pergunta
stringlengths 8
31.4k
| contexto
stringlengths 27
489
| resposta
stringlengths 18
557
|
---|---|---|
Encontre os sobrenomes das faculdades no edifício Barton em ordem alfabética.
|
CREATE TABLE FACULTY (Lname VARCHAR, Building VARCHAR)
|
SELECT Lname FROM FACULTY WHERE Building = "Barton" ORDER BY Lname
|
Encontre os nomes das faculdades de grau de professor em ordem alfabética.
|
CREATE TABLE FACULTY (Fname VARCHAR, Rank VARCHAR)
|
SELECT Fname FROM FACULTY WHERE Rank = "Professor" ORDER BY Fname
|
Encontre o nome do departamento que tem o maior número de estudantes de secundária?
|
CREATE TABLE DEPARTMENT (DName VARCHAR, DNO VARCHAR); CREATE TABLE MINOR_IN (DNO VARCHAR)
|
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY COUNT(*) DESC LIMIT 1
|
Encontrar o nome do departamento que não tem estudantes de secundária?
|
CREATE TABLE DEPARTMENT (DName VARCHAR, DNO VARCHAR); CREATE TABLE MINOR_IN (DNO VARCHAR); CREATE TABLE DEPARTMENT (DName VARCHAR)
|
SELECT DName FROM DEPARTMENT EXCEPT SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MINOR_IN AS T2 ON T1.DNO = T2.DNO
|
Encontre o nome do departamento que tem menos membros.
|
CREATE TABLE MEMBER_OF (DNO VARCHAR); CREATE TABLE DEPARTMENT (DName VARCHAR, DNO VARCHAR)
|
SELECT T1.DName FROM DEPARTMENT AS T1 JOIN MEMBER_OF AS T2 ON T1.DNO = T2.DNO GROUP BY T2.DNO ORDER BY COUNT(*) LIMIT 1
|
Encontre a posição da faculdade a que pertencem as mais poucas faculdades.
|
CREATE TABLE FACULTY (Rank VARCHAR)
|
SELECT Rank FROM FACULTY GROUP BY Rank ORDER BY COUNT(*) LIMIT 1
|
Quais são o nome e o apelido dos instrutores que ensinam os 3 cursos mais importantes?
|
CREATE TABLE COURSE (Instructor VARCHAR); CREATE TABLE FACULTY (Fname VARCHAR, Lname VARCHAR, FacID VARCHAR)
|
SELECT T2.Fname, T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY COUNT(*) DESC LIMIT 3
|
Em que edifício vive o instrutor que ensina mais cursos?
|
CREATE TABLE COURSE (Instructor VARCHAR); CREATE TABLE FACULTY (Building VARCHAR, FacID VARCHAR)
|
SELECT T2.Building FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID GROUP BY T1.Instructor ORDER BY COUNT(*) DESC LIMIT 1
|
Como se chamam os cursos que têm pelo menos cinco inscrições?
|
CREATE TABLE ENROLLED_IN (CID VARCHAR); CREATE TABLE COURSE (CName VARCHAR, CID VARCHAR)
|
SELECT T1.CName FROM COURSE AS T1 JOIN ENROLLED_IN AS T2 ON T1.CID = T2.CID GROUP BY T2.CID HAVING COUNT(*) >= 5
|
Encontre o primeiro nome e sobrenome do instrutor do curso que tem nome do curso
|
CREATE TABLE FACULTY (Fname VARCHAR, Lname VARCHAR, FacID VARCHAR); CREATE TABLE COURSE (Instructor VARCHAR, CName VARCHAR)
|
SELECT T2.Fname, T2.Lname FROM COURSE AS T1 JOIN FACULTY AS T2 ON T1.Instructor = T2.FacID WHERE T1.CName = "COMPUTER LITERACY"
|
Encontre o nome do departamento e sala do curso INTRODUÇÃO À Ciência da Computação.
|
CREATE TABLE COURSE (DNO VARCHAR, CName VARCHAR); CREATE TABLE DEPARTMENT (Dname VARCHAR, Room VARCHAR, DNO VARCHAR)
|
SELECT T2.Dname, T2.Room FROM COURSE AS T1 JOIN DEPARTMENT AS T2 ON T1.DNO = T2.DNO WHERE T1.CName = "INTRODUCTION TO COMPUTER SCIENCE"
|
Encontre o nome e o apelido do aluno e os pontos de todas as matrículas.
|
CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR); CREATE TABLE STUDENT (Fname VARCHAR, LName VARCHAR, StuID VARCHAR); CREATE TABLE GRADECONVERSION (gradepoint VARCHAR, lettergrade VARCHAR)
|
SELECT T3.Fname, T3.LName, T2.gradepoint FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID
|
Encontre os nomes de todos os alunos que tenham nota de pelo menos 3,8 em um curso.
