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SELECT Name FROM country ORDER BY Population DESC LIMIT 3
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Apa nama negara dengan 3 populasi terbesar?
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CREATE TABLE country (Name VARCHAR, Population VARCHAR)
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SELECT Name FROM country ORDER BY Population LIMIT 3
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Apa nama -nama bangsa dengan 3 populasi terendah?
|
CREATE TABLE country (Name VARCHAR, Population VARCHAR)
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SELECT COUNT(*) FROM country WHERE continent = "Asia"
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Berapa banyak negara di Asia?
|
CREATE TABLE country (continent VARCHAR)
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SELECT Name FROM country WHERE continent = "Europe" AND Population = "80000"
|
Apa nama -nama negara yang berada di benua Eropa dan memiliki populasi 80000?
|
CREATE TABLE country (Name VARCHAR, continent VARCHAR, Population VARCHAR)
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SELECT SUM(population), AVG(surfacearea) FROM country WHERE continent = "north america" AND surfacearea > 3000
|
Berapa total populasi dan area rata -rata negara di benua Amerika Utara yang daerahnya lebih besar dari 3000?
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CREATE TABLE country (population INTEGER, surfacearea INTEGER, continent VARCHAR)
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SELECT name FROM city WHERE Population BETWEEN 160000 AND 900000
|
Apa kota yang populasinya antara 160000 dan 900000?
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CREATE TABLE city (name VARCHAR, Population INTEGER)
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SELECT name FROM city WHERE population BETWEEN 160000 AND 900000
|
Kembalikan nama -nama kota yang memiliki populasi antara 160000 dan 900000.
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CREATE TABLE city (name VARCHAR, population INTEGER)
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SELECT LANGUAGE FROM countrylanguage GROUP BY LANGUAGE ORDER BY COUNT(*) DESC LIMIT 1
|
Bahasa mana yang digunakan oleh negara -negara terbesar?
|
CREATE TABLE countrylanguage (LANGUAGE VARCHAR)
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SELECT LANGUAGE, CountryCode, MAX(Percentage) FROM countrylanguage GROUP BY CountryCode
|
Apa bahasa yang digunakan oleh persentase terbesar orang di setiap negara?
|
CREATE TABLE countrylanguage (LANGUAGE VARCHAR, CountryCode VARCHAR, Percentage INTEGER)
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SELECT COUNT(*), MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
|
Berapa total negara di mana bahasa Spanyol diucapkan oleh persentase terbesar orang?
|
CREATE TABLE countrylanguage (Percentage INTEGER, CountryCode VARCHAR, LANGUAGE VARCHAR)
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SELECT CountryCode, MAX(Percentage) FROM countrylanguage WHERE LANGUAGE = "Spanish" GROUP BY CountryCode
|
Apa kode negara di mana bahasa Spanyol diucapkan oleh persentase terbesar orang?
|
CREATE TABLE countrylanguage (CountryCode VARCHAR, Percentage INTEGER, LANGUAGE VARCHAR)
|
SELECT COUNT(*) FROM conductor
|
Ada berapa konduktor?
|
CREATE TABLE conductor (Id VARCHAR)
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SELECT Name FROM conductor ORDER BY Age
|
Sebutkan nama -nama konduktor dalam urutan usia naik.
|
CREATE TABLE conductor (Name VARCHAR, Age VARCHAR)
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SELECT Name FROM conductor WHERE Nationality <> 'USA'
|
Apa nama konduktor yang kebangsaannya bukan "AS"?
|
CREATE TABLE conductor (Name VARCHAR, Nationality VARCHAR)
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SELECT Record_Company FROM orchestra ORDER BY Year_of_Founded DESC
|
Apa saja perusahaan rekaman orkestra dalam urutan yang menurun tahun di mana mereka didirikan?
|
CREATE TABLE orchestra (Record_Company VARCHAR, Year_of_Founded VARCHAR)
|
SELECT AVG(Attendance) FROM SHOW
|
Apa kehadiran rata -rata pertunjukan?
|
CREATE TABLE SHOW (Attendance INTEGER)
|
SELECT MAX(SHARE), MIN(SHARE) FROM performance WHERE TYPE <> "Live final"
|
Apa bagian maksimum dan minimum pertunjukan yang jenisnya bukan "final live".
