"\"\"-1\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def judge(self, input, expected):\r\n        stdout, stdin = sys.stdout, sys.stdin\r\n        sys.stdout, sys.stdin = StringIO(), StringIO(input)\r\n        resolve()\r\n        sys.stdout.seek(0)\r\n        actual = sys.stdout.read()[:-1]\r\n        sys.stdout, sys.stdin = stdout, stdin\r\n        self.assertEqual(expected, actual)\r\n\r\nif __name__ == \"__main__\":\r\n    if \"ATCODER\" in os.environ:\r\n        resolve()\r\n    else:\r\n        unittest.main(verbosity=2)\r\n"
      - "import sys\r\nimport os\r\nfrom io import StringIO\r\nimport unittest\r\nfrom typing import *\r\n\r\nfrom bisect import *\r\nfrom collections import *\r\nfrom heapq import *\r\nfrom itertools import *\r\nfrom math import *\r\n\r\nMOD = 998244353\r\nINF = 1<<60\r\nLABC = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\"\r\nSABC = \"abcdefghijklmnopqrstuvwxyz\"\r\n\r\ndef resolve():\r\n    N, M = map(int, input().split())\r\n    graph = [[] for _ in range(N)]\r\n    for _ in range(M):\r\n        a, b, w = map(int, input().split())\r\n        a -= 1\r\n        b -= 1\r\n        graph[a].append((b, w))\r\n    \r\n    dp = [[set() for _ in range(N)] for _ in range(N + 1)]\r\n    seen = [set() for _ in range(N)]\r\n    for b, w in graph[0]:\r\n        dp[1][b].add(w)\r\n    \r\n    for i in range(1, N):\r\n        for a in range(N):\r\n            if not dp[i][a]:\r\n                continue\r\n            for curr_w in dp[i][a] - seen[a]:\r\n                for b, w in graph[a]:\r\n                    seen[a].add(curr_w)\r\n                    dp[i + 1][b].add(curr_w ^ w)\r\n    \r\n    ans = 1 << 60\r\n    for i in range(N + 1):\r\n        for w in dp[i][N - 1]:\r\n            ans = min(ans, w)\r\n    if ans >= 1 << 60:\r\n        ans = -1\r\n    print(ans)\r\n\r\ndef meguru(judge, ok=-1, ng=1<<60):\r\n    while abs(ok - ng) > 1:\r\n        med = (ok + ng) // 2\r\n        if judge(med):\r\n            ok = med\r\n        else:\r\n            ng = med\r\n    return ok\r\n\r\nclass TestClass(unittest.TestCase):\r\n    def test_sample1(self):\r\n        input = \"\"\"3 3\r\n1 2 4\r\n2 3 5\r\n1 3 2\"\"\"\r\n        expected = \"\"\"1\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def test_sample2(self):\r\n        input = \"\"\"4 4\r\n1 4 7\r\n4 2 2\r\n2 3 4\r\n3 4 1\"\"\"\r\n        expected = \"\"\"0\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def test_sample3(self):\r\n        input = \"\"\"999 4\r\n1 2 9\r\n2 1 8\r\n1 2 7\r\n1 1 6\"\"\"\r\n        expected = \"\"\"-1\"\"\"\r\n        self.judge(input, expected)\r\n\r\n    def judge(self, input, expected):\r\n        stdout, stdin = sys.stdout, sys.stdin\r\n        sys.stdout, sys.stdin = StringIO(), StringIO(input)\r\n        resolve()\r\n        sys.stdout.seek(0)\r\n        actual = sys.stdout.read()[:-1]\r\n        sys.stdout, sys.stdin = stdout, stdin\r\n        self.assertEqual(expected, actual)\r\n\r\nif __name__ == \"__main__\":\r\n    if \"ATCODER\" in os.environ:\r\n        resolve()\r\n    else:\r\n        unittest.main(verbosity=2)\r\n"
      - "a1, a2, a3 = map(int, input().split())\r\nnum1 = a2 - a1\r\nnum2 = a3 - a2\r\nnum3 = a3 - a1\r\nif num3 > 0:\r\n    if num1 <= num2:\r\n        if num3 % 2 == 0:\r\n            print(a3 - num3 // 2 - a2)\r\n        else:\r\n            print(a3 - num3 // 2 - a2 + 1)\r\n    else:\r\n        print(a2 - num2 - a1)\r\nelif num3 < 0:\r\n    if num1 <= num2:\r\n        if num3 % 2 == 0:\r\n            print(a1 + num3 // 2 - a2)\r\n        else:\r\n            print(a1 + num3 // 2 - a2 + 2)\r\n    else:\r\n        print(a2 + num1 - a3)\r\nelse:\r\n    if a1 < a2:\r\n        print((a2 - a1) * 2)\r\n    else:\r\n        print(a1 - a2)\r\n"
  - source_sentence: >-
      You are given an array of n integer numbers a0 , a1 , ..., an - 1. Find
      the distance between two closest (nearest) minimums in it. It is
      guaranteed that in the array a minimum occurs at least two times.

            Input

          The first line contains positive integer n ( 2 ≤ n ≤ 10 5) — size of the given array. The second line contains n integers a0 , a1 , ..., an - 1 ( 1 ≤ ai ≤ 10 9) — elements of the array. It is guaranteed that in the array a minimum occurs at least two times.

            Output

          Print the only number — distance between two nearest minimums in the array.

            Examples
                Input
              2
              3 3
                Output
              1
                Input
              3
              5 6 5
                Output
              2
                Input
              9
              2 1 3 5 4 1 2 3 1
                Output
              3
    sentences:
      - |-
        def is_letter(char):
            return (
                ord('a') <= ord(char) <= ord('z') or
                ord('A') <= ord(char) <= ord('Z')
            )

        n, kk = map(int, input().split())
        placement = [
            [i for i in input()] for j in range(n)
        ]


        kc = 0 

        for row in placement:
            for i in range(len(row)):
                if (row[i] == '.'):
                    count = 0
                    if (i > 0 and row[i - 1] == 'S'):
                        count += 1
                    if (i < len(row) - 1 and row[i + 1] == 'S'):
                        count += 1
                    row[i] = count
                if (row[i] == 'S'):
                    if (i > 0 and is_letter(str(row[i - 1]))):
                        kc += 1
                    if (i < len(row) - 1 and is_letter(str(row[i + 1]))):
                        kc += 1
         
        for i in range(3):
            for j in range(len(placement)):
                if (kk == 0):
                    # print(f'broken here {i}, {j}') 
                    break
                for k in range(len(placement[j])):
                    if placement[j][k] == i:
                        placement[j][k] = 'x'
                        kc += i
                        kk -= 1
                        if (kk == 0):
                            # print("broken")                    
                            break

        kkk = 0

        for i in range(len(placement)):
            for j in range(len(placement[i])):
                if type(placement[i][j]) == type(1):
                    placement[i][j] = '.'

        print(kc)
        for row in placement:
            print(''.join(row))
      - |-
        import sys
        n=int(input())
        l=list(map(int,input().split()))
        m=min(l)
        #print (m)
        indices = [i for i, x in enumerate(l) if x == m]
        #print (indices)
        mi=(sys.maxsize)
        for i in range(len(indices)-1):
            x=(indices[i+1]-indices[i])
            if x<mi:
                mi=x
        print (mi)
      - |-
        n = int(input())

        arr = list(map(int, input().split()))

        minimum = min(arr)

        index1 = arr.index(minimum)

        for i in range(index1+1, len(arr)):
         if arr[i] == minimum:
          print(i - index1)
          break
pipeline_tag: sentence-similarity
library_name: sentence-transformers

SentenceTransformer based on Salesforce/SFR-Embedding-Code-400M_R

This is a sentence-transformers model finetuned from Salesforce/SFR-Embedding-Code-400M_R on the Atcoder, Codechef and Codeforces datasets. It maps sentences & paragraphs to a 1024-dimensional dense vector space and can be used for semantic textual similarity, semantic search, paraphrase mining, text classification, clustering, and more.

Model Details

Model Description

• Model Type: Sentence Transformer
• Base model: Salesforce/SFR-Embedding-Code-400M_R
• Maximum Sequence Length: 8192 tokens
• Output Dimensionality: 1024 dimensions
• Similarity Function: Cosine Similarity
• Training Datasets:
  • Atcoder
  • Codechef
  • Codeforces

Model Sources

• Documentation: Sentence Transformers Documentation
• Repository: Sentence Transformers on GitHub
• Hugging Face: Sentence Transformers on Hugging Face

Full Model Architecture

SentenceTransformer(
  (0): Transformer({'max_seq_length': 8192, 'do_lower_case': False, 'architecture': 'NewModel'})
  (1): Pooling({'word_embedding_dimension': 1024, 'pooling_mode_cls_token': True, 'pooling_mode_mean_tokens': False, 'pooling_mode_max_tokens': False, 'pooling_mode_mean_sqrt_len_tokens': False, 'pooling_mode_weightedmean_tokens': False, 'pooling_mode_lasttoken': False, 'include_prompt': True})
)

Usage

Direct Usage (Sentence Transformers)

First install the Sentence Transformers library:

pip install -U sentence-transformers

Then you can load this model and run inference.

from sentence_transformers import SentenceTransformer

# Download from the 🤗 Hub
model = SentenceTransformer("Nan-Do/CP-Ranker")
# Run inference
sentences = [
    'You are given an array of n integer numbers a0 , a1 , ..., an - 1. Find the distance between two closest (nearest) minimums in it. It is guaranteed that in the array a minimum occurs at least two times.\n\n      Input\n\n    The first line contains positive integer n ( 2 ≤ n ≤ 10 5) — size of the given array. The second line contains n integers a0 , a1 , ..., an - 1 ( 1 ≤ ai ≤ 10 9) — elements of the array. It is guaranteed that in the array a minimum occurs at least two times.\n\n      Output\n\n    Print the only number — distance between two nearest minimums in the array.\n\n      Examples\n          Input\n        2\n        3 3\n          Output\n        1\n          Input\n        3\n        5 6 5\n          Output\n        2\n          Input\n        9\n        2 1 3 5 4 1 2 3 1\n          Output\n        3',
    'import sys\nn=int(input())\nl=list(map(int,input().split()))\nm=min(l)\n#print (m)\nindices = [i for i, x in enumerate(l) if x == m]\n#print (indices)\nmi=(sys.maxsize)\nfor i in range(len(indices)-1):\n    x=(indices[i+1]-indices[i])\n    if x<mi:\n        mi=x\nprint (mi)',
    'n = int(input())\n\narr = list(map(int, input().split()))\n\nminimum = min(arr)\n\nindex1 = arr.index(minimum)\n\nfor i in range(index1+1, len(arr)):\n if arr[i] == minimum:\n  print(i - index1)\n  break',
]
embeddings = model.encode(sentences)
print(embeddings.shape)
# [3, 1024]

# Get the similarity scores for the embeddings
similarities = model.similarity(embeddings, embeddings)
print(similarities)
# tensor([[1.0000, 1.0000, 1.0000],
#         [1.0000, 1.0000, 1.0000],
#         [1.0000, 1.0000, 1.0000]])

Training Details

Training Datasets

Atcoder

• Dataset: Atcoder
• Size: 526,607 training samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 1000 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 91 tokens mean: 387.42 tokens max: 1533 tokens	min: 15 tokens mean: 270.5 tokens max: 2785 tokens	min: 9 tokens mean: 264.89 tokens max: 2839 tokens

• Samples:

  anchor	positive	negative
  You are given N strings W_1,W_2,\dots,W_N consisting of lowercase English letters. If one or more of these strings equal and, not, that, the, or you, then print Yes; otherwise, print No. Constraints * N is an integer between 1 and 100, inclusive. * 1 \le |W_i| \le 50 (|W_i| is the length of W_i.) * W_i consists of lowercase English letters. Input The input is given from Standard Input in the following format: N
  W_1 W_2 \dots W_N
  Output Print the answer. Sample Input 1 10
  in that case you should print yes and not no
  Sample Output 1 Yes
  We have, for instance, W_4= you, so you should print Yes. Sample Input 2 10
  in diesem fall sollten sie no und nicht yes ausgeben
  Sample Output 2 No
  None of the strings W_i equals any of and, not, that, the, and you.	N = int(input())
  W = input().split()
  C = ["and", "not", "that", "the", "you"]
  i = 0
  ans = "No"
  for i in range(N):
  j = 0
  for j in range(5):
  if W[i] == C[j]:
  ans = "Yes"
  break
  print(ans)	N = int(input())
  W = input().split()
  C = ["and", "not", "that", "the", "you"]
  i = 0
  ans = "No"
  for i in range(N):
  j = 0
  for j in range(4):
  if W[i] == C[j]:
  ans = "Yes"
  break
  print(ans)
  Takahashi has two integers X and Y. He computed X + Y and X - Y, and the results were A and B, respectively. Now he cannot remember what X and Y were. Find X and Y for him. Constraints * -100 \leq A, B \leq 100 * For the given integers A and B, there uniquely exist integers X and Y such that X + Y = A and X - Y = B. * All values in input are integers. Input Input is given from Standard Input in the following format: A B
  Output Print X and Y. Sample Input 1 2 -2
  Sample Output 1 0 2
  If X = 0 and Y = 2, they match the situation: 0 + 2 = 2 and 0 - 2 = -2. Sample Input 2 3 1
  Sample Output 2 2 1	a , b= input().split() a= int(a) ; b= int(b) x= (a+b)/2 y= a - x x= int(x) ; y= int(y) print(x , y)	a, b, x, y = input().split() a = int(a) b = int(b) x = int((a + b)/2) y = a - 2 print(x, y)
  In the year 2168, AtCoder Inc., which is much larger than now, is starting a limited express train service called AtCoder Express. In the plan developed by the president Takahashi, the trains will run as follows: * A train will run for (t_1 + t_2 + t_3 + ... + t_N) seconds. * In the first t_1 seconds, a train must run at a speed of at most v_1 m/s (meters per second). Similarly, in the subsequent t_2 seconds, a train must run at a speed of at most v_2 m/s, and so on. According to the specifications of the trains, the acceleration of a train must be always within ±1m/s^2. Additionally, a train must stop at the beginning and the end of the run. Find the maximum possible distance that a train can cover in the run. Constraints * 1 \leq N \leq 100 * 1 \leq t_i \leq 200 * 1 \leq v_i \leq 100 * All input values are integers. Input Input is given from Standard Input in the following format: N
  t_1 t_2 t_3 … t_N
  v_1 v_2 v_3 … v_N
  ...	from sys import stdin,stdout
  raw_input = lambda: stdin.readline().rstrip()
  input = lambda: int(raw_input())
  I=lambda: list(map(int, raw_input().split()))
  P=lambda x: stdout.write(str(x)+'\n')
  def solve():
  n = input()
  tLst = I()
  vLst = I()
  qLst1 = [0]
  prevV = 0
  for i in range(n):
  curV = vLst[i]
  curT = tLst[i]
  if i
  nextV = vLst[i+1]
  else:
  nextV = 0
  prevV = min(prevV+curT, curV, nextV)
  qLst1.append(prevV)
  nextV = 0
  qLst2 = [0]
  for i in range(n-1, -1, -1):
  curV = vLst[i]
  curT = tLst[i]
  if i>0:
  prevV = vLst[i-1]
  else:
  prevV = 0
  nextV = min(nextV+curT, curV, prevV)
  qLst2.append(nextV)
  qLst2.reverse()
  newVLst = []
  for i in range(n+1):
  newVLst.append(min(qLst1[i], qLst2[i]))
  res = 0
  for i in range(n):
  curV = vLst[i]
  prevV = newVLst[i]
  nextV = newVLst[i+1]
  curT = tLst[i]
  if prevV
  t1 = curV-prevV
  else:
  t1 = 0
  if curV>nextV:
  t2 = max(0, curT-(curV-nextV...	from sys import stdin,stdout
  raw_input = lambda: stdin.readline().rstrip()
  input = lambda: int(raw_input())
  I=lambda: list(map(int, raw_input().split()))
  P=lambda x: stdout.write(str(x)+'\n')
  def solve():
  n = input()
  tLst = I()
  vLst = I()
  res = 0
  prevV = 0
  for i in range(n-1, -1, -1):
  curV = vLst[i]
  curT = tLst[i]
  if i
  nextV = vLst[i+1]
  nextT = tLst[i+1]
  else:
  nextV = 0
  nextT = 0
  if i==0:
  prevV = 0
  prevT = 0
  else:
  prevV = vLst[i-1]
  prevT = tLst[i-1]
  if prevV
  t1 = curV-prevV
  else:
  t1 = 0
  if curV>nextV:
  t2 = max(0, curT-(curV-nextV))
  else:
  t2 = curT
  # print(t1, t2, prevV, curV, nextV)
  if t1<=t2:
  res += ((t1*(prevV+curV))/2.0 + (t2-t1)curV + ((curT-t2)(nextV+curV))/2.0)
  else:
  q = (nextV-prevV+curT)/2.0
  q = min(curT, q)
  q = max(0, q)
  res += ((q*(prevV+prevV+q))/2.0 + (curT-q)*((prevV+q+nextV)/2.0))
  prevV = curV
  print(res)
  solve()