|
CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR); CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE GRADECONVERSION (gradepoint VARCHAR, lettergrade VARCHAR)
|
SELECT DISTINCT T3.Fname FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T2.gradepoint >= 3.8
|
Encontre os nomes completos das faculdades que são membros do departamento com o número de departamento 520.
|
CREATE TABLE FACULTY (Fname VARCHAR, Lname VARCHAR, FacID VARCHAR); CREATE TABLE MEMBER_OF (FacID VARCHAR, DNO VARCHAR)
|
SELECT T1.Fname, T1.Lname FROM FACULTY AS T1 JOIN MEMBER_OF AS T2 ON T1.FacID = T2.FacID WHERE T2.DNO = 520
|
Quais são os nomes e apelidos dos alunos que menor no departamento com DNO 140.
|
CREATE TABLE STUDENT (Fname VARCHAR, Lname VARCHAR, StuID VARCHAR); CREATE TABLE MINOR_IN (StuID VARCHAR, DNO VARCHAR)
|
SELECT T2.Fname, T2.Lname FROM MINOR_IN AS T1 JOIN STUDENT AS T2 ON T1.StuID = T2.StuID WHERE T1.DNO = 140
|
Encontre os sobrenomes das faculdades que são membros do departamento de ciência da computação.
|
CREATE TABLE DEPARTMENT (DNO VARCHAR, DName VARCHAR); CREATE TABLE MEMBER_OF (DNO VARCHAR, FacID VARCHAR); CREATE TABLE FACULTY (Lname VARCHAR, FacID VARCHAR)
|
SELECT T2.Lname FROM DEPARTMENT AS T1 JOIN FACULTY AS T2 ON T1.DNO = T3.DNO JOIN MEMBER_OF AS T3 ON T2.FacID = T3.FacID WHERE T1.DName = "Computer Science"
|
Encontre a nota média de um aluno cujo sobrenome é Smith.
|
CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR); CREATE TABLE STUDENT (LName VARCHAR, StuID VARCHAR); CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR)
|
SELECT AVG(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.LName = "Smith"
|
Qual é o ponto máximo e mínimo de nota dos estudantes que vivem em Nova York?
|
CREATE TABLE ENROLLED_IN (Grade VARCHAR, StuID VARCHAR); CREATE TABLE STUDENT (city_code VARCHAR, StuID VARCHAR); CREATE TABLE GRADECONVERSION (gradepoint INTEGER, lettergrade VARCHAR)
|
SELECT MAX(T2.gradepoint), MIN(T2.gradepoint) FROM ENROLLED_IN AS T1 JOIN GRADECONVERSION AS T2 JOIN STUDENT AS T3 ON T1.Grade = T2.lettergrade AND T1.StuID = T3.StuID WHERE T3.city_code = "NYC"
|
Encontre os nomes dos cursos que têm 3 créditos ou 1 crédito, mas 4 horas.
|
CREATE TABLE COURSE (CName VARCHAR, Credits VARCHAR, Hours VARCHAR)
|
SELECT CName FROM COURSE WHERE Credits = 3 UNION SELECT CName FROM COURSE WHERE Credits = 1 AND Hours = 4
|
Encontre os nomes dos departamentos que estão na divisão AS ou na divisão EN e no Edifício NEB.
|
CREATE TABLE DEPARTMENT (DName VARCHAR, Division VARCHAR, Building VARCHAR)
|
SELECT DName FROM DEPARTMENT WHERE Division = "AS" UNION SELECT DName FROM DEPARTMENT WHERE Division = "EN" AND Building = "NEB"
|
Encontre o nome dos alunos que não estão matriculados em nenhum curso.
|
CREATE TABLE STUDENT (Fname VARCHAR, StuID VARCHAR); CREATE TABLE ENROLLED_IN (Fname VARCHAR, StuID VARCHAR)
|
SELECT Fname FROM STUDENT WHERE NOT StuID IN (SELECT StuID FROM ENROLLED_IN)
|
Quais são as identidades dos três produtos que foram comprados em maior quantidade?
|
CREATE TABLE product_suppliers (product_id VARCHAR, total_amount_purchased VARCHAR)
|
SELECT product_id FROM product_suppliers ORDER BY total_amount_purchased DESC LIMIT 3
|
Qual é a identificação do produto e o tipo de produto do produto mais barato?
|
CREATE TABLE products (product_id VARCHAR, product_type_code VARCHAR, product_price VARCHAR)
|
SELECT product_id, product_type_code FROM products ORDER BY product_price LIMIT 1
|
Encontre o número de diferentes tipos de produtos.
|
CREATE TABLE products (product_type_code VARCHAR)
|
SELECT COUNT(DISTINCT product_type_code) FROM products
|
Devolve o endereço do cliente 10.
|
CREATE TABLE customer_addresses (address_id VARCHAR, customer_id VARCHAR); CREATE TABLE addresses (address_details VARCHAR, address_id VARCHAR)
|
SELECT T1.address_details FROM addresses AS T1 JOIN customer_addresses AS T2 ON T1.address_id = T2.address_id WHERE T2.customer_id = 10
|
Quais são as identidades e os sexos de todos os funcionários cujo título de trabalho é Gerente de Departamento?