|
CREATE TABLE performance (SHARE INTEGER, TYPE VARCHAR)
|
SELECT COUNT(DISTINCT Nationality) FROM conductor
|
Berapa banyak negara berbeda yang dimiliki konduktor?
|
CREATE TABLE conductor (Nationality VARCHAR)
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SELECT Name FROM conductor ORDER BY Year_of_Work DESC
|
Daftar nama konduktor dalam urutan kerja tahun yang menurun.
|
CREATE TABLE conductor (Name VARCHAR, Year_of_Work VARCHAR)
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SELECT Name FROM conductor ORDER BY Year_of_Work DESC LIMIT 1
|
Sebutkan nama konduktor dengan pekerjaan terbanyak.
|
CREATE TABLE conductor (Name VARCHAR, Year_of_Work VARCHAR)
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SELECT T1.Name, T2.Orchestra FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID
|
Tunjukkan nama -nama konduktor dan orkestra yang telah mereka lakukan.
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CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR); CREATE TABLE orchestra (Orchestra VARCHAR, Conductor_ID VARCHAR)
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SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID HAVING COUNT(*) > 1
|
Tunjukkan nama konduktor yang telah melakukan lebih dari satu orkestra.
|
CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR)
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SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID GROUP BY T2.Conductor_ID ORDER BY COUNT(*) DESC LIMIT 1
|
Tunjukkan nama konduktor yang telah melakukan orkestra terbanyak.
|
CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR)
|
SELECT T1.Name FROM conductor AS T1 JOIN orchestra AS T2 ON T1.Conductor_ID = T2.Conductor_ID WHERE Year_of_Founded > 2008
|
Harap tunjukkan nama konduktor yang telah melakukan orkestra yang didirikan setelah 2008.
|
CREATE TABLE orchestra (Conductor_ID VARCHAR); CREATE TABLE conductor (Name VARCHAR, Conductor_ID VARCHAR)
|
SELECT Record_Company, COUNT(*) FROM orchestra GROUP BY Record_Company
|
Harap tunjukkan berbagai perusahaan rekaman dan jumlah orkestra yang sesuai.
|
CREATE TABLE orchestra (Record_Company VARCHAR)
|
SELECT Major_Record_Format FROM orchestra GROUP BY Major_Record_Format ORDER BY COUNT(*)
|
Harap tunjukkan format rekaman orkestra dalam urutan penghitungan.
|
CREATE TABLE orchestra (Major_Record_Format VARCHAR)
|
SELECT Record_Company FROM orchestra GROUP BY Record_Company ORDER BY COUNT(*) DESC LIMIT 1
|
Sebutkan perusahaan rekaman yang dibagikan oleh orkestra terbanyak.
|
CREATE TABLE orchestra (Record_Company VARCHAR)
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SELECT Orchestra FROM orchestra WHERE NOT Orchestra_ID IN (SELECT Orchestra_ID FROM performance)
|
Sebutkan nama orkestra yang tidak memiliki kinerja.
|
CREATE TABLE orchestra (Orchestra VARCHAR, Orchestra_ID VARCHAR); CREATE TABLE performance (Orchestra VARCHAR, Orchestra_ID VARCHAR)
|
SELECT Record_Company FROM orchestra WHERE Year_of_Founded < 2003 INTERSECT SELECT Record_Company FROM orchestra WHERE Year_of_Founded > 2003
|
Tunjukkan perusahaan rekaman yang dibagikan oleh orkestra yang didirikan sebelum 2003 dan setelah 2003.
|
CREATE TABLE orchestra (Record_Company VARCHAR, Year_of_Founded INTEGER)
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SELECT COUNT(*) FROM orchestra WHERE Major_Record_Format = "CD" OR Major_Record_Format = "DVD"
|
Temukan jumlah orkestra yang format rekamannya adalah "CD" atau "DVD".
|
CREATE TABLE orchestra (Major_Record_Format VARCHAR)
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SELECT Year_of_Founded FROM orchestra AS T1 JOIN performance AS T2 ON T1.Orchestra_ID = T2.Orchestra_ID GROUP BY T2.Orchestra_ID HAVING COUNT(*) > 1
|
Tunjukkan tahun -tahun di mana orkestra yang telah memberikan lebih dari satu kinerja didirikan.
