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SELECT T1.name FROM instructor AS T1 JOIN advisor AS T2 ON T1.id = T2.i_id GROUP BY T2.i_id HAVING COUNT(*) > 1
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Temukan nama instruktur yang menasihati lebih dari satu siswa.
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CREATE TABLE advisor (i_id VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR)
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SELECT T1.name FROM student AS T1 JOIN advisor AS T2 ON T1.id = T2.s_id GROUP BY T2.s_id HAVING COUNT(*) > 1
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Temukan nama siswa yang memiliki lebih dari satu penasihat?
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CREATE TABLE student (name VARCHAR, id VARCHAR); CREATE TABLE advisor (s_id VARCHAR)
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SELECT COUNT(*), building FROM classroom WHERE capacity > 50 GROUP BY building
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Temukan jumlah kamar dengan lebih dari 50 kapasitas untuk setiap bangunan.
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CREATE TABLE classroom (building VARCHAR, capacity INTEGER)
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SELECT MAX(capacity), AVG(capacity), building FROM classroom GROUP BY building
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Temukan kapasitas maksimum dan rata -rata di antara kamar -kamar di setiap gedung.
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CREATE TABLE classroom (building VARCHAR, capacity INTEGER)
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SELECT title FROM course GROUP BY title HAVING COUNT(*) > 1
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Temukan judul kursus yang ditawarkan oleh lebih dari satu departemen.
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CREATE TABLE course (title VARCHAR)
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SELECT SUM(credits), dept_name FROM course GROUP BY dept_name
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Temukan total kredit kursus yang disediakan oleh departemen yang berbeda.
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CREATE TABLE course (dept_name VARCHAR, credits INTEGER)
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SELECT MIN(salary), dept_name FROM instructor GROUP BY dept_name HAVING AVG(salary) > (SELECT AVG(salary) FROM instructor)
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Temukan gaji minimum untuk departemen yang gaji rata -rata di atas pembayaran rata -rata semua instruktur.
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CREATE TABLE instructor (dept_name VARCHAR, salary INTEGER)
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SELECT COUNT(*), semester, YEAR FROM SECTION GROUP BY semester, YEAR
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Temukan jumlah kursus yang disediakan di setiap semester dan tahun.
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CREATE TABLE SECTION (semester VARCHAR, YEAR VARCHAR)
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SELECT YEAR FROM SECTION GROUP BY YEAR ORDER BY COUNT(*) DESC LIMIT 1
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Temukan tahun yang menawarkan jumlah kursus terbesar.
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CREATE TABLE SECTION (YEAR VARCHAR)
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SELECT semester, YEAR FROM SECTION GROUP BY semester, YEAR ORDER BY COUNT(*) DESC LIMIT 1
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Temukan tahun dan semester ketika menawarkan jumlah kursus terbesar.
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CREATE TABLE SECTION (semester VARCHAR, YEAR VARCHAR)
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SELECT dept_name FROM student GROUP BY dept_name ORDER BY COUNT(*) DESC LIMIT 1
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Temukan nama departemen memiliki jumlah siswa tertinggi?
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CREATE TABLE student (dept_name VARCHAR)
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SELECT COUNT(*), dept_name FROM student GROUP BY dept_name
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Temukan jumlah total siswa di setiap departemen.
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CREATE TABLE student (dept_name VARCHAR)
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SELECT semester, YEAR FROM takes GROUP BY semester, YEAR ORDER BY COUNT(*) LIMIT 1
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Temukan semester dan tahun yang memiliki jumlah siswa yang paling sedikit mengambil kelas apa pun.
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CREATE TABLE takes (semester VARCHAR, YEAR VARCHAR)
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SELECT i_id FROM advisor AS T1 JOIN student AS T2 ON T1.s_id = T2.id WHERE T2.dept_name = 'History'
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Apa ID dari instruktur yang memberi nasihat kepada semua siswa dari departemen sejarah?
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CREATE TABLE advisor (s_id VARCHAR); CREATE TABLE student (id VARCHAR, dept_name VARCHAR)
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SELECT T2.name, T2.salary FROM advisor AS T1 JOIN instructor AS T2 ON T1.i_id = T2.id JOIN student AS T3 ON T1.s_id = T3.id WHERE T3.dept_name = 'History'
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Temukan nama dan gaji instruktur yang merupakan penasihat siswa dari departemen sejarah?
