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sales
|
What is the average number of customers per sales person?
|
average = DIVIDE(COUNT(CustomerID), COUNT(EmployeeID));
|
SELECT CAST(COUNT(T1.CustomerID) AS REAL) / COUNT(T3.EmployeeID) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID
| 5,400 | |
sales
|
Among all customers handled by Innes E. del Castillo, how many have purchased Short-Sleeve Classic Jersey, L?
|
Short-Sleeve Classic Jersey, L' is name of product;
|
SELECT COUNT(T2.CustomerID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T3.FirstName = 'Innes' AND T3.LastName = 'del Castillo' AND T1.Name = 'Short-Sleeve Classic Jersey, L' AND T3.MiddleInitial = 'e'
| 5,401 | |
sales
|
Name the sales person who helped Elizabeth A. White to purchase Road-250 Black, 48.
|
name of the sales person = FirstName, MiddleInitial, LastName; 'Road-250 Black, 48' is name of product;
|
SELECT DISTINCT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID INNER JOIN Customers AS T4 ON T2.CustomerID = T4.CustomerID WHERE T4.MiddleInitial = 'A' AND T4.LastName = 'White' AND T1.Name = 'Road-250 Black, 48' AND T4.FirstName = 'Elizabeth'
| 5,402 | |
sales
|
How many sales people managed to sell Headlights - Weatherproof?
|
Headlights - Weatherproof' is name of product
|
SELECT COUNT(T2.SalesPersonID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Headlights - Weatherproof'
| 5,403 | |
sales
|
Calculate the revenue produced through sales of HL Road Frame - Red, 56.
|
revenue = MULTIPLY(SUM(Quantity, Price)); 'HL Road Frame - Red, 56' is name of product;
|
SELECT SUM(T2.Quantity * T1.Price) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'HL Road Frame - Red, 56'
| 5,404 | |
sales
|
How many sales transactions were given by the customer named Joe L. Lopez?
|
sales transactions refers to SalesID;
|
SELECT COUNT(T1.SalesID) FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Joe' AND T2.MiddleInitial = 'L' AND T2.LastName = 'Lopez'
| 5,405 | |
sales
|
Name the customers who received 'Touring Rim' as a free gift.
|
name of the customer = FirstName, MiddleInitial, LastName; 'Touring Rim' is name of product;
|
SELECT DISTINCT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T3.Name = 'Touring Rim' AND T3.Price = 0
| 5,406 | |
sales
|
Find the number of customers handled by each of the sales people.
|
SELECT COUNT(CustomerID) FROM Sales GROUP BY SalesPersonID
| 5,407 | ||
sales
|
How many sales people are handling all the customers?
|
SELECT COUNT(EmployeeID) FROM Employees
| 5,408 | ||
sales
|
Identify the name of the sales person with employee ID 7.
|
name of the sales person = FirstName, MiddleInitial, LastName;
|
SELECT FirstName, MiddleInitial, LastName FROM Employees WHERE EmployeeID = 7
| 5,409 | |
sales
|
Name the most expensive and the least expensive products available, excluding free gifts.
|
most expensive product refers to MAX(Price); least expensive product refers to MIN(Price); excluding free gifts refers to not including Price = 0;
|
SELECT Name FROM Products WHERE Price IN (( SELECT MAX(Price) FROM Products ), ( SELECT MIN(Price) FROM Products ))
| 5,410 | |
sales
|
Among all the customers who have purchased ML Bottom Bracket, identify the percentage of sales by Albert I. Ringer?
|
ML Bottom Bracket' is name of product; percentage = MULTIPLY(DIVIDE(SUM(CustomerID WHERE FirstName = 'Albert' AND MiddleInitial = 'I' AND LastName = 'Ringer'), COUNT(CustomerID)), 1.0);
|
SELECT CAST(SUM(IIF(T3.FirstName = 'Albert' AND T3.MiddleInitial = 'I' AND T3.LastName = 'Ringer', 1, 0)) AS REAL) * 100 / COUNT(T2.CustomerID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T1.Name = 'ML Bottom Bracket'
| 5,411 | |
sales
|
How many customers have the first name Abigail?
