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Encontre o nome dos médicos cujo título de posição contenha a palavra "senior".
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CREATE TABLE physician (name VARCHAR, POSITION VARCHAR)
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SELECT name FROM physician WHERE POSITION LIKE '%senior%'
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Encontrar o paciente que teve o tratamento mais recente?
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CREATE TABLE undergoes (patient VARCHAR, dateundergoes VARCHAR)
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SELECT patient FROM undergoes ORDER BY dateundergoes LIMIT 1
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Encontre os nomes de todos os pacientes que estão a ser tratados e que estão no quarto 111.
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CREATE TABLE undergoes (patient VARCHAR, Stay VARCHAR); CREATE TABLE stay (StayID VARCHAR, room VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR)
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SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN patient AS T2 ON T1.patient = T2.SSN JOIN stay AS T3 ON T1.Stay = T3.StayID WHERE T3.room = 111
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Enumera os nomes de todas as enfermeiras em ordem alfabética?
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CREATE TABLE nurse (name VARCHAR)
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SELECT DISTINCT name FROM nurse ORDER BY name
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Encontre os nomes dos enfermeiros que estão a tratar um paciente em tratamento.
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CREATE TABLE undergoes (AssistingNurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR)
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SELECT DISTINCT T2.name FROM undergoes AS T1 JOIN nurse AS T2 ON T1.AssistingNurse = T2.EmployeeID
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Escreva os nomes de todos os medicamentos, em ordem alfabética.
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CREATE TABLE medication (name VARCHAR)
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SELECT DISTINCT name FROM medication ORDER BY name
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Qual é o nome do médico que prescreveu a dose mais alta?
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CREATE TABLE prescribes (physician VARCHAR, dose VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR)
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SELECT T1.name FROM physician AS T1 JOIN prescribes AS T2 ON T1.employeeid = T2.physician ORDER BY T2.dose DESC LIMIT 1
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'Liste os ids dos funcionários médicos juntamente com os ids de seus departamentos de afiliação primária.'
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CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR, primaryaffiliation VARCHAR)
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SELECT physician, department FROM affiliated_with WHERE primaryaffiliation = 1
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Escreva os nomes dos departamentos onde alguns médicos são principalmente afiliados.
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CREATE TABLE affiliated_with (department VARCHAR); CREATE TABLE department (name VARCHAR, departmentid VARCHAR)
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SELECT DISTINCT T2.name FROM affiliated_with AS T1 JOIN department AS T2 ON T1.department = T2.departmentid WHERE PrimaryAffiliation = 1
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Que enfermeiras estão de serviço no bloco 1 e no bloco 1?
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CREATE TABLE on_call (nurse VARCHAR, blockfloor VARCHAR, blockcode VARCHAR)
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SELECT nurse FROM on_call WHERE blockfloor = 1 AND blockcode = 1
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Quais são os custos mais elevados, os mais baixos e o custo médio dos procedimentos?
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CREATE TABLE procedures (cost INTEGER)
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SELECT MAX(cost), MIN(cost), AVG(cost) FROM procedures
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Indicar o nome e o custo de todos os procedimentos, ordenados pelo custo, do mais alto para o mais baixo.
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CREATE TABLE procedures (name VARCHAR, cost VARCHAR)
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SELECT name, cost FROM procedures ORDER BY cost DESC
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Encontre os três procedimentos mais caros.
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CREATE TABLE procedures (name VARCHAR, cost VARCHAR)
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SELECT name FROM procedures ORDER BY cost LIMIT 3
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Encontre os médicos que são treinados em um procedimento que custa mais de 5000.
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost INTEGER)
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SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T3.cost > 5000
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Encontrar o médico que foi treinado no procedimento mais caro?
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (name VARCHAR, employeeid VARCHAR); CREATE TABLE procedures (code VARCHAR, cost VARCHAR)
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SELECT T1.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment ORDER BY T3.cost DESC LIMIT 1
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Qual é o custo médio dos procedimentos em que o médico John Wen foi treinado?