|
CREATE TABLE staff_department_assignments (staff_id VARCHAR, job_title_code VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_gender VARCHAR)
|
SELECT T1.staff_id, T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id = T2.staff_id WHERE T2.job_title_code = "Department Manager"
|
Para cada método de pagamento, indicar quantos clientes o utilizam.
|
CREATE TABLE customers (payment_method_code VARCHAR)
|
SELECT payment_method_code, COUNT(*) FROM customers GROUP BY payment_method_code
|
Qual é a identificação do produto que foi mais frequentemente encomendado?
|
CREATE TABLE order_items (product_id VARCHAR)
|
SELECT product_id FROM order_items GROUP BY product_id ORDER BY COUNT(*) DESC LIMIT 1
|
Qual é o nome, número de telefone e endereço de e-mail do cliente que fez o maior número de pedidos?
|
CREATE TABLE customers (customer_name VARCHAR, customer_phone VARCHAR, customer_email VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR)
|
SELECT T1.customer_name, T1.customer_phone, T1.customer_email FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id GROUP BY T2.customer_id ORDER BY COUNT(*) DESC LIMIT 1
|
Qual é o preço médio de cada tipo de produto?
|
CREATE TABLE products (product_type_code VARCHAR, product_price INTEGER)
|
SELECT product_type_code, AVG(product_price) FROM products GROUP BY product_type_code
|
Quantas lojas de departamento tem a rede de lojas South?
|
CREATE TABLE department_stores (dept_store_chain_id VARCHAR); CREATE TABLE department_store_chain (dept_store_chain_id VARCHAR, dept_store_chain_name VARCHAR)
|
SELECT COUNT(*) FROM department_stores AS T1 JOIN department_store_chain AS T2 ON T1.dept_store_chain_id = T2.dept_store_chain_id WHERE T2.dept_store_chain_name = "South"
|
Qual é o nome e o cargo do funcionário que foi designado mais recentemente?
|
CREATE TABLE staff (staff_name VARCHAR, staff_id VARCHAR); CREATE TABLE staff_department_assignments (job_title_code VARCHAR, staff_id VARCHAR, date_assigned_to VARCHAR)
|
SELECT T1.staff_name, T2.job_title_code FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id = T2.staff_id ORDER BY T2.date_assigned_to DESC LIMIT 1
|
Indicar o tipo de produto, o nome e o preço de todos os produtos fornecidos pelo fornecedor id 3.
|
CREATE TABLE products (product_type_code VARCHAR, product_name VARCHAR, product_price VARCHAR, product_id VARCHAR); CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR)
|
SELECT T2.product_type_code, T2.product_name, T2.product_price FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id = T2.product_id WHERE T1.supplier_id = 3
|
Retornar o nome distinto dos clientes cujo estado de encomenda é pendente, na ordem do número de cliente.
|
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_status_code VARCHAR)
|
SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = "Pending" ORDER BY T2.customer_id
|
Encontre o nome e o endereço dos clientes que têm pedidos novos e pendentes.
|
CREATE TABLE customers (customer_name VARCHAR, customer_address VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_status_code VARCHAR)
|
SELECT T1.customer_name, T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = "New" INTERSECT SELECT T1.customer_name, T1.customer_address FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id WHERE T2.order_status_code = "Pending"
|
Identificação dos produtos que são fornecidos pelo fornecedor e que são mais caros do que o preço médio de todos os produtos.
|
CREATE TABLE products (product_id VARCHAR, product_price INTEGER); CREATE TABLE product_suppliers (product_id VARCHAR, supplier_id VARCHAR); CREATE TABLE products (product_price INTEGER)
|
SELECT T1.product_id FROM product_suppliers AS T1 JOIN products AS T2 ON T1.product_id = T2.product_id WHERE T1.supplier_id = 2 AND T2.product_price > (SELECT AVG(product_price) FROM products)
|
Qual é o id e o nome da loja de departamento que possui os departamentos de marketing e gerenciamento?
|
CREATE TABLE department_stores (dept_store_id VARCHAR, store_name VARCHAR); CREATE TABLE departments (dept_store_id VARCHAR, department_name VARCHAR)
|
SELECT T2.dept_store_id, T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id = T2.dept_store_id WHERE T1.department_name = "marketing" INTERSECT SELECT T2.dept_store_id, T2.store_name FROM departments AS T1 JOIN department_stores AS T2 ON T1.dept_store_id = T2.dept_store_id WHERE T1.department_name = "managing"
|
Quais são as ids das duas cadeias de lojas com o maior número de lojas?
|
CREATE TABLE department_stores (dept_store_chain_id VARCHAR)
|
SELECT dept_store_chain_id FROM department_stores GROUP BY dept_store_chain_id ORDER BY COUNT(*) DESC LIMIT 2
|
Qual é a identificação do departamento com o menor número de funcionários?