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Codechef

• Dataset: Codechef
• Size: 75,369 training samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 1000 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 165 tokens mean: 591.51 tokens max: 1588 tokens	min: 21 tokens mean: 233.13 tokens max: 3803 tokens	min: 2 tokens mean: 227.66 tokens max: 3791 tokens

• Samples:

  anchor	positive	negative
  Find the Special Node This is an interactive task There is a tree consisting of $N$ nodes. A certain node $X$ is marked as special, but you don't know $X$ - your task is to find it. To achieve this, you can ask queries to obtain information about $X$. To be specific, you can ask queries in the form: ? Y where $1 \le Y \le N$, and you will be provided with a random node on the path from node $Y$ to node $X$, excluding $Y$. If $Y = X$ you will receive $-1$ instead. You can ask at most $12$ queries. Find the special node $X$. Note: The judge is not adaptive, i.e, node $X$ is chosen at the start before any interaction happens and does not change based on the queries you ask. ### Interaction - Begin the interaction by reading a single integer $T$ denoting the number of test cases. The test cases follow. - For each test case, first read a single integer $N$ denoting the number of nodes in the tree. - $N - 1$ lines follow. The $i^{th}$ of these lines contains two space-separat...	from sys import stdin
  input = stdin.readline
  def query(x):
  print('?' , x , flush = True)
  return int(input())
  def dfs(p , prev):
  global total
  par[p] = prev
  total += 1
  ans = 0
  for i in child[p]:
  if(i == prev or v[i]):continue
  ans += dfs(i , p)
  subsize[p] = ans + 1
  return ans + 1
  def centroid():
  msub = float('inf')
  for i in range(1 , n + 1):
  if(v[i]):continue
  yes , sub , mval = True , 0 , 0
  for j in child[i]:
  if(j == par[i] or v[j]):continue
  sub += subsize[j]
  mval = max(mval , subsize[j])
  mval = max(mval , total - sub)
  if(msub > mval):
  msub = mval
  center = i
  return center
  def setdfs(p , prev , node):
  if(p == node):return
  v[p] = True
  for i in child[p]:
  if(i == prev or v[i]):continue
  setdfs(i , p , node)
  def answer...	from sys import stdin
  input = stdin.readline
  def query(x):
  print('?' , x , flush = True)
  return int(input())
  def dfs(p , prev):
  global total
  par[p] = prev
  total += 1
  ans = 0
  for i in child[p]:
  if(i == prev or v[i]):continue
  ans += dfs(i , p)
  subsize[p] = ans + 1
  return ans + 1
  def centroid():
  msub = float('inf')
  for i in range(1 , n + 1):
  if(v[i]):continue
  yes , sub , mval = True , 0 , 0
  for j in child[i]:
  if(j == par[i] or v[j]):continue
  sub += subsize[j]
  mval = max(mval , subsize[j])
  mval = max(mval , total - sub)
  if(msub > mval):
  msub = mval
  center = i
  return center
  def setdfs(p , prev , c):
  if(p == c):return
  v[p] = False
  for i in child[p]:
  if(i == prev):continue
  setdfs(i , p , c)
  def answer():
  global ...
  Beautification of array Chef has an array and he also likes beautiful things. So he wants to make his array as beautiful as possible. He defines the $Beauty$ of his array as the sum of all pairwise products of the elements of the array. $$ Beauty([A_1, A_2, \dots, A_N]) = \displaystyle\sum\limits_{i=1}^N\displaystyle\sum\limits_{j=i+1}^N A[i] \cdot A[j] $$ To make his array more beautiful, he can do the following operation at most $K$ times:<br>In a single operation, he can increase any element of the array by $1$. That is, he can select any $i$, $1 \leq i \leq N$, and change $A_i$ to $A_i + 1$. Given the original array that Chef has, and $K$, find the maximum $Beauty$ that he can achieve after applying at most $K$ operations. Since the answer might be large, output it modulo $10^9 + 7$. Input Format: - The first line of input will contain a single integer $T$, denoting the number of test cases. - The first line of each testcase contains two integers $N$ and $K$, the size of the ...	def solve(A, n, budget):
  A.sort()
  prefix_sum = [0] * (n + 1)
  for i in range(n):
  prefix_sum[i + 1] = prefix_sum[i] + A[i]
  def bisect_left(lo, hi, predicate):
  while lo < hi:
  mid = (lo + hi) // 2
  if predicate(mid):
  lo = mid + 1
  else:
  hi = mid
  return lo
  lo = A[0]
  hi = A[n - 1] + budget + 1
  def cost(floor):
  x = bisect_left(0, n, lambda x: A[x] < floor)
  return floor * x - prefix_sum[x]
  def predicate(floor):
  return cost(floor) <= budget
  floor = bisect_left(lo, hi, predicate) - 1
  count_le = bisect_left(0, n, lambda x: A[x] <= floor)
  expend = cost(floor)
  remain = budget - expend
  extra, remainder = divmod(remain, count_le)
  B = [max(floor, a) + extra + (i < remainder) for i, a in enumerate(A)]
  prefix_sum_B = [0] * (n + 1)
  for i in range(n):
  prefix_sum_B[i + 1] = prefix...	import sys
  def finish(i,j):
  print 2, i, j
  sys.stdout.flush()
  sys.exit(0)
  def request(i, j, V):
  print 1,i,j
  sys.stdout.flush()
  a = int(raw_input())
  if a == V:
  finish(i,j)
  return a
  def solve(N, K, V, req = request):
  if K < N*N:
  solve_final(N, K, V, req)
  else:
  solve_brute(N, K, V, req)
  def solve_brute(N, K, V, req = request):
  if K < N*N:
  print 2, -1, -1
  return
  for i in xrange(1, N+1):
  for j in xrange(1, N+1):
  req(i, j, V)
  print 2, -1, -1
  class Solver(object):
  def init(self, N, K, V, req = None):
  self.N = N
  self.K = K
  self.V = V
  self.A = [[0]*N for _ in xrange(N)]
  self.row_acc = [True]*(N)
  self.col_acc = [True]*(N)
  self.row_ranges = [[0,N-1] for _ in xrange(N)]
  self.col_ranges = [[0,N-1] for _ in xrange(N)]
  self.req = re...
  Double Trouble Alice has $N$ magical balls placed on the $x$-axis. The $i$-th ball is initially at position $X_i$ and has a power of $P_i$. It is guaranteed that $X_i \lt X_{i+1}$ for $1 \leq i \lt N$. Initially, none of the balls are activated. Alice can do the following at most twice: - Choose an index $i$ ($1 \leq i \leq N$) such that ball $i$ is not activated. - Activate ball $i$, and choose a direction for it (either right or left). When ball $i$ is activated in a certain direction, the following process takes place: - The ball will move $P_i$ units in the chosen direction. - If, while moving, it strikes another ball $j$, ball $i$ will immediately disappear. Then, - If ball $j$ was previously activated, nothing happens, and the process immediately ends. - Otherwise, ball $j$ activates in the same direction as ball $i$ (that is, if ball $i$ was moving left, ball $j$ will move left too). Note that the power of ball $j$ doesn't change, and remains $P_j$. - If it ...	# cook your dish here
  t=int(input())
  def find(pos,power,n):
  ans_exist=0
  right_stop=-1
  left_stop=n
  for i in range(n):
  if i==n-1:
  ans_exist=1
  elif i=pos[i+1]:
  continue
  else:
  right_stop=i
  for j in range(i+1,n):
  if j==n-1:
  ans_exist=1
  elif j=pos[j+1]:
  continue
  else:
  break
  break
  for k in range(n-1,-1,-1):
  if k==0:
  ans_exist=1
  elif k>0 and pos[k]-power[k]<=pos[k-1]:
  continue
  else:
  left_stop=k
  for l in range(k-1,-1,-1):
  if l==0:
  ans_exist=1
  elif l>0 and pos[l]-power[l]<=pos[l-1]:
  continue
  else:
  break
  ...	# cook your dish here
  t=int(input())
  def find(pos,power,n):
  ans_exist=0
  for i in range(n):
  if i==n-1:
  ans_exist=1
  elif pos[i]+power[i]>=pos[i+1]:
  continue
  else:
  right_stop=i
  for j in range(i+1,n):
  if j==n-1:
  ans_exist=1
  elif pos[j]+power[j]>=pos[j+1]:
  continue
  else:
  break
  break
  for k in range(n-1,-1,-1):
  if k==0:
  ans_exist=1
  elif k>0 and pos[k]-power[k]<=pos[k-1]:
  continue
  else:
  left_stop=k
  for l in range(k-1,-1,-1):
  if l==0:
  ans_exist=1
  elif pos[l]-power[l]<=pos[l-1]:
  continue
  else:
  break
  break
  if right_stop>=left_stop:
  ans_exist= ...

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Codeforces

• Dataset: Codeforces
• Size: 263,242 training samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 1000 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 38 tokens mean: 361.54 tokens max: 2342 tokens	min: 10 tokens mean: 127.68 tokens max: 1826 tokens	min: 8 tokens mean: 131.15 tokens max: 1384 tokens

• Samples:

  anchor	positive	negative
  Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word. Note, that during capitalization all the letters except the first one remains unchanged. Input A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 10 3. Output Output the given word after capitalization. Examples Input ApPLe Output ApPLe Input konjac Output Konjac	def wordCapitalization(str) : return str[0].upper() + str[1:] inputword = input() print(wordCapitalization(inputword))	str=input() s=str[0].uppar+str[1:] print(s) #3t
  You are given a rectangular board of M × N squares. Also you are given an unlimited number of standard domino pieces of 2 × 1 squares. You are allowed to rotate the pieces. You are asked to place as many dominoes as possible on the board so as to meet the following conditions: 1. Each domino completely covers two squares. 2. No two dominoes overlap. 3. Each domino lies entirely inside the board. It is allowed to touch the edges of the board. Find the maximum number of dominoes, which can be placed under these restrictions. Input In a single line you are given two integers M and N — board sizes in squares ( 1 ≤ M ≤ N ≤ 16 ). Output Output one number — the maximal number of dominoes, which can be placed. Examples Input 2 4 Output 4 Input 3 3 Output 4	a,b=map(int,input().split()) c=0 while(a>=2): c+=b a=a-2 if(a==1): while(b>=2): c+=1 b=b-2 print(c)	a = input() a=a.replace(' ','') k=int(a[0])*int(a[1]) print(int(k/2))
  One day, Twilight Sparkle is interested in how to sort a sequence of integers a1 , a2 , ..., an in non-decreasing order. Being a young unicorn, the only operation she can perform is a unit shift. That is, she can move the last element of the sequence to its beginning: a1 , a2 , ..., an → an , a1 , a2 , ..., an - 1 . Help Twilight Sparkle to calculate: what is the minimum number of operations that she needs to sort the sequence? Input The first line contains an integer n (2 ≤ n ≤ 10 5 ) . The second line contains n integer numbers a1 , a2 , ..., an (1 ≤ ai ≤ 10 5 ) . Output If it's impossible to sort the sequence output -1 . Otherwise output the minimum number of operations Twilight Sparkle needs to sort it. Examples Input 2 2 1 Output 1 Input 3 1 3 2 Output -1 Input 2 1 2 Output 0	n = int(input()) a = [int(i) for i in input().split()] out = 0 inc_ord = True for i in range(n-1): if inc_ord: if a[i]>a[i+1]: inc_ord = False out = i+1 if a[i+1] > a[0]: out = -1 break else: if a[i+1]>a[0] or a[i] > a[i+1]: out = -1 break if(out <= 0) : print(out) else: print(n-out)	n=int(input()) l=list(map(int,input().split())) s=sorted(l) if s==l: print(0) else: c=0 f=0 o='' for i in range(n): c=c+1 if l[n-1-i:n]+l[0:n-i-1]==s: f=1 break if f: print(c) else: print(-1)

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Evaluation Datasets

Atcoder

• Dataset: Atcoder
• Size: 5,320 evaluation samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 1000 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 91 tokens mean: 382.01 tokens max: 1406 tokens	min: 14 tokens mean: 260.01 tokens max: 2920 tokens	min: 14 tokens mean: 262.16 tokens max: 3098 tokens

• Samples:

  anchor	positive	negative
  You are given a sequence A of non-negative integers of length N, and an integer K. It is guaranteed that the binomial coefficient \dbinom{N}{K} is at most 10^6. When choosing K distinct elements from A, find the maximum possible value of the XOR of the K chosen elements. That is, find \underset{1\leq i_1\lt i_2\lt \ldots\lt i_K\leq N}{\max} A_{i_1}\oplus A_{i_2}\oplus \ldots \oplus A_{i_K}. About XOR For non-negative integers A,B, the XOR A \oplus B is defined as follows: * In the binary representation of A \oplus B, the bit corresponding to 2^k (k \ge 0) is 1 if and only if exactly one of the bits corresponding to 2^k in A and B is 1, and is 0 otherwise. For example, 3 \oplus 5 = 6 (in binary notation: 011 \oplus 101 = 110). In general, the XOR of K integers p_1, \dots, p_k is defined as (\cdots((p_1 \oplus p_2) \oplus p_3) \oplus \cdots \oplus p_k). It can be proved that it does not depend on the order of p_1, \dots, p_k. Constraints * 1\leq K\leq N\leq 2\tim...	import itertools
  N, K = map(int, input().split())
  A = list(map(int, input().split()))
  ans = 0
  if K <= N - K:
  for a in itertools.combinations(A, K):
  xor = 0
  for i in a:
  xor ^= i
  ans = max(ans, xor)
  else:
  all_xor = 0
  for i in range(N):
  all_xor ^= A[i]
  for a in itertools.combinations(A, N - K):
  xor = all_xor
  for i in a:
  xor ^= i
  ans = max(ans, xor)
  print(ans)
  	from itertools import combinations
  N, K = map(int, input().split())
  A = list(map(int, input().split()))
  xA = [[0]*60 for _ in range(N)]
  for i in range(N):
  for j in range(60):
  xA[i][j] = (A[i] >> j) & 1
  ans = 0
  if K <= N - K:
  for c in combinations(range(N), K):
  count = [0] * 60
  for i in range(K):
  ci = c[i]
  for j in range(60):
  count[j] += xA[ci][j]
  x = 0
  for j in range(60):
  if count[j] % 2 == 1:
  x += 1 << j
  ans = max(ans, x)
  else:
  count = [0] * 60
  for i in range(K):
  for j in range(60):
  count[j] += xA[i][j]
  x = 0
  for j in range(60):
  if count[j] % 2 == 1:
  x += 1 << j
  sum_ = x
  for c in combinations(range(N), N-K):
  count = [0] * 60
  for i in range(N-K):
  ci = c[i]
  for j in range(60):
  ...
  You are given integers x_1, x_2, and x_3. For these integers, you can perform the following operation any number of times, possibly zero. * Choose a permutation (i,j,k) of (1,2,3), that is, a triple of integers (i,j,k) such that 1\leq i,j,k\leq 3 and i\neq j, i\neq k, j\neq k. * Then, simultaneously replace x_i with x_i+3, x_j with x_j+5, and x_k with x_k+7. Your objective is to satisfy x_1=x_2=x_3. Determine whether it is achievable. If it is, print the minimum number of times you need to perform the operation to achieve it. You have T test cases to solve. Constraints * 1\leq T\leq 2\times 10^5 * 1\leq x_1, x_2, x_3 \leq 10^9 Input The input is given from Standard Input in the following format: T
  \text{case}_1
  \vdots
  \text{case}_T
  Each test case is in the following format: x_1 x_2 x_3
  Output Print T lines. The i-th line should contain the following value for the i-th test case. * The minimu...	import bisect, collections, copy, heapq, itertools, math, sys sys.setrecursionlimit(107) input = sys.stdin.readline # P = 109+7 P = 998244353 T = int(input()) for _ in range(T): A = list(map(int, input().split())) if A[0]%2 != A[1]%2 or A[0]%2 != A[2]%2: print(-1) continue A.sort() ans = min(A[2]-A[1], A[1]-A[0])//2 t = max(A[2]-A[1], A[1]-A[0]) - min(A[2]-A[1], A[1]-A[0]) if t%6 == 0: print(ans + t//3) else: print(-1)	import bisect, collections, copy, heapq, itertools, math, sys sys.setrecursionlimit(107) input = sys.stdin.readline # P = 109+7 P = 998244353 T = int(input()) for _ in range(T): A = list(map(int, input().split())) if A[0]%2 != A[1]%2 or A[0]%2 != A[2]%2: print(-1) continue ans = 0 if A[2]-A[1] < A[1]-A[0]: ans += (A[2]-A[1])//2 A[0] += A[2]-A[1] A[2] = A[1] elif A[1]-A[0] < A[2]-A[1]: ans += (A[1]-A[0])//2 A[2] -= A[1]-A[0] A[0] = A[1] if (A[1]-A[0])%6 + (A[2]-A[1])%6 == 0: ans += ((A[1]-A[0])//6 + (A[2]-A[1])//6)*2 print(ans) else: print(-1)
  A positive integer not less than 10 whose top digit (the most significant digit) in decimal representation is strictly larger than every other digit in that number is called a Snake number. For example, 31 and 201 are Snake numbers, but 35 and 202 are not. Find how many Snake numbers exist between L and R, inclusive. Constraints * 10 \leq L \leq R \leq 10^{18} * All input values are integers. Input The input is given from Standard Input in the following format: L R Output Print the answer. Sample Input 1 97 210 Sample Output 1 6 The Snake numbers between 97 and 210, inclusive, are 97, 98, 100, 200, 201, and 210: there are six. Sample Input 2 1000 9999 Sample Output 2 2025 Sample Input 3 252509054433933519 760713016476190692 Sample Output 3 221852052834757	def count(r):
  def conv(limit, org): # 最大のヘビ数に変換
  i = next((i+1 for i in range(len(org)-1, -1, -1) if org[i] > limit), 0)
  return [limit]*i + org[i:]
  rev = [*map(int, str(r)[::-1])]
  top = rev.pop()
  n = len(rev)
  rev = conv(top-1, rev)
  # print(f'{r=} {top=} {rev=}')
  ret = 0
  while n:
  # print(f'{n=} {top=} {rev=}')
  for d0 in range(top, 0, -1):
  # print(f'{d0=} {rev=}')
  c1 = 1
  c2 = sum(d*d0**j for j, d in enumerate(rev))
  d = c1+c2
  ret += d
  rev = [d0-2]*n
  # print(f'{c1,c2=} {d=} {ret=}')
  top = 9
  n -= 1
  rev = [8]*n
  # print(f'---------------')
  # print(f'{r=} {ret=}')
  # print(f'========')
  return ret
  L, R = map(int, input().split())
  print(count(R) - count(L-1))	from functools import cache
  @cache
  def dfs(top, limit, i, rev, s):
  # print(f'{top=} {limit=} {i=} {rev=} {s=}')
  # print(f'{top=} {limit=} {i=} {R=} {s=}')
  if i == -1:
  return 1
  ret = 0
  # ri = int(R[i])
  # ri = int(ri)
  # limit = limit*10 + int(ri)
  ri = rev % 10
  nrev = rev//10
  limit = limit*10 + ri
  for d in range(0, top):
  ns = s*10 + d
  # print(f'{s=} {d=} {ns=} {limit=}')
  if ns <= limit:
  ret += dfs(top, limit, i-1, nrev, ns)
  # ret += dfs(top, limit, i-1, R, ns)
  # else:
  # print(f'out range! ===========')
  return ret
  def f(org):
  # print(f'{org=}')
  R = str(org)
  R = [int(r) for r in R[::-1]]
  top = R[-1]
  r = R.pop()
  n = len(R)
  # print(f'{R=} {r=} {top=}')
  # print(f'x1 -------------')
  rev = int(str(org)[::-1])//10
  x1 = dfs(top, top, n-1, rev, top)
  # r = R.pop()
  r -= 1
  # print(f'...

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Codechef

• Dataset: Codechef
• Size: 762 evaluation samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 762 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 174 tokens mean: 600.35 tokens max: 1588 tokens	min: 21 tokens mean: 234.42 tokens max: 3698 tokens	min: 2 tokens mean: 234.5 tokens max: 2887 tokens

• Samples:

  anchor	positive	negative
  Palindromic Score Alice has three types of characters: $A$, $B$ and $C$. She is given exactly $X$ copies of $A$, $Y$ copies of $B$, and $Z$ copies of $C$. Alice must use all these characters to form a string. She is free to arrange the characters in any order of her choosing. After Alice forms her string, Bob makes a move. Bob will choose one character type from { $A$, $B$, $C$ } and delete all its occurrences from the string. Alice’s final score is defined as the length of the longest palindromic subsequence of the string after Bob’s deletion. Both players play optimally: - Alice’s goal is to arrange characters to maximize her final score. - Bob’s goal is to choose a character to delete such that Alice’s score is minimized. Determine the maximum achievable score that Alice can obtain through her optimal arrangement of characters. --- A palindromic $^{\dagger}$subsequence is a subsequence which reads the same from left to right and right to left. $^{\dagger}$ A string $T$ ...	# cook your dish here
  for _ in range(int(input())):
  a=list(map(int,input().split()))
  k=max(a)
  a.remove(k)
  m,n=a[0],a[1]
  if m&1 and n&1:
  print(m+n-1)
  else:
  print(m+n)
  	# cook your dish here
  for _ in range(int(input())):
  x=map(int,input().split())
  c=0
  m=0
  x,y,z=sorted(x)
  if x&1 and y&1:
  print(max(x+y-1))
  elif x&1 :
  print(x+y)
  elif y&1:
  print(x+y)
  else:
  print(max(0,x+y))
  Make Permutation Chef has an array $A$ of size $N$. He wants to make a permutation$^{\dagger}$ using this array. Find whether there exists an array $B$ consisting of $N$ non-negative integers, such that the array $C$ constructed as $C_i = A_i + B_i$ is a permutation. $^{\dagger}$ A permutation of size $N$ is an array of $N$ distinct elements in the range $[1, N]$. For example, $[4, 2, 1, 3]$ is a permutation of size $4$, while $[3, 2, 2, 1]$ and $[1, 3, 4]$ are not. Input Format: - The first line of input will contain a single integer $T$, denoting the number of test cases. - Each test case consists of multiple lines of input. - The first line of each test case consists of $N$ - the size of the array $A$ - The next line contains $N$ space-separated integers - $A_1, A_2, \ldots, A_N$ - the elements of array $A$. Output Format: For each test case, output YES if there exists an array $B$ such that array $C$ constructed as $C_i = A_i + B_i$ is a permutation, otherwise output...	while True:
  try:
  T=int(input())
  if(1<=T<=100):
  break
  except valueError:
  continue
  for j in range(T):
  while True:
  try:
  N=int(input())
  if(1<=N<=100):
  break
  except valueError:
  continue
  lst=list(map(int,input().split()))
  #print(lst)
  lst.sort()
  flag=1
  for i in range(N):
  if((lst[i]>(i+1))):
  flag=0
  break
  if(flag==0):
  print("NO")
  else:
  print("YES")	while True:
  try:
  T=int(input())
  if(1<=T<=100):
  break
  except valueError:
  continue
  while True:
  try:
  N=int(input())
  if(1<=N<=100):
  break
  except valueError:
  continue
  lst=map(int,input().split())
  lst.sort()
  flag=1
  for i in range(N):
  if(!(lst[i]<=(i+1))):
  flag=0
  break
  if(flag=0):
  print("NO")
  else:
  print("YES")
  Array Concatanation Count the number of boolean arrays with $a$ zeroes and $b$ ones, such that the following holds. Let $A$ be the boolean array and $A_i$ = $\text{subarray}$($A_1$, $A_2$ .... $A_i$). Concatenate $A_1$, $A_2$ ... $A_{a+b}$ and call this array $B$. The number of ones on odd and even indexes in the array $B$ are equal. Print the answer modulo $1000000007$. Note: $a$ + $b$ is always even. Input Format: - The first line of input will contain a single integer $T$, denoting the number of test cases. - Each test case consists of one line of input. - The first line and only line of each test case contain two integers $a$ and $b$. Output Format: For each test case, output on a new line the answer to the problem. Constraints: - $1 \leq T \leq 100$ - $0 \leq a \leq 210^{6}$ - $0 \leq b \leq 210^{6}$ - $a + b > 0$ - $a + b$ is even. - The sum of $a + b$ over all test cases won't exceed $2 \cdot 10^6$. Sample 1: Input: 3 2 2 1 5 1005 2005 Output: 2 2 7497456...	import sys
  from collections import defaultdict,deque,Counter
  from heapq import heappush,heappop,heapify
  from math import inf,comb,ceil,log,lcm,gcd
  from functools import cache
  from itertools import accumulate,combinations,permutations
  from bisect import bisect_left,bisect_right,insort_left
  from random import randint
  input=lambda:sys.stdin.readline().rstrip()
  inp=lambda:map(int,input().split())
  t=int(input())
  xor=randint(1,2**32-1)
  mod=10**9+7
  #0 -> 0 1 3 6
  #a[i] -> vi,vi+(i+1),vi+(i+1)+(i+2)...(n-i termes) vi=(i+1)(i+2)//2-1
  #1 3 6 10 15 21
  #1 1 0 0 1 1..
  #0 0 1 1 0 0
  #1 1 -1 -1 1 1 0 0 ...
  for _ in range(t):
  a,b=inp()
  n=a+b
  v1=v2=z=0
  for i in range(n):
  if i%2==0:
  z+=1
  else:
  #x=(i+1)*(i+2)//2-1
  if (i+1)%4==0:
  v1+=1
  else:
  v2+=1
  v1,v2=sorted([v1,v2])
  combs=[1]*(n+1)
  combs2=[1]*(n+1)
  combs3=[1]*(n+1)
  for i in range(1,max(v...	import sys
  from collections import defaultdict,deque,Counter
  from heapq import heappush,heappop,heapify
  from math import inf,comb,ceil,log,lcm,gcd
  from functools import cache
  from itertools import accumulate,combinations,permutations
  from bisect import bisect_left,bisect_right,insort_left
  from random import randint
  input=lambda:sys.stdin.readline().rstrip()
  inp=lambda:map(int,input().split())
  t=int(input())
  xor=randint(1,2**32-1)
  mod=10**9+7
  #0 -> 0 1 3 6
  #a[i] -> vi,vi+(i+1),vi+(i+1)+(i+2)...(n-i termes) vi=(i+1)(i+2)//2-1
  #1 3 6 10 15 21
  #1 1 0 0 1 1..
  #0 0 1 1 0 0
  #1 1 -1 -1 1 1 0 0 ...
  for _ in range(t):
  a,b=inp()
  n=a+b
  v1=v2=z=0
  for i in range(n):
  if i%2==0:
  z+=1
  else:
  x=(i+1)*(i+2)//2-1
  if x%2:
  v1+=1
  else:
  v2+=1
  v1,v2=sorted([v1,v2])
  combs=[1]*(n+1)
  combs2=[1]*(n+1)
  combs3=[1]*(n+1)
  for i in range(1,n+1):
  ...

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Codeforces

• Dataset: Codeforces
• Size: 2,660 evaluation samples
• Columns: anchor, positive, and negative
• Approximate statistics based on the first 1000 samples:

  	anchor	positive	negative
  type	string	string	string
  details	min: 38 tokens mean: 347.2 tokens max: 2342 tokens	min: 13 tokens mean: 130.04 tokens max: 1826 tokens	min: 8 tokens mean: 134.53 tokens max: 1572 tokens

• Samples:

  anchor	positive	negative
  Vasiliy spent his vacation in a sanatorium, came back and found that he completely forgot details of his vacation! Every day there was a breakfast, a dinner and a supper in a dining room of the sanatorium (of course, in this order). The only thing that Vasiliy has now is a card from the dining room contaning notes how many times he had a breakfast, a dinner and a supper (thus, the card contains three integers). Vasiliy could sometimes have missed some meal, for example, he could have had a breakfast and a supper, but a dinner, or, probably, at some days he haven't been at the dining room at all. Vasiliy doesn't remember what was the time of the day when he arrived to sanatorium (before breakfast, before dinner, before supper or after supper), and the time when he left it (before breakfast, before dinner, before supper or after supper). So he considers any of these options. After Vasiliy arrived to the sanatorium, he was there all the time until he left. Please note, that it's...	def hren(): input_list = input().split(' ') supper = [int(x.strip()) for x in input_list] supper.sort(reverse=True) result = supper[0] - supper[1] + supper[0] - supper[2] if supper[0] != supper[1]: result -= 1 if supper[0] != supper[2]: result -= 1 return result if name == 'main': print(hren())	def main(arr,i,a): # # # f = arr[0][0] m = arr[1][0] a = arr[2][0] fc,mc,ac = 0,0,0 while True: if f == max(f,m,a) and abs(max(f,m,a)-min(f,m,a)) > 0 and fc < 1: f-=1 fc+=1 if m == max(f,m,a) and abs(max(f,m,a)-min(f,m,a)) > 0 and mc < 2: m-=1 mc+=1 if a == max(f,m,a) and abs(max(f,m,a)-min(f,m,a)) > 0 and ac < 1: a-=1 ac+=1 else: break print(abs(max(f,m,a)-min(f,m,a))) # # # # # I = 0 a = 0 ARR = [] #I = len(ARR) #a = int(input()) ARR = input().split(' ') #for x in range(a): ARR.append(input()) for x in range(len(ARR)): ARR[x] = ARR[x].split() ARR[x] = [int(y) for y in ARR[x]] main(ARR,I,a)
  To make a paper airplane, one has to use a rectangular piece of paper. From a sheet of standard size you can make $$$s$$$ airplanes. A group of $$$k$$$ people decided to make $$$n$$$ airplanes each. They are going to buy several packs of paper, each of them containing $$$p$$$ sheets, and then distribute the sheets between the people. Each person should have enough sheets to make $$$n$$$ airplanes. How many packs should they buy? Input The only line contains four integers $$$k$$$, $$$n$$$, $$$s$$$, $$$p$$$ ($$$1 \le k, n, s, p \le 10^4$$$) — the number of people, the number of airplanes each should make, the number of airplanes that can be made using one sheet and the number of sheets in one pack, respectively. Output Print a single integer — the minimum number of packs they should buy. Examples Input 5 3 2 3 Output 4 Input 5 3 100 1 Output 5 Note In the first sample th...	import math people ,airplaneEach ,noOfAirplaneSheet ,SheetPerPack = map(int, input().split()) SheetRequired = math.ceil(airplaneEach/noOfAirplaneSheet) total_sheet = SheetRequired*people print(math.ceil(total_sheet/SheetPerPack))	l=input().split() k=int(l[0]) n=int(l[1]) s=int(l[2]) p=int(l[3]) print (((n-1) % s+1)*k-1)%p+1
  Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium. The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan. Input The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol " | " indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale. The second line contains a non-empty sequence containing uppercase English letters. Each let...	a=list(map(str,input().split('|'))) #print(a) b=input() l1,l2=len(a[0]),len(a[1]) l=abs(l1-l2) if(l==len(b)): if l1 print(a[0]+b+'|'+a[1]) else: print(a[0]+'|'+a[1]+b) elif l if(l1 a[0]=a[0]+b[:l] else: a[1]=a[1]+b[:l] if((len(b)-l)%2==0): l3=len(b)-l a[0]=a[0]+b[l:l+l3//2] a[1]=a[1]+b[l+l3//2:] print(a[0]+'|'+a[1]) else: print("Impossible") else: print("Impossible")	from sys import stdin, stdout def solve(curr, free): wages = curr.split('|') left = len(wages[0]) right = len(wages[1]) result = None if (left + right + len(free)) % 2 == 0 and len(free) >= abs(left - right): while len(wages[0]) > len(wages[1]): wages[1] += free[0] free = free[1:] while len(wages[1]) > len(wages[0]): wages[0] += free[0] free = free[1:] result = wages[0] + '|' + wages[1] else: result = 'Impossible' return result if name == 'main': curr = stdin.readline()[:-1] free = stdin.readline()[:-1] # cards = [int(c) for c in cards_s] result = solve(curr, free) print(result)