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (cost INTEGER, code VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR)
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SELECT AVG(T3.cost) FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
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Encontre os nomes dos procedimentos em que o médico John Wen foi treinado.
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
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SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
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Encontre todos os procedimentos que custaram mais de mil ou em que o médico John Wen foi treinado.
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
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SELECT name FROM procedures WHERE cost > 1000 UNION SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
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Encontre os nomes de todos os procedimentos que custaram mais de 1000, mas em que médico John Wen não foi treinado?
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
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SELECT name FROM procedures WHERE cost > 1000 EXCEPT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
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Encontre os nomes de todos os procedimentos de tal forma que o custo seja inferior a 5000 e o médico John Wen tenha sido treinado.
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CREATE TABLE trained_in (physician VARCHAR, treatment VARCHAR); CREATE TABLE procedures (name VARCHAR, cost INTEGER); CREATE TABLE physician (employeeid VARCHAR, name VARCHAR); CREATE TABLE procedures (name VARCHAR, code VARCHAR)
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SELECT name FROM procedures WHERE cost < 5000 INTERSECT SELECT T3.name FROM physician AS T1 JOIN trained_in AS T2 ON T1.employeeid = T2.physician JOIN procedures AS T3 ON T3.code = T2.treatment WHERE T1.name = "John Wen"
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Encontre o nome dos médicos que estão afiliados ao departamento de Cirurgia e do de Psiquiatria.
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CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR)
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SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' INTERSECT SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Psychiatry'
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Encontre o nome dos médicos que estão afiliados ao departamento de Cirurgia ou Psiquiatria.
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CREATE TABLE affiliated_with (physician VARCHAR, department VARCHAR); CREATE TABLE department (DepartmentID VARCHAR, name VARCHAR); CREATE TABLE physician (name VARCHAR, EmployeeID VARCHAR)
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SELECT T1.name FROM physician AS T1 JOIN affiliated_with AS T2 ON T1.EmployeeID = T2.physician JOIN department AS T3 ON T2.department = T3.DepartmentID WHERE T3.name = 'Surgery' OR T3.name = 'Psychiatry'
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Encontre os nomes dos pacientes que não estão a tomar o medicamento de Procrastin-X.
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CREATE TABLE Prescribes (Patient VARCHAR, Medication VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR); CREATE TABLE patient (name VARCHAR, SSN VARCHAR); CREATE TABLE patient (name VARCHAR)
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SELECT name FROM patient EXCEPT SELECT T1.name FROM patient AS T1 JOIN Prescribes AS T2 ON T2.Patient = T1.SSN JOIN Medication AS T3 ON T2.Medication = T3.Code WHERE T3.name = 'Procrastin-X'
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Calcule o número de pacientes que não estão a tomar o medicamento de Procrastin-X.
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CREATE TABLE Prescribes (patient VARCHAR, Medication VARCHAR); CREATE TABLE patient (SSN VARCHAR); CREATE TABLE Medication (Code VARCHAR, name VARCHAR)
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SELECT COUNT(*) FROM patient WHERE NOT SSN IN (SELECT T1.patient FROM Prescribes AS T1 JOIN Medication AS T2 ON T1.Medication = T2.Code WHERE T2.name = 'Procrastin-X')
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Quantas consultas há?
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CREATE TABLE appointment (Id VARCHAR)
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SELECT COUNT(*) FROM appointment
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Encontre os nomes das enfermeiras que estão de serviço.
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CREATE TABLE on_call (nurse VARCHAR); CREATE TABLE nurse (name VARCHAR, EmployeeID VARCHAR)
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SELECT DISTINCT T1.name FROM nurse AS T1 JOIN on_call AS T2 ON T1.EmployeeID = T2.nurse
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Quantos navios há?
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CREATE TABLE ship (Id VARCHAR)
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SELECT COUNT(*) FROM ship
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Indicar o nome dos navios em ordem ascendente de tonelagem.
