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Qual é o nome da tempestade e a velocidade máxima que afetou o maior número de regiões?
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CREATE TABLE storm (name VARCHAR, max_speed VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR)
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SELECT T1.name, T1.max_speed FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id ORDER BY COUNT(*) DESC LIMIT 1
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Mostre o nome das tempestades que não afetaram a região registrada.
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CREATE TABLE affected_region (name VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR)
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SELECT name FROM storm WHERE NOT storm_id IN (SELECT storm_id FROM affected_region)
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Mostrar o nome da tempestade com pelo menos duas regiões e 10 cidades afetadas.
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CREATE TABLE affected_region (storm_id VARCHAR, number_city_affected INTEGER); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR)
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SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2 INTERSECT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING SUM(T2.number_city_affected) >= 10
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Mostrar todos os nomes de tempestades, exceto aqueles com pelo menos duas regiões afetadas.
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CREATE TABLE storm (name VARCHAR); CREATE TABLE affected_region (storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR)
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SELECT name FROM storm EXCEPT SELECT T1.name FROM storm AS T1 JOIN affected_region AS T2 ON T1.storm_id = T2.storm_id GROUP BY T1.storm_id HAVING COUNT(*) >= 2
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Quais são os nomes das regiões afetadas pela tempestade com um número de mortes de pelo menos 10?
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CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, number_deaths VARCHAR)
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SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T3.number_deaths >= 10
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Mostrar todos os nomes de tempestades que afetam a região "Dinamarca".
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CREATE TABLE region (region_id VARCHAR, region_name VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (name VARCHAR, storm_id VARCHAR)
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SELECT T3.name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.region_name = 'Denmark'
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Mostrar o nome da região com pelo menos duas tempestades.
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CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR)
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SELECT T1.region_name FROM region AS T1 JOIN affected_region AS T2 ON T1.region_id = T2.region_id GROUP BY T1.region_id HAVING COUNT(*) >= 2
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Encontre os nomes das regiões que foram afetadas pela tempestade que matou o maior número de pessoas.
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CREATE TABLE region (region_name VARCHAR, region_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE storm (storm_id VARCHAR, Number_Deaths VARCHAR)
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SELECT T2.region_name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id ORDER BY T3.Number_Deaths DESC LIMIT 1
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Encontre o nome da tempestade que afetou as regiões do Afeganistão e da Albânia.
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CREATE TABLE storm (Name VARCHAR, storm_id VARCHAR); CREATE TABLE affected_region (region_id VARCHAR, storm_id VARCHAR); CREATE TABLE region (region_id VARCHAR, Region_name VARCHAR)
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SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Afghanistan' INTERSECT SELECT T3.Name FROM affected_region AS T1 JOIN region AS T2 ON T1.region_id = T2.region_id JOIN storm AS T3 ON T1.storm_id = T3.storm_id WHERE T2.Region_name = 'Albania'
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Quantos condados há no total?
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CREATE TABLE county (Id VARCHAR)
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SELECT COUNT(*) FROM county
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Indicar o nome do condado e a população de todos os condados.
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CREATE TABLE county (County_name VARCHAR, Population VARCHAR)
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SELECT County_name, Population FROM county
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Mostrar a população média de todos os condados.
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CREATE TABLE county (Population INTEGER)
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SELECT AVG(Population) FROM county
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Retorne a população máxima e mínima entre todos os condados.
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CREATE TABLE county (Population INTEGER)
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SELECT MAX(Population), MIN(Population) FROM county
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Mostre todos os distritos para as eleições.
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CREATE TABLE election (District VARCHAR)
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SELECT DISTINCT District FROM election
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Mostre o código postal do condado com o nome "Howard".
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CREATE TABLE county (Zip_code VARCHAR, County_name VARCHAR)
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SELECT Zip_code FROM county WHERE County_name = "Howard"
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Mostre o delegado do distrito 1 nas eleições.
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CREATE TABLE election (Delegate VARCHAR, District VARCHAR)
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SELECT Delegate FROM election WHERE District = 1
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Mostre ao delegado e à comissão informações sobre as eleições.
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CREATE TABLE election (Delegate VARCHAR, Committee VARCHAR)
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SELECT Delegate, Committee FROM election
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Quantos governadores diferentes há?