|
SELECT COUNT(CustomerID) FROM Customers WHERE FirstName = 'Abigail'
| 5,412 | ||
sales
|
Indicate the quantity of Blade products sold.
|
Blade' is name of product;
|
SELECT DISTINCT T2.Quantity FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Blade'
| 5,413 | |
sales
|
Give the full name of the employee who has sold the most quantity.
|
full name of the employee = FirstName, LastName; most quantity refers to MAX(Quantity);
|
SELECT T1.FirstName, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID ORDER BY T2.Quantity DESC LIMIT 1
| 5,414 | |
sales
|
List the full name of the customer who purchased the most quantity of products.
|
full name of the customer = FirstName, LastName; most quantity refers to MAX(Quantity);
|
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID ORDER BY T2.Quantity DESC LIMIT 1
| 5,415 | |
sales
|
What is the name of the product that is most sold by sale person id 20?
|
most sold refers to MAX(Quantity);
|
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.SalesPersonID = 20 ORDER BY T2.Quantity DESC LIMIT 1
| 5,416 | |
sales
|
List the first names of employees with trading quantity for more than 500.
|
trading quantity for more than 500 refers to Quantity > 500;
|
SELECT DISTINCT T1.FirstName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID WHERE T2.Quantity > 500
| 5,417 | |
sales
|
List the first names of customers who have purchased products from sale person id 1.
|
SELECT T1.FirstName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.SalesPersonID = 1
| 5,418 | ||
sales
|
Calculate the total trading quantity of Abraham sold to Aaron Alexander.
|
total trading quantity = SUM(Quantity WHERE Employees.FirstName = 'Abraham' AND Customers.FirstName = 'Aaron' AND Customers.LastName = 'Alexander');
|
SELECT SUM(T2.Quantity) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Employees AS T3 ON T2.SalesPersonID = T3.EmployeeID WHERE T2.SalesPersonID = 1 AND T1.FirstName = 'Aaron' AND T1.LastName = 'Alexander' AND T3.FirstName = 'Abraham'
| 5,419 | |
sales
|
List the full names of customers who have purchased products in quantity over 600.
|
full names of customers = FirstName, LastName; quantity over 600 refers to quantity > 600;
|
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.Quantity > 600
| 5,420 | |
sales
|
Among the customers whose first name is Cameron, who bought the product in the most quantity?
|
most quantity refers to MAX(Quantity); who refers to FirstName, LastName;
|
SELECT T1.FirstName, T1.LastName FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.FirstName = 'Cameron' ORDER BY T2.Quantity DESC LIMIT 1
| 5,421 | |
sales
|
Please provide sales ID for products named Hex Nut with a price greater than 100.
|
price greater than 100 refers to price > 100;
|
SELECT T2.SalesID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE 'Hex Nut%' AND T1.Price > 100
| 5,422 | |
sales
|
Identify customer IDs who bought products priced from 1000 to 2000.
|
priced from 1000 to 2000 refers to Price BETWEEN 1000 AND 2000;
|
SELECT DISTINCT T2.CustomerID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price BETWEEN 1000 AND 2000
| 5,423 | |
sales
|
Calculate the total quantity of products that are gifts.
|
total quantity = SUM(Quantity); gifts refers to Price = 0;
|
SELECT SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price = 0
| 5,424 | |
sales
|
Calculate the quantity percentage of the gift products in the total trading quantity.
|
percentage = MULTIPLY(DIVIDE(SUM(Quantity WHERE Price = 0), SUM(Quantity)), 1.0); gift products refers to Price = 0;
|
SELECT CAST(SUM(IIF(T1.Price = 0, T2.Quantity, 0)) AS REAL) * 100 / SUM(T2.Quantity)FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID
| 5,425 | |
sales
|
Calculate the percentage of sold blades in the total number of transactions.
|
percentage = MULTIPLY(DIVIDE(SUM(Quantity WHERE Name = 'Blade'), SUM(Quantity)), 1.0); 'blades' refers to name of product;
|
SELECT CAST(SUM(IIF(T1.Name = 'Blade', T2.Quantity, 0)) AS REAL) * 100 / SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID
| 5,426 | |
sales
|
How many of the employees have the last name "Ringer" ?