|
CREATE TABLE performance (Orchestra_ID VARCHAR); CREATE TABLE orchestra (Orchestra_ID VARCHAR)
|
SELECT COUNT(*) FROM Highschooler
|
Ada berapa siswa sekolah menengah?
|
CREATE TABLE Highschooler (Id VARCHAR)
|
SELECT name, grade FROM Highschooler
|
Tunjukkan nama dan nilai masing -masing siswa sekolah menengah.
|
CREATE TABLE Highschooler (name VARCHAR, grade VARCHAR)
|
SELECT grade FROM Highschooler
|
Tunjukkan semua nilai siswa sekolah menengah.
|
CREATE TABLE Highschooler (grade VARCHAR)
|
SELECT grade FROM Highschooler WHERE name = "Kyle"
|
Di kelas berapa Kyle?
|
CREATE TABLE Highschooler (grade VARCHAR, name VARCHAR)
|
SELECT name FROM Highschooler WHERE grade = 10
|
Tunjukkan nama semua siswa sekolah menengah di kelas 10.
|
CREATE TABLE Highschooler (name VARCHAR, grade VARCHAR)
|
SELECT ID FROM Highschooler WHERE name = "Kyle"
|
Tunjukkan ID dari siswa sekolah menengah bernama Kyle.
|
CREATE TABLE Highschooler (ID VARCHAR, name VARCHAR)
|
SELECT COUNT(*) FROM Highschooler WHERE grade = 9 OR grade = 10
|
Berapa banyak siswa sekolah menengah di kelas 9 atau 10?
|
CREATE TABLE Highschooler (grade VARCHAR)
|
SELECT grade, COUNT(*) FROM Highschooler GROUP BY grade
|
Tunjukkan jumlah siswa sekolah menengah untuk setiap kelas.
|
CREATE TABLE Highschooler (grade VARCHAR)
|
SELECT grade FROM Highschooler GROUP BY grade ORDER BY COUNT(*) DESC LIMIT 1
|
Kelas mana yang memiliki siswa sekolah menengah mana pun?
|
CREATE TABLE Highschooler (grade VARCHAR)
|
SELECT grade FROM Highschooler GROUP BY grade HAVING COUNT(*) >= 4
|
Tunjukkan semua nilai yang memiliki setidaknya 4 siswa.
|
CREATE TABLE Highschooler (grade VARCHAR)
|
SELECT student_id, COUNT(*) FROM Friend GROUP BY student_id
|
Tunjukkan ID siswa dan jumlah teman yang sesuai dengan masing -masing.
|
CREATE TABLE Friend (student_id VARCHAR)
|
SELECT T2.name, COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
|
Tunjukkan nama -nama siswa sekolah menengah dan jumlah teman mereka yang sesuai.
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR)
|
SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
|
Apa nama siswa sekolah menengah yang memiliki jumlah teman terbesar?
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR)
|
SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 3
|
Tunjukkan nama -nama siswa sekolah menengah yang memiliki setidaknya 3 teman.
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR)
|
SELECT T3.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id JOIN Highschooler AS T3 ON T1.friend_id = T3.id WHERE T2.name = "Kyle"
|
Tunjukkan nama -nama semua teman sekolah menengah Kyle.
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, friend_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR)
|
SELECT COUNT(*) FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
|
Berapa banyak teman yang dimiliki siswa sekolah menengah Kyle?
|
CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR)
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SELECT id FROM Highschooler EXCEPT SELECT student_id FROM Friend
|
Tunjukkan ID dari semua siswa yang tidak punya teman.
|
CREATE TABLE Highschooler (id VARCHAR, student_id VARCHAR); CREATE TABLE Friend (id VARCHAR, student_id VARCHAR)
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SELECT name FROM Highschooler EXCEPT SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id
|
Tunjukkan nama semua siswa sekolah menengah yang tidak punya teman.