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CREATE TABLE party (Governor VARCHAR)
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SELECT COUNT(DISTINCT Governor) FROM party
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Mostre o vice-governador e o controlador do Partido Democrata.
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CREATE TABLE party (Lieutenant_Governor VARCHAR, Comptroller VARCHAR, Party VARCHAR)
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SELECT Lieutenant_Governor, Comptroller FROM party WHERE Party = "Democratic"
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Em que anos diferentes foi o governador "Eliot Spitzer"?
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CREATE TABLE party (YEAR VARCHAR, Governor VARCHAR)
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SELECT DISTINCT YEAR FROM party WHERE Governor = "Eliot Spitzer"
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Mostra-me todas as informações sobre a eleição.
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CREATE TABLE election (Id VARCHAR)
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SELECT * FROM election
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Mostre os delegados e os nomes do condado a que pertencem.
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CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR)
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SELECT T2.Delegate, T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District
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Que delegados são de condados com população inferior a 100000?
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CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER)
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SELECT T2.Delegate FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population < 100000
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Quantos delegados são de condados com população superior a 50.000?
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CREATE TABLE election (Delegate VARCHAR, District VARCHAR); CREATE TABLE county (County_id VARCHAR, Population INTEGER)
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SELECT COUNT(DISTINCT T2.Delegate) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T1.Population > 50000
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Quais são os nomes do condado de onde pertencem os delegados do comité de dotações?
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CREATE TABLE election (District VARCHAR, Committee VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR)
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SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District WHERE T2.Committee = "Appropriations"
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Mostre os delegados e os nomes do partido a que pertencem.
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CREATE TABLE election (Delegate VARCHAR, Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR)
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SELECT T1.Delegate, T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID
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Quem eram os governadores dos partidos associados com os delegados do distrito 1?
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CREATE TABLE party (Governor VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR)
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SELECT T2.Governor FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1
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Quem eram os controladores dos partidos associados aos delegados do distrito 1 ou do distrito 2?
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CREATE TABLE party (Comptroller VARCHAR, Party_ID VARCHAR); CREATE TABLE election (Party VARCHAR, District VARCHAR)
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SELECT T2.Comptroller FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.District = 1 OR T1.District = 2
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Devolva todas as comissões que têm delegados do Partido Democrata.
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CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR)
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SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic"
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Indique o nome de cada condado, juntamente com o número correspondente de delegados desse condado.
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CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR)
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SELECT T1.County_name, COUNT(*) FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id
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Indicar o nome de cada partido e o número correspondente de delegados desse partido.
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CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR)
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SELECT T2.Party, COUNT(*) FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party
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Retornar os nomes de todos os condados ordenados por população em ordem ascendente.
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CREATE TABLE county (County_name VARCHAR, Population VARCHAR)
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SELECT County_name FROM county ORDER BY Population
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Retornar os nomes de todos os condados ordenados por nome de condado em ordem alfabética decrescente.
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CREATE TABLE county (County_name VARCHAR)
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SELECT County_name FROM county ORDER BY County_name DESC
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Mostrar o nome do condado com a maior população.
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CREATE TABLE county (County_name VARCHAR, Population VARCHAR)
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SELECT County_name FROM county ORDER BY Population DESC LIMIT 1
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Mostre os 3 condados com a menor população.
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CREATE TABLE county (County_name VARCHAR, Population VARCHAR)
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SELECT County_name FROM county ORDER BY Population LIMIT 3
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Mostrar os nomes dos condados que têm pelo menos dois delegados.
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CREATE TABLE election (District VARCHAR); CREATE TABLE county (County_name VARCHAR, County_id VARCHAR)
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SELECT T1.County_name FROM county AS T1 JOIN election AS T2 ON T1.County_id = T2.District GROUP BY T1.County_id HAVING COUNT(*) >= 2
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Mostrar o nome da parte que tem pelo menos dois registos.
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CREATE TABLE party (Party VARCHAR)
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SELECT Party FROM party GROUP BY Party HAVING COUNT(*) >= 2
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Mostre o nome do partido que tem mais delegados.
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CREATE TABLE election (Party VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR)
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SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID GROUP BY T1.Party ORDER BY COUNT(*) DESC LIMIT 1
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Mostra as pessoas que foram governador mais vezes.