|
CREATE TABLE staff_department_assignments (department_id VARCHAR)
|
SELECT department_id FROM staff_department_assignments GROUP BY department_id ORDER BY COUNT(*) LIMIT 1
|
Para cada tipo de produto, indicar o preço máximo e mínimo.
|
CREATE TABLE products (product_type_code VARCHAR, product_price INTEGER)
|
SELECT product_type_code, MAX(product_price), MIN(product_price) FROM products GROUP BY product_type_code
|
Determine o tipo de produto cujo preço médio seja superior ao preço médio de todos os produtos.
|
CREATE TABLE products (product_type_code VARCHAR, product_price INTEGER)
|
SELECT product_type_code FROM products GROUP BY product_type_code HAVING AVG(product_price) > (SELECT AVG(product_price) FROM products)
|
Encontre a identificação e o nome do pessoal que foi designado para o período mais curto.
|
CREATE TABLE Staff_Department_Assignments (staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_name VARCHAR)
|
SELECT T1.staff_id, T1.staff_name FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id = T2.staff_id ORDER BY date_assigned_to - date_assigned_from LIMIT 1
|
Indicar os nomes e identificadores de todos os produtos cujo preço se situe entre 600 e 700.
|
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR, product_price INTEGER)
|
SELECT product_name, product_id FROM products WHERE product_price BETWEEN 600 AND 700
|
Encontre as identidades de todos os clientes que fizeram pedidos depois de alguns pedidos serem cancelados.
|
CREATE TABLE Customer_Orders (customer_id VARCHAR, order_date INTEGER, order_status_code VARCHAR)
|
SELECT DISTINCT customer_id FROM Customer_Orders WHERE order_date > (SELECT MIN(order_date) FROM Customer_Orders WHERE order_status_code = "Cancelled")
|
Qual é a identidade do pessoal que teve uma atribuição do Departamento de pessoal antes de qualquer funcionário?
|
CREATE TABLE Staff_Department_Assignments (staff_id VARCHAR, date_assigned_to INTEGER, job_title_code VARCHAR)
|
SELECT staff_id FROM Staff_Department_Assignments WHERE date_assigned_to < (SELECT MAX(date_assigned_to) FROM Staff_Department_Assignments WHERE job_title_code = 'Clerical Staff')
|
Quais são os nomes e identidades dos clientes cujo endereço contém TN?
|
CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR, customer_address VARCHAR)
|
SELECT customer_name, customer_id FROM customers WHERE customer_address LIKE "%TN%"
|
Indicar o nome e o sexo do pessoal que foi designado em 2016.
|
CREATE TABLE staff (staff_name VARCHAR, staff_gender VARCHAR, staff_id VARCHAR); CREATE TABLE staff_department_assignments (staff_id VARCHAR, date_assigned_from VARCHAR)
|
SELECT T1.staff_name, T1.staff_gender FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id = T2.staff_id WHERE T2.date_assigned_from LIKE "2016%"
|
Indicar o nome do pessoal que tenha sido atribuído a várias tarefas.
|
CREATE TABLE staff (staff_name VARCHAR, staff_id VARCHAR); CREATE TABLE staff_department_assignments (staff_id VARCHAR)
|
SELECT T1.staff_name FROM staff AS T1 JOIN staff_department_assignments AS T2 ON T1.staff_id = T2.staff_id GROUP BY T2.staff_id HAVING COUNT(*) > 1
|
Indicar o nome e o número de telefone de todos os fornecedores na ordem alfabética dos seus endereços.
|
CREATE TABLE addresses (address_id VARCHAR, address_details VARCHAR); CREATE TABLE supplier_addresses (supplier_id VARCHAR, address_id VARCHAR); CREATE TABLE Suppliers (supplier_name VARCHAR, supplier_phone VARCHAR, supplier_id VARCHAR)
|
SELECT T1.supplier_name, T1.supplier_phone FROM Suppliers AS T1 JOIN supplier_addresses AS T2 ON T1.supplier_id = T2.supplier_id JOIN addresses AS T3 ON T2.address_id = T3.address_id ORDER BY T3.address_details
|
Quais são os números de telefone de todos os clientes e fornecedores.
|
CREATE TABLE suppliers (customer_phone VARCHAR, supplier_phone VARCHAR); CREATE TABLE customers (customer_phone VARCHAR, supplier_phone VARCHAR)
|
SELECT customer_phone FROM customers UNION SELECT supplier_phone FROM suppliers
|
Retornem as identidades de todos os produtos que foram encomendados mais de três vezes ou fornecidos mais de 80000.
|
CREATE TABLE Order_Items (product_id VARCHAR, total_amount_purchased INTEGER); CREATE TABLE Product_Suppliers (product_id VARCHAR, total_amount_purchased INTEGER)
|
SELECT product_id FROM Order_Items GROUP BY product_id HAVING COUNT(*) > 3 UNION SELECT product_id FROM Product_Suppliers GROUP BY product_id HAVING SUM(total_amount_purchased) > 80000
|
Qual é a identificação e o nome dos produtos cujo preço seja inferior a 600 ou superior a 900?
