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Encontre o primeiro nome do companheiro de banda que tocou na maioria das músicas.
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CREATE TABLE Songs (SongId VARCHAR); CREATE TABLE Band (firstname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR)
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SELECT t2.firstname FROM Performance AS t1 JOIN Band AS t2 ON t1.bandmate = t2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId GROUP BY firstname ORDER BY COUNT(*) DESC LIMIT 1
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Que tipo de voz é que o colega de banda com o nome "Marianne" tocou mais?
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CREATE TABLE vocals (bandmate VARCHAR); CREATE TABLE band (id VARCHAR)
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SELECT TYPE FROM vocals AS T1 JOIN band AS T2 ON T1.bandmate = T2.id WHERE firstname = "Marianne" GROUP BY TYPE ORDER BY COUNT(*) DESC LIMIT 1
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Quem está a tocar no fundo da cena na canção "Der Kapitan"?
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CREATE TABLE Band (firstname VARCHAR, lastname VARCHAR, id VARCHAR); CREATE TABLE Performance (bandmate VARCHAR, SongId VARCHAR, StagePosition VARCHAR); CREATE TABLE Songs (SongId VARCHAR, Title VARCHAR)
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SELECT T2.firstname, T2.lastname FROM Performance AS T1 JOIN Band AS T2 ON T1.bandmate = T2.id JOIN Songs AS T3 ON T3.SongId = T1.SongId WHERE T3.Title = "Der Kapitan" AND T1.StagePosition = "back"
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Quais são as canções do álbum "A Kiss Before You Go: Live in Hamburg"?
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CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR, title VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
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SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE T1.title = "A Kiss Before You Go: Live in Hamburg"
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Quais são as músicas dos álbuns da Universal Music Group?
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CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
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SELECT T3.title FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.label = "Universal Music Group"
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Encontre o número de músicas em todos os álbuns de estúdio.
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CREATE TABLE songs (title VARCHAR, songid VARCHAR); CREATE TABLE albums (aid VARCHAR); CREATE TABLE tracklists (albumid VARCHAR, songid VARCHAR)
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SELECT COUNT(DISTINCT T3.title) FROM albums AS T1 JOIN tracklists AS T2 ON T1.aid = T2.albumid JOIN songs AS T3 ON T2.songid = T3.songid WHERE t1.type = "Studio"
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Quem é o fundador da Sony?
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CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR)
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SELECT founder FROM manufacturers WHERE name = 'Sony'
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Onde está a sede da empresa fundada por James?
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CREATE TABLE manufacturers (headquarter VARCHAR, founder VARCHAR)
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SELECT headquarter FROM manufacturers WHERE founder = 'James'
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Encontre os nomes de todos os fabricantes e a sede, ordenados pelos que têm mais receita.
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CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR)
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SELECT name, headquarter FROM manufacturers ORDER BY revenue DESC
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Quais são as receitas médias, máximas e totais de todas as empresas?
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CREATE TABLE manufacturers (revenue INTEGER)
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SELECT AVG(revenue), MAX(revenue), SUM(revenue) FROM manufacturers
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Quantas empresas foi criado por Andy?
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CREATE TABLE manufacturers (founder VARCHAR)
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SELECT COUNT(*) FROM manufacturers WHERE founder = 'Andy'
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Encontre a receita total criada pelas empresas cuja sede está localizada em Austin.
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CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
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SELECT SUM(revenue) FROM manufacturers WHERE headquarter = 'Austin'
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Quais são as diferentes cidades listadas?
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CREATE TABLE manufacturers (headquarter VARCHAR)
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SELECT DISTINCT headquarter FROM manufacturers
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Encontre o número de fabricantes que estão baseados em Tóquio ou Pequim.
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CREATE TABLE manufacturers (headquarter VARCHAR)
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SELECT COUNT(*) FROM manufacturers WHERE headquarter = 'Tokyo' OR headquarter = 'Beijing'
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Encontre o fundador da empresa cujo nome começa com a letra "S".