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CREATE TABLE instructor (name VARCHAR, salary VARCHAR, id VARCHAR); CREATE TABLE advisor (i_id VARCHAR, s_id VARCHAR); CREATE TABLE student (id VARCHAR, dept_name VARCHAR)
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SELECT course_id FROM course EXCEPT SELECT course_id FROM prereq
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Temukan ID kursus yang tidak memiliki prasyarat?
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CREATE TABLE prereq (course_id VARCHAR); CREATE TABLE course (course_id VARCHAR)
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SELECT title FROM course WHERE course_id IN (SELECT T1.prereq_id FROM prereq AS T1 JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T2.title = 'International Finance')
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Apa judul Kursus Keuangan Internasional Prasyarat?
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CREATE TABLE course (title VARCHAR, course_id VARCHAR); CREATE TABLE prereq (prereq_id VARCHAR, course_id VARCHAR); CREATE TABLE course (course_id VARCHAR, title VARCHAR)
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SELECT title FROM course WHERE course_id IN (SELECT T1.course_id FROM prereq AS T1 JOIN course AS T2 ON T1.prereq_id = T2.course_id WHERE T2.title = 'Differential Geometry')
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Temukan judul tentu saja prasyaratnya adalah geometri diferensial kursus.
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CREATE TABLE prereq (course_id VARCHAR, prereq_id VARCHAR); CREATE TABLE course (title VARCHAR, course_id VARCHAR); CREATE TABLE course (course_id VARCHAR, title VARCHAR)
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SELECT name FROM student WHERE id IN (SELECT id FROM takes WHERE semester = 'Fall' AND YEAR = 2003)
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Temukan nama -nama siswa yang telah mengambil kursus apa pun di semester musim gugur tahun 2003.
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CREATE TABLE student (name VARCHAR, id VARCHAR, semester VARCHAR, YEAR VARCHAR); CREATE TABLE takes (name VARCHAR, id VARCHAR, semester VARCHAR, YEAR VARCHAR)
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SELECT T1.title FROM course AS T1 JOIN SECTION AS T2 ON T1.course_id = T2.course_id WHERE building = 'Chandler' AND semester = 'Fall' AND YEAR = 2010
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Apa judul kursus yang ditawarkan di Building Chandler selama semester musim gugur pada tahun 2010?
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CREATE TABLE course (title VARCHAR, course_id VARCHAR); CREATE TABLE SECTION (course_id VARCHAR)
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SELECT T1.name FROM instructor AS T1 JOIN teaches AS T2 ON T1.id = T2.id JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T3.title = 'C Programming'
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Temukan nama instruktur yang mengajar kursus pemrograman C sebelumnya.
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CREATE TABLE teaches (id VARCHAR, course_id VARCHAR); CREATE TABLE course (course_id VARCHAR, title VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR)
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SELECT T2.name, T2.salary FROM advisor AS T1 JOIN instructor AS T2 ON T1.i_id = T2.id JOIN student AS T3 ON T1.s_id = T3.id WHERE T3.dept_name = 'Math'
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Temukan nama dan gaji instruktur yang merupakan penasihat siswa dari departemen matematika.
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CREATE TABLE instructor (name VARCHAR, salary VARCHAR, id VARCHAR); CREATE TABLE advisor (i_id VARCHAR, s_id VARCHAR); CREATE TABLE student (id VARCHAR, dept_name VARCHAR)
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SELECT T2.name FROM advisor AS T1 JOIN instructor AS T2 ON T1.i_id = T2.id JOIN student AS T3 ON T1.s_id = T3.id WHERE T3.dept_name = 'Math' ORDER BY T3.tot_cred
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Temukan nama instruktur yang merupakan penasihat siswa dari departemen matematika, dan mengurutkan hasilnya berdasarkan total kredit siswa.
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CREATE TABLE student (id VARCHAR, dept_name VARCHAR, tot_cred VARCHAR); CREATE TABLE advisor (i_id VARCHAR, s_id VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR)
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SELECT title FROM course WHERE course_id IN (SELECT T1.prereq_id FROM prereq AS T1 JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T2.title = 'Mobile Computing')
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Apa judul kursus dari prasyarat komputasi seluler tentu saja?