• Loss: TripletLoss with these parameters:

  {
      "distance_metric": "TripletDistanceMetric.COSINE",
      "triplet_margin": 0.3
  }
  

Training Hyperparameters

Non-Default Hyperparameters

• per_device_train_batch_size: 1
• per_device_eval_batch_size: 1
• gradient_accumulation_steps: 16
• num_train_epochs: 1
• lr_scheduler_type: constant
• bf16: True
• batch_sampler: no_duplicates

All Hyperparameters

Click to expand

• overwrite_output_dir: False
• do_predict: False
• eval_strategy: no
• prediction_loss_only: True
• per_device_train_batch_size: 1
• per_device_eval_batch_size: 1
• per_gpu_train_batch_size: None
• per_gpu_eval_batch_size: None
• gradient_accumulation_steps: 16
• eval_accumulation_steps: None
• torch_empty_cache_steps: None
• learning_rate: 5e-05
• weight_decay: 0.0
• adam_beta1: 0.9
• adam_beta2: 0.999
• adam_epsilon: 1e-08
• max_grad_norm: 1.0
• num_train_epochs: 1
• max_steps: -1
• lr_scheduler_type: constant
• lr_scheduler_kwargs: {}
• warmup_ratio: 0.0
• warmup_steps: 0
• log_level: passive
• log_level_replica: warning
• log_on_each_node: True
• logging_nan_inf_filter: True
• save_safetensors: True
• save_on_each_node: False
• save_only_model: False
• restore_callback_states_from_checkpoint: False
• no_cuda: False
• use_cpu: False
• use_mps_device: False
• seed: 42
• data_seed: None
• jit_mode_eval: False
• bf16: True
• fp16: False
• fp16_opt_level: O1
• half_precision_backend: auto
• bf16_full_eval: False
• fp16_full_eval: False
• tf32: None
• local_rank: 0
• ddp_backend: None
• tpu_num_cores: None
• tpu_metrics_debug: False
• debug: []
• dataloader_drop_last: False
• dataloader_num_workers: 0
• dataloader_prefetch_factor: None
• past_index: -1
• disable_tqdm: False
• remove_unused_columns: True
• label_names: None
• load_best_model_at_end: False
• ignore_data_skip: False
• fsdp: []
• fsdp_min_num_params: 0
• fsdp_config: {'min_num_params': 0, 'xla': False, 'xla_fsdp_v2': False, 'xla_fsdp_grad_ckpt': False}
• fsdp_transformer_layer_cls_to_wrap: None
• accelerator_config: {'split_batches': False, 'dispatch_batches': None, 'even_batches': True, 'use_seedable_sampler': True, 'non_blocking': False, 'gradient_accumulation_kwargs': None}
• parallelism_config: None
• deepspeed: None
• label_smoothing_factor: 0.0
• optim: adamw_torch_fused
• optim_args: None
• adafactor: False
• group_by_length: False
• length_column_name: length
• project: huggingface
• trackio_space_id: trackio
• ddp_find_unused_parameters: None
• ddp_bucket_cap_mb: None
• ddp_broadcast_buffers: False
• dataloader_pin_memory: True
• dataloader_persistent_workers: False
• skip_memory_metrics: True
• use_legacy_prediction_loop: False
• push_to_hub: False
• resume_from_checkpoint: None
• hub_model_id: None
• hub_strategy: every_save
• hub_private_repo: None
• hub_always_push: False
• hub_revision: None
• gradient_checkpointing: False
• gradient_checkpointing_kwargs: None
• include_inputs_for_metrics: False
• include_for_metrics: []
• eval_do_concat_batches: True
• fp16_backend: auto
• push_to_hub_model_id: None
• push_to_hub_organization: None
• mp_parameters:
• auto_find_batch_size: False
• full_determinism: False
• torchdynamo: None
• ray_scope: last
• ddp_timeout: 1800
• torch_compile: False
• torch_compile_backend: None
• torch_compile_mode: None
• include_tokens_per_second: False
• include_num_input_tokens_seen: no
• neftune_noise_alpha: None
• optim_target_modules: None
• batch_eval_metrics: False
• eval_on_start: False
• use_liger_kernel: False
• liger_kernel_config: None
• eval_use_gather_object: False
• average_tokens_across_devices: True
• prompts: None
• batch_sampler: no_duplicates
• multi_dataset_batch_sampler: proportional
• router_mapping: {}
• learning_rate_mapping: {}