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CREATE TABLE party (Governor VARCHAR)
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SELECT Governor FROM party GROUP BY Governor ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar as pessoas que foram controlador o maior número de vezes e o número correspondente de vezes.
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CREATE TABLE party (Comptroller VARCHAR)
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SELECT Comptroller, COUNT(*) FROM party GROUP BY Comptroller ORDER BY COUNT(*) DESC LIMIT 1
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Quais são os nomes dos partidos que não têm delegados nas eleições?
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CREATE TABLE election (Party VARCHAR, Party_ID VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR)
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SELECT Party FROM party WHERE NOT Party_ID IN (SELECT Party FROM election)
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Quais são os nomes dos partidos que têm delegados no comité "Aprovisões" e
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CREATE TABLE election (Party VARCHAR, Committee VARCHAR); CREATE TABLE party (Party VARCHAR, Party_ID VARCHAR)
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SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Appropriations" INTERSECT SELECT T2.Party FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T1.Committee = "Economic Matters"
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Quais comitês têm delegados tanto do partido democrata quanto do partido liberal?
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CREATE TABLE election (Committee VARCHAR, Party VARCHAR); CREATE TABLE party (Party_ID VARCHAR, Party VARCHAR)
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SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Democratic" INTERSECT SELECT T1.Committee FROM election AS T1 JOIN party AS T2 ON T1.Party = T2.Party_ID WHERE T2.Party = "Liberal"
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Quantos jornalistas há?
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CREATE TABLE journalist (Id VARCHAR)
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SELECT COUNT(*) FROM journalist
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Escreva os nomes dos jornalistas em ordem ascendente de anos de trabalho.
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CREATE TABLE journalist (Name VARCHAR, Years_working VARCHAR)
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SELECT Name FROM journalist ORDER BY Years_working
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Quais são as nacionalidades e idades dos jornalistas?
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CREATE TABLE journalist (Nationality VARCHAR, Age VARCHAR)
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SELECT Nationality, Age FROM journalist
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Mostre os nomes de jornalistas de "Inglaterra" ou "Gales".
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CREATE TABLE journalist (Name VARCHAR, Nationality VARCHAR)
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SELECT Name FROM journalist WHERE Nationality = "England" OR Nationality = "Wales"
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Qual é o número médio de anos de trabalho como jornalista?
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CREATE TABLE journalist (Years_working INTEGER)
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SELECT AVG(Years_working) FROM journalist
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Qual é a nacionalidade do jornalista com o maior número de anos de trabalho?
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CREATE TABLE journalist (Nationality VARCHAR, Years_working VARCHAR)
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SELECT Nationality FROM journalist ORDER BY Years_working DESC LIMIT 1
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Indicar as diferentes nacionalidades e o número de jornalistas de cada nacionalidade.
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CREATE TABLE journalist (Nationality VARCHAR)
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SELECT Nationality, COUNT(*) FROM journalist GROUP BY Nationality
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Mostrar a nacionalidade mais comum dos jornalistas.
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CREATE TABLE journalist (Nationality VARCHAR)
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SELECT Nationality FROM journalist GROUP BY Nationality ORDER BY COUNT(*) DESC LIMIT 1
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Mostre os países que têm jornalistas com mais de 10 anos de trabalho e jornalistas com menos de 3 anos de trabalho.
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CREATE TABLE journalist (Nationality VARCHAR, Years_working INTEGER)
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SELECT Nationality FROM journalist WHERE Years_working > 10 INTERSECT SELECT Nationality FROM journalist WHERE Years_working < 3
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Mostre as datas, os locais e os nomes dos eventos em ordem decrescente de número de presentes.
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CREATE TABLE event (Date VARCHAR, Name VARCHAR, venue VARCHAR, Event_Attendance VARCHAR)
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SELECT Date, Name, venue FROM event ORDER BY Event_Attendance DESC
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Mostrar os nomes dos jornalistas e as datas dos eventos que relataram.
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CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Date VARCHAR, Event_ID VARCHAR)
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SELECT T3.Name, T2.Date FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID
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Mostrar os nomes dos jornalistas e os nomes dos eventos que relataram em ordem crescente
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CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Name VARCHAR, Event_ID VARCHAR, Event_Attendance VARCHAR)
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SELECT T3.Name, T2.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID ORDER BY T2.Event_Attendance
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Mostrar os nomes dos jornalistas e o número de eventos que relataram.