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CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR)
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SELECT Name FROM ship ORDER BY Tonnage
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Qual é o tipo e a nacionalidade dos navios?
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CREATE TABLE ship (TYPE VARCHAR, Nationality VARCHAR)
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SELECT TYPE, Nationality FROM ship
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Indique o nome dos navios cuja nacionalidade não seja "Estados Unidos".
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CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR)
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SELECT Name FROM ship WHERE Nationality <> "United States"
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Indicar o nome dos navios cuja nacionalidade seja os Estados Unidos ou o Reino Unido.
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CREATE TABLE ship (Name VARCHAR, Nationality VARCHAR)
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SELECT Name FROM ship WHERE Nationality = "United States" OR Nationality = "United Kingdom"
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Qual é o nome do navio com a maior tonelagem?
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CREATE TABLE ship (Name VARCHAR, Tonnage VARCHAR)
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SELECT Name FROM ship ORDER BY Tonnage DESC LIMIT 1
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Indicar os diferentes tipos de navios e o número de navios de cada tipo.
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CREATE TABLE ship (TYPE VARCHAR)
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SELECT TYPE, COUNT(*) FROM ship GROUP BY TYPE
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Indicar o tipo de navio mais comum.
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CREATE TABLE ship (TYPE VARCHAR)
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SELECT TYPE FROM ship GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
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Escreva as nações que têm mais de dois navios.
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CREATE TABLE ship (Nationality VARCHAR)
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SELECT Nationality FROM ship GROUP BY Nationality HAVING COUNT(*) > 2
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Indicar os diferentes tipos de navios e a tonelagem média de cada tipo de navios.
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CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER)
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SELECT TYPE, AVG(Tonnage) FROM ship GROUP BY TYPE
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Mostrar códigos e destinos de missões, e nomes de naves envolvidas.
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CREATE TABLE mission (Code VARCHAR, Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
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SELECT T1.Code, T1.Fate, T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID
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Mostrar os nomes dos navios envolvidos numa missão lançada após 1928.
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CREATE TABLE mission (Ship_ID VARCHAR, Launched_Year INTEGER); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
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SELECT T2.Name FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T1.Launched_Year > 1928
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Mostrar o destino distinto das missões que envolvem navios com nacionalidade "Estados Unidos"
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CREATE TABLE mission (Fate VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Ship_ID VARCHAR, Nationality VARCHAR)
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SELECT DISTINCT T1.Fate FROM mission AS T1 JOIN ship AS T2 ON T1.Ship_ID = T2.Ship_ID WHERE T2.Nationality = "United States"
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Indicar o nome dos navios que não estão envolvidos em nenhuma missão
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CREATE TABLE mission (Name VARCHAR, Ship_ID VARCHAR); CREATE TABLE ship (Name VARCHAR, Ship_ID VARCHAR)
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SELECT Name FROM ship WHERE NOT Ship_ID IN (SELECT Ship_ID FROM mission)
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Indicar os tipos de navios que têm navios com arqueação superior a 6000 e navios com arqueação inferior a 4000.
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CREATE TABLE ship (TYPE VARCHAR, Tonnage INTEGER)
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SELECT TYPE FROM ship WHERE Tonnage > 6000 INTERSECT SELECT TYPE FROM ship WHERE Tonnage < 4000
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Encontre o número total de alunos.
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CREATE TABLE list (Id VARCHAR)
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SELECT COUNT(*) FROM list
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Encontre os sobrenomes dos estudantes que estudam no quarto 111.
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CREATE TABLE list (lastname VARCHAR, classroom VARCHAR)
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SELECT lastname FROM list WHERE classroom = 111
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Encontre os nomes dos alunos que estudam no quarto 108.
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CREATE TABLE list (firstname VARCHAR, classroom VARCHAR)
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SELECT firstname FROM list WHERE classroom = 108
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Quais são os primeiros nomes dos estudantes que estudam no quarto 107?
