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computer_student
What is the average number of courses taught by a professor?
professor refers to professor = 1; average number of courses = divide(count(taughtBy.course_id), count(taughtBy.p_id) where professor = 1 )
SELECT CAST(COUNT(T1.course_id) AS REAL) / COUNT(DISTINCT T2.p_id) AS num FROM taughtBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.professor = 1
1,000
computer_student
What is the ratio of professors and students?
professors refers to professor = 1; students refers to student = 1; ratio = divide(count(person.p_id) when professor = 1, count(person.p_id) when student = 1)
SELECT CAST(SUM(CASE WHEN professor = 1 THEN 1 ELSE 0 END) AS REAL) * 100 / SUM(CASE WHEN student = 1 THEN 1 ELSE 0 END) AS per FROM person
1,001
computer_student
Calculate the percentage of high-level undergraduate course.
high-level undergraduate course refers to courseLevel = 'Level_400'; percentage = divide(count(course.course_id) when courseLevel = 'Level_400', count(course.course_id)) * 100%
SELECT CAST(SUM(CASE WHEN courseLevel = 'Level_400' THEN 1 ELSE 0 END) AS REAL) * 100 / COUNT(*) AS per FROM course
1,002
computer_student
List down all the person IDs who taught course ID of 18.
person IDs refers to taughtBy.p_id; course ID of 18  refers to taughtBy.course_id = 18
SELECT p_id FROM taughtBy WHERE course_id = 18
1,003
computer_student
Provide the position status and IDs of professor who advised student ID "303".
position status refers to hasPosition; IDs of professor refers to p_id_dummy; student ID "303" refers to advisedBy.p_id = 303
SELECT T2.hasPosition, T1.p_id_dummy FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id_dummy = T2.p_id WHERE T1.p_id = 303
1,004
computer_student
List the person IDs and course levels of the affiliated professors in faculty.
person IDs refers to person.p_id; affiliated professors in faculty refers to professor = 1 and hasPosition = 'Faculty_aff'
SELECT T1.p_id, T3.courseLevel FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id WHERE T1.hasPosition = 'Faculty_aff'
1,005
computer_student
Describe the year in program and in phase status for the student with most number in advisor.
student refers to advisedBy.p_id; most number in advisor refers to max(count(p_id_dummy))
SELECT T2.yearsInProgram, T2.inPhase FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id GROUP BY T1.p_id ORDER BY COUNT(*) DESC LIMIT 1
1,006
computer_student
List down the advised student IDs and IDs of employing professor in faculty.
advised student IDs refers to person.p_id; IDs of employing professor in faculty refers to p_id_dummy and hasPosition = 'Faculty_eme'
SELECT T1.p_id, T2.p_id FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id_dummy = T2.p_id WHERE hasPosition = 'Faculty_eme'
1,007
computer_student
List the course IDs and levels of person IDs from 40 to 50.
course IDs and levels refers to course.course_id and courseLevel; person IDs from 40 to 50 refers to taughtBy.p_id between 40 and 50
SELECT T1.course_id, T1.courseLevel FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T2.p_id BETWEEN 40 AND 50
1,008
computer_student
Describe the course level and list of person IDs who taught course ID of 147.
person IDs refers to taughtBy.p_id; course ID of 147 refers to course.course_id = 147
SELECT T1.courseLevel, T1.course_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T2.p_id = 141
1,009
computer_student
Mention the person ID of faculty professor who taught course ID 104 and the course level.
person ID refers to person.p_id; faculty professor refers to professor = 1 and hasPosition ! = 0
SELECT T1.p_id, T3.courseLevel FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id WHERE T3.course_id = 104 AND T1.hasPosition <> 0
1,010
computer_student
Find the professor ID and position in faculty who taught high-level undergraduate course of less than 10 in ID.
professor ID refers to person.p_id when professor = 1; position in faculty refers to hasPosition; high-level undergraduate course refers to courseLevel = 'Level_400'; less than 10 in ID refers to course.course_id < 10
SELECT T1.p_id, T1.hasPosition FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id WHERE T3.courseLevel = 'Level_400' AND T2.course_id < 10
1,011
computer_student
List the professor ID who taught the course ID from 121 to 130 of basic undergraduate courses.
professor ID refers to taughtBy.p_id; course ID from 121 to 130 of basic undergraduate courses refers to courseLevel = 'Level_300' and course.course_id between 121 and 130
SELECT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_300' AND T1.course_id > 121 AND T1.course_id < 130
1,012
computer_student
List the advisor IDs for students with eighth year of program and position status in faculty of those professors.