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CREATE TABLE course (title VARCHAR, course_id VARCHAR); CREATE TABLE prereq (prereq_id VARCHAR, course_id VARCHAR); CREATE TABLE course (course_id VARCHAR, title VARCHAR)
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SELECT T2.name FROM advisor AS T1 JOIN instructor AS T2 ON T1.i_id = T2.id JOIN student AS T3 ON T1.s_id = T3.id ORDER BY T3.tot_cred DESC LIMIT 1
|
Temukan nama instruktur yang merupakan penasihat siswa yang memiliki jumlah total kredit tertinggi.
|
CREATE TABLE student (id VARCHAR, tot_cred VARCHAR); CREATE TABLE advisor (i_id VARCHAR, s_id VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR)
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SELECT name FROM instructor WHERE NOT id IN (SELECT id FROM teaches)
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Temukan nama instruktur yang tidak mengajarkan kursus apa pun?
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CREATE TABLE teaches (name VARCHAR, id VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR)
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SELECT id FROM instructor EXCEPT SELECT id FROM teaches
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Temukan ID instruktur yang tidak mengajarkan kursus apa pun?
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CREATE TABLE teaches (id VARCHAR); CREATE TABLE instructor (id VARCHAR)
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SELECT name FROM instructor WHERE NOT id IN (SELECT id FROM teaches WHERE semester = 'Spring')
|
Temukan nama instruktur yang tidak masing -masing kursus di semester musim semi apa pun.
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CREATE TABLE teaches (name VARCHAR, id VARCHAR, semester VARCHAR); CREATE TABLE instructor (name VARCHAR, id VARCHAR, semester VARCHAR)
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SELECT dept_name FROM instructor GROUP BY dept_name ORDER BY AVG(salary) DESC LIMIT 1
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Temukan nama departemen yang memiliki gaji rata -rata profesor tertinggi.
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CREATE TABLE instructor (dept_name VARCHAR, salary INTEGER)
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SELECT AVG(T1.salary), COUNT(*) FROM instructor AS T1 JOIN department AS T2 ON T1.dept_name = T2.dept_name ORDER BY T2.budget DESC LIMIT 1
|
Temukan jumlah dan gaji rata -rata semua instruktur yang berada di departemen dengan anggaran tertinggi.
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CREATE TABLE department (dept_name VARCHAR, budget VARCHAR); CREATE TABLE instructor (salary INTEGER, dept_name VARCHAR)
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SELECT T3.title, T3.credits FROM classroom AS T1 JOIN SECTION AS T2 ON T1.building = T2.building AND T1.room_number = T2.room_number JOIN course AS T3 ON T2.course_id = T3.course_id WHERE T1.capacity = (SELECT MAX(capacity) FROM classroom)
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Apa judul dan kredit kursus yang diajarkan di kelas terbesar (dengan kapasitas tertinggi)?
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CREATE TABLE SECTION (course_id VARCHAR, building VARCHAR, room_number VARCHAR); CREATE TABLE course (title VARCHAR, credits VARCHAR, course_id VARCHAR); CREATE TABLE classroom (capacity INTEGER, building VARCHAR, room_number VARCHAR); CREATE TABLE classroom (capacity INTEGER)
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SELECT name FROM student WHERE NOT id IN (SELECT T1.id FROM takes AS T1 JOIN course AS T2 ON T1.course_id = T2.course_id WHERE T2.dept_name = 'Biology')
|
Temukan nama siswa yang tidak mengambil kursus apa pun dari departemen biologi.
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CREATE TABLE student (name VARCHAR, id VARCHAR); CREATE TABLE course (course_id VARCHAR, dept_name VARCHAR); CREATE TABLE takes (id VARCHAR, course_id VARCHAR)
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SELECT COUNT(DISTINCT T2.id), COUNT(DISTINCT T3.id), T3.dept_name FROM department AS T1 JOIN student AS T2 ON T1.dept_name = T2.dept_name JOIN instructor AS T3 ON T1.dept_name = T3.dept_name GROUP BY T3.dept_name
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Temukan jumlah total siswa dan jumlah total instruktur untuk setiap departemen.
|
CREATE TABLE department (dept_name VARCHAR); CREATE TABLE student (id VARCHAR, dept_name VARCHAR); CREATE TABLE instructor (dept_name VARCHAR, id VARCHAR)
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SELECT T1.name FROM student AS T1 JOIN takes AS T2 ON T1.id = T2.id WHERE T2.course_id IN (SELECT T4.prereq_id FROM course AS T3 JOIN prereq AS T4 ON T3.course_id = T4.course_id WHERE T3.title = 'International Finance')
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Temukan nama siswa yang telah mengikuti kursus prasyarat dengan judul keuangan internasional.