|
CREATE TABLE products (product_id VARCHAR, product_name VARCHAR, product_price VARCHAR)
|
SELECT product_id, product_name FROM products WHERE product_price < 600 OR product_price > 900
|
Determine a identificação dos fornecedores cuja quantidade média comprada para cada produto seja superior a 50000 ou inferior a 30000.
|
CREATE TABLE Product_Suppliers (supplier_id VARCHAR, total_amount_purchased INTEGER)
|
SELECT supplier_id FROM Product_Suppliers GROUP BY supplier_id HAVING AVG(total_amount_purchased) > 50000 OR AVG(total_amount_purchased) < 30000
|
Qual é a quantidade média comprada e o valor comprado para o fornecedor que fornece a maioria dos produtos?
|
CREATE TABLE Product_Suppliers (total_amount_purchased INTEGER, total_value_purchased INTEGER, supplier_id VARCHAR)
|
SELECT AVG(total_amount_purchased), AVG(total_value_purchased) FROM Product_Suppliers WHERE supplier_id = (SELECT supplier_id FROM Product_Suppliers GROUP BY supplier_id ORDER BY COUNT(*) DESC LIMIT 1)
|
Qual é o maior e o menor código do cliente?
|
CREATE TABLE Customers (customer_code INTEGER)
|
SELECT MAX(customer_code), MIN(customer_code) FROM Customers
|
Escreva os nomes de todos os clientes que compraram um teclado.
|
CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T2.order_id = T3.order_id JOIN products AS T4 ON T3.product_id = T4.product_id WHERE T4.product_name = "keyboard"
|
Escreva os nomes e números de telefone de todos os fornecedores que fornecem jeans vermelhos.
|
CREATE TABLE product_suppliers (supplier_id VARCHAR, product_id VARCHAR); CREATE TABLE suppliers (supplier_name VARCHAR, supplier_phone VARCHAR, supplier_id VARCHAR); CREATE TABLE products (product_id VARCHAR, product_name VARCHAR)
|
SELECT DISTINCT T1.supplier_name, T1.supplier_phone FROM suppliers AS T1 JOIN product_suppliers AS T2 ON T1.supplier_id = T2.supplier_id JOIN products AS T3 ON T2.product_id = T3.product_id WHERE T3.product_name = "red jeans"
|
Quais são os preços mais altos e os mais baixos dos produtos, agrupados por tipo de produto e ordenados por ordem alfabética?
|
CREATE TABLE products (product_type_code VARCHAR, product_price INTEGER)
|
SELECT MAX(product_price), MIN(product_price), product_type_code FROM products GROUP BY product_type_code ORDER BY product_type_code
|
Lista a identificação da encomenda, o número do cliente para as encomendas no estado de cancelado, ordenado por suas datas de encomenda.
|
CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR, order_status_code VARCHAR, order_date VARCHAR)
|
SELECT order_id, customer_id FROM customer_orders WHERE order_status_code = "Cancelled" ORDER BY order_date
|
Encontre os nomes dos produtos que foram comprados por pelo menos dois clientes distintos.
|
CREATE TABLE products (product_name VARCHAR, product_id VARCHAR); CREATE TABLE customer_orders (order_id VARCHAR, customer_id VARCHAR); CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR)
|
SELECT DISTINCT T3.product_name FROM customer_orders AS T1 JOIN order_items AS T2 ON T1.order_id = T2.order_id JOIN products AS T3 ON T2.product_id = T3.product_id GROUP BY T3.product_id HAVING COUNT(DISTINCT T1.customer_id) >= 2
|
Encontre os nomes de clientes que compraram pelo menos três produtos distintos.
|
CREATE TABLE order_items (order_id VARCHAR, product_id VARCHAR); CREATE TABLE customers (customer_name VARCHAR, customer_id VARCHAR); CREATE TABLE customer_orders (customer_id VARCHAR, order_id VARCHAR)
|
SELECT DISTINCT T1.customer_name FROM customers AS T1 JOIN customer_orders AS T2 ON T1.customer_id = T2.customer_id JOIN order_items AS T3 ON T2.order_id = T3.order_id GROUP BY T1.customer_id HAVING COUNT(DISTINCT T3.product_id) >= 3
|
Encontre o nome e o sexo do pessoal que foi designado para o cargo de vendedor, mas nunca de funcionário.
|
CREATE TABLE staff (staff_name VARCHAR, staff_gender VARCHAR, staff_id VARCHAR); CREATE TABLE Staff_Department_Assignments (staff_id VARCHAR, job_title_code VARCHAR)
|
SELECT T1.staff_name, T1.staff_gender FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id = T2.staff_id WHERE T2.job_title_code = "Sales Person" EXCEPT SELECT T1.staff_name, T1.staff_gender FROM staff AS T1 JOIN Staff_Department_Assignments AS T2 ON T1.staff_id = T2.staff_id WHERE T2.job_title_code = "Clerical Staff"
|
Encontre o id e o nome de clientes cujo endereço contém WY estado e não usar cartão de crédito para o pagamento.