advisor IDs refers to p_id_dummy and person.p_id where professor = 1; eighth year of program refers to yearsInprogram = 'Year_8'; position status in faculty of those professors refers to hasPosition
SELECT T1.p_id_dummy, T2.hasPosition FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_8'
1,013
computer_student
List any five of course IDs with professor IDs who taught master courses.
professor IDs refers to taughtBy.p_id; master course refers to courseLevel = 'Level_500'
SELECT T1.course_id, T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_500' LIMIT 5
1,014
computer_student
How many students are under advisor 415?
advisor 415 refers to p_id_dummy = 415
SELECT COUNT(*) FROM advisedBy WHERE p_id_dummy = 415
1,015
computer_student
How many professional or master/graduate courses are there?
professional or master/graduate courses refers to courseLevel = 'Level_500'
SELECT COUNT(*) FROM course WHERE courseLevel = 'Level_500'
1,016
computer_student
How many non-faculty members are not undergoing the phase of qualifications?
non-faculty members refers to hasPosition = 0; are not undergoing the phase of qualifications refers to inPhase = 0
SELECT COUNT(*) FROM person WHERE hasPosition = 0 AND inPhase = 0
1,017
computer_student
Which professor taught the least amount of courses?
professor refers to taughtBy.p_id; least amount of courses refers to min(count(course_id))
SELECT p_id FROM taughtBy GROUP BY p_id ORDER BY COUNT(course_id) ASC LIMIT 1
1,018
computer_student
Among the students being advised by Advisor 5, how many students are in the 5th year?
Advisor 5 refers to p_id_dummy = 5; are in the 5th year refers to yearsInProgram = 'Year_5'
SELECT COUNT(*) FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T1.p_id_dummy = 5 AND T2.student = 1 AND T2.yearsInProgram = 'Year_5'
1,019
computer_student
Which professor teaches the highest number of professional or master/graduate courses?
professor refers to taughtBy.p_id; highest number of professional or master/graduate courses refers to max(count(taughtBy.course_id)) where courseLevel = 'Level_500'
SELECT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_500' GROUP BY T2.p_id ORDER BY COUNT(T2.course_id) DESC LIMIT 1
1,020
computer_student
Among the faculty affiliated professor, how many professors teaches professional or master/undergraduate courses?
faculty affiliated professor refers to professor = 1 and hasPosition = 'Faculty_aff'; professional or master/undergraduate courses refers to courseLevel = 'Level_500'
SELECT COUNT(*) FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id WHERE T1.hasPosition = 'Faculty_aff' AND T1.professor = 1 AND T3.courseLevel = 'Level_500'
1,021
computer_student
Who are the top 5 professors who teaches the highest number of professional or master/undergraduate courses?
professors refers to course.p_id; highest number of professional or master/undergraduate courses refers to max(count(course.course_id)) where courseLevel = 'Level_500'
SELECT T2.p_id FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_500' GROUP BY T2.p_id ORDER BY COUNT(T2.p_id) DESC LIMIT 5
1,022
computer_student
How many advisors are in charge of advising all the students in 1st year?
advisors refers to p_id_dummy; students in 1st year refers to student = 1 and yearsInProgram = 'Year_1'
SELECT COUNT(T1.p_id_dummy) FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.yearsInProgram = 'Year_1' AND T2.student = 1
1,023
computer_student
How many professors teaches no more than two high-level or harder undergraduate courses?
professors refers to taughtBy.p_id; high-level or harder undergraduate courses  refers to courseLevel = 'Level_400' ; no more than two refers to count(taughtBy.course_id) < = 2
SELECT COUNT(*) FROM ( SELECT COUNT(T2.p_id) FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_400' GROUP BY T2.p_id HAVING COUNT(DISTINCT T1.course_id) <= 2 )
1,024
computer_student
Between the faculty employee professors, how many teaches high-level or harder undergraduate courses? Indicate each of the professors unique identifying number.
faculty employee professors refers to hasPosition = 'Faculty_eme' and professor = 1; high-level or harder undergraduate courses refers to courseLevel = 'Level_400'; professors unique identifying number refers to person.p_id
SELECT COUNT(*) FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id WHERE T1.hasPosition = 'Faculty_eme' AND T1.professor = 1 AND T3.courseLevel = 'Level_400'
1,025
computer_student
What is the position in the faculty of the professor who teaches the highest number of courses?