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CREATE TABLE student (name VARCHAR, id VARCHAR); CREATE TABLE course (course_id VARCHAR, title VARCHAR); CREATE TABLE prereq (prereq_id VARCHAR, course_id VARCHAR); CREATE TABLE takes (id VARCHAR, course_id VARCHAR)
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SELECT name, salary FROM instructor WHERE salary < (SELECT AVG(salary) FROM instructor WHERE dept_name = 'Physics')
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Temukan nama dan gaji instruktur yang gajinya di bawah gaji rata -rata instruktur di departemen fisika.
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CREATE TABLE instructor (name VARCHAR, salary INTEGER, dept_name VARCHAR)
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SELECT T3.name FROM course AS T1 JOIN takes AS T2 ON T1.course_id = T2.course_id JOIN student AS T3 ON T2.id = T3.id WHERE T1.dept_name = 'Statistics'
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Temukan nama siswa yang mengambil beberapa kursus yang ditawarkan oleh Departemen Statistik.
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CREATE TABLE student (name VARCHAR, id VARCHAR); CREATE TABLE takes (course_id VARCHAR, id VARCHAR); CREATE TABLE course (course_id VARCHAR, dept_name VARCHAR)
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SELECT T2.building, T2.room_number, T2.semester, T2.year FROM course AS T1 JOIN SECTION AS T2 ON T1.course_id = T2.course_id WHERE T1.dept_name = 'Psychology' ORDER BY T1.title
|
Temukan bangunan, nomor kamar, semester, dan tahun semua kursus yang ditawarkan oleh departemen psikologi diurutkan berdasarkan judul kursus.
|
CREATE TABLE SECTION (building VARCHAR, room_number VARCHAR, semester VARCHAR, year VARCHAR, course_id VARCHAR); CREATE TABLE course (course_id VARCHAR, dept_name VARCHAR, title VARCHAR)
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SELECT name FROM instructor WHERE dept_name = 'Comp. Sci.'
|
Temukan nama semua instruktur di departemen ilmu komputer
|
CREATE TABLE instructor (name VARCHAR, dept_name VARCHAR)
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SELECT name FROM instructor WHERE dept_name = 'Comp. Sci.' AND salary > 80000
|
Temukan nama semua instruktur di komputer.Sains.Departemen dengan gaji> 80000.
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CREATE TABLE instructor (name VARCHAR, dept_name VARCHAR, salary VARCHAR)
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SELECT name, course_id FROM instructor AS T1 JOIN teaches AS T2 ON T1.ID = T2.ID
|
Temukan nama semua instruktur yang telah mengajar kursus dan kursus_id.
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CREATE TABLE instructor (ID VARCHAR); CREATE TABLE teaches (ID VARCHAR)
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SELECT name, course_id FROM instructor AS T1 JOIN teaches AS T2 ON T1.ID = T2.ID WHERE T1.dept_name = 'Art'
|
Temukan nama semua instruktur di departemen seni yang telah mengajar kursus dan kursus_id.
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CREATE TABLE instructor (ID VARCHAR, dept_name VARCHAR); CREATE TABLE teaches (ID VARCHAR)
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SELECT name FROM instructor WHERE name LIKE '%dar%'
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Temukan nama semua instruktur yang namanya termasuk substring "dar".
|
CREATE TABLE instructor (name VARCHAR)
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SELECT DISTINCT name FROM instructor ORDER BY name
|
Daftar dalam urutan alfabet nama semua instruktur yang berbeda.
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CREATE TABLE instructor (name VARCHAR)
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SELECT course_id FROM SECTION WHERE semester = 'Fall' AND YEAR = 2009 UNION SELECT course_id FROM SECTION WHERE semester = 'Spring' AND YEAR = 2010
|
Temukan kursus yang berjalan pada musim gugur 2009 atau di musim semi 2010.
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CREATE TABLE SECTION (course_id VARCHAR, semester VARCHAR, YEAR VARCHAR)
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SELECT course_id FROM SECTION WHERE semester = 'Fall' AND YEAR = 2009 INTERSECT SELECT course_id FROM SECTION WHERE semester = 'Spring' AND YEAR = 2010
|
Temukan kursus yang berjalan pada musim gugur 2009 dan pada musim semi 2010.