|
CREATE TABLE customers (customer_id VARCHAR, customer_name VARCHAR, customer_address VARCHAR, payment_method_code VARCHAR)
|
SELECT customer_id, customer_name FROM customers WHERE customer_address LIKE "%WY%" AND payment_method_code <> "Credit Card"
|
Encontre o preço médio de todas as roupas de produto.
|
CREATE TABLE products (product_price INTEGER, product_type_code VARCHAR)
|
SELECT AVG(product_price) FROM products WHERE product_type_code = 'Clothes'
|
Encontre o nome do produto de hardware mais caro.
|
CREATE TABLE products (product_name VARCHAR, product_type_code VARCHAR, product_price VARCHAR)
|
SELECT product_name FROM products WHERE product_type_code = 'Hardware' ORDER BY product_price DESC LIMIT 1
|
Quantos aviões há?
|
CREATE TABLE aircraft (Id VARCHAR)
|
SELECT COUNT(*) FROM aircraft
|
A descrição de todas as aeronaves.
|
CREATE TABLE aircraft (Description VARCHAR)
|
SELECT Description FROM aircraft
|
Qual é o número médio de passageiros internacionais de todos os aeroportos?
|
CREATE TABLE airport (International_Passengers INTEGER)
|
SELECT AVG(International_Passengers) FROM airport
|
Qual é o número de passageiros internacionais e domésticos do aeroporto londrino "Heathrow"?
|
CREATE TABLE airport (International_Passengers VARCHAR, Domestic_Passengers VARCHAR, Airport_Name VARCHAR)
|
SELECT International_Passengers, Domestic_Passengers FROM airport WHERE Airport_Name = "London Heathrow"
|
Qual é o número total de passageiros domésticos de aeroportos que contêm a palavra "Londres"?
|
CREATE TABLE airport (Domestic_Passengers INTEGER, Airport_Name VARCHAR)
|
SELECT SUM(Domestic_Passengers) FROM airport WHERE Airport_Name LIKE "%London%"
|
Qual o número máximo e mínimo de passageiros em trânsito de todos os aeroportos?
|
CREATE TABLE airport (Transit_Passengers INTEGER)
|
SELECT MAX(Transit_Passengers), MIN(Transit_Passengers) FROM airport
|
Como se chamam os pilotos com 25 anos ou mais?
|
CREATE TABLE pilot (Name VARCHAR, Age VARCHAR)
|
SELECT Name FROM pilot WHERE Age >= 25
|
Escreva todos os nomes dos pilotos em ordem alfabética.
|
CREATE TABLE pilot (Name VARCHAR)
|
SELECT Name FROM pilot ORDER BY Name
|
Lista os nomes de todos os pilotos com 30 anos ou menos em ordem alfabética descendente.
|
CREATE TABLE pilot (Name VARCHAR, Age VARCHAR)
|
SELECT Name FROM pilot WHERE Age <= 30 ORDER BY Name DESC
|
Indicar os nomes das aeronaves associadas ao aeroporto com o nome "London Gatwick".
|
CREATE TABLE airport (Airport_ID VARCHAR, Airport_Name VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR); CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR)
|
SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID = T3.Airport_ID WHERE T3.Airport_Name = "London Gatwick"
|
Indicar os nomes e descrições das aeronaves associadas a aeroportos com um número total de passageiros superior a 10000000.
|
CREATE TABLE airport (Airport_ID VARCHAR, Total_Passengers INTEGER); CREATE TABLE aircraft (Aircraft VARCHAR, Description VARCHAR, Aircraft_ID VARCHAR); CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR)
|
SELECT T1.Aircraft, T1.Description FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID = T3.Airport_ID WHERE T3.Total_Passengers > 10000000
|
Qual é o número médio total de passageiros dos aeroportos que estão associados a aeronaves "Robinson R-22"?
|
CREATE TABLE airport (Total_Passengers INTEGER, Airport_ID VARCHAR); CREATE TABLE aircraft (Aircraft_ID VARCHAR, Aircraft VARCHAR); CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR)
|
SELECT AVG(T3.Total_Passengers) FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID = T3.Airport_ID WHERE T1.Aircraft = "Robinson R-22"
|
Por favor, indique a localização e o nome do avião vencedor.
|
CREATE TABLE MATCH (Location VARCHAR, Winning_Aircraft VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR)
|
SELECT T2.Location, T1.Aircraft FROM aircraft AS T1 JOIN MATCH AS T2 ON T1.Aircraft_ID = T2.Winning_Aircraft
|
Indique o nome da aeronave que foi nomeada aeronave vencedora o maior número de vezes.