Training Logs

Click to expand

Epoch	Step	Training Loss
0.0002	10	0.2934
0.0004	20	0.3003
0.0006	30	0.2934
0.0007	40	0.2858
0.0009	50	0.2912
0.0011	60	0.2894
0.0013	70	0.2957
0.0015	80	0.2915
0.0017	90	0.2889
0.0018	100	0.2868
0.0020	110	0.2935
0.0022	120	0.2893
0.0024	130	0.2785
0.0026	140	0.2774
0.0028	150	0.2732
0.0030	160	0.279
0.0031	170	0.285
0.0033	180	0.2856
0.0035	190	0.2826
0.0037	200	0.2709
0.0039	210	0.2818
0.0041	220	0.2623
0.0043	230	0.2651
0.0044	240	0.2741
0.0046	250	0.2767
0.0048	260	0.2956
0.0050	270	0.2948
0.0052	280	0.2934
0.0054	290	0.297
0.0055	300	0.298
0.0057	310	0.2714
0.0059	320	0.2739
0.0061	330	0.2875
0.0063	340	0.2935
0.0065	350	0.2592
0.0067	360	0.2763
0.0068	370	0.2865
0.0070	380	0.2764
0.0072	390	0.2917
0.0074	400	0.2776
0.0076	410	0.2553
0.0078	420	0.2559
0.0080	430	0.2678
0.0081	440	0.267
0.0083	450	0.2708
0.0085	460	0.2608
0.0087	470	0.277
0.0089	480	0.2699
0.0091	490	0.2761
0.0092	500	0.2674
0.0094	510	0.2675
0.0096	520	0.2791
0.0098	530	0.2698
0.0100	540	0.2745
0.0102	550	0.2637
0.0104	560	0.2651
0.0105	570	0.2693
0.0107	580	0.2792
0.0109	590	0.2593
0.0111	600	0.247
0.0113	610	0.2725
0.0115	620	0.2935
0.0117	630	0.2594
0.0118	640	0.26
0.0120	650	0.2778
0.0122	660	0.2446
0.0124	670	0.2802
0.0126	680	0.2841
0.0128	690	0.2807
0.0129	700	0.2764
0.0131	710	0.2601
0.0133	720	0.2658
0.0135	730	0.2909
0.0137	740	0.254
0.0139	750	0.2623
0.0141	760	0.2672
0.0142	770	0.2774
0.0144	780	0.2556
0.0146	790	0.2636
0.0148	800	0.2777
0.0150	810	0.2784
0.0152	820	0.2844
0.0153	830	0.2745
0.0155	840	0.2853
0.0157	850	0.2671
0.0159	860	0.2839
0.0161	870	0.2613
0.0163	880	0.2776
0.0165	890	0.2732
0.0166	900	0.2766
0.0168	910	0.2552
0.0170	920	0.2508
0.0172	930	0.2799
0.0174	940	0.2695
0.0176	950	0.3049
0.0178	960	0.2995
0.0179	970	0.3001
0.0181	980	0.3034
0.0183	990	0.3051
0.0185	1000	0.2965
0.0187	1010	0.2953
0.0189	1020	0.3057
0.0190	1030	0.2937
0.0192	1040	0.3044
0.0194	1050	0.309
0.0196	1060	0.3035
0.0198	1070	0.2987
0.0200	1080	0.3002
0.0202	1090	0.2992
0.0203	1100	0.2987
0.0205	1110	0.3003
0.0207	1120	0.2976
0.0209	1130	0.2987
0.0211	1140	0.3043
0.0213	1150	0.2996
0.0215	1160	0.3051
0.0216	1170	0.3029
0.0218	1180	0.2995
0.0220	1190	0.3011
0.0222	1200	0.2982
0.0224	1210	0.2945
0.0226	1220	0.2983
0.0227	1230	0.3008
0.0229	1240	0.2976
0.0231	1250	0.2921
0.0233	1260	0.3008
0.0235	1270	0.3023
0.0237	1280	0.301
0.0239	1290	0.3
0.0240	1300	0.3001
0.0242	1310	0.3011
0.0244	1320	0.3048
0.0246	1330	0.3008
0.0248	1340	0.2975
0.0250	1350	0.3036
0.0251	1360	0.2954
0.0253	1370	0.2947
0.0255	1380	0.2973
0.0257	1390	0.2991
0.0259	1400	0.2994
0.0261	1410	0.2955
0.0263	1420	0.295
0.0264	1430	0.2961
0.0266	1440	0.298
0.0268	1450	0.298
0.0270	1460	0.2955
0.0272	1470	0.301
0.0274	1480	0.3004
0.0276	1490	0.2902
0.0277	1500	0.2929
0.0279	1510	0.2994
0.0281	1520	0.293
0.0283	1530	0.3147
0.0285	1540	0.2916
0.0287	1550	0.3029
0.0288	1560	0.2951
0.0290	1570	0.309
0.0292	1580	0.3077
0.0294	1590	0.2936
0.0296	1600	0.3016
0.0298	1610	0.2787
0.0300	1620	0.3055
0.0301	1630	0.2948
0.0303	1640	0.3053
0.0305	1650	0.3095
0.0307	1660	0.3139
0.0309	1670	0.3044
0.0311	1680	0.3053
0.0313	1690	0.2946
0.0314	1700	0.3062
0.0316	1710	0.2915
0.0318	1720	0.2918
0.0320	1730	0.3026
0.0322	1740	0.2968
0.0324	1750	0.3002
0.0325	1760	0.3097
0.0327	1770	0.3055
0.0329	1780	0.3039
0.0331	1790	0.3045
0.0333	1800	0.3017
0.0335	1810	0.3007
0.0337	1820	0.3002
0.0338	1830	0.3021
0.0340	1840	0.3011
0.0342	1850	0.2993
0.0344	1860	0.3017
0.0346	1870	0.2972
0.0348	1880	0.3009
0.0350	1890	0.3018
0.0351	1900	0.2975
0.0353	1910	0.2966
0.0355	1920	0.2958
0.0357	1930	0.3036
0.0359	1940	0.3027
0.0361	1950	0.3013
0.0362	1960	0.2983
0.0364	1970	0.2971
0.0366	1980	0.3043
0.0368	1990	0.2939
0.0370	2000	0.2976
0.0372	2010	0.2931
0.0374	2020	0.2991
0.0375	2030	0.2996
0.0377	2040	0.3052
0.0379	2050	0.3018
0.0381	2060	0.3014
0.0383	2070	0.2992
0.0385	2080	0.2981
0.0386	2090	0.3056
0.0388	2100	0.294
0.0390	2110	0.3033
0.0392	2120	0.303
0.0394	2130	0.301
0.0396	2140	0.3005
0.0398	2150	0.2983
0.0399	2160	0.2977
0.0401	2170	0.2982
0.0403	2180	0.2987
0.0405	2190	0.3008
0.0407	2200	0.3028
0.0409	2210	0.3007
0.0411	2220	0.2978
0.0412	2230	0.3047
0.0414	2240	0.3003
0.0416	2250	0.3018
0.0418	2260	0.302
0.0420	2270	0.3005
0.0422	2280	0.2968
0.0423	2290	0.3035
0.0425	2300	0.3018
0.0427	2310	0.299
0.0429	2320	0.3017
0.0431	2330	0.3013
0.0433	2340	0.2988
0.0435	2350	0.2961
0.0436	2360	0.297
0.0438	2370	0.302
0.0440	2380	0.3004
0.0442	2390	0.3004
0.0444	2400	0.3013
0.0446	2410	0.3031
0.0448	2420	0.3006
0.0449	2430	0.3013
0.0451	2440	0.2993
0.0453	2450	0.2981
0.0455	2460	0.2979
0.0457	2470	0.3015
0.0459	2480	0.3025
0.0460	2490	0.2998
0.0462	2500	0.2963
0.0464	2510	0.2992
0.0466	2520	0.2994
0.0468	2530	0.2966
0.0470	2540	0.295
0.0472	2550	0.2962
0.0473	2560	0.3039
0.0475	2570	0.301
0.0477	2580	0.3008
0.0479	2590	0.3002
0.0481	2600	0.2998
0.0483	2610	0.2999
0.0485	2620	0.299
0.0486	2630	0.2984
0.0488	2640	0.3013
0.0490	2650	0.2976
0.0492	2660	0.2975
0.0494	2670	0.3022
0.0496	2680	0.3029
0.0497	2690	0.3018
0.0499	2700	0.2984
0.0501	2710	0.2987
0.0503	2720	0.299
0.0505	2730	0.2963
0.0507	2740	0.292
0.0509	2750	0.2985
0.0510	2760	0.2991
0.0512	2770	0.2973
0.0514	2780	0.2997
0.0516	2790	0.3022
0.0518	2800	0.3031
0.0520	2810	0.2995
0.0521	2820	0.2976
0.0523	2830	0.3001
0.0525	2840	0.3016
0.0527	2850	0.3004
0.0529	2860	0.3025
0.0531	2870	0.2947
0.0533	2880	0.301
0.0534	2890	0.298
0.0536	2900	0.3018
0.0538	2910	0.2978
0.0540	2920	0.301
0.0542	2930	0.3016
0.0544	2940	0.2979
0.0546	2950	0.3025
0.0547	2960	0.2971
0.0549	2970	0.2993
0.0551	2980	0.2996
0.0553	2990	0.2999
0.0555	3000	0.2994
0.0557	3010	0.3011
0.0558	3020	0.2975
0.0560	3030	0.3021
0.0562	3040	0.3025
0.0564	3050	0.2998
0.0566	3060	0.2997
0.0568	3070	0.2906
0.0570	3080	0.3012
0.0571	3090	0.296
0.0573	3100	0.2983
0.0575	3110	0.3007
0.0577	3120	0.3036
0.0579	3130	0.3004
0.0581	3140	0.3011
0.0583	3150	0.3011
0.0584	3160	0.2968
0.0586	3170	0.2983
0.0588	3180	0.2989
0.0590	3190	0.295
0.0592	3200	0.2999
0.0594	3210	0.2974
0.0595	3220	0.2969
0.0597	3230	0.2948
0.0599	3240	0.3005
0.0601	3250	0.299
0.0603	3260	0.2989
0.0605	3270	0.2965
0.0607	3280	0.2944
0.0608	3290	0.3015
0.0610	3300	0.295
0.0612	3310	0.2952
0.0614	3320	0.2987
0.0616	3330	0.2991
0.0618	3340	0.2953
0.0619	3350	0.302
0.0621	3360	0.2977
0.0623	3370	0.3019
0.0625	3380	0.2949
0.0627	3390	0.3019
0.0629	3400	0.2984
0.0631	3410	0.3013
0.0632	3420	0.3014
0.0634	3430	0.301
0.0636	3440	0.2975
0.0638	3450	0.297
0.0640	3460	0.2985
0.0642	3470	0.2937
0.0644	3480	0.2981
0.0645	3490	0.2958
0.0647	3500	0.2998
0.0649	3510	0.2973
0.0651	3520	0.3019
0.0653	3530	0.2996
0.0655	3540	0.2989
0.0656	3550	0.2995
0.0658	3560	0.3033
0.0660	3570	0.2973
0.0662	3580	0.2992
0.0664	3590	0.3021
0.0666	3600	0.2987
0.0668	3610	0.2982
0.0669	3620	0.2999
0.0671	3630	0.2982
0.0673	3640	0.3002
0.0675	3650	0.293
0.0677	3660	0.2998
0.0679	3670	0.2998
0.0681	3680	0.2991
0.0682	3690	0.3026
0.0684	3700	0.2987
0.0686	3710	0.2992
0.0688	3720	0.2998
0.0690	3730	0.3012
0.0692	3740	0.3014
0.0693	3750	0.2987
0.0695	3760	0.3004
0.0697	3770	0.2984
0.0699	3780	0.2989
0.0701	3790	0.3014
0.0703	3800	0.3013
0.0705	3810	0.2991
0.0706	3820	0.2948
0.0708	3830	0.2979
0.0710	3840	0.2986
0.0712	3850	0.2997
0.0714	3860	0.3007
0.0716	3870	0.3021
0.0718	3880	0.2995
0.0719	3890	0.3034
0.0721	3900	0.2999
0.0723	3910	0.3003
0.0725	3920	0.2984
0.0727	3930	0.3028
0.0729	3940	0.2997
0.0730	3950	0.2962
0.0732	3960	0.2967
0.0734	3970	0.2988
0.0736	3980	0.3002
0.0738	3990	0.2991
0.0740	4000	0.302
0.0742	4010	0.2988
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0.0747	4040	0.2993
0.0749	4050	0.2983
0.0751	4060	0.3005
0.0753	4070	0.3029
0.0754	4080	0.3004
0.0756	4090	0.2954
0.0758	4100	0.2966
0.0760	4110	0.2984
0.0762	4120	0.2976
0.0764	4130	0.297
0.0766	4140	0.3003
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0.0769	4160	0.3019
0.0771	4170	0.3024
0.0773	4180	0.3001
0.0775	4190	0.2996
0.0777	4200	0.2949
0.0779	4210	0.2997
0.0780	4220	0.3006
0.0782	4230	0.298
0.0784	4240	0.2991
0.0786	4250	0.2999
0.0788	4260	0.3
0.0790	4270	0.2991
0.0791	4280	0.2975
0.0793	4290	0.3009
0.0795	4300	0.2967
0.0797	4310	0.2955
0.0799	4320	0.2981
0.0801	4330	0.2997
0.0803	4340	0.3018
0.0804	4350	0.3005
0.0806	4360	0.3012
0.0808	4370	0.3007
0.0810	4380	0.2973
0.0812	4390	0.2957
0.0814	4400	0.3015
0.0816	4410	0.2977
0.0817	4420	0.3008
0.0819	4430	0.2995
0.0821	4440	0.2996
0.0823	4450	0.3011
0.0825	4460	0.2981
0.0827	4470	0.2953
0.0828	4480	0.2992
0.0830	4490	0.2997
0.0832	4500	0.3013
0.0834	4510	0.2987
0.0836	4520	0.3015
0.0838	4530	0.2998
0.0840	4540	0.3038
0.0841	4550	0.3014
0.0843	4560	0.3004
0.0845	4570	0.2962
0.0847	4580	0.2998
0.0849	4590	0.3009
0.0851	4600	0.2986
0.0853	4610	0.2985
0.0854	4620	0.297
0.0856	4630	0.2958
0.0858	4640	0.2971
0.0860	4650	0.3043
0.0862	4660	0.3002
0.0864	4670	0.3012
0.0865	4680	0.3007
0.0867	4690	0.2976
0.0869	4700	0.2967
0.0871	4710	0.3012
0.0873	4720	0.3012
0.0875	4730	0.2988
0.0877	4740	0.3012
0.0878	4750	0.2985
0.0880	4760	0.2979
0.0882	4770	0.3
0.0884	4780	0.3014
0.0886	4790	0.3001
0.0888	4800	0.2974
0.0889	4810	0.2972
0.0891	4820	0.3
0.0893	4830	0.2993
0.0895	4840	0.2999
0.0897	4850	0.2979
0.0899	4860	0.3019
0.0901	4870	0.3015
0.0902	4880	0.3021
0.0904	4890	0.2995
0.0906	4900	0.3004
0.0908	4910	0.2995
0.0910	4920	0.2993
0.0912	4930	0.3019
0.0914	4940	0.2995
0.0915	4950	0.3025
0.0917	4960	0.2995
0.0919	4970	0.3009
0.0921	4980	0.3012
0.0923	4990	0.2967
0.0925	5000	0.3028
0.0926	5010	0.2972
0.0928	5020	0.3017
0.0930	5030	0.3009
0.0932	5040	0.3032
0.0934	5050	0.2954
0.0936	5060	0.3007
0.0938	5070	0.3011
0.0939	5080	0.2976
0.0941	5090	0.3002
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0.0945	5110	0.2998
0.0947	5120	0.3006
0.0949	5130	0.3011
0.0951	5140	0.2998
0.0952	5150	0.304
0.0954	5160	0.2998
0.0956	5170	0.2977
0.0958	5180	0.2978
0.0960	5190	0.2975
0.0962	5200	0.2971
0.0963	5210	0.3018
0.0965	5220	0.2983
0.0967	5230	0.3001
0.0969	5240	0.2982
0.0971	5250	0.2977
0.0973	5260	0.3019
0.0975	5270	0.2997
0.0976	5280	0.2971
0.0978	5290	0.3001
0.0980	5300	0.3009
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0.0984	5320	0.2985
0.0986	5330	0.2976
0.0987	5340	0.3007
0.0989	5350	0.2981
0.0991	5360	0.3013
0.0993	5370	0.3012
0.0995	5380	0.2984
0.0997	5390	0.297
0.0999	5400	0.3016
0.1000	5410	0.2995
0.1002	5420	0.3021
0.1004	5430	0.301
0.1006	5440	0.2997
0.1008	5450	0.3012
0.1010	5460	0.2997
0.1012	5470	0.3009
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0.1015	5490	0.3007
0.1017	5500	0.2972
0.1019	5510	0.2967
0.1021	5520	0.3003
0.1023	5530	0.3006
0.1024	5540	0.3003
0.1026	5550	0.3016
0.1028	5560	0.3004
0.1030	5570	0.3004
0.1032	5580	0.3031
0.1034	5590	0.2992
0.1036	5600	0.3007
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0.1039	5620	0.304
0.1041	5630	0.2987
0.1043	5640	0.3002
0.1045	5650	0.2986
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0.1049	5670	0.301
0.1050	5680	0.3035
0.1052	5690	0.301
0.1054	5700	0.301
0.1056	5710	0.3008
0.1058	5720	0.3027
0.1060	5730	0.2991
0.1061	5740	0.2956
0.1063	5750	0.3008
0.1065	5760	0.2986
0.1067	5770	0.3
0.1069	5780	0.3031
0.1071	5790	0.2998
0.1073	5800	0.2971
0.1074	5810	0.3027
0.1076	5820	0.2994
0.1078	5830	0.3007
0.1080	5840	0.3043
0.1082	5850	0.2984
0.1084	5860	0.3025
0.1086	5870	0.298
0.1087	5880	0.2979
0.1089	5890	0.3016
0.1091	5900	0.2994
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0.1095	5920	0.3008
0.1097	5930	0.3024
0.1098	5940	0.3013
0.1100	5950	0.3017
0.1102	5960	0.2996
0.1104	5970	0.301
0.1106	5980	0.3033
0.1108	5990	0.2976
0.1110	6000	0.2996
0.1111	6010	0.2987
0.1113	6020	0.2982
0.1115	6030	0.2958
0.1117	6040	0.3003
0.1119	6050	0.3011
0.1121	6060	0.2987
0.1122	6070	0.3012
0.1124	6080	0.2984
0.1126	6090	0.2988
0.1128	6100	0.2998
0.1130	6110	0.2969
0.1132	6120	0.3
0.1134	6130	0.3015
0.1135	6140	0.296
0.1137	6150	0.2991
0.1139	6160	0.2983
0.1141	6170	0.3002
0.1143	6180	0.2977
0.1145	6190	0.2972
0.1147	6200	0.2999
0.1148	6210	0.3002
0.1150	6220	0.2998
0.1152	6230	0.3
0.1154	6240	0.2989
0.1156	6250	0.302
0.1158	6260	0.3022
0.1159	6270	0.3016
0.1161	6280	0.2968
0.1163	6290	0.2981
0.1165	6300	0.299
0.1167	6310	0.3057
0.1169	6320	0.2994
0.1171	6330	0.299
0.1172	6340	0.2996
0.1174	6350	0.2972
0.1176	6360	0.3001
0.1178	6370	0.2968
0.1180	6380	0.2996
0.1182	6390	0.2995
0.1184	6400	0.3015
0.1185	6410	0.2964
0.1187	6420	0.2982
0.1189	6430	0.2979
0.1191	6440	0.2975
0.1193	6450	0.3
0.1195	6460	0.2998
0.1196	6470	0.302
0.1198	6480	0.3027
0.1200	6490	0.2988
0.1202	6500	0.2978
0.1204	6510	0.2987
0.1206	6520	0.2967
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0.1209	6540	0.2994
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0.1215	6570	0.2995
0.1217	6580	0.2988
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0.1221	6600	0.2998
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0.1224	6620	0.2963
0.1226	6630	0.3019
0.1228	6640	0.2967
0.1230	6650	0.2989
0.1232	6660	0.2984
0.1233	6670	0.3014
0.1235	6680	0.3023
0.1237	6690	0.3018
0.1239	6700	0.2997
0.1241	6710	0.2983
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0.1245	6730	0.2987
0.1246	6740	0.2971
0.1248	6750	0.3023
0.1250	6760	0.3008
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0.1254	6780	0.3008
0.1256	6790	0.2995
0.1257	6800	0.2996
0.1259	6810	0.3031
0.1261	6820	0.3003