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CREATE TABLE manufacturers (founder VARCHAR, name VARCHAR)
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SELECT founder FROM manufacturers WHERE name LIKE 'S%'
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Encontre o nome das empresas cuja receita está entre 100 e 150.
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CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
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SELECT name FROM manufacturers WHERE revenue BETWEEN 100 AND 150
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Qual é a receita total de todas as empresas cuja sede principal está em Tóquio ou em Taiwan?
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CREATE TABLE manufacturers (revenue INTEGER, Headquarter VARCHAR)
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SELECT SUM(revenue) FROM manufacturers WHERE Headquarter = 'Tokyo' OR Headquarter = 'Taiwan'
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Encontre o nome do produto que é produzido por ambas as empresas Creative Labs e Sony.
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CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
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SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Creative Labs' INTERSECT SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony'
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Encontre o nome, sede e fundador do fabricante que tem a maior receita.
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CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, founder VARCHAR, revenue VARCHAR)
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SELECT name, headquarter, founder FROM manufacturers ORDER BY revenue DESC LIMIT 1
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Encontre o nome, sede e receita de todos os fabricantes ordenados por sua receita em ordem decrescente.
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CREATE TABLE manufacturers (name VARCHAR, headquarter VARCHAR, revenue VARCHAR)
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SELECT name, headquarter, revenue FROM manufacturers ORDER BY revenue DESC
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Encontre o nome das empresas cuja receita é maior do que a receita média de todas as empresas.
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CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
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SELECT name FROM manufacturers WHERE revenue > (SELECT AVG(revenue) FROM manufacturers)
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Encontre o nome das empresas cuja receita é menor do que a receita de todas as empresas baseadas em Austin.
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CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER, headquarter VARCHAR)
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SELECT name FROM manufacturers WHERE revenue < (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')
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Encontre a receita total de empresas cuja receita é maior do que a receita de algumas empresas baseadas em Austin.
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CREATE TABLE manufacturers (revenue INTEGER, headquarter VARCHAR)
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SELECT SUM(revenue) FROM manufacturers WHERE revenue > (SELECT MIN(revenue) FROM manufacturers WHERE headquarter = 'Austin')
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Encontre a receita total das empresas de cada fundador.
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CREATE TABLE manufacturers (founder VARCHAR, revenue INTEGER)
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SELECT SUM(revenue), founder FROM manufacturers GROUP BY founder
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Encontre o nome e a receita da empresa que ganha a maior receita em cada cidade.
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CREATE TABLE manufacturers (name VARCHAR, Headquarter VARCHAR, revenue INTEGER)
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SELECT name, MAX(revenue), Headquarter FROM manufacturers GROUP BY Headquarter
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Calcule a receita total de cada fabricante.
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CREATE TABLE manufacturers (name VARCHAR, revenue INTEGER)
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SELECT SUM(revenue), name FROM manufacturers GROUP BY name
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Encontre os preços médios de todos os produtos de cada fabricante e liste o nome de cada empresa.
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CREATE TABLE products (price INTEGER, Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
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SELECT AVG(T1.price), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
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Encontre o número de produtos diferentes que são produzidos por empresas em diferentes cidades sede.
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CREATE TABLE manufacturers (Headquarter VARCHAR, code VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
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SELECT COUNT(DISTINCT T1.name), T2.Headquarter FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.Headquarter
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Encontre o número de produtos que a Sony não faz.
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CREATE TABLE manufacturers (code VARCHAR, name VARCHAR); CREATE TABLE products (name VARCHAR); CREATE TABLE products (name VARCHAR, Manufacturer VARCHAR)
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SELECT COUNT(DISTINCT name) FROM products WHERE NOT name IN (SELECT T1.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T2.name = 'Sony')
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Encontre o nome das empresas que não fazem a unidade de DVD.