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CREATE TABLE SECTION (course_id VARCHAR, semester VARCHAR, YEAR VARCHAR)
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SELECT course_id FROM SECTION WHERE semester = 'Fall' AND YEAR = 2009 EXCEPT SELECT course_id FROM SECTION WHERE semester = 'Spring' AND YEAR = 2010
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Temukan kursus yang berjalan pada musim gugur 2009 tetapi tidak pada musim semi 2010.
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CREATE TABLE SECTION (course_id VARCHAR, semester VARCHAR, YEAR VARCHAR)
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SELECT DISTINCT salary FROM instructor WHERE salary < (SELECT MAX(salary) FROM instructor)
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Temukan gaji semua instruktur berbeda yang kurang dari gaji terbesar.
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CREATE TABLE instructor (salary INTEGER)
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SELECT COUNT(DISTINCT ID) FROM teaches WHERE semester = 'Spring' AND YEAR = 2010
|
Temukan jumlah total instruktur yang mengajar kursus di semester musim semi 2010.
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CREATE TABLE teaches (ID VARCHAR, semester VARCHAR, YEAR VARCHAR)
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SELECT dept_name, AVG(salary) FROM instructor GROUP BY dept_name HAVING AVG(salary) > 42000
|
Temukan nama dan gaji rata -rata semua departemen yang gaji rata -rata lebih besar dari 42000.
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CREATE TABLE instructor (dept_name VARCHAR, salary INTEGER)
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SELECT name FROM instructor WHERE salary > (SELECT MIN(salary) FROM instructor WHERE dept_name = 'Biology')
|
Temukan nama instruktur dengan gaji lebih besar dari beberapa (setidaknya satu) instruktur di departemen biologi.
|
CREATE TABLE instructor (name VARCHAR, salary INTEGER, dept_name VARCHAR)
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SELECT name FROM instructor WHERE salary > (SELECT MAX(salary) FROM instructor WHERE dept_name = 'Biology')
|
Temukan nama semua instruktur yang gajinya lebih besar dari gaji semua instruktur di departemen biologi.
|
CREATE TABLE instructor (name VARCHAR, salary INTEGER, dept_name VARCHAR)
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SELECT COUNT(*) FROM debate
|
Ada berapa banyak perdebatan?
|
CREATE TABLE debate (Id VARCHAR)
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SELECT Venue FROM debate ORDER BY Num_of_Audience
|
Sebutkan tempat -tempat debat dalam urutan naik dari jumlah audiens.
|
CREATE TABLE debate (Venue VARCHAR, Num_of_Audience VARCHAR)
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SELECT Date, Venue FROM debate
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Apa tanggal dan tempat setiap debat?
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CREATE TABLE debate (Date VARCHAR, Venue VARCHAR)
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SELECT Date FROM debate WHERE Num_of_Audience > 150
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Sebutkan tanggal debat dengan jumlah audiens yang lebih besar dari 150
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CREATE TABLE debate (Date VARCHAR, Num_of_Audience INTEGER)
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SELECT Name FROM people WHERE Age = 35 OR Age = 36
|
Tunjukkan nama orang berusia 35 atau 36.
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CREATE TABLE people (Name VARCHAR, Age VARCHAR)
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SELECT Party FROM people ORDER BY Age LIMIT 1
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Apa pesta orang -orang termuda?
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CREATE TABLE people (Party VARCHAR, Age VARCHAR)
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SELECT Party, COUNT(*) FROM people GROUP BY Party
|
Tunjukkan berbagai pihak orang bersama dengan jumlah orang di masing -masing partai.
|
CREATE TABLE people (Party VARCHAR)
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SELECT Party FROM people GROUP BY Party ORDER BY COUNT(*) DESC LIMIT 1
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Tunjukkan pesta yang memiliki kebanyakan orang.
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CREATE TABLE people (Party VARCHAR)
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SELECT DISTINCT Venue FROM debate
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Tunjukkan tempat debat yang berbeda
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CREATE TABLE debate (Venue VARCHAR)
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SELECT T3.Name, T2.Date, T2.Venue FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Affirmative = T3.People_ID
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Tunjukkan nama orang, dan tanggal dan tempat debat mereka berada di sisi afirmatif.
|
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE debate (Date VARCHAR, Venue VARCHAR, Debate_ID VARCHAR); CREATE TABLE debate_people (Debate_ID VARCHAR, Affirmative VARCHAR)
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SELECT T3.Name, T2.Date, T2.Venue FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Negative = T3.People_ID ORDER BY T3.Name
|
Tunjukkan nama -nama orang, dan tanggal dan tempat debat mereka berada di sisi negatif, dipesan dalam urutan nama abjad naik.