position in the faculty refers to hasPosition; professor refers to professor = 1; teaches the highest number of courses refers to max(count(taughtBy.course_id))
SELECT T1.hasPosition FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id WHERE T1.professor = 1 GROUP BY T1.p_id ORDER BY COUNT(T2.course_id) DESC LIMIT 1
1,026
computer_student
What year in the program do the students with more than 2 advisors are in?
students refers to student = 1; more than 2 advisors refers to count(p_id_dummy) > 2
SELECT T2.yearsInProgram FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.student = 1 GROUP BY T2.p_id HAVING COUNT(T2.p_id) > 2
1,027
computer_student
How many professors teaches basic or medium undergraduate courses?
professors refers to taughtBy.p_id; basic or medium undergraduate courses refers to couresLevel = 'Level_300'
SELECT COUNT(*) FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_300'
1,028
computer_student
Among the students being advised by advisors, which students' year in the program do the advisors advise the majority of?
students refers to student = 1; students' year in the program do the advisors advise the majority of refers to max(count(yearsInProgram))
SELECT T2.yearsInProgram FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.student = 1 GROUP BY T2.yearsInProgram ORDER BY COUNT(T1.p_id_dummy) DESC LIMIT 1
1,029
computer_student
How many students that are undergoing the pre-phase of qualification have advisors?
students refers to student = 1 and ; undergoing the phase of pre-qualification refers to inPhase = 'Pre-Quals'; have advisors refers to advisedBy.p_id
SELECT COUNT(T1.p_id_dummy) FROM advisedBy AS T1 INNER JOIN person AS T2 ON T1.p_id = T2.p_id WHERE T2.inPhase = 'Pre_Quals' AND T2.student = 1
1,030
computer_student
What is the average number of professional or master/undergraduate courses being taught by each professor?
professional or master/undergraduate courses refers to courseLevel = 'Level_500'; average number = divide(count(taughtBy.course_id), count(taughtBy.p_id))
SELECT CAST(COUNT(T1.course_id) AS REAL) / COUNT(DISTINCT T2.p_id) FROM course AS T1 INNER JOIN taughtBy AS T2 ON T1.course_id = T2.course_id WHERE T1.courseLevel = 'Level_500'
1,031
computer_student
How many courses were taught by more than 4 people?
courses refers to taughtBy.course_id; more than 4 people refers to count(taughtBy.p_id) > 4
SELECT COUNT(*) FROM ( SELECT COUNT(course_id) FROM taughtBy GROUP BY course_id HAVING COUNT(course_id) > 4 )
1,032
computer_student
What is the total of professional courses available at the university? List out all the course id.
professional courses refers to courseLevel = 'Level_500'; course id refers to course.course_id
SELECT COUNT(course_id) FROM course WHERE courseLevel = 'Level_500'
1,033
computer_student
What is the sum of year 1 and year 2 students?
year 1 and year 2 students refers to yearsInProgram = 'Year_1' and yearsInProgram = 'Year_2' and student = 1
SELECT COUNT(*) FROM person WHERE yearsInProgram = 'Year_1' OR yearsInProgram = 'Year_2'
1,034
computer_student
How many courses were taught by a professor who is currently the member of faculty?
professor refers to professor = 1;  member of faculty refers to hasPosition <> 0
SELECT COUNT(*) FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id WHERE T1.professor = 1 AND T1.hasPosition <> 0
1,035
computer_student
Which professor taught the most courses and what is the position of this person in the university?
professor refers to taughtBy.p_id; most courses refers to max(taughtBy.p_id); position refers to hasPosition
SELECT T1.p_id, T1.hasPosition FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id GROUP BY T1.p_id ORDER BY COUNT(T2.course_id) DESC LIMIT 1
1,036
computer_student
Which courses were taught by a professor who is not a faculty member?
courses refers to taughtBy.course_id; professor refers to professor = 1; is not a faculty member refers to hasPosition = 0
SELECT DISTINCT T2.course_id FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id WHERE T1.professor = 1 AND T1.hasPosition = 0
1,037
computer_student
Which member of the faculty are teaching the most courses and what is his/her general course level?
member of the faculty refers to hasPosition <> 0, most courses refers to max(count(course.course_id))
SELECT T1.p_id, T3.courseLevel FROM person AS T1 INNER JOIN taughtBy AS T2 ON T1.p_id = T2.p_id INNER JOIN course AS T3 ON T3.course_id = T2.course_id GROUP BY T1.p_id ORDER BY COUNT(T2.course_id) DESC LIMIT 1
1,038
talkingdata
What is the device id of the oldest user?