|
SELECT COUNT(LastName) FROM Employees WHERE LastName = 'Ringer'
| 5,427 | ||
sales
|
Among the products with product ID lower than 15, how many of them costs 10 and below?
|
product ID lower than 15 refers to ProductID < 15; costs 10 and below refers to Price; Price < = 10;
|
SELECT COUNT(ProductID) FROM Products WHERE ProductID < 15 AND Price <= 10
| 5,428 | |
sales
|
Give the product's name brought by Aaron Alexander.
|
SELECT DISTINCT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Aaron' AND T3.LastName = 'Alexander'
| 5,429 | ||
sales
|
Give the product ID and name of the product with the highest prices among the quantity ranges from 400 to 500.
|
highest prices refers to MAX(Price); quantity ranges from 400 to 500 refers to Quantity BETWEEN 400 AND 500;
|
SELECT T1.ProductID, T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.quantity BETWEEN 400 AND 500 ORDER BY T1.Price DESC LIMIT 1
| 5,430 | |
sales
|
Among customers named Kate, who has the highest quantity?
|
highest quantity refers to MAX(Quantity);
|
SELECT T2.FirstName, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Kate' ORDER BY T1.Quantity DESC LIMIT 1
| 5,431 | |
sales
|
Among the products that have price ranges from 100 to 150, what is the customer ID and sales ID of the product with a quantity lower than 25?
|
price ranges from 100 to 150 refers to Price BETWEEN 100 AND 150; quantity lower than 25 refers to Quantity < 25;
|
SELECT T2.CustomerID, T2.SalesID FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Price BETWEEN 100 AND 150 AND T2.Quantity < 25
| 5,432 | |
sales
|
List the quantity and price of the product bought by Abigail Henderson.
|
SELECT T2.Quantity, T1.Price FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Abigail' AND T3.LastName = 'Henderson'
| 5,433 | ||
sales
|
In sales with a quantity of 60, how many of them have a price not greater than 500?
|
SELECT COUNT(T1.ProductID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T2.quantity = 60 AND T1.Price <= 500
| 5,434 | ||
sales
|
In customers with the first name of Erica, how many of them bought a quantity below 200?
|
quantity below 200 refers to quantity < 200;
|
SELECT COUNT(T1.ProductID) FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T2.FirstName = 'Erica' AND T1.Quantity < 200
| 5,435 | |
sales
|
Among products bought by Kathryn Ashe, what is the name of the product with the highest quantity?
|
highest quantity refers to MAX(Quantity);
|
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T3.FirstName = 'Kathryn' AND T3.LastName = 'Ashe' ORDER BY T2.Quantity DESC LIMIT 1
| 5,436 | |
sales
|
What is the price and quantity of the product named Seat Tube?
|
SELECT DISTINCT T2.Price, T1.Quantity FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'Seat Tube'
| 5,437 | ||
sales
|
What is the price and name of the product bought by Erica Xu?
|
SELECT T3.Price, T3.Name FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T1.ProductID = T3.ProductID WHERE T2.FirstName = 'Erica' AND T2.LastName = 'Xu'
| 5,438 | ||
sales
|
List the sales ID of the product with a quantity of 590 and named "External Lock Washer 7".
|
External Lock Washer 7' is name of product;
|
SELECT T1.SalesID FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'External Lock Washer 7' AND T1.Quantity = 590
| 5,439 | |
sales
|
In sales ID between 30 and 40, who is the customer that bought a total quantity of 403?
|
who refers to FirstName, LastName;
|
SELECT T2.FirstName, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.Quantity = 403 AND T1.SalesID BETWEEN 30 AND 40
| 5,440 | |
sales
|
List the customer's ID and last name of the customer that purchased a product with a quantity greater than 90% of the average quantity of all listed products.
|
quantity greater than 90% of the average quantity = Quantity > MULTIPLY(AVG(Quantity), 0.9);
|
SELECT T2.CustomerID, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.Quantity > ( SELECT AVG(Quantity) FROM Sales ) * 0.9
| 5,441 | |
sales
|
Among the sales ID ranges from 1 to 200, what is the percentage of the products with a price ranging from 200 to 300?