|
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE debate (Date VARCHAR, Venue VARCHAR, Debate_ID VARCHAR); CREATE TABLE debate_people (Debate_ID VARCHAR, Negative VARCHAR)
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SELECT T3.Name FROM debate_people AS T1 JOIN debate AS T2 ON T1.Debate_ID = T2.Debate_ID JOIN people AS T3 ON T1.Affirmative = T3.People_ID WHERE T2.Num_of_Audience > 200
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Tunjukkan nama -nama orang yang berada di sisi afirmatif debat dengan jumlah penonton yang lebih besar dari 200.
|
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE debate (Debate_ID VARCHAR, Num_of_Audience INTEGER); CREATE TABLE debate_people (Debate_ID VARCHAR, Affirmative VARCHAR)
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SELECT T2.Name, COUNT(*) FROM debate_people AS T1 JOIN people AS T2 ON T1.Affirmative = T2.People_ID GROUP BY T2.Name
|
Tunjukkan nama orang dan berapa kali mereka berada di sisi debat afirmatif.
|
CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE debate_people (Affirmative VARCHAR)
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SELECT T2.Name FROM debate_people AS T1 JOIN people AS T2 ON T1.Negative = T2.People_ID GROUP BY T2.Name HAVING COUNT(*) >= 2
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Tunjukkan nama orang yang telah berada di sisi negatif dari perdebatan setidaknya dua kali.
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CREATE TABLE debate_people (Negative VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
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SELECT Name FROM people WHERE NOT People_id IN (SELECT Affirmative FROM debate_people)
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Sebutkan nama orang yang belum berada di sisi debat afirmatif.
|
CREATE TABLE debate_people (Name VARCHAR, People_id VARCHAR, Affirmative VARCHAR); CREATE TABLE people (Name VARCHAR, People_id VARCHAR, Affirmative VARCHAR)
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SELECT customer_details FROM customers ORDER BY customer_details
|
Sebutkan nama semua pelanggan dalam urutan abjad.
|
CREATE TABLE customers (customer_details VARCHAR)
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SELECT policy_type_code FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t2.customer_details = "Dayana Robel"
|
Temukan semua kode jenis kebijakan yang terkait dengan pelanggan "Dayana Robel"
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CREATE TABLE customers (customer_id VARCHAR, customer_details VARCHAR); CREATE TABLE policies (customer_id VARCHAR)
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SELECT policy_type_code FROM policies GROUP BY policy_type_code ORDER BY COUNT(*) DESC LIMIT 1
|
Jenis kebijakan apa yang paling sering digunakan?Beri saya kode jenis kebijakan.
|
CREATE TABLE policies (policy_type_code VARCHAR)
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SELECT policy_type_code FROM policies GROUP BY policy_type_code HAVING COUNT(*) > 2
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Temukan semua jenis kebijakan yang digunakan oleh lebih dari 2 pelanggan.
|
CREATE TABLE policies (policy_type_code VARCHAR)
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SELECT SUM(amount_piad), AVG(amount_piad) FROM claim_headers
|
Temukan jumlah total dan rata -rata yang dibayarkan di header klaim.
|
CREATE TABLE claim_headers (amount_piad INTEGER)
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SELECT SUM(t1.amount_claimed) FROM claim_headers AS t1 JOIN claims_documents AS t2 ON t1.claim_header_id = t2.claim_id WHERE t2.created_date = (SELECT created_date FROM claims_documents ORDER BY created_date LIMIT 1)
|
Temukan jumlah total yang diklaim dalam dokumen yang paling baru dibuat.
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CREATE TABLE claim_headers (amount_claimed INTEGER, claim_header_id VARCHAR); CREATE TABLE claims_documents (claim_id VARCHAR, created_date VARCHAR); CREATE TABLE claims_documents (created_date VARCHAR)
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SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_claimed = (SELECT MAX(amount_claimed) FROM claim_headers)
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Apa nama pelanggan yang telah membuat sejumlah klaim terbesar dalam satu klaim?