0.1263	6830	0.2957
0.1265	6840	0.2977
0.1267	6850	0.3016
0.1269	6860	0.2956
0.1270	6870	0.3043
0.1272	6880	0.3043
0.1274	6890	0.3002
0.1276	6900	0.3012
0.1278	6910	0.2976
0.1280	6920	0.2991
0.1282	6930	0.2988
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0.1285	6950	0.2994
0.1287	6960	0.2954
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0.1293	6990	0.2997
0.1294	7000	0.2988
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0.1298	7020	0.2993
0.1300	7030	0.3019
0.1302	7040	0.3013
0.1304	7050	0.3018
0.1306	7060	0.2986
0.1307	7070	0.2995
0.1309	7080	0.3003
0.1311	7090	0.3021
0.1313	7100	0.3033
0.1315	7110	0.3015
0.1317	7120	0.2983
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0.1320	7140	0.2973
0.1322	7150	0.2999
0.1324	7160	0.2973
0.1326	7170	0.3005
0.1328	7180	0.298
0.1330	7190	0.3
0.1331	7200	0.3013
0.1333	7210	0.2983
0.1335	7220	0.2984
0.1337	7230	0.2993
0.1339	7240	0.2987
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0.1343	7260	0.3
0.1344	7270	0.2967
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0.1350	7300	0.2975
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0.1354	7320	0.3004
0.1355	7330	0.3033
0.1357	7340	0.2991
0.1359	7350	0.2963
0.1361	7360	0.3025
0.1363	7370	0.295
0.1365	7380	0.3002
0.1367	7390	0.2974
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0.1370	7410	0.2978
0.1372	7420	0.2937
0.1374	7430	0.299
0.1376	7440	0.2984
0.1378	7450	0.3005
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0.1381	7470	0.301
0.1383	7480	0.3014
0.1385	7490	0.2995
0.1387	7500	0.2978
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0.1391	7520	0.2947
0.1392	7530	0.2992
0.1394	7540	0.2973
0.1396	7550	0.3012
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0.1400	7570	0.2988
0.1402	7580	0.2991
0.1404	7590	0.2979
0.1405	7600	0.2961
0.1407	7610	0.2997
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0.1418	7670	0.3031
0.1420	7680	0.3033
0.1422	7690	0.3013
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0.1426	7710	0.294
0.1428	7720	0.3014
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0.1433	7750	0.304
0.1435	7760	0.2997
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0.1441	7790	0.2999
0.1442	7800	0.2974
0.1444	7810	0.3005
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0.1448	7830	0.3
0.1450	7840	0.2963
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0.1454	7860	0.3018
0.1455	7870	0.2995
0.1457	7880	0.2978
0.1459	7890	0.3015
0.1461	7900	0.2997
0.1463	7910	0.297
0.1465	7920	0.3019
0.1466	7930	0.2993
0.1468	7940	0.2999
0.1470	7950	0.2982
0.1472	7960	0.3035
0.1474	7970	0.3026
0.1476	7980	0.3019
0.1478	7990	0.3004
0.1479	8000	0.3009
0.1481	8010	0.299
0.1483	8020	0.3015
0.1485	8030	0.2928
0.1487	8040	0.3
0.1489	8050	0.3025
0.1490	8060	0.2994
0.1492	8070	0.3017
0.1494	8080	0.3013
0.1496	8090	0.2954
0.1498	8100	0.2997
0.1500	8110	0.2986
0.1502	8120	0.3005
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0.1509	8160	0.2941
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0.1516	8200	0.3016
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0.1520	8220	0.2977
0.1522	8230	0.3022
0.1524	8240	0.2969
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0.1527	8260	0.297
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0.1531	8280	0.301
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0.1535	8300	0.2978
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0.1539	8320	0.2975
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0.1542	8340	0.298
0.1544	8350	0.3006
0.1546	8360	0.2991
0.1548	8370	0.2953
0.1550	8380	0.3001
0.1552	8390	0.2977
0.1553	8400	0.3
0.1555	8410	0.3014
0.1557	8420	0.2996
0.1559	8430	0.3028
0.1561	8440	0.3009
0.1563	8450	0.3003
0.1564	8460	0.297
0.1566	8470	0.299
0.1568	8480	0.298
0.1570	8490	0.2993
0.1572	8500	0.2961
0.1574	8510	0.298
0.1576	8520	0.298
0.1577	8530	0.2969
0.1579	8540	0.2982
0.1581	8550	0.3014
0.1583	8560	0.2966
0.1585	8570	0.2979
0.1587	8580	0.3005
0.1589	8590	0.2989
0.1590	8600	0.2953
0.1592	8610	0.2992
0.1594	8620	0.3023
0.1596	8630	0.2978
0.1598	8640	0.298
0.1600	8650	0.2952
0.1601	8660	0.3002
0.1603	8670	0.3012
0.1605	8680	0.2985
0.1607	8690	0.2952
0.1609	8700	0.2983
0.1611	8710	0.3015
0.1613	8720	0.3
0.1614	8730	0.2961
0.1616	8740	0.2924
0.1618	8750	0.3064
0.1620	8760	0.3009
0.1622	8770	0.3005
0.1624	8780	0.3
0.1625	8790	0.2918
0.1627	8800	0.298
0.1629	8810	0.2951
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0.1633	8830	0.2996
0.1635	8840	0.3009
0.1637	8850	0.2986
0.1638	8860	0.2964
0.1640	8870	0.2945
0.1642	8880	0.2983
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0.1646	8900	0.2979
0.1648	8910	0.3019
0.1650	8920	0.3033
0.1651	8930	0.2958
0.1653	8940	0.2998
0.1655	8950	0.302
0.1657	8960	0.3046
0.1659	8970	0.3011
0.1661	8980	0.2957
0.1662	8990	0.2986
0.1664	9000	0.3002
0.1666	9010	0.2998
0.1668	9020	0.3053
0.1670	9030	0.2991
0.1672	9040	0.304
0.1674	9050	0.3002
0.1675	9060	0.2998
0.1677	9070	0.3
0.1679	9080	0.3056
0.1681	9090	0.2984
0.1683	9100	0.2965
0.1685	9110	0.3021
0.1687	9120	0.3008
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0.1690	9140	0.3003
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0.1694	9160	0.297
0.1696	9170	0.3019
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0.1699	9190	0.2944
0.1701	9200	0.3015
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0.1707	9230	0.2974
0.1709	9240	0.2984
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0.1712	9260	0.3011
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0.1716	9280	0.299
0.1718	9290	0.3051
0.1720	9300	0.3032
0.1722	9310	0.2978
0.1723	9320	0.3011
0.1725	9330	0.297
0.1727	9340	0.2986
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0.1731	9360	0.3012
0.1733	9370	0.2979
0.1735	9380	0.3009
0.1736	9390	0.2962
0.1738	9400	0.2994
0.1740	9410	0.3018
0.1742	9420	0.2977
0.1744	9430	0.302
0.1746	9440	0.2988
0.1748	9450	0.3004
0.1749	9460	0.2977
0.1751	9470	0.3011
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0.1755	9490	0.2985
0.1757	9500	0.3016
0.1759	9510	0.3008
0.1760	9520	0.2957
0.1762	9530	0.3032
0.1764	9540	0.2991
0.1766	9550	0.3
0.1768	9560	0.3033
0.1770	9570	0.3003
0.1772	9580	0.3013
0.1773	9590	0.2979
0.1775	9600	0.299
0.1777	9610	0.3029
0.1779	9620	0.3009
0.1781	9630	0.3023
0.1783	9640	0.2967
0.1785	9650	0.2971
0.1786	9660	0.3057
0.1788	9670	0.2962
0.1790	9680	0.2958
0.1792	9690	0.2942
0.1794	9700	0.3036
0.1796	9710	0.2993
0.1797	9720	0.28
0.1799	9730	0.2746
0.1801	9740	0.2698
0.1803	9750	0.2538
0.1805	9760	0.2732
0.1807	9770	0.2758
0.1809	9780	0.2609
0.1810	9790	0.2715
0.1812	9800	0.2921
0.1814	9810	0.2773
0.1816	9820	0.2886
0.1818	9830	0.2998
0.1820	9840	0.2748
0.1822	9850	0.283
0.1823	9860	0.2734
0.1825	9870	0.2617
0.1827	9880	0.2746
0.1829	9890	0.2634
0.1831	9900	0.2669
0.1833	9910	0.2731
0.1834	9920	0.2624
0.1836	9930	0.2765
0.1838	9940	0.2973
0.1840	9950	0.2904
0.1842	9960	0.2769
0.1844	9970	0.2905
0.1846	9980	0.2837
0.1847	9990	0.28
0.1849	10000	0.289
0.1851	10010	0.2553
0.1853	10020	0.2928
0.1855	10030	0.2738
0.1857	10040	0.2824
0.1858	10050	0.2976
0.1860	10060	0.2687
0.1862	10070	0.2762
0.1864	10080	0.3042
0.1866	10090	0.2913
0.1868	10100	0.2925
0.1870	10110	0.2966
0.1871	10120	0.2959
0.1873	10130	0.2954
0.1875	10140	0.2884
0.1877	10150	0.2778
0.1879	10160	0.3167
0.1881	10170	0.2953
0.1883	10180	0.305
0.1884	10190	0.3015
0.1886	10200	0.2913
0.1888	10210	0.2961
0.1890	10220	0.2993
0.1892	10230	0.3047
0.1894	10240	0.2924
0.1895	10250	0.2988
0.1897	10260	0.283
0.1899	10270	0.2782
0.1901	10280	0.2859
0.1903	10290	0.3
0.1905	10300	0.3046
0.1907	10310	0.2956
0.1908	10320	0.2957
0.1910	10330	0.2892
0.1912	10340	0.2872
0.1914	10350	0.2885
0.1916	10360	0.2798
0.1918	10370	0.2982
0.1920	10380	0.3049
0.1921	10390	0.2983
0.1923	10400	0.3012
0.1925	10410	0.3085
0.1927	10420	0.3031
0.1929	10430	0.2966
0.1931	10440	0.3044
0.1932	10450	0.2999
0.1934	10460	0.2987
0.1936	10470	0.2996
0.1938	10480	0.2954
0.1940	10490	0.2944
0.1942	10500	0.2963
0.1944	10510	0.2952
0.1945	10520	0.303
0.1947	10530	0.3001
0.1949	10540	0.2994
0.1951	10550	0.2998
0.1953	10560	0.2966
0.1955	10570	0.2974
0.1957	10580	0.3041
0.1958	10590	0.2967
0.1960	10600	0.3001
0.1962	10610	0.2983
0.1964	10620	0.3025
0.1966	10630	0.2996
0.1968	10640	0.3014
0.1969	10650	0.2944
0.1971	10660	0.2992
0.1973	10670	0.2976
0.1975	10680	0.3054
0.1977	10690	0.2997
0.1979	10700	0.2957
0.1981	10710	0.2987
0.1982	10720	0.3031
0.1984	10730	0.2965
0.1986	10740	0.2975
0.1988	10750	0.2978
0.1990	10760	0.3001
0.1992	10770	0.2993
0.1993	10780	0.2989
0.1995	10790	0.2935
0.1997	10800	0.2954
0.1999	10810	0.3
0.2001	10820	0.3046
0.2003	10830	0.3004
0.2005	10840	0.2984
0.2006	10850	0.3033
0.2008	10860	0.2986
0.2010	10870	0.2985
0.2012	10880	0.3015
0.2014	10890	0.2949
0.2016	10900	0.2986
0.2018	10910	0.2963
0.2019	10920	0.3007
0.2021	10930	0.3036
0.2023	10940	0.2978
0.2025	10950	0.2998
0.2027	10960	0.3001
0.2029	10970	0.2993
0.2030	10980	0.3003
0.2032	10990	0.2947
0.2034	11000	0.3022
0.2036	11010	0.299
0.2038	11020	0.3009
0.2040	11030	0.2977
0.2042	11040	0.2999
0.2043	11050	0.2999
0.2045	11060	0.2989
0.2047	11070	0.3005
0.2049	11080	0.2993
0.2051	11090	0.2975
0.2053	11100	0.2984
0.2055	11110	0.2982
0.2056	11120	0.3014
0.2058	11130	0.3021
0.2060	11140	0.3034
0.2062	11150	0.2984
0.2064	11160	0.3009
0.2066	11170	0.3032
0.2067	11180	0.2966
0.2069	11190	0.3016
0.2071	11200	0.2973
0.2073	11210	0.2999
0.2075	11220	0.2996
0.2077	11230	0.3004
0.2079	11240	0.3003
0.2080	11250	0.3034
0.2082	11260	0.3018
0.2084	11270	0.297
0.2086	11280	0.3001
0.2088	11290	0.3007
0.2090	11300	0.3015
0.2091	11310	0.2966
0.2093	11320	0.3007
0.2095	11330	0.304
0.2097	11340	0.3002
0.2099	11350	0.2992
0.2101	11360	0.3015
0.2103	11370	0.3022
0.2104	11380	0.2993
0.2106	11390	0.3021
0.2108	11400	0.2931
0.2110	11410	0.2989
0.2112	11420	0.2999
0.2114	11430	0.2983
0.2116	11440	0.3032
0.2117	11450	0.2993
0.2119	11460	0.2997
0.2121	11470	0.3013
0.2123	11480	0.3011
0.2125	11490	0.2979
0.2127	11500	0.3013
0.2128	11510	0.298
0.2130	11520	0.3035
0.2132	11530	0.2999
0.2134	11540	0.2958
0.2136	11550	0.2977
0.2138	11560	0.2957
0.2140	11570	0.2976
0.2141	11580	0.3027
0.2143	11590	0.298
0.2145	11600	0.2994
0.2147	11610	0.3014
0.2149	11620	0.2993
0.2151	11630	0.3014
0.2153	11640	0.2942
0.2154	11650	0.3018
0.2156	11660	0.3016
0.2158	11670	0.2995
0.2160	11680	0.3001
0.2162	11690	0.3001
0.2164	11700	0.2961
0.2165	11710	0.3014
0.2167	11720	0.3016
0.2169	11730	0.2972
0.2171	11740	0.2994
0.2173	11750	0.299
0.2175	11760	0.298
0.2177	11770	0.3001
0.2178	11780	0.3026
0.2180	11790	0.3009
0.2182	11800	0.3
0.2184	11810	0.2988
0.2186	11820	0.2986
0.2188	11830	0.2986
0.2190	11840	0.3032
0.2191	11850	0.3
0.2193	11860	0.3027
0.2195	11870	0.2991
0.2197	11880	0.299
0.2199	11890	0.2986
0.2201	11900	0.3035
0.2202	11910	0.2982
0.2204	11920	0.3022
0.2206	11930	0.3022
0.2208	11940	0.3005
0.2210	11950	0.3004
0.2212	11960	0.2956
0.2214	11970	0.3031
0.2215	11980	0.2952
0.2217	11990	0.3009
0.2219	12000	0.2975
0.2221	12010	0.2948
0.2223	12020	0.2979
0.2225	12030	0.2999
0.2226	12040	0.2979
0.2228	12050	0.2948
0.2230	12060	0.2956
0.2232	12070	0.2984
0.2234	12080	0.3014
0.2236	12090	0.2979
0.2238	12100	0.2975
0.2239	12110	0.2997
0.2241	12120	0.2926
0.2243	12130	0.2985
0.2245	12140	0.2967
0.2247	12150	0.298
0.2249	12160	0.2982
0.2251	12170	0.3025
0.2252	12180	0.3
0.2254	12190	0.3002
0.2256	12200	0.296
0.2258	12210	0.2988
0.2260	12220	0.2939
0.2262	12230	0.3017
0.2263	12240	0.3027
0.2265	12250	0.3
0.2267	12260	0.2978
0.2269	12270	0.3032
0.2271	12280	0.2991
0.2273	12290	0.2983
0.2275	12300	0.301
0.2276	12310	0.3025
0.2278	12320	0.2963
0.2280	12330	0.3019
0.2282	12340	0.3003
0.2284	12350	0.3016
0.2286	12360	0.2981
0.2288	12370	0.2965
0.2289	12380	0.3021
0.2291	12390	0.3013
0.2293	12400	0.2981
0.2295	12410	0.296
0.2297	12420	0.3017
0.2299	12430	0.3015
0.2300	12440	0.3008
0.2302	12450	0.298
0.2304	12460	0.3015
0.2306	12470	0.2989
0.2308	12480	0.3002
0.2310	12490	0.2995
0.2312	12500	0.2965
0.2313	12510	0.2998
0.2315	12520	0.3002
0.2317	12530	0.3
0.2319	12540	0.3007
0.2321	12550	0.3031
0.2323	12560	0.2991
0.2325	12570	0.2959
0.2326	12580	0.2997
0.2328	12590	0.2973
0.2330	12600	0.2983
0.2332	12610	0.3005
0.2334	12620	0.3003
0.2336	12630	0.2984
0.2337	12640	0.3014
0.2339	12650	0.3009
0.2341	12660	0.2998
0.2343	12670	0.3019
0.2345	12680	0.2999
0.2347	12690	0.3013
0.2349	12700	0.2972
0.2350	12710	0.3009
0.2352	12720	0.2989
0.2354	12730	0.2974
0.2356	12740	0.2971
0.2358	12750	0.297
0.2360	12760	0.301
0.2361	12770	0.3009
0.2363	12780	0.2975
0.2365	12790	0.3008
0.2367	12800	0.2995
0.2369	12810	0.3017
0.2371	12820	0.3009
0.2373	12830	0.3
0.2374	12840	0.3011
0.2376	12850	0.3017
0.2378	12860	0.2986
0.2380	12870	0.2992
0.2382	12880	0.2954
0.2384	12890	0.2991
0.2386	12900	0.302
0.2387	12910	0.3035
0.2389	12920	0.2983
0.2391	12930	0.2992
0.2393	12940	0.3007
0.2395	12950	0.3001
0.2397	12960	0.2992
0.2398	12970	0.2996
0.2400	12980	0.3009
0.2402	12990	0.3014
0.2404	13000	0.3012
0.2406	13010	0.2988
0.2408	13020	0.3006
0.2410	13030	0.3007
0.2411	13040	0.2983
0.2413	13050	0.2999
0.2415	13060	0.3016
0.2417	13070	0.2975
0.2419	13080	0.3015
0.2421	13090	0.3005
0.2423	13100	0.2989
0.2424	13110	0.2996
0.2426	13120	0.2992
0.2428	13130	0.3005
0.2430	13140	0.3022
0.2432	13150	0.3012
0.2434	13160	0.3
0.2435	13170	0.301
0.2437	13180	0.3006
0.2439	13190	0.3014
0.2441	13200	0.2996