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CREATE TABLE list (firstname VARCHAR, classroom VARCHAR)
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SELECT DISTINCT firstname FROM list WHERE classroom = 107
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Para cada sala de aula, relate a série que é ensinada nela. Relate apenas o número da sala de aula e o número da série.
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT DISTINCT classroom, grade FROM list
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Que classe está a estudar na sala 103?
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CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
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SELECT DISTINCT grade FROM list WHERE classroom = 103
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Encontre a nota de estudo no quarto 105.
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CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
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SELECT DISTINCT grade FROM list WHERE classroom = 105
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Que salas de aula são usadas pelo 4o ano?
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT DISTINCT classroom FROM list WHERE grade = 4
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Que salas de aula são usadas pelo 5o ano?
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT DISTINCT classroom FROM list WHERE grade = 5
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Encontre os sobrenomes dos professores que ensinam o quinto ano.
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR)
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SELECT DISTINCT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 5
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Encontre os nomes dos professores que ensinam o primeiro ano.
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR)
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SELECT DISTINCT T2.firstname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE grade = 1
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Encontre os primeiros nomes de todos os professores que ensinam na sala de aula 110.
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CREATE TABLE teachers (firstname VARCHAR, classroom VARCHAR)
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SELECT firstname FROM teachers WHERE classroom = 110
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Encontre os sobrenomes dos professores que ensinam na sala 109.
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CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR)
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SELECT lastname FROM teachers WHERE classroom = 109
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Indique o nome e o apelido de todos os professores.
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CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR)
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SELECT DISTINCT firstname, lastname FROM teachers
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Relata o nome e apelido de todos os alunos.
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CREATE TABLE list (firstname VARCHAR, lastname VARCHAR)
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SELECT DISTINCT firstname, lastname FROM list
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Encontre todos os alunos ensinados por Otha Moyer.
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CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"
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Encontre todos os alunos ensinados por MARROTTE KIRK. Exiba os primeiros e últimos nomes dos alunos.
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CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "MARROTTE" AND T2.lastname = "KIRK"
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Encontre o nome e o apelido de todos os professores que ensinam a EVELINA BROMLEY.
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CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "EVELINA" AND T1.lastname = "BROMLEY"
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Encontre os sobrenomes de todos os professores que ensinam GELL TAMI.
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CREATE TABLE teachers (lastname VARCHAR, classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "GELL" AND T1.lastname = "TAMI"
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Quantos alunos a Loria Ondersma ensina?
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "LORIA" AND T2.lastname = "ONDERSMA"
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Quantos alunos é que o Kawa Gordon ensina?
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "KAWA" AND T2.lastname = "GORDON"
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Encontre o número de alunos ensinados por TARRING LEIA.
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "TARRING" AND T2.lastname = "LEIA"
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Quantos professores tem a aluna chamada Chrissy Nabozny?
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CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "CHRISSY" AND T1.lastname = "NABOZNY"
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Quantos professores tem o aluno chamado MADLOCK RAY?
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CREATE TABLE teachers (classroom VARCHAR); CREATE TABLE list (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT COUNT(*) FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.firstname = "MADLOCK" AND T1.lastname = "RAY"
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Encontre todos os alunos de 1o ano que não são ensinados pela OTHA MOYER.
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CREATE TABLE list (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, firstname VARCHAR, lastname VARCHAR)
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SELECT DISTINCT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 1 EXCEPT SELECT T1.firstname, T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T2.firstname = "OTHA" AND T2.lastname = "MOYER"
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Encontre os sobrenomes dos alunos da terceira série que não são ensinados por COVIN JEROME.
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CREATE TABLE list (lastname VARCHAR, classroom VARCHAR, grade VARCHAR); CREATE TABLE teachers (classroom VARCHAR, lastname VARCHAR, firstname VARCHAR)
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SELECT DISTINCT T1.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom WHERE T1.grade = 3 AND T2.firstname <> "COVIN" AND T2.lastname <> "JEROME"
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Para cada grau, indique o grau, o número de salas de aula em que é ministrado e o número total de alunos no grau.