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CREATE TABLE manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Manufacturer VARCHAR, name VARCHAR); CREATE TABLE manufacturers (name VARCHAR)
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SELECT name FROM manufacturers EXCEPT SELECT T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code WHERE T1.name = 'DVD drive'
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Encontre o número de produtos de cada fabricante, indicando o nome de cada empresa.
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CREATE TABLE products (Manufacturer VARCHAR); CREATE TABLE manufacturers (name VARCHAR, code VARCHAR)
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SELECT COUNT(*), T2.name FROM products AS T1 JOIN manufacturers AS T2 ON T1.Manufacturer = T2.code GROUP BY T2.name
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Selecione os nomes de todos os produtos da loja.
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CREATE TABLE Products (Name VARCHAR)
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SELECT Name FROM Products
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Selecione os nomes e os preços de todos os produtos da loja.
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CREATE TABLE products (name VARCHAR, price VARCHAR)
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SELECT name, price FROM products
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Selecione o nome dos produtos com um preço inferior ou igual a US$ 200.
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CREATE TABLE products (name VARCHAR, price VARCHAR)
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SELECT name FROM products WHERE price <= 200
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Encontre todas as informações de todos os produtos com um preço entre US $ 60 e US $ 120.
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CREATE TABLE products (price INTEGER)
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SELECT * FROM products WHERE price BETWEEN 60 AND 120
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Calcular o preço médio de todos os produtos.
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CREATE TABLE products (price INTEGER)
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SELECT AVG(price) FROM products
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Calcular o preço médio de todos os produtos com código do fabricante igual a 2.
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CREATE TABLE products (price INTEGER, Manufacturer VARCHAR)
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SELECT AVG(price) FROM products WHERE Manufacturer = 2
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Calcule o número de produtos com um preço maior ou igual a US $ 180.
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CREATE TABLE products (price VARCHAR)
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SELECT COUNT(*) FROM products WHERE price >= 180
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Selecione o nome e o preço de todos os produtos com um preço superior ou igual a R$ 180, e classifique primeiro por preço (em ordem decrescente), e depois por nome (em ordem ascendente).
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CREATE TABLE products (name VARCHAR, price VARCHAR)
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SELECT name, price FROM products WHERE price >= 180 ORDER BY price DESC, name
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Selecionar todos os dados dos produtos e do fabricante de cada produto.
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CREATE TABLE products (manufacturer VARCHAR); CREATE TABLE Manufacturers (code VARCHAR)
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SELECT * FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code
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Selecionar o preço médio dos produtos de cada fabricante, indicando apenas o código do fabricante.
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CREATE TABLE Products (Manufacturer VARCHAR, Price INTEGER)
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SELECT AVG(Price), Manufacturer FROM Products GROUP BY Manufacturer
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Selecionar o preço médio dos produtos de cada fabricante, indicando o nome do fabricante.
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CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR)
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SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
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Selecione os nomes do fabricante cujos produtos têm um preço médio superior ou igual a US$ 150.
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CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Price INTEGER, manufacturer VARCHAR, price INTEGER)
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SELECT AVG(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name HAVING AVG(T1.price) >= 150
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Selecione o nome e o preço do produto mais barato.
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CREATE TABLE Products (name VARCHAR, price VARCHAR)
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SELECT name, price FROM Products ORDER BY price LIMIT 1
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Selecione o nome de cada fabricante, juntamente com o nome e o preço do produto mais caro.
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CREATE TABLE Manufacturers (name VARCHAR, code VARCHAR); CREATE TABLE products (Name VARCHAR, Price INTEGER, manufacturer VARCHAR)
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SELECT T1.Name, MAX(T1.Price), T2.name FROM products AS T1 JOIN Manufacturers AS T2 ON T1.manufacturer = T2.code GROUP BY T2.name
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Selecionar o código do produto que é mais barato em cada categoria de produto.