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CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR); CREATE TABLE claim_headers (amount_claimed INTEGER); CREATE TABLE policies (policy_id VARCHAR, customer_id VARCHAR); CREATE TABLE claim_headers (policy_id VARCHAR, amount_claimed INTEGER)
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SELECT t3.customer_details FROM claim_headers AS t1 JOIN policies AS t2 ON t1.policy_id = t2.policy_id JOIN customers AS t3 ON t2.customer_id = t3.customer_id WHERE t1.amount_piad = (SELECT MIN(amount_piad) FROM claim_headers)
|
Apa nama pelanggan yang telah melakukan jumlah pembayaran minimum dalam satu klaim?
|
CREATE TABLE claim_headers (amount_piad INTEGER); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR); CREATE TABLE policies (policy_id VARCHAR, customer_id VARCHAR); CREATE TABLE claim_headers (policy_id VARCHAR, amount_piad INTEGER)
|
SELECT customer_details FROM customers EXCEPT SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id
|
Temukan nama pelanggan yang tidak memiliki kebijakan yang terkait.
|
CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_details VARCHAR); CREATE TABLE policies (customer_id VARCHAR)
|
SELECT COUNT(*) FROM claims_processing_stages
|
Berapa banyak tahapan pemrosesan klaim secara total?
|
CREATE TABLE claims_processing_stages (Id VARCHAR)
|
SELECT t2.claim_status_name FROM claims_processing AS t1 JOIN claims_processing_stages AS t2 ON t1.claim_stage_id = t2.claim_stage_id GROUP BY t1.claim_stage_id ORDER BY COUNT(*) DESC LIMIT 1
|
Apa nama tahap pemrosesan klaim yang diaktifkan sebagian besar klaim?
|
CREATE TABLE claims_processing (claim_stage_id VARCHAR); CREATE TABLE claims_processing_stages (claim_status_name VARCHAR, claim_stage_id VARCHAR)
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SELECT customer_details FROM customers WHERE customer_details LIKE "%Diana%"
|
Temukan nama -nama pelanggan yang namanya berisi "Diana".
|
CREATE TABLE customers (customer_details VARCHAR)
|
SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy"
|
Temukan nama -nama pelanggan yang memiliki kebijakan Wakil.
|
CREATE TABLE policies (customer_id VARCHAR, policy_type_code VARCHAR); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR)
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SELECT DISTINCT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.policy_type_code = "Deputy" OR t1.policy_type_code = "Uniform"
|
Temukan nama pelanggan yang memiliki kebijakan wakil atau kebijakan berseragam.
|
CREATE TABLE policies (customer_id VARCHAR, policy_type_code VARCHAR); CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR)
|
SELECT customer_details FROM customers UNION SELECT staff_details FROM staff
|
Temukan nama semua pelanggan dan anggota staf.
|
CREATE TABLE staff (customer_details VARCHAR, staff_details VARCHAR); CREATE TABLE customers (customer_details VARCHAR, staff_details VARCHAR)
|
SELECT policy_type_code, COUNT(*) FROM policies GROUP BY policy_type_code
|
Temukan jumlah catatan dari setiap jenis kebijakan dan kode jenisnya.
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CREATE TABLE policies (policy_type_code VARCHAR)
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SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id GROUP BY t2.customer_details ORDER BY COUNT(*) DESC LIMIT 1
|
Temukan nama pelanggan yang telah terlibat dalam kebijakan terbanyak.
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CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR); CREATE TABLE policies (customer_id VARCHAR)
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SELECT claim_status_description FROM claims_processing_stages WHERE claim_status_name = "Open"
|
Apa deskripsi status klaim "terbuka"?
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CREATE TABLE claims_processing_stages (claim_status_description VARCHAR, claim_status_name VARCHAR)
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SELECT COUNT(DISTINCT claim_outcome_code) FROM claims_processing
|
Ada berapa kode hasil klaim berbeda?
|
CREATE TABLE claims_processing (claim_outcome_code VARCHAR)
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SELECT t2.customer_details FROM policies AS t1 JOIN customers AS t2 ON t1.customer_id = t2.customer_id WHERE t1.start_date = (SELECT MAX(start_date) FROM policies)
|
Pelanggan mana yang dikaitkan dengan kebijakan terbaru?
|
CREATE TABLE customers (customer_details VARCHAR, customer_id VARCHAR); CREATE TABLE policies (start_date INTEGER); CREATE TABLE policies (customer_id VARCHAR, start_date INTEGER)
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SELECT account_id, date_account_opened, account_name, other_account_details FROM Accounts
|
Tunjukkan ID, tanggal akun yang dibuka, nama akun, dan detail akun lainnya untuk semua akun.