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CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR)
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SELECT T3.Name, COUNT(*) FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name
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Mostrar os nomes dos jornalistas que reportaram mais de um evento.
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CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Event_ID VARCHAR, journalist_ID VARCHAR); CREATE TABLE event (Event_ID VARCHAR)
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SELECT T3.Name FROM news_report AS T1 JOIN event AS T2 ON T1.Event_ID = T2.Event_ID JOIN journalist AS T3 ON T1.journalist_ID = T3.journalist_ID GROUP BY T3.Name HAVING COUNT(*) > 1
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Escreva os nomes dos jornalistas que não relataram nenhum evento.
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CREATE TABLE journalist (Name VARCHAR, journalist_ID VARCHAR); CREATE TABLE news_report (Name VARCHAR, journalist_ID VARCHAR)
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SELECT Name FROM journalist WHERE NOT journalist_ID IN (SELECT journalist_ID FROM news_report)
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Qual a média e a média máxima de assistência de todos os eventos?
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CREATE TABLE event (Event_Attendance INTEGER)
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SELECT AVG(Event_Attendance), MAX(Event_Attendance) FROM event
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Encontre a idade média e a duração do trabalho dos jornalistas que trabalham em diferentes tipos de funções.
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CREATE TABLE news_report (work_type VARCHAR, journalist_id VARCHAR); CREATE TABLE journalist (age INTEGER, journalist_id VARCHAR)
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SELECT AVG(t1.age), AVG(Years_working), t2.work_type FROM journalist AS t1 JOIN news_report AS t2 ON t1.journalist_id = t2.journalist_id GROUP BY t2.work_type
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Liste os locais do evento e os nomes que têm o número de pessoas mais frequentadas.
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CREATE TABLE event (venue VARCHAR, name VARCHAR, Event_Attendance VARCHAR)
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SELECT venue, name FROM event ORDER BY Event_Attendance DESC LIMIT 2
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Mostra-me todos os restaurantes.
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CREATE TABLE Restaurant (ResName VARCHAR)
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SELECT ResName FROM Restaurant
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Qual é o endereço do restaurante Subway?
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CREATE TABLE Restaurant (Address VARCHAR, ResName VARCHAR)
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SELECT Address FROM Restaurant WHERE ResName = "Subway"
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Qual é a classificação do restaurante Subway?
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CREATE TABLE Restaurant (Rating VARCHAR, ResName VARCHAR)
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SELECT Rating FROM Restaurant WHERE ResName = "Subway"
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Escreva todos os tipos de restaurantes.
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CREATE TABLE Restaurant_Type (ResTypeName VARCHAR)
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SELECT ResTypeName FROM Restaurant_Type
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Qual é a descrição do restaurante tipo Sandwich?
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CREATE TABLE Restaurant_Type (ResTypeDescription VARCHAR, ResTypeName VARCHAR)
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SELECT ResTypeDescription FROM Restaurant_Type WHERE ResTypeName = "Sandwich"
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Que restaurantes têm a classificação mais alta?
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CREATE TABLE Restaurant (ResName VARCHAR, Rating VARCHAR)
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SELECT ResName, Rating FROM Restaurant ORDER BY Rating DESC LIMIT 1
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Que idade tem a estudante Linda Smith?
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CREATE TABLE Student (Age VARCHAR, Fname VARCHAR, Lname VARCHAR)
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SELECT Age FROM Student WHERE Fname = "Linda" AND Lname = "Smith"
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Qual é o sexo da estudante Linda Smith?
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CREATE TABLE Student (Sex VARCHAR, Fname VARCHAR, Lname VARCHAR)
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SELECT Sex FROM Student WHERE Fname = "Linda" AND Lname = "Smith"
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Escreve os nomes e apelidos de todos os estudantes que se especializaram em 600.
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Major VARCHAR)
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SELECT Fname, Lname FROM Student WHERE Major = 600
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Em que cidade vive a estudante Linda Smith?
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CREATE TABLE Student (city_code VARCHAR, Fname VARCHAR, Lname VARCHAR)
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SELECT city_code FROM Student WHERE Fname = "Linda" AND Lname = "Smith"
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O conselheiro 1121 tem quantos alunos?