0.2443	13210	0.301
0.2445	13220	0.3003
0.2447	13230	0.2993
0.2448	13240	0.3002
0.2450	13250	0.3015
0.2452	13260	0.3016
0.2454	13270	0.3006
0.2456	13280	0.3017
0.2458	13290	0.2986
0.2459	13300	0.2979
0.2461	13310	0.3019
0.2463	13320	0.3011
0.2465	13330	0.2994
0.2467	13340	0.3009
0.2469	13350	0.2983
0.2471	13360	0.2997
0.2472	13370	0.2997
0.2474	13380	0.3019
0.2476	13390	0.2978
0.2478	13400	0.2964
0.2480	13410	0.297
0.2482	13420	0.3007
0.2484	13430	0.2992
0.2485	13440	0.3013
0.2487	13450	0.2988
0.2489	13460	0.2972
0.2491	13470	0.3002
0.2493	13480	0.3035
0.2495	13490	0.2998
0.2496	13500	0.3002
0.2498	13510	0.2969
0.2500	13520	0.2993
0.2502	13530	0.302
0.2504	13540	0.2982
0.2506	13550	0.2937
0.2508	13560	0.3021
0.2509	13570	0.3012
0.2511	13580	0.3041
0.2513	13590	0.299
0.2515	13600	0.3001
0.2517	13610	0.3006
0.2519	13620	0.2994
0.2521	13630	0.3005
0.2522	13640	0.2973
0.2524	13650	0.2998
0.2526	13660	0.3003
0.2528	13670	0.2998
0.2530	13680	0.3007
0.2532	13690	0.2997
0.2533	13700	0.3001
0.2535	13710	0.3034
0.2537	13720	0.3
0.2539	13730	0.2962
0.2541	13740	0.2977
0.2543	13750	0.3005
0.2545	13760	0.2985
0.2546	13770	0.3024
0.2548	13780	0.2999
0.2550	13790	0.2991
0.2552	13800	0.3033
0.2554	13810	0.3002
0.2556	13820	0.3007
0.2558	13830	0.2956
0.2559	13840	0.2935
0.2561	13850	0.3034
0.2563	13860	0.3014
0.2565	13870	0.3012
0.2567	13880	0.3037
0.2569	13890	0.3019
0.2570	13900	0.2988
0.2572	13910	0.2997
0.2574	13920	0.2975
0.2576	13930	0.2977
0.2578	13940	0.2996
0.2580	13950	0.3054
0.2582	13960	0.3006
0.2583	13970	0.301
0.2585	13980	0.3023
0.2587	13990	0.2997
0.2589	14000	0.2966
0.2591	14010	0.3002
0.2593	14020	0.2964
0.2594	14030	0.3022
0.2596	14040	0.2949
0.2598	14050	0.2985
0.2600	14060	0.3021
0.2602	14070	0.3
0.2604	14080	0.3
0.2606	14090	0.3007
0.2607	14100	0.2975
0.2609	14110	0.302
0.2611	14120	0.2992
0.2613	14130	0.3013
0.2615	14140	0.2979
0.2617	14150	0.3005
0.2619	14160	0.2968
0.2620	14170	0.3009
0.2622	14180	0.2988
0.2624	14190	0.2987
0.2626	14200	0.2988
0.2628	14210	0.298
0.2630	14220	0.3011
0.2631	14230	0.2996
0.2633	14240	0.301
0.2635	14250	0.2991
0.2637	14260	0.304
0.2639	14270	0.2982
0.2641	14280	0.3004
0.2643	14290	0.2963
0.2644	14300	0.2969
0.2646	14310	0.2994
0.2648	14320	0.3018
0.2650	14330	0.2947
0.2652	14340	0.2994
0.2654	14350	0.3002
0.2656	14360	0.302
0.2657	14370	0.3
0.2659	14380	0.2978
0.2661	14390	0.2993
0.2663	14400	0.2964
0.2665	14410	0.3006
0.2667	14420	0.2996
0.2668	14430	0.2991
0.2670	14440	0.3019
0.2672	14450	0.297
0.2674	14460	0.299
0.2676	14470	0.303
0.2678	14480	0.3045
0.2680	14490	0.2999
0.2681	14500	0.3008
0.2683	14510	0.298
0.2685	14520	0.2999
0.2687	14530	0.3006
0.2689	14540	0.2993
0.2691	14550	0.2979
0.2693	14560	0.3008
0.2694	14570	0.2983
0.2696	14580	0.2988
0.2698	14590	0.2993
0.2700	14600	0.2989
0.2702	14610	0.3014
0.2704	14620	0.2995
0.2705	14630	0.2988
0.2707	14640	0.2995
0.2709	14650	0.3007
0.2711	14660	0.2999
0.2713	14670	0.2977
0.2715	14680	0.2945
0.2717	14690	0.2962
0.2718	14700	0.303
0.2720	14710	0.2981
0.2722	14720	0.3
0.2724	14730	0.3007
0.2726	14740	0.295
0.2728	14750	0.3006
0.2729	14760	0.3022
0.2731	14770	0.3024
0.2733	14780	0.2995
0.2735	14790	0.3022
0.2737	14800	0.3006
0.2739	14810	0.301
0.2741	14820	0.2992
0.2742	14830	0.3013
0.2744	14840	0.2996
0.2746	14850	0.296
0.2748	14860	0.2986
0.2750	14870	0.2977
0.2752	14880	0.3009
0.2754	14890	0.2988
0.2755	14900	0.2977
0.2757	14910	0.2993
0.2759	14920	0.3001
0.2761	14930	0.302
0.2763	14940	0.3008
0.2765	14950	0.2982
0.2766	14960	0.2993
0.2768	14970	0.2969
0.2770	14980	0.3014
0.2772	14990	0.2985
0.2774	15000	0.2971
0.2776	15010	0.2981
0.2778	15020	0.3014
0.2779	15030	0.2988
0.2781	15040	0.3002
0.2783	15050	0.295
0.2785	15060	0.298
0.2787	15070	0.2979
0.2789	15080	0.2996
0.2791	15090	0.303
0.2792	15100	0.3012
0.2794	15110	0.3007
0.2796	15120	0.302
0.2798	15130	0.3012
0.2800	15140	0.2995
0.2802	15150	0.2994
0.2803	15160	0.3009
0.2805	15170	0.3037
0.2807	15180	0.2982
0.2809	15190	0.2993
0.2811	15200	0.2974
0.2813	15210	0.3003
0.2815	15220	0.303
0.2816	15230	0.2993
0.2818	15240	0.3019
0.2820	15250	0.3004
0.2822	15260	0.302
0.2824	15270	0.2974
0.2826	15280	0.2954
0.2827	15290	0.3026
0.2829	15300	0.3038
0.2831	15310	0.3021
0.2833	15320	0.2963
0.2835	15330	0.3026
0.2837	15340	0.295
0.2839	15350	0.2979
0.2840	15360	0.297
0.2842	15370	0.299
0.2844	15380	0.3016
0.2846	15390	0.2985
0.2848	15400	0.298
0.2850	15410	0.3018
0.2852	15420	0.3008
0.2853	15430	0.2999
0.2855	15440	0.2987
0.2857	15450	0.2992
0.2859	15460	0.2986
0.2861	15470	0.3005
0.2863	15480	0.2996
0.2864	15490	0.2965
0.2866	15500	0.2982
0.2868	15510	0.2992
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0.3950	21360	0.2984
0.3952	21370	0.3005
0.3954	21380	0.3014
0.3956	21390	0.3024
0.3957	21400	0.2983
0.3959	21410	0.3019
0.3961	21420	0.298
0.3963	21430	0.3003
0.3965	21440	0.2953
0.3967	21450	0.2991
0.3968	21460	0.2973
0.3970	21470	0.2991
0.3972	21480	0.3025
0.3974	21490	0.299
0.3976	21500	0.2944
0.3978	21510	0.3028
0.3980	21520	0.3002
0.3981	21530	0.2987
0.3983	21540	0.2969
0.3985	21550	0.3008
0.3987	21560	0.2958
0.3989	21570	0.2998
0.3991	21580	0.2975
0.3993	21590	0.3026
0.3994	21600	0.2998
0.3996	21610	0.2954
0.3998	21620	0.3033
0.4000	21630	0.2943
0.4002	21640	0.298
0.4004	21650	0.3
0.4005	21660	0.3
0.4007	21670	0.3019
0.4009	21680	0.2998
0.4011	21690	0.2995
0.4013	21700	0.3004
0.4015	21710	0.3009
0.4017	21720	0.2999
0.4018	21730	0.2976
0.4020	21740	0.2994
0.4022	21750	0.3021
0.4024	21760	0.3034
0.4026	21770	0.2983
0.4028	21780	0.3003
0.4030	21790	0.3011
0.4031	21800	0.2963
0.4033	21810	0.3008
0.4035	21820	0.3011
0.4037	21830	0.3001
0.4039	21840	0.2963
0.4041	21850	0.2982
0.4042	21860	0.3008
0.4044	21870	0.2977
0.4046	21880	0.2995
0.4048	21890	0.2999
0.4050	21900	0.2991
0.4052	21910	0.2988
0.4054	21920	0.3002
0.4055	21930	0.2986
0.4057	21940	0.3024
0.4059	21950	0.2961
0.4061	21960	0.2978
0.4063	21970	0.3
0.4065	21980	0.2968
0.4066	21990	0.3018
0.4068	22000	0.3037
0.4070	22010	0.2959
0.4072	22020	0.3008
0.4074	22030	0.2994
0.4076	22040	0.2997
0.4078	22050	0.2991
0.4079	22060	0.2957
0.4081	22070	0.3003
0.4083	22080	0.2975
0.4085	22090	0.2975
0.4087	22100	0.303
0.4089	22110	0.2963
0.4091	22120	0.2976
0.4092	22130	0.3001
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0.4098	22160	0.2978
0.4100	22170	0.2987
0.4102	22180	0.2971
0.4103	22190	0.3012
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0.4107	22210	0.2968
0.4109	22220	0.3003
0.4111	22230	0.2973
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0.4115	22250	0.2965
0.4116	22260	0.2976
0.4118	22270	0.2937
0.4120	22280	0.2994
0.4122	22290	0.2996
0.4124	22300	0.3013
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0.4128	22320	0.2962
0.4129	22330	0.299
0.4131	22340	0.2945
0.4133	22350	0.3024
0.4135	22360	0.2963
0.4137	22370	0.2962
0.4139	22380	0.2981
0.4140	22390	0.3008
0.4142	22400	0.2979
0.4144	22410	0.2996
0.4146	22420	0.3013
0.4148	22430	0.2984
0.4150	22440	0.3024
0.4152	22450	0.2975
0.4153	22460	0.3013
0.4155	22470	0.3005
0.4157	22480	0.3033
0.4159	22490	0.3005
0.4161	22500	0.2984
0.4163	22510	0.3021
0.4164	22520	0.2934
0.4166	22530	0.2988
0.4168	22540	0.2996
0.4170	22550	0.2957
0.4172	22560	0.3
0.4174	22570	0.2961
0.4176	22580	0.2948
0.4177	22590	0.2953
0.4179	22600	0.3033
0.4181	22610	0.2981
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0.4185	22630	0.2954
0.4187	22640	0.2949
0.4189	22650	0.2933
0.4190	22660	0.2983
0.4192	22670	0.3022
0.4194	22680	0.3
0.4196	22690	0.3005
0.4198	22700	0.3015
0.4200	22710	0.2996
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0.4203	22730	0.2988
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0.4207	22750	0.3007
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0.4211	22770	0.3002
0.4213	22780	0.3007
0.4214	22790	0.2977
0.4216	22800	0.2956
0.4218	22810	0.2988
0.4220	22820	0.2964
0.4222	22830	0.2991
0.4224	22840	0.2972
0.4226	22850	0.3025
0.4227	22860	0.2971
0.4229	22870	0.3014
0.4231	22880	0.2967
0.4233	22890	0.3008
0.4235	22900	0.2963
0.4237	22910	0.2942
0.4238	22920	0.2967
0.4240	22930	0.301
0.4242	22940	0.3011
0.4244	22950	0.2969
0.4246	22960	0.3003
0.4248	22970	0.2978
0.4250	22980	0.2987
0.4251	22990	0.3014
0.4253	23000	0.2997
0.4255	23010	0.2986
0.4257	23020	0.2996
0.4259	23030	0.2982
0.4261	23040	0.298
0.4263	23050	0.2993
0.4264	23060	0.3027
0.4266	23070	0.2971
0.4268	23080	0.2995
0.4270	23090	0.2972
0.4272	23100	0.2996
0.4274	23110	0.3004
0.4275	23120	0.3019
0.4277	23130	0.2983
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0.4281	23150	0.2971
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0.4285	23170	0.3002
0.4287	23180	0.2993
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0.4290	23200	0.298
0.4292	23210	0.2962
0.4294	23220	0.2987
0.4296	23230	0.2965
0.4298	23240	0.2961
0.4299	23250	0.2954
0.4301	23260	0.3014
0.4303	23270	0.3019
0.4305	23280	0.2996
0.4307	23290	0.2977
0.4309	23300	0.2982
0.4311	23310	0.298
0.4312	23320	0.2986
0.4314	23330	0.3014
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0.4318	23350	0.2954
0.4320	23360	0.3014
0.4322	23370	0.2979
0.4324	23380	0.2957
0.4325	23390	0.3011
0.4327	23400	0.3017
0.4329	23410	0.3005
0.4331	23420	0.298
0.4333	23430	0.2942
0.4335	23440	0.2966
0.4336	23450	0.3015
0.4338	23460	0.2998
0.4340	23470	0.2968
0.4342	23480	0.2989
0.4344	23490	0.3003
0.4346	23500	0.3018
0.4348	23510	0.2997
0.4349	23520	0.2981
0.4351	23530	0.2971
0.4353	23540	0.3012
0.4355	23550	0.2985
0.4357	23560	0.3005
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0.4361	23580	0.3005
0.4362	23590	0.2963
0.4364	23600	0.2919
0.4366	23610	0.2997
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0.4370	23630	0.2951
0.4372	23640	0.2972
0.4373	23650	0.2947
0.4375	23660	0.2989
0.4377	23670	0.3052
0.4379	23680	0.297
0.4381	23690	0.301
0.4383	23700	0.2997
0.4385	23710	0.3035
0.4386	23720	0.2987
0.4388	23730	0.2968
0.4390	23740	0.3014
0.4392	23750	0.3026
0.4394	23760	0.2963
0.4396	23770	0.295
0.4398	23780	0.295
0.4399	23790	0.3006
0.4401	23800	0.3002
0.4403	23810	0.3015
0.4405	23820	0.2987
0.4407	23830	0.2943
0.4409	23840	0.2992
0.4410	23850	0.2946
0.4412	23860	0.2982
0.4414	23870	0.2954
0.4416	23880	0.2983
0.4418	23890	0.299
0.4420	23900	0.3003
0.4422	23910	0.2938
0.4423	23920	0.3009
0.4425	23930	0.299
0.4427	23940	0.297
0.4429	23950	0.2979
0.4431	23960	0.3033
0.4433	23970	0.2968
0.4434	23980	0.2977
0.4436	23990	0.3008
0.4438	24000	0.2997
0.4440	24010	0.3013
0.4442	24020	0.2994
0.4444	24030	0.3029
0.4446	24040	0.2961
0.4447	24050	0.3009
0.4449	24060	0.3002
0.4451	24070	0.2991
0.4453	24080	0.2973
0.4455	24090	0.2998
0.4457	24100	0.2934
0.4459	24110	0.3014
0.4460	24120	0.299
0.4462	24130	0.2999
0.4464	24140	0.2977
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0.4470	24170	0.3002
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0.4473	24190	0.2983
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0.4477	24210	0.3005
0.4479	24220	0.3031
0.4481	24230	0.296
0.4483	24240	0.2949
0.4484	24250	0.3001
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0.4488	24270	0.3001
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0.4494	24300	0.2976
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0.4499	24330	0.2972
0.4501	24340	0.297
0.4503	24350	0.2941
0.4505	24360	0.3002
0.4507	24370	0.296
0.4508	24380	0.2971
0.4510	24390	0.2999
0.4512	24400	0.2996
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0.4516	24420	0.2973
0.4518	24430	0.2965
0.4520	24440	0.3006
0.4521	24450	0.2977
0.4523	24460	0.2971
0.4525	24470	0.3005
0.4527	24480	0.3012
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0.4531	24500	0.2941
0.4532	24510	0.2977
0.4534	24520	0.2965
0.4536	24530	0.2976
0.4538	24540	0.3003
0.4540	24550	0.2973
0.4542	24560	0.3006
0.4544	24570	0.2957
0.4545	24580	0.3003
0.4547	24590	0.2976
0.4549	24600	0.2933
0.4551	24610	0.2996
0.4553	24620	0.2994
0.4555	24630	0.3012
0.4557	24640	0.3014
0.4558	24650	0.2986
0.4560	24660	0.3016
0.4562	24670	0.3022
0.4564	24680	0.2994
0.4566	24690	0.2977
0.4568	24700	0.2974
0.4569	24710	0.2998
0.4571	24720	0.2999
0.4573	24730	0.3029
0.4575	24740	0.2984
0.4577	24750	0.2981
0.4579	24760	0.2978
0.4581	24770	0.2995
0.4582	24780	0.295
0.4584	24790	0.2972
0.4586	24800	0.3002
0.4588	24810	0.2986
0.4590	24820	0.2972
0.4592	24830	0.2972
0.4594	24840	0.2991
0.4595	24850	0.2989
0.4597	24860	0.2982
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0.4601	24880	0.2928
0.4603	24890	0.3028
0.4605	24900	0.2977
0.4606	24910	0.3024
0.4608	24920	0.2929
0.4610	24930	0.3018
0.4612	24940	0.296
0.4614	24950	0.3
0.4616	24960	0.3006
0.4618	24970	0.2991
0.4619	24980	0.2972
0.4621	24990	0.2998
0.4623	25000	0.2985
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0.4627	25020	0.3022
0.4629	25030	0.2992
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0.4634	25060	0.3018
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0.4638	25080	0.2992
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0.4642	25100	0.3007
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0.4645	25120	0.2986
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0.4662	25210	0.3006
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0.4669	25250	0.3002
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0.4673	25270	0.3012
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0.4677	25290	0.3007