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Highschooler (name VARCHAR); CREATE TABLE Friend (student_id VARCHAR)
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SELECT student_id FROM Friend INTERSECT SELECT liked_id FROM Likes
|
Tunjukkan ID dari siswa sekolah menengah yang memiliki teman dan juga disukai oleh orang lain.
|
CREATE TABLE Likes (student_id VARCHAR, liked_id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, liked_id VARCHAR)
|
SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id INTERSECT SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.liked_id = T2.id
|
Tunjukkan nama semua siswa yang memiliki beberapa teman dan juga disukai oleh orang lain.
|
CREATE TABLE Highschooler (name VARCHAR, id VARCHAR); CREATE TABLE Likes (student_id VARCHAR, liked_id VARCHAR); CREATE TABLE Friend (student_id VARCHAR, liked_id VARCHAR)
|
SELECT student_id, COUNT(*) FROM Likes GROUP BY student_id
|
Hitung jumlah suka untuk setiap ID siswa.
|
CREATE TABLE Likes (student_id VARCHAR)
|
SELECT T2.name, COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id
|
Tunjukkan nama -nama siswa sekolah menengah yang memiliki suka, dan jumlah suka untuk masing -masing.
|
CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR)
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SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id ORDER BY COUNT(*) DESC LIMIT 1
|
Apa nama siswa sekolah menengah yang memiliki jumlah suka terbesar?
|
CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR)
|
SELECT T2.name FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id GROUP BY T1.student_id HAVING COUNT(*) >= 2
|
Tunjukkan nama -nama siswa yang memiliki setidaknya 2 suka.
|
CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR)
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SELECT T2.name FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.grade > 5 GROUP BY T1.student_id HAVING COUNT(*) >= 2
|
Tunjukkan nama -nama siswa yang memiliki nilai lebih tinggi dari 5 dan memiliki setidaknya 2 teman.
|
CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (name VARCHAR, id VARCHAR, grade INTEGER)
|
SELECT COUNT(*) FROM Likes AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id WHERE T2.name = "Kyle"
|
Berapa banyak suka yang dimiliki Kyle?
|
CREATE TABLE Likes (student_id VARCHAR); CREATE TABLE Highschooler (id VARCHAR, name VARCHAR)
|
SELECT AVG(grade) FROM Highschooler WHERE id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
|
Temukan nilai rata -rata semua siswa yang memiliki beberapa teman.
|
CREATE TABLE Highschooler (id VARCHAR); CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (grade INTEGER, id VARCHAR)
|
SELECT MIN(grade) FROM Highschooler WHERE NOT id IN (SELECT T1.student_id FROM Friend AS T1 JOIN Highschooler AS T2 ON T1.student_id = T2.id)
|
Temukan nilai minimum siswa yang tidak punya teman.
|
CREATE TABLE Highschooler (id VARCHAR); CREATE TABLE Friend (student_id VARCHAR); CREATE TABLE Highschooler (grade INTEGER, id VARCHAR)
|
SELECT state FROM Owners INTERSECT SELECT state FROM Professionals
|
Negara bagian mana yang memiliki pemilik dan profesional yang tinggal di sana?
|
CREATE TABLE Owners (state VARCHAR); CREATE TABLE Professionals (state VARCHAR)
|
SELECT AVG(age) FROM Dogs WHERE dog_id IN (SELECT dog_id FROM Treatments)
|
Berapa usia rata -rata anjing yang telah menjalani perawatan apa pun?
|
CREATE TABLE Dogs (age INTEGER, dog_id VARCHAR); CREATE TABLE Treatments (age INTEGER, dog_id VARCHAR)
|
SELECT professional_id, last_name, cell_number FROM Professionals WHERE state = 'Indiana' UNION SELECT T1.professional_id, T1.last_name, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) > 2
|
Profesional mana yang tinggal di negara bagian Indiana atau telah melakukan perawatan lebih dari 2 perawatan?Sebutkan ID, nama belakang, dan ponselnya.
|
CREATE TABLE Treatments (professional_id VARCHAR); CREATE TABLE Professionals (professional_id VARCHAR, last_name VARCHAR, cell_number VARCHAR); CREATE TABLE Professionals (professional_id VARCHAR, last_name VARCHAR, cell_number VARCHAR, state VARCHAR)
|
SELECT name FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments GROUP BY dog_id HAVING SUM(cost_of_treatment) > 1000)
|
Anjing mana yang tidak dikenakan biaya lebih dari 1000 pemiliknya untuk perawatan?Buat daftar nama anjing.
|
CREATE TABLE dogs (name VARCHAR, dog_id VARCHAR, cost_of_treatment INTEGER); CREATE TABLE treatments (name VARCHAR, dog_id VARCHAR, cost_of_treatment INTEGER)
|
SELECT first_name FROM Professionals UNION SELECT first_name FROM Owners EXCEPT SELECT name FROM Dogs
|
Nama depan mana yang digunakan untuk profesional atau pemilik tetapi tidak digunakan sebagai nama anjing?