oldest user refers to MAX(age);
SELECT device_id FROM gender_age WHERE age = ( SELECT MAX(age) FROM gender_age )
1,039
talkingdata
How many events were held at coordinate 97,40?
coordinate 97,40 refers to longitude = 97 AND latitude = 40;
SELECT COUNT(event_id) FROM `events` WHERE latitude = 40 AND longitude = 97
1,040
talkingdata
How many male users are in the age group of M32-38?
male refers to gender = 'M'; age group refers to group; `group` = 'M32-38';
SELECT COUNT(gender) FROM gender_age WHERE gender = 'M' AND `group` = 'M32-38'
1,041
talkingdata
How many female users over the age of 50 are there?
female refers to gender = 'F'; over the age of 50 refers to age > 50;
SELECT COUNT(gender) FROM gender_age WHERE age > 50 AND gender = 'F'
1,042
talkingdata
How many active users were there in the event id 2?
active users refers to is_active = 1;
SELECT COUNT(is_active) FROM app_events WHERE event_id = 2 AND is_active = 1
1,043
talkingdata
What is the gender of the youngest user?
youngest user refers to MIN(age);
SELECT gender FROM gender_age WHERE age = ( SELECT MIN(age) FROM gender_age )
1,044
talkingdata
What is the name of the category which most users belong to?
most users belong to refers to MAX(COUNT(app_id)); name of category refers to category;
SELECT T.category FROM ( SELECT T2.category, COUNT(T1.app_id) AS num FROM app_labels AS T1 INNER JOIN label_categories AS T2 ON T2.label_id = T1.label_id GROUP BY T1.app_id, T2.category ) AS T ORDER BY T.num DESC LIMIT 1
1,045
talkingdata
What is the model of the oldest user's device?
model of the device refers to device_model; oldest user refers to MAX(age);
SELECT T1.device_model FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id ORDER BY T2.age DESC LIMIT 1
1,046
talkingdata
How many users are there in the Home Decoration category?
SELECT COUNT(T1.app_id) FROM app_labels AS T1 INNER JOIN label_categories AS T2 ON T2.label_id = T1.label_id WHERE T2.category = 'Home Decoration'
1,047
talkingdata
How many male users are active in the events held on 5/1/2016?
male refers to gender = 'M'; active refers to is_active = 1; on 5/1/2016 refers to timestamp LIKE '2016-05-01%';
SELECT COUNT(T3.gender) FROM app_events AS T1 INNER JOIN events_relevant AS T2 ON T2.event_id = T1.event_id INNER JOIN gender_age AS T3 ON T3.device_id = T2.device_id WHERE T1.is_active = 1 AND T3.gender = 'M' AND T2.timestamp LIKE '2016-05-01%'
1,048
talkingdata
How many female users use ZenFone 5 devices?
female refers to gender = 'F'; ZenFone 5 refers to device_model = 'ZenFone 5';
SELECT COUNT(T1.gender) FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T2.device_id = T1.device_id WHERE T1.gender = 'F' AND T2.device_model = 'ZenFone 5'
1,049
talkingdata
What is the age of the oldest active user that participated in the event held on 5/6/2016 at coordinates 121, 31?
oldest user refers to MAX(age); active user refers to is_active = 1; on 5/6/2016 refers to timestamp LIKE '2016-05-06%'; coordinates 121, 31 refers to longitude = 121 AND latitude = 31;
SELECT T3.age FROM app_events AS T1 INNER JOIN events_relevant AS T2 ON T1.event_id = T2.event_id INNER JOIN gender_age AS T3 ON T2.device_id = T3.device_id WHERE T1.is_active = 1 AND T2.longitude = 121 AND T2.latitude = 31 AND SUBSTR(T2.timestamp, 1, 10) = '2016-05-06' ORDER BY T3.age DESC LIMIT 1
1,050
talkingdata
What is the most common device model among female users between the ages 27 to 28?
most common device model refers to MAX(COUNT(device_id)); female refers to gender = 'F'; between the ages 27 to 28 refers to group = 'F27-28';
SELECT T2.device_model FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T1.`group` = 'F27-28' AND T1.gender = 'F' ORDER BY T2.device_id DESC LIMIT 1
1,051
talkingdata
What are the categories of the top 2 oldest events?