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0.4680	25310	0.2998
0.4682	25320	0.2999
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0.4688	25350	0.3002
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0.4697	25400	0.2956
0.4699	25410	0.3033
0.4701	25420	0.3003
0.4703	25430	0.2978
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0.4706	25450	0.294
0.4708	25460	0.2998
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0.4712	25480	0.2984
0.4714	25490	0.2968
0.4716	25500	0.2978
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0.4721	25530	0.2996
0.4723	25540	0.3014
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0.4727	25560	0.297
0.4729	25570	0.3002
0.4730	25580	0.2977
0.4732	25590	0.2975
0.4734	25600	0.2994
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0.4738	25620	0.2988
0.4740	25630	0.2992
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0.4743	25650	0.2984
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0.4747	25670	0.2983
0.4749	25680	0.3022
0.4751	25690	0.2986
0.4753	25700	0.3003
0.4754	25710	0.2994
0.4756	25720	0.2997
0.4758	25730	0.2999
0.4760	25740	0.3
0.4762	25750	0.2953
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0.4766	25770	0.3019
0.4767	25780	0.2986
0.4769	25790	0.302
0.4771	25800	0.3009
0.4773	25810	0.3002
0.4775	25820	0.2997
0.4777	25830	0.2996
0.4778	25840	0.2954
0.4780	25850	0.2999
0.4782	25860	0.3002
0.4784	25870	0.2976
0.4786	25880	0.3007
0.4788	25890	0.3007
0.4790	25900	0.3003
0.4791	25910	0.2981
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0.4795	25930	0.3011
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0.4799	25950	0.2985
0.4801	25960	0.3013
0.4802	25970	0.2998
0.4804	25980	0.3016
0.4806	25990	0.3013
0.4808	26000	0.2985
0.4810	26010	0.2998
0.4812	26020	0.3028
0.4814	26030	0.297
0.4815	26040	0.2993
0.4817	26050	0.2985
0.4819	26060	0.3002
0.4821	26070	0.2985
0.4823	26080	0.3013
0.4825	26090	0.2967
0.4827	26100	0.2987
0.4828	26110	0.3018
0.4830	26120	0.2996
0.4832	26130	0.2983
0.4834	26140	0.2978
0.4836	26150	0.3005
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0.4839	26170	0.2992
0.4841	26180	0.3031
0.4843	26190	0.3028
0.4845	26200	0.2979
0.4847	26210	0.3004
0.4849	26220	0.2989
0.4851	26230	0.2961
0.4852	26240	0.2979
0.4854	26250	0.3001
0.4856	26260	0.2988
0.4858	26270	0.2967
0.4860	26280	0.2979
0.4862	26290	0.2993
0.4864	26300	0.298
0.4865	26310	0.3012
0.4867	26320	0.2996
0.4869	26330	0.2995
0.4871	26340	0.3016
0.4873	26350	0.2988
0.4875	26360	0.2982
0.4876	26370	0.2999
0.4878	26380	0.3021
0.4880	26390	0.2986
0.4882	26400	0.2972
0.4884	26410	0.3025
0.4886	26420	0.2977
0.4888	26430	0.3018
0.4889	26440	0.3004
0.4891	26450	0.3001
0.4893	26460	0.3005
0.4895	26470	0.3002
0.4897	26480	0.3017
0.4899	26490	0.3018
0.4900	26500	0.3025
0.4902	26510	0.2966
0.4904	26520	0.3005
0.4906	26530	0.3023
0.4908	26540	0.2942
0.4910	26550	0.3002
0.4912	26560	0.3012
0.4913	26570	0.2981
0.4915	26580	0.2971
0.4917	26590	0.3009
0.4919	26600	0.2998
0.4921	26610	0.3001
0.4923	26620	0.298
0.4925	26630	0.2994
0.4926	26640	0.3003
0.4928	26650	0.2984
0.4930	26660	0.3014
0.4932	26670	0.2983
0.4934	26680	0.3034
0.4936	26690	0.2984
0.4937	26700	0.3005
0.4939	26710	0.3
0.4941	26720	0.2984
0.4943	26730	0.3015
0.4945	26740	0.2992
0.4947	26750	0.2989
0.4949	26760	0.3033
0.4950	26770	0.2982
0.4952	26780	0.2983
0.4954	26790	0.2995
0.4956	26800	0.3013
0.4958	26810	0.2996
0.4960	26820	0.297
0.4962	26830	0.2973
0.4963	26840	0.2982
0.4965	26850	0.2992
0.4967	26860	0.3006
0.4969	26870	0.2971
0.4971	26880	0.2975
0.4973	26890	0.2987
0.4974	26900	0.2987
0.4976	26910	0.2995
0.4978	26920	0.2953
0.4980	26930	0.3002
0.4982	26940	0.2963
0.4984	26950	0.3005
0.4986	26960	0.2965
0.4987	26970	0.2986
0.4989	26980	0.303
0.4991	26990	0.2983
0.4993	27000	0.2988
0.4995	27010	0.299
0.4997	27020	0.2974
0.4999	27030	0.3026
0.5000	27040	0.2976
0.5002	27050	0.2984
0.5004	27060	0.3001
0.5006	27070	0.2996
0.5008	27080	0.3001
0.5010	27090	0.2972
0.5011	27100	0.2984
0.5013	27110	0.2969
0.5015	27120	0.2981
0.5017	27130	0.3015
0.5019	27140	0.2953
0.5021	27150	0.3001
0.5023	27160	0.2973
0.5024	27170	0.3002
0.5026	27180	0.2978
0.5028	27190	0.2977
0.5030	27200	0.2992
0.5032	27210	0.3033
0.5034	27220	0.3009
0.5035	27230	0.3003
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0.5428	29350	0.2976
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0.5502	29750	0.3003
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0.5511	29800	0.3011
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0.5577	30160	0.299
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0.5600	30280	0.3
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0.5918	32000	0.3037
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0.5921	32020	0.3
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0.5962	32240	0.2991
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0.5969	32280	0.303
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0.6010	32500	0.2998
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0.6014	32520	0.3034
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0.6019	32550	0.2971
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0.6082	32890	0.3004
0.6084	32900	0.2992
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0.6097	32970	0.3011
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0.6101	32990	0.2987
0.6103	33000	0.3045
0.6104	33010	0.296
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0.6115	33070	0.296
0.6117	33080	0.2972
0.6119	33090	0.3008
0.6121	33100	0.2992
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0.9370	50670	0.3016
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0.9374	50690	0.2982
0.9376	50700	0.2989
0.9378	50710	0.3015
0.9379	50720	0.2992
0.9381	50730	0.2989
0.9383	50740	0.3008
0.9385	50750	0.2958
0.9387	50760	0.3009
0.9389	50770	0.3018
0.9390	50780	0.2982
0.9392	50790	0.3003
0.9394	50800	0.2968
0.9396	50810	0.2993
0.9398	50820	0.3015
0.9400	50830	0.2983
0.9402	50840	0.2978
0.9403	50850	0.3002
0.9405	50860	0.2963
0.9407	50870	0.2984
0.9409	50880	0.2994
0.9411	50890	0.3009
0.9413	50900	0.3012
0.9415	50910	0.2955
0.9416	50920	0.3003
0.9418	50930	0.3024
0.9420	50940	0.3014
0.9422	50950	0.2984
0.9424	50960	0.3001
0.9426	50970	0.2956
0.9427	50980	0.3034
0.9429	50990	0.2992
0.9431	51000	0.2986
0.9433	51010	0.3016
0.9435	51020	0.2985
0.9437	51030	0.299
0.9439	51040	0.2972
0.9440	51050	0.2995
0.9442	51060	0.3002
0.9444	51070	0.2992
0.9446	51080	0.2984
0.9448	51090	0.2988
0.9450	51100	0.3006
0.9451	51110	0.3012
0.9453	51120	0.2981
0.9455	51130	0.2953
0.9457	51140	0.3004
0.9459	51150	0.2976
0.9461	51160	0.2985
0.9463	51170	0.301
0.9464	51180	0.301
0.9466	51190	0.2951
0.9468	51200	0.2978
0.9470	51210	0.3
0.9472	51220	0.2973
0.9474	51230	0.299
0.9476	51240	0.2979
0.9477	51250	0.299
0.9479	51260	0.2949
0.9481	51270	0.2993
0.9483	51280	0.2996
0.9485	51290	0.299
0.9487	51300	0.2967
0.9488	51310	0.2974
0.9490	51320	0.301
0.9492	51330	0.2988
0.9494	51340	0.2969
0.9496	51350	0.297
0.9498	51360	0.2984
0.9500	51370	0.3009
0.9501	51380	0.2951
0.9503	51390	0.2987
0.9505	51400	0.2994
0.9507	51410	0.2967
0.9509	51420	0.2997
0.9511	51430	0.2989
0.9513	51440	0.2995
0.9514	51450	0.3002
0.9516	51460	0.2981
0.9518	51470	0.3021
0.9520	51480	0.3017
0.9522	51490	0.2955
0.9524	51500	0.3001
0.9525	51510	0.2986
0.9527	51520	0.2989
0.9529	51530	0.3041
0.9531	51540	0.2965
0.9533	51550	0.2996
0.9535	51560	0.2985
0.9537	51570	0.3006
0.9538	51580	0.3003
0.9540	51590	0.3001
0.9542	51600	0.2998
0.9544	51610	0.2999
0.9546	51620	0.2959
0.9548	51630	0.2973
0.9550	51640	0.2998
0.9551	51650	0.2978
0.9553	51660	0.297
0.9555	51670	0.2931
0.9557	51680	0.2977
0.9559	51690	0.3001
0.9561	51700	0.3
0.9562	51710	0.2942
0.9564	51720	0.3007
0.9566	51730	0.3003
0.9568	51740	0.2976
0.9570	51750	0.3014
0.9572	51760	0.3009
0.9574	51770	0.2976
0.9575	51780	0.3003
0.9577	51790	0.2974
0.9579	51800	0.2976
0.9581	51810	0.2972
0.9583	51820	0.3006
0.9585	51830	0.2993
0.9586	51840	0.2964
0.9588	51850	0.2972
0.9590	51860	0.2997
0.9592	51870	0.2996
0.9594	51880	0.3028
0.9596	51890	0.2972
0.9598	51900	0.2995
0.9599	51910	0.302
0.9601	51920	0.2991
0.9603	51930	0.3005
0.9605	51940	0.3001
0.9607	51950	0.3025
0.9609	51960	0.3003
0.9611	51970	0.2962
0.9612	51980	0.2977
0.9614	51990	0.2991
0.9616	52000	0.2983
0.9618	52010	0.2995
0.9620	52020	0.2992
0.9622	52030	0.3006
0.9623	52040	0.2963
0.9625	52050	0.2963
0.9627	52060	0.2994
0.9629	52070	0.3034
0.9631	52080	0.3006
0.9633	52090	0.2998
0.9635	52100	0.2991
0.9636	52110	0.3009
0.9638	52120	0.2997
0.9640	52130	0.2994
0.9642	52140	0.2996
0.9644	52150	0.3008
0.9646	52160	0.296
0.9648	52170	0.2985
0.9649	52180	0.3008
0.9651	52190	0.2988
0.9653	52200	0.2999
0.9655	52210	0.2919
0.9657	52220	0.3039
0.9659	52230	0.2983
0.9660	52240	0.3015
0.9662	52250	0.2983
0.9664	52260	0.3013
0.9666	52270	0.3009
0.9668	52280	0.3012
0.9670	52290	0.2998
0.9672	52300	0.2992
0.9673	52310	0.2989
0.9675	52320	0.2974
0.9677	52330	0.3036
0.9679	52340	0.2962
0.9681	52350	0.3011
0.9683	52360	0.2999
0.9684	52370	0.2997
0.9686	52380	0.2976
0.9688	52390	0.2999
0.9690	52400	0.2995
0.9692	52410	0.3013
0.9694	52420	0.2977
0.9696	52430	0.2988
0.9697	52440	0.2975
0.9699	52450	0.3
0.9701	52460	0.3002
0.9703	52470	0.3
0.9705	52480	0.2966
0.9707	52490	0.2982
0.9709	52500	0.2987
0.9710	52510	0.304
0.9712	52520	0.3003
0.9714	52530	0.2968
0.9716	52540	0.2981
0.9718	52550	0.2967
0.9720	52560	0.301
0.9721	52570	0.3007
0.9723	52580	0.3003
0.9725	52590	0.3008
0.9727	52600	0.2981
0.9729	52610	0.3008
0.9731	52620	0.3021
0.9733	52630	0.2988
0.9734	52640	0.297
0.9736	52650	0.297
0.9738	52660	0.3002
0.9740	52670	0.2982
0.9742	52680	0.3038
0.9744	52690	0.298
0.9746	52700	0.2998
0.9747	52710	0.2984
0.9749	52720	0.3008
0.9751	52730	0.3008
0.9753	52740	0.2974
0.9755	52750	0.2989
0.9757	52760	0.3005
0.9758	52770	0.3008
0.9760	52780	0.2929
0.9762	52790	0.3014
0.9764	52800	0.2979
0.9766	52810	0.2977
0.9768	52820	0.3008
0.9770	52830	0.2952
0.9771	52840	0.2986
0.9773	52850	0.2994
0.9775	52860	0.295
0.9777	52870	0.3004
0.9779	52880	0.3005
0.9781	52890	0.2989
0.9783	52900	0.2959
0.9784	52910	0.3001
0.9786	52920	0.3017
0.9788	52930	0.2966
0.9790	52940	0.2998
0.9792	52950	0.3001
0.9794	52960	0.2986
0.9795	52970	0.3019
0.9797	52980	0.3003
0.9799	52990	0.2983
0.9801	53000	0.2991
0.9803	53010	0.2968
0.9805	53020	0.2998
0.9807	53030	0.2967
0.9808	53040	0.2919
0.9810	53050	0.2985
0.9812	53060	0.2976
0.9814	53070	0.2981
0.9816	53080	0.2989
0.9818	53090	0.2996
0.9819	53100	0.2986
0.9821	53110	0.2988
0.9823	53120	0.2979
0.9825	53130	0.3013
0.9827	53140	0.3017
0.9829	53150	0.2977
0.9831	53160	0.2991
0.9832	53170	0.2982
0.9834	53180	0.2994
0.9836	53190	0.2996
0.9838	53200	0.297
0.9840	53210	0.2992
0.9842	53220	0.2979
0.9844	53230	0.3044
0.9845	53240	0.2999
0.9847	53250	0.3025
0.9849	53260	0.302
0.9851	53270	0.2984
0.9853	53280	0.3021
0.9855	53290	0.3
0.9856	53300	0.297
0.9858	53310	0.3003
0.9860	53320	0.299
0.9862	53330	0.2971
0.9864	53340	0.3006
0.9866	53350	0.3001
0.9868	53360	0.2986
0.9869	53370	0.3017
0.9871	53380	0.3
0.9873	53390	0.2993
0.9875	53400	0.299
0.9877	53410	0.3007
0.9879	53420	0.2992
0.9881	53430	0.301
0.9882	53440	0.2947
0.9884	53450	0.2985
0.9886	53460	0.3013
0.9888	53470	0.2971
0.9890	53480	0.3011
0.9892	53490	0.3019
0.9893	53500	0.2982
0.9895	53510	0.2988
0.9897	53520	0.2975
0.9899	53530	0.3015
0.9901	53540	0.2951
0.9903	53550	0.299
0.9905	53560	0.3002
0.9906	53570	0.3037
0.9908	53580	0.2998
0.9910	53590	0.2972
0.9912	53600	0.2972
0.9914	53610	0.3021
0.9916	53620	0.2997
0.9918	53630	0.3002
0.9919	53640	0.3008
0.9921	53650	0.2992
0.9923	53660	0.3003
0.9925	53670	0.2994
0.9927	53680	0.3003
0.9929	53690	0.3023
0.9930	53700	0.3013
0.9932	53710	0.3001
0.9934	53720	0.2998
0.9936	53730	0.2994
0.9938	53740	0.2979
0.9940	53750	0.3032
0.9942	53760	0.2972
0.9943	53770	0.2997
0.9945	53780	0.2995
0.9947	53790	0.3007
0.9949	53800	0.3001
0.9951	53810	0.2988
0.9953	53820	0.2972
0.9954	53830	0.2983
0.9956	53840	0.2962
0.9958	53850	0.3011
0.9960	53860	0.2957
0.9962	53870	0.2978
0.9964	53880	0.3009
0.9966	53890	0.3006
0.9967	53900	0.2995
0.9969	53910	0.302
0.9971	53920	0.299
0.9973	53930	0.3006
0.9975	53940	0.3001
0.9977	53950	0.3023
0.9979	53960	0.2951
0.9980	53970	0.3005
0.9982	53980	0.3004
0.9984	53990	0.2984
0.9986	54000	0.2989
0.9988	54010	0.3016
0.9990	54020	0.2968
0.9991	54030	0.3019
0.9993	54040	0.3015
0.9995	54050	0.3016
0.9997	54060	0.2985
0.9999	54070	0.2989

Framework Versions

• Python: 3.12.11
• Sentence Transformers: 5.1.2
• Transformers: 4.57.1
• PyTorch: 2.8.0+cu129
• Accelerate: 1.11.0
• Datasets: 4.3.0
• Tokenizers: 0.22.1

Citation

BibTeX

Sentence Transformers

@inproceedings{reimers-2019-sentence-bert,
    title = "Sentence-BERT: Sentence Embeddings using Siamese BERT-Networks",
    author = "Reimers, Nils and Gurevych, Iryna",
    booktitle = "Proceedings of the 2019 Conference on Empirical Methods in Natural Language Processing",
    month = "11",
    year = "2019",
    publisher = "Association for Computational Linguistics",
    url = "https://arxiv.org/abs/1908.10084",
}

TripletLoss

@misc{hermans2017defense,
    title={In Defense of the Triplet Loss for Person Re-Identification},
    author={Alexander Hermans and Lucas Beyer and Bastian Leibe},
    year={2017},
    eprint={1703.07737},
    archivePrefix={arXiv},
    primaryClass={cs.CV}
}