|
CREATE TABLE Owners (first_name VARCHAR, name VARCHAR); CREATE TABLE Dogs (first_name VARCHAR, name VARCHAR); CREATE TABLE Professionals (first_name VARCHAR, name VARCHAR)
|
SELECT professional_id, role_code, email_address FROM Professionals EXCEPT SELECT T1.professional_id, T1.role_code, T1.email_address FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id
|
Profesional mana yang tidak mengoperasikan perawatan pada anjing?Sebutkan ID, peran, dan email profesional.
|
CREATE TABLE Professionals (professional_id VARCHAR, role_code VARCHAR, email_address VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR)
|
SELECT T1.owner_id, T2.first_name, T2.last_name FROM Dogs AS T1 JOIN Owners AS T2 ON T1.owner_id = T2.owner_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
|
Pemilik mana yang memiliki anjing terbanyak?Sebutkan ID pemilik, nama depan dan nama belakang.
|
CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR)
|
SELECT T1.professional_id, T1.role_code, T1.first_name FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
|
Profesional mana yang telah melakukan setidaknya dua perawatan?Sebutkan ID, peran, dan nama depan profesional.
|
CREATE TABLE Professionals (professional_id VARCHAR, role_code VARCHAR, first_name VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR)
|
SELECT T1.breed_name FROM Breeds AS T1 JOIN Dogs AS T2 ON T1.breed_code = T2.breed_code GROUP BY T1.breed_name ORDER BY COUNT(*) DESC LIMIT 1
|
Apa nama trah dengan anjing terbanyak?
|
CREATE TABLE Dogs (breed_code VARCHAR); CREATE TABLE Breeds (breed_name VARCHAR, breed_code VARCHAR)
|
SELECT T1.owner_id, T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY COUNT(*) DESC LIMIT 1
|
Pemilik mana yang telah membayar untuk perawatan paling banyak pada anjingnya?Sebutkan ID pemilik dan nama belakang.
|
CREATE TABLE Owners (owner_id VARCHAR, last_name VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR)
|
SELECT T1.treatment_type_description FROM Treatment_types AS T1 JOIN Treatments AS T2 ON T1.treatment_type_code = T2.treatment_type_code GROUP BY T1.treatment_type_code ORDER BY SUM(cost_of_treatment) LIMIT 1
|
Apa deskripsi dari jenis perawatan yang membutuhkan biaya paling sedikit?
|
CREATE TABLE Treatments (treatment_type_code VARCHAR); CREATE TABLE Treatment_types (treatment_type_description VARCHAR, treatment_type_code VARCHAR)
|
SELECT T1.owner_id, T1.zip_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id JOIN Treatments AS T3 ON T2.dog_id = T3.dog_id GROUP BY T1.owner_id ORDER BY SUM(T3.cost_of_treatment) DESC LIMIT 1
|
Pemilik mana yang telah membayar jumlah uang terbesar secara total untuk anjing mereka?Tunjukkan ID pemilik dan kode pos.
|
CREATE TABLE Treatments (dog_id VARCHAR, cost_of_treatment INTEGER); CREATE TABLE Owners (owner_id VARCHAR, zip_code VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, dog_id VARCHAR)
|
SELECT T1.professional_id, T1.cell_number FROM Professionals AS T1 JOIN Treatments AS T2 ON T1.professional_id = T2.professional_id GROUP BY T1.professional_id HAVING COUNT(*) >= 2
|
Profesional mana yang telah melakukan setidaknya dua jenis perawatan?Sebutkan ID profesional dan ponsel.
|
CREATE TABLE Professionals (professional_id VARCHAR, cell_number VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR)
|
SELECT DISTINCT T1.first_name, T1.last_name FROM Professionals AS T1 JOIN Treatments AS T2 WHERE cost_of_treatment < (SELECT AVG(cost_of_treatment) FROM Treatments)
|
Siapa nama depan dan nama belakang para profesional yang telah melakukan perawatan dengan biaya di bawah rata -rata?