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CREATE TABLE Student (Advisor VARCHAR)
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SELECT COUNT(*) FROM Student WHERE Advisor = 1121
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Qual é o conselheiro que tem mais alunos?
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CREATE TABLE Student (Advisor VARCHAR)
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SELECT Advisor, COUNT(*) FROM Student GROUP BY Advisor ORDER BY COUNT(Advisor) DESC LIMIT 1
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Qual é a especialidade que tem menos alunos?
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CREATE TABLE Student (Major VARCHAR)
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SELECT Major, COUNT(*) FROM Student GROUP BY Major ORDER BY COUNT(Major) LIMIT 1
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Qual é a especialidade que tem entre 2 e 30 alunos?
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CREATE TABLE Student (Major VARCHAR)
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SELECT Major, COUNT(*) FROM Student GROUP BY Major HAVING COUNT(Major) BETWEEN 2 AND 30
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Qual aluno tem mais de 18 anos e está a fazer a especialização em 600?
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Age VARCHAR, Major VARCHAR)
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SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major = 600
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Lista todas as estudantes do sexo feminino com mais de 18 anos que não estão se especializando em 600.
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CREATE TABLE Student (Fname VARCHAR, Lname VARCHAR, Sex VARCHAR, Age VARCHAR, Major VARCHAR)
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SELECT Fname, Lname FROM Student WHERE Age > 18 AND Major <> 600 AND Sex = 'F'
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Quantos restaurantes são do tipo Sandwich?
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CREATE TABLE Type_Of_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR); CREATE TABLE Restaurant_Type (Id VARCHAR)
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SELECT COUNT(*) FROM Restaurant JOIN Type_Of_Restaurant ON Restaurant.ResID = Type_Of_Restaurant.ResID JOIN Restaurant_Type ON Type_Of_Restaurant.ResTypeID = Restaurant_Type.ResTypeID GROUP BY Type_Of_Restaurant.ResTypeID HAVING Restaurant_Type.ResTypeName = 'Sandwich'
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Quanto tempo a estudante Linda Smith gasta no restaurante no total?
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CREATE TABLE Visits_Restaurant (Spent INTEGER); CREATE TABLE Student (Spent INTEGER)
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SELECT SUM(Spent) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith"
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Quantas vezes a estudante Linda Smith visitou o Subway?
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CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR)
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SELECT COUNT(*) FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway"
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Quando é que a Linda Smith visitou a Subway?
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CREATE TABLE Restaurant (TIME VARCHAR); CREATE TABLE Visits_Restaurant (TIME VARCHAR); CREATE TABLE Student (TIME VARCHAR)
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SELECT TIME FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID WHERE Student.Fname = "Linda" AND Student.Lname = "Smith" AND Restaurant.ResName = "Subway"
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Em que restaurante os estudantes passaram menos tempo?
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CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Restaurant (Id VARCHAR)
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SELECT Restaurant.ResName, SUM(Visits_Restaurant.Spent) FROM Visits_Restaurant JOIN Restaurant ON Visits_Restaurant.ResID = Restaurant.ResID GROUP BY Restaurant.ResID ORDER BY SUM(Visits_Restaurant.Spent) LIMIT 1
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Qual aluno visitou o restaurante com mais frequência? Escreva o nome e o apelido do aluno.
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CREATE TABLE Visits_Restaurant (Id VARCHAR); CREATE TABLE Student (Id VARCHAR)
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SELECT Student.Fname, Student.Lname FROM Student JOIN Visits_Restaurant ON Student.StuID = Visits_Restaurant.StuID GROUP BY Student.StuID ORDER BY COUNT(*) DESC LIMIT 1
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Encontre as ids de ordens cujo estado é "Successo".
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CREATE TABLE actual_orders (actual_order_id VARCHAR, order_status_code VARCHAR)
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SELECT actual_order_id FROM actual_orders WHERE order_status_code = 'Success'
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Encontre o nome e o preço do produto que foi encomendado o maior número de vezes.