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CREATE TABLE products (code VARCHAR, name VARCHAR, price INTEGER)
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SELECT code, name, MIN(price) FROM products GROUP BY name
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Qual é o id do log de problemas que foi criado mais recentemente?
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CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR)
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SELECT problem_log_id FROM problem_log ORDER BY log_entry_date DESC LIMIT 1
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Qual é a identificação de registo mais antiga e a identificação do problema correspondente?
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CREATE TABLE problem_log (problem_log_id VARCHAR, problem_id VARCHAR, log_entry_date VARCHAR)
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SELECT problem_log_id, problem_id FROM problem_log ORDER BY log_entry_date LIMIT 1
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Encontre todas as ids e datas dos registros para o problema cujo id é 10.
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CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_date VARCHAR, problem_id VARCHAR)
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SELECT problem_log_id, log_entry_date FROM problem_log WHERE problem_id = 10
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Lista todas as ids de log e suas descrições dos logs de problemas.
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CREATE TABLE problem_log (problem_log_id VARCHAR, log_entry_description VARCHAR)
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SELECT problem_log_id, log_entry_description FROM problem_log
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Escrever os nomes e apelidos de todos os membros do pessoal que são designados para o problema cujo id é 1.
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CREATE TABLE problem_log (assigned_to_staff_id VARCHAR, problem_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
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SELECT DISTINCT staff_first_name, staff_last_name FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T2.problem_id = 1
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Escreva o problema e o ID do log que são atribuídos ao pessoal chamado Rylan Homenick.
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CREATE TABLE problem_log (problem_id VARCHAR, problem_log_id VARCHAR, assigned_to_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
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SELECT DISTINCT T2.problem_id, T2.problem_log_id FROM staff AS T1 JOIN problem_log AS T2 ON T1.staff_id = T2.assigned_to_staff_id WHERE T1.staff_first_name = "Rylan" AND T1.staff_last_name = "Homenick"
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Quantos problemas há para o produto voluptatem?
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CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
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SELECT COUNT(*) FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id WHERE T1.product_name = "voluptatem"
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Quantos problemas tem o produto com mais problemas?
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CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
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SELECT COUNT(*), T1.product_name FROM product AS T1 JOIN problems AS T2 ON T1.product_id = T2.product_id GROUP BY T1.product_name ORDER BY COUNT(*) DESC LIMIT 1
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Dê-me uma lista de descrições dos problemas que são relatados pela equipe cujo primeiro nome é Christop.
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CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR); CREATE TABLE problems (problem_description VARCHAR, reported_by_staff_id VARCHAR)
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SELECT T1.problem_description FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop"
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Encontre os identificadores dos problemas que são relatados pelo pessoal cujo sobrenome é Bosco.
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CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_last_name VARCHAR)
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SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_last_name = "Bosco"
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Quais são as identidades dos problemas que são relatados após 1978-06-26?
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CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
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SELECT problem_id FROM problems WHERE date_problem_reported > "1978-06-26"
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Quais são as identidades dos problemas que são relatados antes de 1978-06-26?
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CREATE TABLE problems (problem_id VARCHAR, date_problem_reported INTEGER)
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SELECT problem_id FROM problems WHERE date_problem_reported < "1978-06-26"
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Para cada produto que tenha problemas, qual o número de problemas e a identificação do produto?
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CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_id VARCHAR)
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SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_id
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Para cada produto com problemas, encontrar o número de problemas notificados após 1986-11-13 e o id do produto?
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CREATE TABLE product (product_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, date_problem_reported INTEGER)
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SELECT COUNT(*), T2.product_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T1.date_problem_reported > "1986-11-13" GROUP BY T2.product_id
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Enumere os nomes de todos os nomes distintos dos produtos em ordem alfabética?
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CREATE TABLE product (product_name VARCHAR)
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SELECT DISTINCT product_name FROM product ORDER BY product_name
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A lista de todos os nomes de produtos distintos ordenados por id do produto?