|
CREATE TABLE Treatments (cost_of_treatment INTEGER); CREATE TABLE Professionals (first_name VARCHAR, last_name VARCHAR); CREATE TABLE Treatments (Id VARCHAR)
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SELECT T1.date_of_treatment, T2.first_name FROM Treatments AS T1 JOIN Professionals AS T2 ON T1.professional_id = T2.professional_id
|
Sebutkan tanggal setiap perawatan, bersama dengan nama depan profesional yang mengoperasikannya.
|
CREATE TABLE Treatments (date_of_treatment VARCHAR, professional_id VARCHAR); CREATE TABLE Professionals (first_name VARCHAR, professional_id VARCHAR)
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SELECT T1.cost_of_treatment, T2.treatment_type_description FROM Treatments AS T1 JOIN treatment_types AS T2 ON T1.treatment_type_code = T2.treatment_type_code
|
Sebutkan biaya setiap perawatan dan deskripsi jenis perawatan yang sesuai.
|
CREATE TABLE Treatments (cost_of_treatment VARCHAR, treatment_type_code VARCHAR); CREATE TABLE treatment_types (treatment_type_description VARCHAR, treatment_type_code VARCHAR)
|
SELECT T1.first_name, T1.last_name, T2.size_code FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
|
Sebutkan nama depan masing -masing pemilik, nama belakang, dan ukurannya untuk anjingnya.
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CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (size_code VARCHAR, owner_id VARCHAR)
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SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id
|
Daftar pasangan nama depan pemilik dan nama anjing.
|
CREATE TABLE Dogs (name VARCHAR, owner_id VARCHAR); CREATE TABLE Owners (first_name VARCHAR, owner_id VARCHAR)
|
SELECT T1.name, T2.date_of_treatment FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id WHERE T1.breed_code = (SELECT breed_code FROM Dogs GROUP BY breed_code ORDER BY COUNT(*) LIMIT 1)
|
Sebutkan nama -nama anjing dari jenis yang paling langka dan tanggal perawatan mereka.
|
CREATE TABLE Dogs (name VARCHAR, dog_id VARCHAR, breed_code VARCHAR); CREATE TABLE Treatments (date_of_treatment VARCHAR, dog_id VARCHAR); CREATE TABLE Dogs (breed_code VARCHAR)
|
SELECT T1.first_name, T2.name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T1.state = 'Virginia'
|
Anjing mana yang dimiliki oleh seseorang yang tinggal di Virginia?Sebutkan nama depan pemilik dan nama anjing.
|
CREATE TABLE Dogs (name VARCHAR, owner_id VARCHAR); CREATE TABLE Owners (first_name VARCHAR, owner_id VARCHAR, state VARCHAR)
|
SELECT DISTINCT T1.date_arrived, T1.date_departed FROM Dogs AS T1 JOIN Treatments AS T2 ON T1.dog_id = T2.dog_id
|
Apa tanggal yang tiba dan tanggal berangkat dari anjing -anjing yang telah menjalani perawatan?
|
CREATE TABLE Dogs (date_arrived VARCHAR, date_departed VARCHAR, dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR)
|
SELECT T1.last_name FROM Owners AS T1 JOIN Dogs AS T2 ON T1.owner_id = T2.owner_id WHERE T2.age = (SELECT MAX(age) FROM Dogs)
|
Sebutkan nama belakang pemilik yang memiliki anjing termuda.
|
CREATE TABLE Owners (last_name VARCHAR, owner_id VARCHAR); CREATE TABLE Dogs (owner_id VARCHAR, age INTEGER); CREATE TABLE Dogs (age INTEGER)
|
SELECT email_address FROM Professionals WHERE state = 'Hawaii' OR state = 'Wisconsin'
|
Sebutkan email para profesional yang tinggal di negara bagian Hawaii atau negara bagian Wisconsin.
|
CREATE TABLE Professionals (email_address VARCHAR, state VARCHAR)
|
SELECT date_arrived, date_departed FROM Dogs
|
Apa tanggal yang tiba dan tanggal berangkat dari semua anjing?
|
CREATE TABLE Dogs (date_arrived VARCHAR, date_departed VARCHAR)
|
SELECT COUNT(DISTINCT dog_id) FROM Treatments
|
Berapa banyak anjing yang menjalani perawatan?
|
CREATE TABLE Treatments (dog_id VARCHAR)
|
SELECT COUNT(DISTINCT professional_id) FROM Treatments
|
Berapa banyak profesional yang melakukan perawatan pada anjing?
|
CREATE TABLE Treatments (professional_id VARCHAR)
|
SELECT role_code, street, city, state FROM professionals WHERE city LIKE '%West%'
|
Profesional mana yang tinggal di kota yang berisi 'barat' substring?Sebutkan perannya, jalan, kota, dan negara bagiannya.