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CREATE TABLE list (grade VARCHAR, classroom VARCHAR)
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SELECT grade, COUNT(DISTINCT classroom), COUNT(*) FROM list GROUP BY grade
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Para cada sala de aula, notifique o número da sala e o número de notas que a utilizam.
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT classroom, COUNT(DISTINCT grade) FROM list GROUP BY classroom
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Qual sala de aula tem mais alunos?
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CREATE TABLE list (classroom VARCHAR)
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SELECT classroom FROM list GROUP BY classroom ORDER BY COUNT(*) DESC LIMIT 1
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Relate o número de alunos em cada sala de aula.
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CREATE TABLE list (classroom VARCHAR)
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SELECT classroom, COUNT(*) FROM list GROUP BY classroom
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Para cada sala de aula do grau 0, informar o número total de alunos.
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT classroom, COUNT(*) FROM list WHERE grade = "0" GROUP BY classroom
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Relata o número total de alunos para cada sala de aula de 4o ano.
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CREATE TABLE list (classroom VARCHAR, grade VARCHAR)
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SELECT classroom, COUNT(*) FROM list WHERE grade = "4" GROUP BY classroom
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Encontre o nome do professor que ensina o maior número de alunos.
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CREATE TABLE list (classroom VARCHAR); CREATE TABLE teachers (firstname VARCHAR, lastname VARCHAR, classroom VARCHAR)
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SELECT T2.firstname, T2.lastname FROM list AS T1 JOIN teachers AS T2 ON T1.classroom = T2.classroom GROUP BY T2.firstname, T2.lastname ORDER BY COUNT(*) DESC LIMIT 1
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Encontre o número de alunos em uma sala de aula.
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CREATE TABLE list (classroom VARCHAR)
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SELECT COUNT(*), classroom FROM list GROUP BY classroom
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Quantas empresas têm sede nos EUA?
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CREATE TABLE company (Headquarters VARCHAR)
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SELECT COUNT(*) FROM company WHERE Headquarters = 'USA'
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Escreva os nomes das empresas por número ascendente de vendas.
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CREATE TABLE company (Name VARCHAR, Sales_in_Billion VARCHAR)
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SELECT Name FROM company ORDER BY Sales_in_Billion
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Quais são as sedes e as indústrias de todas as empresas?
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CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR)
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SELECT Headquarters, Industry FROM company
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Mostrar os nomes das empresas do setor bancário ou do varejo?
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CREATE TABLE company (Name VARCHAR, Industry VARCHAR)
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SELECT Name FROM company WHERE Industry = "Banking" OR Industry = "Retailing"
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Qual é o valor de mercado máximo e mínimo das empresas?
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CREATE TABLE company (Market_Value_in_Billion INTEGER)
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SELECT MAX(Market_Value_in_Billion), MIN(Market_Value_in_Billion) FROM company
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Qual é a sede da empresa com as maiores vendas?
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CREATE TABLE company (Headquarters VARCHAR, Sales_in_Billion VARCHAR)
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SELECT Headquarters FROM company ORDER BY Sales_in_Billion DESC LIMIT 1
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Indicar as diferentes sedes e o número de empresas em cada sede.
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CREATE TABLE company (Headquarters VARCHAR)
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SELECT Headquarters, COUNT(*) FROM company GROUP BY Headquarters
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Mostrar a sede mais comum para empresas.
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CREATE TABLE company (Headquarters VARCHAR)
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SELECT Headquarters FROM company GROUP BY Headquarters ORDER BY COUNT(*) DESC LIMIT 1
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Mostre a sede que tem pelo menos duas companhias.
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CREATE TABLE company (Headquarters VARCHAR)
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SELECT Headquarters FROM company GROUP BY Headquarters HAVING COUNT(*) >= 2
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Mostrar a sede que tem ambas as empresas na indústria bancária e empresas na indústria de petróleo e gás.