|
sales ID ranges from 1 to 200 refers to SalesID between 1 and 200; percentage = MULTIPLY(DIVIDE(SUM(Price between 200 and 300), COUNT(Price)), 1.0);
|
SELECT CAST(SUM(IIF(T2.Price BETWEEN 200 AND 300, 1, 0)) AS REAL) * 100 / COUNT(T2.Price) FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T1.SalesID BETWEEN 1 AND 200
| 5,442 | |
sales
|
What is the name of the most expensive product?
|
most expensive product refers to MAX(Price);
|
SELECT Name FROM Products WHERE Price = ( SELECT MAX(Price) FROM Products )
| 5,443 | |
sales
|
How many customers are named Madison?
|
SELECT COUNT(CustomerID) FROM Customers WHERE FirstName = 'Madison'
| 5,444 | ||
sales
|
How many types of "HL Touring Frames" are there?
|
types of HL Touring Frames refers to Name like '%HL Touring Frame%';
|
SELECT COUNT(ProductID) FROM Products WHERE Name LIKE '%HL Touring Frame%'
| 5,445 | |
sales
|
How many customers share the most common last name?
|
most common last name refers to MAX(COUNT(LastName));
|
SELECT COUNT(CustomerID) FROM Customers GROUP BY LastName ORDER BY COUNT(LastName) DESC LIMIT 1
| 5,446 | |
sales
|
How many free or gift products are there?
|
free gift refers to Price = 0;
|
SELECT COUNT(ProductID) FROM Products WHERE Price = 0
| 5,447 | |
sales
|
What is the name of the sales person who handled the highest number of sales?
|
name of the sales person = FirstName, MiddleInitial, LastName; highest number of sales refers to MAX(COUNT(SalesID));
|
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T2.SalesPersonID = T1.EmployeeID GROUP BY T2.SalesPersonID, T1.FirstName, T1.MiddleInitial, T1.LastName ORDER BY COUNT(T2.SalesID) DESC LIMIT 1
| 5,448 | |
sales
|
What is the full name of the customer who purchased the highest amount of total price in a single purchase?
|
full name of the customer = FirstName, MiddleInitial, LastName; highest amount of total price refers to MAX(MULTIPLY(Quantity, Price));
|
SELECT T2.FirstName, T2.MiddleInitial, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID INNER JOIN Products AS T3 ON T1.ProductID = T3.ProductID GROUP BY T1.SalesID, T1.Quantity, T3.Price, FirstName, MiddleInitial, LastName ORDER BY T1.Quantity * T3.Price DESC LIMIT 1
| 5,449 | |
sales
|
How many "Mountain-500 Black 42" were sold in total?
|
Mountain-500 Black 42' is name of product; sold in total = SUM(Quantity);
|
SELECT SUM(T2.Quantity) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Mountain-500 Black, 42'
| 5,450 | |
sales
|
How much is the total amount of sales handled by Heather McBadden?
|
total amount of sales = SUM(MULTIPLY(Quantity, Price));
|
SELECT SUM(T2.Quantity * T3.Price) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Heather' AND T1.LastName = 'McBadden'
| 5,451 | |
sales
|
How many "Mountain-100 Silver, 38" were sold by Stearns MacFeather?
|
Mountain-100 Silver, 38' is name of product;
|
SELECT SUM(T2.Quantity) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Stearns' AND T1.LastName = 'MacFeather' AND T3.Name = 'Mountain-100 Silver, 38'
| 5,452 | |
sales
|
How many type of products did Dalton M. Coleman purchase?
|
SELECT COUNT(T2.ProductID) FROM Customers AS T1 INNER JOIN Sales AS T2 ON T1.CustomerID = T2.CustomerID WHERE T1.FirstName = 'Dalton' AND T1.MiddleInitial = 'M' AND T1.LastName = 'Coleman'
| 5,453 | ||
sales
|
What are the full names of the top 3 employees who handled the highest number of sales?