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CREATE TABLE professionals (role_code VARCHAR, street VARCHAR, city VARCHAR, state VARCHAR)
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SELECT first_name, last_name, email_address FROM Owners WHERE state LIKE '%North%'
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Pemilik mana yang tinggal di negara bagian yang namanya berisi substring 'utara'?Sebutkan nama depan, nama belakang, dan emailnya.
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CREATE TABLE Owners (first_name VARCHAR, last_name VARCHAR, email_address VARCHAR, state VARCHAR)
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SELECT COUNT(*) FROM Dogs WHERE age < (SELECT AVG(age) FROM Dogs)
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Berapa banyak anjing yang memiliki usia di bawah rata -rata?
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CREATE TABLE Dogs (age INTEGER)
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SELECT cost_of_treatment FROM Treatments ORDER BY date_of_treatment DESC LIMIT 1
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Berapa biaya perawatan terbaru?
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CREATE TABLE Treatments (cost_of_treatment VARCHAR, date_of_treatment VARCHAR)
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SELECT COUNT(*) FROM Dogs WHERE NOT dog_id IN (SELECT dog_id FROM Treatments)
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Berapa banyak anjing yang belum menjalani perawatan apa pun?
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CREATE TABLE Dogs (dog_id VARCHAR); CREATE TABLE Treatments (dog_id VARCHAR)
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SELECT COUNT(*) FROM dogs WHERE NOT dog_id IN (SELECT dog_id FROM treatments)
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Ceritakan jumlah anjing yang belum menerima perawatan apa pun.
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CREATE TABLE treatments (dog_id VARCHAR); CREATE TABLE dogs (dog_id VARCHAR)
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SELECT COUNT(*) FROM Owners WHERE NOT owner_id IN (SELECT owner_id FROM Dogs)
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Berapa banyak pemilik sementara yang tidak punya anjing?
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CREATE TABLE Dogs (owner_id VARCHAR); CREATE TABLE Owners (owner_id VARCHAR)
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SELECT COUNT(*) FROM Professionals WHERE NOT professional_id IN (SELECT professional_id FROM Treatments)
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Berapa banyak profesional yang tidak mengoperasikan perawatan pada anjing?
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CREATE TABLE Professionals (professional_id VARCHAR); CREATE TABLE Treatments (professional_id VARCHAR)
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SELECT name, age, weight FROM Dogs WHERE abandoned_yn = 1
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Sebutkan nama anjing, usia dan berat anjing yang telah ditinggalkan?1 adalah singkatan dari ya, dan 0 adalah singkatan dari tidak.
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CREATE TABLE Dogs (name VARCHAR, age VARCHAR, weight VARCHAR, abandoned_yn VARCHAR)
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SELECT AVG(age) FROM Dogs
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Berapa usia rata -rata semua anjing?
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CREATE TABLE Dogs (age INTEGER)
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SELECT MAX(age) FROM Dogs
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Berapa usia anjing tertua?
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CREATE TABLE Dogs (age INTEGER)
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SELECT charge_type, charge_amount FROM Charges
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Berapa biaya setiap jenis biaya?Sebutkan jenis dan jumlah pengisian daya.
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CREATE TABLE Charges (charge_type VARCHAR, charge_amount VARCHAR)
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SELECT MAX(charge_amount) FROM Charges
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Berapa biaya jenis biaya paling mahal?
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CREATE TABLE Charges (charge_amount INTEGER)
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SELECT email_address, cell_number, home_phone FROM professionals
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Sebutkan email, ponsel, dan telepon rumah dari semua profesional.
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CREATE TABLE professionals (email_address VARCHAR, cell_number VARCHAR, home_phone VARCHAR)
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SELECT DISTINCT breed_code, size_code FROM dogs
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Apa saja jenis kombinasi jenis jenis breed dan ukuran yang mungkin?
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CREATE TABLE dogs (breed_code VARCHAR, size_code VARCHAR)
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