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CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
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SELECT DISTINCT product_name FROM product ORDER BY product_id
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Quais são os problemas relatados pelo pessoal chamado Dameon Frami ou Jolie Weber?
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CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR)
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SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Dameon" AND T2.staff_last_name = "Frami" UNION SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Jolie" AND T2.staff_last_name = "Weber"
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Quais são os identificadores dos produtos para os problemas relatados por Christop Berge com o fechamento autorizado por Ashley Medhurst?
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CREATE TABLE problems (reported_by_staff_id VARCHAR, closure_authorised_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR)
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SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Christop" AND T2.staff_last_name = "Berge" INTERSECT SELECT product_id FROM problems AS T1 JOIN staff AS T2 ON T1.closure_authorised_by_staff_id = T2.staff_id WHERE T2.staff_first_name = "Ashley" AND T2.staff_last_name = "Medhurst"
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Quais são as ids dos problemas relatados antes da data de qualquer problema relatado por Lysanne Turcotte?
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CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
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SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported < (SELECT MIN(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Lysanne" AND T4.staff_last_name = "Turcotte")
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Quais são as ids dos problemas relatados após a data de qualquer problema relatado por Rylan Homenick?
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CREATE TABLE problems (problem_id VARCHAR, reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (reported_by_staff_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR)
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SELECT T1.problem_id FROM problems AS T1 JOIN staff AS T2 ON T1.reported_by_staff_id = T2.staff_id WHERE date_problem_reported > (SELECT MAX(date_problem_reported) FROM problems AS T3 JOIN staff AS T4 ON T3.reported_by_staff_id = T4.staff_id WHERE T4.staff_first_name = "Rylan" AND T4.staff_last_name = "Homenick")
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Encontrar os três produtos que apresentam o maior número de problemas?
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CREATE TABLE problems (product_id VARCHAR); CREATE TABLE product (product_name VARCHAR, product_id VARCHAR)
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SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id GROUP BY T2.product_name ORDER BY COUNT(*) DESC LIMIT 3
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A lista dos problemas do produto "voluptatem" que foram notificados após 1995?
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CREATE TABLE problems (problem_id VARCHAR, product_id VARCHAR, date_problem_reported VARCHAR); CREATE TABLE product (product_id VARCHAR, product_name VARCHAR)
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SELECT T1.problem_id FROM problems AS T1 JOIN product AS T2 ON T1.product_id = T2.product_id WHERE T2.product_name = "voluptatem" AND T1.date_problem_reported > "1995"
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Encontrar o nome e o apelido dos funcionários que relataram problemas com o produto "rem" mas não com o "aut"?
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CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_first_name VARCHAR, staff_last_name VARCHAR, staff_id VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR)
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SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "rem" EXCEPT SELECT T3.staff_first_name, T3.staff_last_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T2.product_name = "aut"
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Encontrar os produtos que têm problemas relatados por Lacey Bosco e Kenton Champlin?
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CREATE TABLE product (product_name VARCHAR, product_id VARCHAR); CREATE TABLE staff (staff_id VARCHAR, staff_first_name VARCHAR, staff_last_name VARCHAR); CREATE TABLE problems (product_id VARCHAR, reported_by_staff_id VARCHAR)
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SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Lacey" AND T3.staff_last_name = "Bosco" INTERSECT SELECT T2.product_name FROM problems AS T1 JOIN product AS T2 JOIN staff AS T3 ON T1.product_id = T2.product_id AND T1.reported_by_staff_id = T3.staff_id WHERE T3.staff_first_name = "Kenton" AND T3.staff_last_name = "Champlin"
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Quantas filiais têm mais do que o número médio de membros?
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CREATE TABLE branch (membership_amount INTEGER)
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SELECT COUNT(*) FROM branch WHERE membership_amount > (SELECT AVG(membership_amount) FROM branch)
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Mostrar o nome, a estrada e a cidade de todas as filiais ordenadas por ano de abertura.