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CREATE TABLE products (product_name VARCHAR, product_price VARCHAR, product_id VARCHAR); CREATE TABLE regular_order_products (product_id VARCHAR)
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SELECT t1.product_name, t1.product_price FROM products AS t1 JOIN regular_order_products AS t2 ON t1.product_id = t2.product_id GROUP BY t2.product_id ORDER BY COUNT(*) DESC LIMIT 1
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Encontre o número total de clientes.
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CREATE TABLE customers (Id VARCHAR)
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SELECT COUNT(*) FROM customers
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Quantos métodos de pagamento diferentes existem?
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CREATE TABLE customers (payment_method VARCHAR)
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SELECT COUNT(DISTINCT payment_method) FROM customers
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Mostre os detalhes de todos os camiões na ordem do número de matrícula.
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CREATE TABLE trucks (truck_details VARCHAR, truck_licence_number VARCHAR)
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SELECT truck_details FROM trucks ORDER BY truck_licence_number
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Encontre o nome do produto mais caro.
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CREATE TABLE products (product_name VARCHAR, product_price VARCHAR)
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SELECT product_name FROM products ORDER BY product_price DESC LIMIT 1
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Encontre os nomes dos clientes que não moram no estado da Califórnia.
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CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR)
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SELECT customer_name FROM customers EXCEPT SELECT t1.customer_name FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California'
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Escreva os nomes e e-mails dos clientes que pagaram com cartão Visa.
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CREATE TABLE customers (customer_email VARCHAR, customer_name VARCHAR, payment_method VARCHAR)
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SELECT customer_email, customer_name FROM customers WHERE payment_method = 'Visa'
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Encontre os nomes e números de telefone de clientes que vivem no estado da Califórnia.
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CREATE TABLE customer_addresses (customer_id VARCHAR, address_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_id VARCHAR, state_province_county VARCHAR)
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SELECT t1.customer_name, t1.customer_phone FROM customers AS t1 JOIN customer_addresses AS t2 ON t1.customer_id = t2.customer_id JOIN addresses AS t3 ON t2.address_id = t3.address_id WHERE t3.state_province_county = 'California'
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Encontre os estados que não têm nenhum empregado no seu registo.
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CREATE TABLE Employees (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR, employee_address_id VARCHAR)
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SELECT state_province_county FROM addresses WHERE NOT address_id IN (SELECT employee_address_id FROM Employees)
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Escreva os nomes, números de telefone e e-mails de todos os clientes, ordenados por suas datas de se tornarem clientes.
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CREATE TABLE Customers (customer_name VARCHAR, customer_phone VARCHAR, customer_email VARCHAR, date_became_customer VARCHAR)
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SELECT customer_name, customer_phone, customer_email FROM Customers ORDER BY date_became_customer
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Encontre o nome dos primeiros cinco clientes.
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CREATE TABLE Customers (customer_name VARCHAR, date_became_customer VARCHAR)
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SELECT customer_name FROM Customers ORDER BY date_became_customer LIMIT 5
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Encontre o método de pagamento mais utilizado.
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CREATE TABLE Customers (payment_method VARCHAR)
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SELECT payment_method FROM Customers GROUP BY payment_method ORDER BY COUNT(*) DESC LIMIT 1
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"Liste os nomes de todas as rotas em ordem alfabética."
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CREATE TABLE Delivery_Routes (route_name VARCHAR)
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SELECT route_name FROM Delivery_Routes ORDER BY route_name
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Encontre o nome da rota que tem o maior número de entregas.
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CREATE TABLE Delivery_Routes (route_name VARCHAR, route_id VARCHAR); CREATE TABLE Delivery_Route_Locations (route_id VARCHAR)
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SELECT t1.route_name FROM Delivery_Routes AS t1 JOIN Delivery_Route_Locations AS t2 ON t1.route_id = t2.route_id GROUP BY t1.route_id ORDER BY COUNT(*) DESC LIMIT 1
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Escreva os nomes dos estados e o número de clientes que vivem em cada estado.
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CREATE TABLE customer_addresses (address_id VARCHAR); CREATE TABLE addresses (state_province_county VARCHAR, address_id VARCHAR)
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SELECT t2.state_province_county, COUNT(*) FROM customer_addresses AS t1 JOIN addresses AS t2 ON t1.address_id = t2.address_id GROUP BY t2.state_province_county
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Quantos autores há?
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CREATE TABLE authors (Id VARCHAR)
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SELECT COUNT(*) FROM authors
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