|
CREATE TABLE MATCH (Winning_Aircraft VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR)
|
SELECT T1.Aircraft FROM aircraft AS T1 JOIN MATCH AS T2 ON T1.Aircraft_ID = T2.Winning_Aircraft GROUP BY T2.Winning_Aircraft ORDER BY COUNT(*) DESC LIMIT 1
|
Escreva os nomes das aeronaves e o número de vezes que ganhou os combates.
|
CREATE TABLE MATCH (Winning_Aircraft VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR)
|
SELECT T1.Aircraft, COUNT(*) FROM aircraft AS T1 JOIN MATCH AS T2 ON T1.Aircraft_ID = T2.Winning_Aircraft GROUP BY T2.Winning_Aircraft
|
Lista os nomes de todos os pilotos em ordem decrescente de idade.
|
CREATE TABLE pilot (Name VARCHAR, Age VARCHAR)
|
SELECT Name FROM pilot ORDER BY Age DESC
|
Escreva os nomes de aeronaves que ganharam pelo menos duas partidas.
|
CREATE TABLE MATCH (Winning_Aircraft VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR)
|
SELECT T1.Aircraft FROM aircraft AS T1 JOIN MATCH AS T2 ON T1.Aircraft_ID = T2.Winning_Aircraft GROUP BY T2.Winning_Aircraft HAVING COUNT(*) >= 2
|
Escreva os nomes de aviões e que não ganharam nenhuma partida.
|
CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR, Winning_Aircraft VARCHAR); CREATE TABLE MATCH (Aircraft VARCHAR, Aircraft_ID VARCHAR, Winning_Aircraft VARCHAR)
|
SELECT Aircraft FROM aircraft WHERE NOT Aircraft_ID IN (SELECT Winning_Aircraft FROM MATCH)
|
Mostrar os nomes de aeronaves que estão associadas tanto a um aeroporto chamado "London Heathrow" e um aeroporto chamado "London Gatwick"
|
CREATE TABLE airport (Airport_ID VARCHAR, Airport_Name VARCHAR); CREATE TABLE aircraft (Aircraft VARCHAR, Aircraft_ID VARCHAR); CREATE TABLE airport_aircraft (Aircraft_ID VARCHAR, Airport_ID VARCHAR)
|
SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID = T3.Airport_ID WHERE T3.Airport_Name = "London Heathrow" INTERSECT SELECT T1.Aircraft FROM aircraft AS T1 JOIN airport_aircraft AS T2 ON T1.Aircraft_ID = T2.Aircraft_ID JOIN airport AS T3 ON T2.Airport_ID = T3.Airport_ID WHERE T3.Airport_Name = "London Gatwick"
|
Mostrar todas as informações sobre o aeroporto que tem o maior número de passageiros internacionais.
|
CREATE TABLE airport (International_Passengers VARCHAR)
|
SELECT * FROM airport ORDER BY International_Passengers DESC LIMIT 1
|
Encontre o nome e a idade do piloto que ganhou mais vezes entre os pilotos com menos de 30 anos.
|
CREATE TABLE MATCH (winning_pilot VARCHAR); CREATE TABLE pilot (name VARCHAR, age INTEGER, pilot_id VARCHAR)
|
SELECT t1.name, t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id = t2.winning_pilot WHERE t1.age < 30 GROUP BY t2.winning_pilot ORDER BY COUNT(*) DESC LIMIT 1
|
Qual é o nome e idade do piloto mais jovem vencedor?
|
CREATE TABLE pilot (name VARCHAR, age VARCHAR, pilot_id VARCHAR); CREATE TABLE MATCH (winning_pilot VARCHAR)
|
SELECT t1.name, t1.age FROM pilot AS t1 JOIN MATCH AS t2 ON t1.pilot_id = t2.winning_pilot ORDER BY t1.age LIMIT 1
|
Encontre o nome dos pilotos que não ganharam as lutas realizadas no país da Austrália.
|
CREATE TABLE MATCH (name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR, country VARCHAR); CREATE TABLE pilot (name VARCHAR, pilot_id VARCHAR, Winning_Pilot VARCHAR, country VARCHAR)
|
SELECT name FROM pilot WHERE NOT pilot_id IN (SELECT Winning_Pilot FROM MATCH WHERE country = 'Australia')
|
Quantos moradores tem cada propriedade?
|
CREATE TABLE properties (property_id VARCHAR); CREATE TABLE residents (property_id VARCHAR)
|
SELECT T1.property_id, COUNT(*) FROM properties AS T1 JOIN residents AS T2 ON T1.property_id = T2.property_id GROUP BY T1.property_id
|
Quais são os diferentes tipos de serviços que são prestados pela organização que tem detalhe "Denesik e Filhos Partido"?
|
CREATE TABLE services (service_type_code VARCHAR, organization_id VARCHAR); CREATE TABLE organizations (organization_id VARCHAR, organization_details VARCHAR)
|
SELECT DISTINCT T1.service_type_code FROM services AS T1 JOIN organizations AS T2 ON T1.organization_id = T2.organization_id WHERE T2.organization_details = 'Denesik and Sons Party'
|
Quantos serviços cada residente solicitou?