oldest event refers to MIN(timestamp);
SELECT T4.category FROM events_relevant AS T1 INNER JOIN app_events_relevant AS T2 ON T1.event_id = T2.event_id INNER JOIN app_labels AS T3 ON T3.app_id = T2.app_id INNER JOIN label_categories AS T4 ON T3.label_id = T4.label_id ORDER BY T1.timestamp LIMIT 2
1,052
talkingdata
What is the gender of the majority of Vivo phone users?
majority of Vivo phone users refers to MAX(COUNT(phone_brand = 'vivo'));
SELECT T.gender FROM ( SELECT T2.gender, COUNT(T2.gender) AS num FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'vivo' GROUP BY T2.gender ) AS T ORDER BY T.num DESC LIMIT 1
1,053
talkingdata
Which category has the highest number of users?
highest number of users refers to MAX(COUNT(app_id));
SELECT T.category FROM ( SELECT T2.category, COUNT(T1.app_id) AS num FROM app_labels AS T1 INNER JOIN label_categories AS T2 ON T2.label_id = T1.label_id GROUP BY T1.app_id, T2.category ) AS T ORDER BY T.num DESC LIMIT 1
1,054
talkingdata
How many users belong to the MOBA category?
SELECT COUNT(T2.app_id) FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T2.label_id = T1.label_id WHERE T1.category = 'MOBA'
1,055
talkingdata
What is the percentage of female OPPO users against the male OPPO users?
percentage = DIVIDE(MULTIPLY(CONCAT(COUNT(device_id WHERE phone_brand = 'OPPO' AND gender = 'F'), 100), COUNT(device_id)), '%') AS 'the percentage of female OPPO users'; DIVIDE(MULTIPLY(CONCAT(COUNT(device_id WHERE phone_brand = 'OPPO' AND gender = 'M'), 100), COUNT(device_id)), '%') AS 'the percentage of male OPPO users';
SELECT SUM(IIF(T2.gender = 'F', 1, 0)) * 100 / COUNT(T2.device_id) AS perFemale , SUM(IIF(T2.gender = 'M', 1, 0)) * 100 / COUNT(T2.device_id) AS perMale FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'OPPO'
1,056
talkingdata
What were the locations of the events on 8th May, 2016?
location = longitude, latitude; on 8th May, 2016 refers to `timestamp` LIKE '2016-05-08%';
SELECT longitude, latitude FROM `events` WHERE SUBSTR(`timestamp`, 1, 10) = '2016-05-08'
1,057
talkingdata
List the app users IDs and installed status for the event ID of 844.
app user IDs refers to app_id; is_installed = 1 means the app status is installed; is_installed = 0 means the app status is not installed;
SELECT app_id , IIF(is_installed = 1, 'YES', 'NO') AS status FROM app_events WHERE event_id = 844
1,058
talkingdata
How many events were there on 30th April, 2016?
on 30th April, 2016 refers to `timestamp` LIKE '2016-04-30%';
SELECT COUNT(event_id) FROM events WHERE SUBSTR(`timestamp`, 1, 10) = '2016-04-30'
1,059
talkingdata
How many users used Vivo Xplay3S model?
Vivo Xplay3S model refers to phone_brand = 'vivo' AND device_model = 'Xplay3S';
SELECT COUNT(device_id) FROM phone_brand_device_model2 WHERE device_model = 'Xplay3S' AND phone_brand = 'vivo'
1,060
talkingdata
What is the ratio of male and female users in 27-28 age group?
ratio = DIVIDE(COUNT(device_id WHERE gender = 'M' AND `group` = 'M27-28'), COUNT(device_id WHERE gender = 'F' AND `group` = 'F27-28')); 27-28 age group refers to `group` = 'F27-28';
SELECT SUM(IIF(gender = 'M' AND `group` = 'M27-28', 1, 0)) / SUM(IIF(gender = 'F' AND `group` = 'F27-28', 1, 0)) AS r FROM gender_age
1,061
talkingdata
What are the labels' IDs of online shopping and online malls categories?