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CREATE TABLE branch (name VARCHAR, address_road VARCHAR, city VARCHAR, open_year VARCHAR)
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SELECT name, address_road, city FROM branch ORDER BY open_year
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Quais são os nomes dos três ramos com o maior número de membros?
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CREATE TABLE branch (name VARCHAR, membership_amount VARCHAR)
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SELECT name FROM branch ORDER BY membership_amount DESC LIMIT 3
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Mostrar todas as cidades onde estão localizadas filiais com pelo menos 100 membros.
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CREATE TABLE branch (city VARCHAR, membership_amount VARCHAR)
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SELECT DISTINCT city FROM branch WHERE membership_amount >= 100
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Lista todos os anos em que foram abertas pelo menos duas lojas.
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CREATE TABLE branch (open_year VARCHAR)
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SELECT open_year FROM branch GROUP BY open_year HAVING COUNT(*) >= 2
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Indicar o número mínimo e máximo de membros para todas as sucursais abertas em 2011 ou localizadas na cidade de Londres.
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CREATE TABLE branch (membership_amount INTEGER, open_year VARCHAR, city VARCHAR)
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SELECT MIN(membership_amount), MAX(membership_amount) FROM branch WHERE open_year = 2011 OR city = 'London'
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Mostre a cidade e o número de filiais abertas antes de 2010 para cada cidade.
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CREATE TABLE branch (city VARCHAR, open_year INTEGER)
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SELECT city, COUNT(*) FROM branch WHERE open_year < 2010 GROUP BY city
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Quantos níveis diferentes têm os membros?
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CREATE TABLE member (LEVEL VARCHAR)
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SELECT COUNT(DISTINCT LEVEL) FROM member
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Mostre o número do cartão, o nome e a cidade natal de todos os membros em ordem decrescente de nível.
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CREATE TABLE member (card_number VARCHAR, name VARCHAR, hometown VARCHAR, LEVEL VARCHAR)
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SELECT card_number, name, hometown FROM member ORDER BY LEVEL DESC
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Mostrar o nível de adesão com o maior número de membros.
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CREATE TABLE member (LEVEL VARCHAR)
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SELECT LEVEL FROM member GROUP BY LEVEL ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar todos os nomes dos membros e das sucursais registadas, ordenados por ano de registo.
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CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR)
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SELECT T3.name, T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id ORDER BY T1.register_year
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Mostre todos os nomes de filiais com o número de membros em cada filial registrada após 2015.
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CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year INTEGER)
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SELECT T2.name, COUNT(*) FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year > 2015 GROUP BY T2.branch_id
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Mostrar nomes de membros sem qualquer filial registrada.
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CREATE TABLE member (name VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (name VARCHAR, member_id VARCHAR)
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SELECT name FROM member WHERE NOT member_id IN (SELECT member_id FROM membership_register_branch)
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Escreva o nome e a cidade da filial sem membros registrados.
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CREATE TABLE membership_register_branch (name VARCHAR, city VARCHAR, branch_id VARCHAR); CREATE TABLE branch (name VARCHAR, city VARCHAR, branch_id VARCHAR)
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SELECT name, city FROM branch WHERE NOT branch_id IN (SELECT branch_id FROM membership_register_branch)
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Qual é o nome e ano de abertura da filial com o maior número de membros registrados em 2016?
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CREATE TABLE membership_register_branch (branch_id VARCHAR, register_year VARCHAR); CREATE TABLE branch (name VARCHAR, open_year VARCHAR, branch_id VARCHAR)
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SELECT T2.name, T2.open_year FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T1.register_year = 2016 GROUP BY T2.branch_id ORDER BY COUNT(*) DESC LIMIT 1
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Mostrar o nome e a cidade natal dos membros que registraram uma filial em 2016.