|
CREATE TABLE Residents_Services (resident_id VARCHAR); CREATE TABLE Residents (resident_id VARCHAR, other_details VARCHAR)
|
SELECT T1.resident_id, T1.other_details, COUNT(*) FROM Residents AS T1 JOIN Residents_Services AS T2 ON T1.resident_id = T2.resident_id GROUP BY T1.resident_id ORDER BY COUNT(*) DESC
|
Qual é o número máximo de serviços prestados?
|
CREATE TABLE Services (service_id VARCHAR, service_details VARCHAR); CREATE TABLE Residents_Services (service_id VARCHAR)
|
SELECT T1.service_id, T1.service_details, COUNT(*) FROM Services AS T1 JOIN Residents_Services AS T2 ON T1.service_id = T2.service_id GROUP BY T1.service_id ORDER BY COUNT(*) DESC LIMIT 1
|
Escreva a identificação e o tipo de cada coisa, e os detalhes da organização que a possui.
|
CREATE TABLE Organizations (organization_details VARCHAR, organization_id VARCHAR); CREATE TABLE Things (thing_id VARCHAR, type_of_Thing_Code VARCHAR, organization_id VARCHAR)
|
SELECT T1.thing_id, T1.type_of_Thing_Code, T2.organization_details FROM Things AS T1 JOIN Organizations AS T2 ON T1.organization_id = T2.organization_id
|
Qual é a identidade e os dados dos clientes que têm pelo menos 3 eventos?
|
CREATE TABLE Customers (customer_id VARCHAR, customer_details VARCHAR); CREATE TABLE Customer_Events (customer_id VARCHAR)
|
SELECT T1.customer_id, T1.customer_details FROM Customers AS T1 JOIN Customer_Events AS T2 ON T1.customer_id = T2.customer_id GROUP BY T1.customer_id HAVING COUNT(*) >= 3
|
Qual é a data de mudança de cada cliente, e o ID e os detalhes do cliente correspondentes?
|
CREATE TABLE Customer_Events (date_moved_in VARCHAR, customer_id VARCHAR); CREATE TABLE Customers (customer_id VARCHAR, customer_details VARCHAR)
|
SELECT T2.date_moved_in, T1.customer_id, T1.customer_details FROM Customers AS T1 JOIN Customer_Events AS T2 ON T1.customer_id = T2.customer_id
|
Que eventos têm o número de notas entre um e três?
|
CREATE TABLE Customer_Events (Customer_Event_ID VARCHAR, property_id VARCHAR, customer_event_id VARCHAR); CREATE TABLE Customer_Event_Notes (Customer_Event_ID VARCHAR)
|
SELECT T1.Customer_Event_ID, T1.property_id FROM Customer_Events AS T1 JOIN Customer_Event_Notes AS T2 ON T1.Customer_Event_ID = T2.Customer_Event_ID GROUP BY T1.customer_event_id HAVING COUNT(*) BETWEEN 1 AND 3
|
Qual é a identificação e o tipo distintos da coisa que tem o status "Close" ou tem um registro de status antes da data "2017-06-19 02:59:21"
|
CREATE TABLE Timed_Status_of_Things (thing_id VARCHAR, Status_of_Thing_Code VARCHAR, Date_and_Date VARCHAR); CREATE TABLE Things (thing_id VARCHAR, Type_of_Thing_Code VARCHAR)
|
SELECT DISTINCT T2.thing_id, T2.Type_of_Thing_Code FROM Timed_Status_of_Things AS T1 JOIN Things AS T2 ON T1.thing_id = T2.thing_id WHERE T1.Status_of_Thing_Code = 'Close' OR T1.Date_and_Date < '2017-06-19 02:59:21'
|
Em quantos locais diferentes as coisas com detalhe de serviço "insatisfeito" foram localizadas?
|
CREATE TABLE Timed_Locations_of_Things (Location_Code VARCHAR, thing_id VARCHAR); CREATE TABLE Things (thing_id VARCHAR, service_details VARCHAR)
|
SELECT COUNT(DISTINCT T2.Location_Code) FROM Things AS T1 JOIN Timed_Locations_of_Things AS T2 ON T1.thing_id = T2.thing_id WHERE T1.service_details = 'Unsatisfied'
|
Quantos códigos de estado diferentes há?
|
CREATE TABLE Timed_Status_of_Things (Status_of_Thing_Code VARCHAR)
|
SELECT COUNT(DISTINCT Status_of_Thing_Code) FROM Timed_Status_of_Things
|
Que organizações não são uma organização-mãe de outras?
|
CREATE TABLE organizations (organization_id VARCHAR, parent_organization_id VARCHAR)
|
SELECT organization_id FROM organizations EXCEPT SELECT parent_organization_id FROM organizations
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.