SELECT label_id FROM label_categories WHERE category IN ('online shopping', 'online malls')
1,062
talkingdata
Describe the phone brands and models of the users who participated in events on 5th May, 2016 at the coordinates of (112,44).
models refers to device_model; on 5th May, 2016 refers to timestamp LIKE '2016-05-05%'; coordinates of (112,44) refers to longitude = 112 AND latitude = 44;
SELECT DISTINCT T2.phone_brand, T2.device_model FROM events AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T2.device_id = T1.device_id WHERE T1.timestamp LIKE '2016-05-05%' AND T1.longitude = 112 AND T1.latitude = 44
1,063
talkingdata
Provide the app users IDs and time for the event ID of 82.
app user IDs refers to app_id; time refers to timestamp;
SELECT T1.app_id, T2.timestamp FROM app_events AS T1 INNER JOIN events AS T2 ON T2.event_id = T1.event_id WHERE T2.event_id = 82
1,064
talkingdata
Describe the device user gender and age of the event ID of 15251.
SELECT T1.gender, T1.age FROM gender_age AS T1 INNER JOIN events AS T2 ON T2.device_id = T1.device_id WHERE T2.event_id = 15251
1,065
talkingdata
How many events did the 88-years-old male users participate on 4th May,2016?
88-years-old refers to age = 88; male refers to gender = 'M'; on 4th May, 2016 refers to timestamp LIKE '2016-05-04%';
SELECT COUNT(T2.event_id) FROM gender_age AS T1 INNER JOIN events AS T2 ON T2.device_id = T1.device_id WHERE T1.gender = 'M' AND SUBSTR(`timestamp`, 1, 10) = '2016-05-04' AND T1.age = 88
1,066
talkingdata
Describe the ages, genders and numbers of events participated by the users at coordinates of (-102,38).
coordinates of (-102,38) refers to longitude = -102, latitude = 38;
SELECT DISTINCT T1.age, T1.gender, COUNT(T2.event_id) FROM gender_age AS T1 INNER JOIN `events` AS T2 ON T2.device_id = T1.device_id WHERE T2.longitude = -102 AND T2.latitude = 38 GROUP BY T1.age, T1.gender, T2.longitude, T2.latitude
1,067
talkingdata
Provide the phone brands and models of the users who were at the coordinates of (80,44).
models refers to device_model; coordinates of (80,44) refers to longitude = 80 AND latitude = 44;
SELECT DISTINCT T1.phone_brand, T1.device_model FROM phone_brand_device_model2 AS T1 INNER JOIN events AS T2 ON T2.device_id = T1.device_id WHERE T2.longitude = 80 AND T2.latitude = 44
1,068
talkingdata
List the included categories in the event ID of 155.
SELECT DISTINCT T1.category FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T2.label_id = T1.label_id INNER JOIN app_events AS T3 ON T3.app_id = T2.app_id WHERE T3.event_id = 155
1,069
talkingdata
Among HTC Butterfly phone users, list any five devices' IDs used by females.
HTC Butterfly refers to phone_brand = 'HTC' AND device_model = 'Butterfly'; females refers to gender = 'F';
SELECT T2.device_id FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.device_model = 'Butterfly' AND T2.gender = 'F' AND T1.phone_brand = 'HTC' LIMIT 5
1,070
talkingdata
How many app IDs were included under science fiction category?
SELECT COUNT(T2.app_id) FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T2.label_id = T1.label_id WHERE T1.category = 'science fiction'
1,071
talkingdata
What are the ages and genders of the LG L70 users?
LG L70 refers to phone_brand = 'LG' AND device_model = 'L70';
SELECT T2.age, T2.gender FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'LG' AND T1.device_model = 'L70'
1,072
talkingdata
Calculate the percentage of the app user IDs under Industry tag category.
percentage = DIVIDE(MULTIPLY(CONCAT(COUNT(app_id WHERE category = 'Industry tag'), 100), COUNT(app_id)),'%');
SELECT SUM(IIF(T1.category = 'Industry tag', 1, 0)) * 100 / COUNT(T2.app_id) AS per FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T2.label_id = T1.label_id
1,073
talkingdata
Among the LG brand users, calculate the percentage of the Nexus 5 model user. What is the ratio of male and female users of it?