|
CREATE TABLE Accounts (account_id VARCHAR, date_account_opened VARCHAR, account_name VARCHAR, other_account_details VARCHAR)
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SELECT T1.account_id, T1.date_account_opened, T1.account_name, T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = 'Meaghan'
|
Tunjukkan ID, nama akun, dan detail akun lainnya untuk semua akun oleh pelanggan dengan nama depan 'Meaghan'.
|
CREATE TABLE Accounts (account_id VARCHAR, date_account_opened VARCHAR, account_name VARCHAR, other_account_details VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR)
|
SELECT T1.account_name, T1.other_account_details FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T2.customer_first_name = "Meaghan" AND T2.customer_last_name = "Keeling"
|
Tunjukkan nama akun dan detail akun lainnya untuk semua akun oleh pelanggan dengan nama depan Meaghan dan nama belakang Keeling.
|
CREATE TABLE Customers (customer_id VARCHAR, customer_first_name VARCHAR, customer_last_name VARCHAR); CREATE TABLE Accounts (account_name VARCHAR, other_account_details VARCHAR, customer_id VARCHAR)
|
SELECT T2.customer_first_name, T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id WHERE T1.account_name = "900"
|
Tampilkan nama depan dan nama belakang untuk pelanggan dengan nama akun 900.
|
CREATE TABLE Accounts (customer_id VARCHAR, account_name VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
|
SELECT DISTINCT T1.customer_first_name, T1.customer_last_name, T1.phone_number FROM Customers AS T1 JOIN Accounts AS T2 ON T1.customer_id = T2.customer_id
|
Tunjukkan nama depan, nama belakang, dan nomor telepon yang unik untuk semua pelanggan dengan akun apa pun.
|
CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, phone_number VARCHAR, customer_id VARCHAR)
|
SELECT customer_id FROM Customers EXCEPT SELECT customer_id FROM Accounts
|
Tunjukkan ID Pelanggan yang tidak memiliki akun.
|
CREATE TABLE Customers (customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR)
|
SELECT COUNT(*), customer_id FROM Accounts GROUP BY customer_id
|
Berapa banyak akun yang dimiliki setiap pelanggan?Sebutkan nomor dan ID pelanggan.
|
CREATE TABLE Accounts (customer_id VARCHAR)
|
SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id ORDER BY COUNT(*) DESC LIMIT 1
|
Apa ID Pelanggan, nama depan dan belakang dengan sebagian besar akun.
|
CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
|
SELECT T1.customer_id, T2.customer_first_name, T2.customer_last_name, COUNT(*) FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id
|
Tampilkan ID, nama depan, dan nama belakang untuk semua pelanggan dan jumlah akun.
|
CREATE TABLE Accounts (customer_id VARCHAR); CREATE TABLE Customers (customer_first_name VARCHAR, customer_last_name VARCHAR, customer_id VARCHAR)
|
SELECT T2.customer_first_name, T1.customer_id FROM Accounts AS T1 JOIN Customers AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) >= 2
|
Tampilkan nama depan dan ID untuk semua pelanggan dengan setidaknya 2 akun.
|
CREATE TABLE Customers (customer_first_name VARCHAR, customer_id VARCHAR); CREATE TABLE Accounts (customer_id VARCHAR)
|
SELECT gender, COUNT(*) FROM Customers GROUP BY gender
|
Tunjukkan jumlah pelanggan untuk setiap jenis kelamin.
|
CREATE TABLE Customers (gender VARCHAR)
|
SELECT COUNT(*) FROM Financial_transactions
|
Berapa banyak transaksi yang kita miliki?
|
CREATE TABLE Financial_transactions (Id VARCHAR)
|
SELECT COUNT(*), account_id FROM Financial_transactions
|
Berapa banyak transaksi yang dimiliki setiap akun?Tunjukkan nomor dan ID akun.
|
CREATE TABLE Financial_transactions (account_id VARCHAR)
|
SELECT COUNT(*) FROM Financial_transactions AS T1 JOIN Accounts AS T2 ON T1.account_id = T2.account_id WHERE T2.account_name = "337"
|
Berapa banyak transaksi yang dimiliki akun dengan nama 337?
|
CREATE TABLE Accounts (account_id VARCHAR, account_name VARCHAR); CREATE TABLE Financial_transactions (account_id VARCHAR)
|
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