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CREATE TABLE member (name VARCHAR, hometown VARCHAR, member_id VARCHAR); CREATE TABLE membership_register_branch (member_id VARCHAR, register_year VARCHAR)
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SELECT T2.name, T2.hometown FROM membership_register_branch AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T1.register_year = 2016
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Mostre todas as cidades com uma filial aberta em 2001 e uma filial com mais de 100 membros.
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CREATE TABLE branch (city VARCHAR, open_year VARCHAR, membership_amount VARCHAR)
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SELECT city FROM branch WHERE open_year = 2001 AND membership_amount > 100
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Mostre todas as cidades sem filiais com mais de 100 membros.
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CREATE TABLE branch (city VARCHAR, membership_amount INTEGER)
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SELECT city FROM branch EXCEPT SELECT city FROM branch WHERE membership_amount > 100
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Qual é a soma de libras totais de compra no ano de 2018 para todas as filiais em Londres?
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CREATE TABLE purchase (branch_id VARCHAR, year VARCHAR); CREATE TABLE branch (branch_id VARCHAR, city VARCHAR)
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SELECT SUM(total_pounds) FROM purchase AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id WHERE T2.city = 'London' AND T1.year = 2018
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Qual é o número total de compras para membros com nível 6?
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CREATE TABLE member (member_id VARCHAR, level VARCHAR); CREATE TABLE purchase (member_id VARCHAR)
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SELECT COUNT(*) FROM purchase AS T1 JOIN member AS T2 ON T1.member_id = T2.member_id WHERE T2.level = 6
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Encontre o nome de filiais onde alguns membros têm a cidade natal em Louisville, Kentucky e alguns em Hiram, Georgia.
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CREATE TABLE member (member_id VARCHAR, Hometown VARCHAR); CREATE TABLE branch (name VARCHAR, branch_id VARCHAR); CREATE TABLE membership_register_branch (branch_id VARCHAR, member_id VARCHAR)
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SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Louisville , Kentucky' INTERSECT SELECT T2.name FROM membership_register_branch AS T1 JOIN branch AS T2 ON T1.branch_id = T2.branch_id JOIN member AS T3 ON T1.member_id = T3.member_id WHERE T3.Hometown = 'Hiram , Georgia'
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Escreva o número de cartão de todos os membros cujo endereço de casa inclua a palavra "Kentucky".
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CREATE TABLE member (card_number VARCHAR, Hometown VARCHAR)
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SELECT card_number FROM member WHERE Hometown LIKE "%Kentucky%"
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Encontre o número total de alunos.
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CREATE TABLE STUDENT (Id VARCHAR)
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SELECT COUNT(*) FROM STUDENT
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Encontre o número total de registos de votação.
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CREATE TABLE VOTING_RECORD (Id VARCHAR)
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SELECT COUNT(*) FROM VOTING_RECORD
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Encontre o número distinto de votos presidenciais.
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CREATE TABLE VOTING_RECORD (President_Vote VARCHAR)
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SELECT COUNT(DISTINCT President_Vote) FROM VOTING_RECORD
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Encontre a idade máxima de todos os alunos.
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CREATE TABLE STUDENT (Age INTEGER)
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SELECT MAX(Age) FROM STUDENT
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Encontre os sobrenomes dos estudantes com 50 anos.
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CREATE TABLE STUDENT (LName VARCHAR, Major VARCHAR)
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SELECT LName FROM STUDENT WHERE Major = 50
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Encontre os nomes dos alunos com mais de 22 anos.
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CREATE TABLE STUDENT (Fname VARCHAR, Age INTEGER)
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SELECT Fname FROM STUDENT WHERE Age > 22
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Quais são os cursos de estudantes do sexo masculino?
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CREATE TABLE STUDENT (Major VARCHAR, Sex VARCHAR)
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SELECT Major FROM STUDENT WHERE Sex = "M"
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Qual é a idade média dos estudantes do sexo feminino (sexo é F)?
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CREATE TABLE STUDENT (Age INTEGER, Sex VARCHAR)
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SELECT AVG(Age) FROM STUDENT WHERE Sex = "F"
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