LG brand refers to phone_brand = 'LG'; percentage = DIVIDE(MULTIPLY(CONCAT(COUNT(device_id WHERE device_model = 'Nexus 5'), 100), COUNT(device_id)),'%'); ratio = DIVIDE(COUNT(device_id WHERE device_model = 'Nexus 5' AND gender = 'M'), COUNT(device_id WHERE device_model = 'Nexus 5' AND gender = 'F')); Nexus 5 model refers to device_model = 'Nexus 5';
SELECT SUM(IIF(T1.device_model = 'Nexus 5', 1, 0)) * 100 / COUNT(T1.device_id) AS per , SUM(IIF(T1.device_model = 'Nexus 5' AND T2.gender = 'M', 1, 0)) / SUM(IIF(T1.device_model = 'Nexus 5' AND T2.gender = 'F', 1, 0)) AS r FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'LG'
1,074
talkingdata
How many users of the app were not active when event no.2 happened?
not active refers to is_active = 0; event no. refers to event_id; event_id = 2;
SELECT COUNT(event_id) FROM app_events WHERE event_id = 2 AND is_active = 0
1,075
talkingdata
How many events in total have happened on the devices in 2016?
in 2016 refers to `timestamp` LIKE '2016%';
SELECT COUNT(event_id) FROM `events` WHERE SUBSTR(`timestamp`, 1, 4) = '2016'
1,076
talkingdata
How many events have happened on device no.29182687948017100 in 2016?
device no. refers to device_id; device_id = 29182687948017100; in 2016 refers to `timestamp` LIKE '2016%';
SELECT COUNT(event_id) FROM `events` WHERE SUBSTR(`timestamp`, 1, 4) = '2016' AND device_id = 29182687948017100
1,077
talkingdata
How many device users are male?
male refers to gender = 'M';
SELECT COUNT(device_id) FROM gender_age WHERE gender = 'M'
1,078
talkingdata
What is the age of the oldest device user?
oldest device user refers to MAX(age);
SELECT MAX(age) FROM gender_age
1,079
talkingdata
Among the female users of the devices, how many of them are under 30?
female refers to gender = 'F'; under 30 refers to age < 30;
SELECT COUNT(device_id) FROM gender_age WHERE age < 30 AND gender = 'F'
1,080
talkingdata
Among the users who use a Galaxy Note 2, how many of them are female?
Galaxy Note 2 refers to device_model = 'Galaxy Note 2'; female refers to gender = 'F';
SELECT COUNT(T1.device_id) FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T2.gender = 'F' AND T1.device_model = 'Galaxy Note 2'
1,081
talkingdata
Please list the ages of all the users who use a Galaxy Note 2.
Galaxy Note 2 refers to device_model = 'Galaxy Note 2';
SELECT T2.age FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.device_model = 'Galaxy Note 2'
1,082
talkingdata
What is the device model of the device used by the oldest user?
oldest user refers to MAX(age);
SELECT device_model FROM phone_brand_device_model2 WHERE device_id IN ( SELECT device_id FROM gender_age WHERE age = ( SELECT MAX(age) FROM gender_age ) )
1,083
talkingdata
To which user group do most of the users who uses a vivo device belong?
user group where most of the users belong refers to MAX(COUNT(group)); vivo device refers to phone_brand = 'vivo';
SELECT T.`group` FROM ( SELECT T2.`group`, COUNT(`group`) AS num FROM phone_brand_device_model2 AS T1 INNER JOIN gender_age AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'vivo' GROUP BY T2.`group` ) AS T ORDER BY T.num DESC LIMIT 1
1,084
talkingdata
How many app users belong to the category of Securities?
SELECT COUNT(T1.app_id) FROM app_labels AS T1 INNER JOIN label_categories AS T2 ON T2.label_id = T1.label_id WHERE T2.category = 'Securities'
1,085
talkingdata
To which categories does app user no.1977658975649780000 belong?
app no. refers to app_id; app_id = 1977658975649780000;
SELECT T1.category FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T1.label_id = T2.label_id WHERE T2.app_id = 1977658975649780000
1,086
talkingdata
Please list the categories of the app users who are not active when event no.2 happened.
not active refers to is_active = 0; event no. refers to event_id; event_id = 2;
SELECT DISTINCT T1.category FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T1.label_id = T2.label_id INNER JOIN app_events AS T3 ON T2.app_id = T3.app_id WHERE T3.event_id = 2 AND T3.is_active = 0
1,087
talkingdata
Please list the location coordinates of all the devices with an inactive app user when event no.2 happened.
location coordinates = longitude, latitude; inactive refers to is_active = 0; event no. refers to event_id; event_id = 2;
SELECT DISTINCT T2.longitude, T2.latitude FROM app_events AS T1 INNER JOIN events AS T2 ON T2.event_id = T1.event_id WHERE T2.event_id = 2 AND T1.is_active = 0
1,088
talkingdata
Among all the times event no.2 happened when the app user was not active, when was the earliest time this situation happened?
event no. refers to event_id; event_id = 2; not active refers to is_active = 0; earliest time refers to MIN(timestamp);
SELECT T2.timestamp FROM app_events AS T1 INNER JOIN events AS T2 ON T2.event_id = T1.event_id WHERE T1.is_active = 0 AND T2.event_id = 2 ORDER BY T2.timestamp LIMIT 1
1,089
talkingdata
Please list the IDs of the events happened on all the vivo devices.