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CREATE TABLE company (Headquarters VARCHAR, Industry VARCHAR)
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SELECT Headquarters FROM company WHERE Industry = "Banking" INTERSECT SELECT Headquarters FROM company WHERE Industry = "Oil and gas"
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Indicar os nomes das empresas e dos trabalhadores.
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CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
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SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID
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Indicar os nomes das empresas e os dos empregados em ordem decrescente do número de anos de trabalho para esse empregado.
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CREATE TABLE people (Name VARCHAR, People_ID VARCHAR); CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR, Year_working VARCHAR)
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SELECT T3.Name, T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID ORDER BY T1.Year_working
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Mostre os nomes dos funcionários que trabalham para empresas com vendas maiores que 200.
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CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR); CREATE TABLE company (Company_ID VARCHAR, Sales_in_Billion INTEGER); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
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SELECT T2.Name FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID WHERE T3.Sales_in_Billion > 200
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Indicar os nomes das empresas e o número de empregados que têm
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CREATE TABLE company (Name VARCHAR, Company_ID VARCHAR); CREATE TABLE people (People_ID VARCHAR); CREATE TABLE employment (People_ID VARCHAR, Company_ID VARCHAR)
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SELECT T3.Name, COUNT(*) FROM employment AS T1 JOIN people AS T2 ON T1.People_ID = T2.People_ID JOIN company AS T3 ON T1.Company_ID = T3.Company_ID GROUP BY T3.Name
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Escrever os nomes das pessoas que não são empregadas por nenhuma empresa
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CREATE TABLE employment (Name VARCHAR, People_ID VARCHAR); CREATE TABLE people (Name VARCHAR, People_ID VARCHAR)
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SELECT Name FROM people WHERE NOT People_ID IN (SELECT People_ID FROM employment)
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A Comissão considera que a Comissão não pode ter a menor dúvida sobre a existência de um auxílio estatal.
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CREATE TABLE company (name VARCHAR, Sales_in_Billion INTEGER, Profits_in_Billion VARCHAR)
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SELECT name FROM company WHERE Sales_in_Billion > 200 ORDER BY Sales_in_Billion, Profits_in_Billion DESC
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Quantos filmes há?
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CREATE TABLE film (Id VARCHAR)
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SELECT COUNT(*) FROM film
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Escreva o diretor de todos os filmes.
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CREATE TABLE film (Director VARCHAR)
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SELECT DISTINCT Director FROM film
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Qual é a média das vendas de bilhetes brutos em dólares de filmes?
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CREATE TABLE film (Gross_in_dollar INTEGER)
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SELECT AVG(Gross_in_dollar) FROM film
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Quais são as estimativas baixas e altas dos mercados cinematográficos?
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CREATE TABLE film_market_estimation (Low_Estimate VARCHAR, High_Estimate VARCHAR)
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SELECT Low_Estimate, High_Estimate FROM film_market_estimation
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Quais são os tipos de estimativas do mercado cinematográfico no ano de 1995?
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CREATE TABLE film_market_estimation (TYPE VARCHAR, YEAR VARCHAR)
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SELECT TYPE FROM film_market_estimation WHERE YEAR = 1995
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Qual é o número máximo e mínimo de cidades em todos os mercados.
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CREATE TABLE market (Number_cities INTEGER)
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SELECT MAX(Number_cities), MIN(Number_cities) FROM market
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Quantos mercados têm cidades com menos de 300 habitantes?
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CREATE TABLE market (Number_cities INTEGER)
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SELECT COUNT(*) FROM market WHERE Number_cities < 300
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Lista todos os países de mercados em ordem alfabética ascendente.
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CREATE TABLE market (Country VARCHAR)
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SELECT Country FROM market ORDER BY Country
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Lista todos os países de mercados em ordem decrescente do número de cidades.
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CREATE TABLE market (Country VARCHAR, Number_cities VARCHAR)
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SELECT Country FROM market ORDER BY Number_cities DESC
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