IDs of the events refers to event_id; vivo devices refers to phone_brand = 'vivo';
SELECT T2.event_id FROM phone_brand_device_model2 AS T1 INNER JOIN events AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'vivo'
1,090
talkingdata
Among the devices with event no.2 happening, how many of them are vivo devices?
event no. refers to event_id; event_id = 2; vivo devices refers to phone_brand = 'vivo';
SELECT COUNT(T1.device_id) FROM phone_brand_device_model2 AS T1 INNER JOIN events AS T2 ON T2.device_id = T1.device_id WHERE T1.phone_brand = 'vivo' AND T2.event_id = 2
1,091
talkingdata
Please list the time when event no.2 happened on a vivo device.
time refers to timestamp; event no. refers to event_id; event_id = '2'; vivo device refers to phone_brand = 'vivo';
SELECT T1.timestamp FROM events AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.event_id = T2.device_id WHERE T2.phone_brand = 'vivo' AND T1.event_id = '2'
1,092
talkingdata
How many events in total have happened on all the vivo devices in the year 2016?
vivo devices refers to phone_brand = 'vivo'; in the year 2016 refers to year(timestamp) = 2016;
SELECT COUNT(T1.event_id) FROM events AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.event_id = T2.device_id WHERE STRFTIME('%Y', T1.timestamp) = '2016' AND T2.phone_brand = 'vivo'
1,093
talkingdata
Among the users who uses a vivo device, how many of them are female and under 30?
vivo device refers to phone_brand = 'vivo'; female refers to gender = 'F'; under 30 refers to age < 30;
SELECT COUNT(T1.device_id) FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T1.gender = 'F' AND T2.phone_brand = 'vivo' AND T1.age < 30
1,094
talkingdata
What is the category that the most app users belong to?
most app users refers to MAX(COUNT(app_id));
SELECT T.category FROM ( SELECT T1.category, COUNT(T2.app_id) AS num FROM label_categories AS T1 INNER JOIN app_labels AS T2 ON T1.label_id = T2.label_id GROUP BY T1.label_id ) AS T ORDER BY T.num DESC LIMIT 1
1,095
talkingdata
What is the brand of the device used by the youngest female user?
brand of the device refers to phone_brand; youngest refers to MIN(age); female refers to gender = 'F';
SELECT phone_brand FROM phone_brand_device_model2 WHERE device_id IN ( SELECT * FROM ( SELECT device_id FROM gender_age WHERE gender = 'F' ORDER BY age LIMIT 1 ) AS T )
1,096
talkingdata
How many users in user group M23-26 use a vivo device?
user group M23-26 refers to group = 'M23-26'; vivo device refers to phone_brand = 'vivo';
SELECT COUNT(T2.device_id) FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T1.`group` = 'M23-26' AND T2.phone_brand = 'vivo'
1,097
talkingdata
Among all the users who use a vivo device, what is the percentage of the users in the M23-26 user group?
vivo device refers to phone_brand = 'vivo'; percentage = MULTIPLY(DIVIDE(COUNT(phone_brand = 'vivo WHERE group = 'M23-26), COUNT(phone_brand = 'vivo)), 100); M23-26 user group refers to group = 'M23-26';
SELECT SUM(IIF(T1.`group` = 'M23-26', 1.0, 0)) / COUNT(T1.device_id) AS per FROM gender_age AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.device_id = T2.device_id WHERE T2.phone_brand = 'vivo'
1,098
talkingdata
Among all the devices with event no.2 happening, what is the percentage of the device being a vivo phone?
event no. refers to event_id; event_id = '2'; percentage = SUM(IF(phone_brand = 'vivo',1,0)), COUNT(device_id) WHERE event_id = '2'; vivo phone refers to phone_brand = 'vivo';
SELECT SUM(IIF(T2.phone_brand = 'vivo', 1, 0)) / COUNT(T1.device_id) AS per FROM events AS T1 INNER JOIN phone_brand_device_model2 AS T2 ON T1.event_id = T2.device_id WHERE T1.event_id = '2'
1,099