|
full names of employees = FirstName, MiddleInitital, LastName; highest number of sales refers to MAX(COUNT(SalesID));
|
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID GROUP BY T2.SalesPersonID, T1.FirstName, T1.MiddleInitial, T1.LastName ORDER BY COUNT(T2.SalesID) DESC LIMIT 3
| 5,454 | |
sales
|
Among the "Mountain-500 Black" product types, which type was purchased the most?
|
Mountain-500 Black product types refers to Name like 'Mountain-500 Black%'; purchased the most refers to MAX(SUM(Quantity));
|
SELECT T1.Name FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE 'Mountain-500 Black%' GROUP BY T2.Quantity, T1.Name ORDER BY SUM(T2.Quantity) DESC LIMIT 1
| 5,455 | |
sales
|
How many employees sold "ML Road Frame-W - Yellow, 40"?
|
ML Road Frame-W - Yellow, 40' is name of product;
|
SELECT COUNT(T2.SalesPersonID) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'ML Road Frame-W - Yellow, 40'
| 5,456 | |
sales
|
How many chainring bolts were sold under sales ID 551971?
|
Chainring Bolts' is name of product;
|
SELECT T1.Quantity FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T2.Name = 'Chainring Bolts' AND T1.SalesID = 551971
| 5,457 | |
sales
|
How many employees sold over 20,000 quantities of "Touring-2000 Blue, 50"?
|
over 20,000 quantities refers to Quantity > 20000; 'Touring-2000 Blue, 50' is name of product;
|
SELECT COUNT(*) FROM ( SELECT SUM(Quantity) FROM Sales WHERE ProductID IN ( SELECT ProductID FROM Products WHERE Name = 'Touring-2000 Blue, 50' ) GROUP BY Quantity, SalesPersonID HAVING SUM(Quantity) > 20000 )
| 5,458 | |
sales
|
What is the total cost of all the "Road-650, Red, 60" products that Abraham E. Bennet sold?
|
total cost = SUM(MULTIPLY(Quantity, Price)); 'Road-650, Red, 60' is name of product;
|
SELECT SUM(T2.Quantity * T3.Price) FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID WHERE T1.FirstName = 'Abraham' AND T1.MiddleInitial = 'e' AND T1.LastName = 'Bennet' AND T3.Name = 'Road-650 Red, 60'
| 5,459 | |
sales
|
Which product has the highest total amount of quantity sold? Calculate its overall total price.
|
highest total amount of quantity refers to MAX(Quantity); overall total price = SUM(MULTIPLY(Quantity, Price));
|
SELECT T1.Name, SUM(T2.Quantity * T1.Price) FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID GROUP BY T1.ProductID, T1.Name ORDER BY SUM(T2.Quantity) DESC LIMIT 1
| 5,460 | |
sales
|
List the first name of all the customers whose last name is Chen.
|
SELECT FirstName, LastName FROM Customers WHERE LastName = 'Chen'
| 5,461 | ||
sales
|
Among the employee names, what is the most common middle initial?
|
most common middle initial refers to MAX(COUNT(MiddleInitial));
|
SELECT MiddleInitial FROM Employees GROUP BY MiddleInitial ORDER BY COUNT(MiddleInitial) DESC LIMIT 1
| 5,462 | |
sales
|
What is the average price of products that cost between 100 and 200?
|
average price = DIVIDE(SUM(Price, COUNT(Price))); cost refers to Price; Price BETWEEN 100 AND 200;
|
SELECT AVG(Price) FROM Products WHERE Price BETWEEN 100 AND 200
| 5,463 | |
sales
|
Find and list the full name of customers who bought products above-average quantity.
|
full name of the customer = FirstName, MiddleInitial, LastName; above-average quantity = Quantity > AVG(Quantity);
|
SELECT T2.FirstName, T2.MiddleInitial, T2.LastName FROM Sales AS T1 INNER JOIN Customers AS T2 ON T1.CustomerID = T2.CustomerID GROUP BY T1.Quantity HAVING T1.Quantity > ( SELECT AVG(Quantity) FROM Sales )
| 5,464 | |
sales
|
Give the full name of the customer who bought the most amount of products.
|
full name of the customer = FirstName, MiddleInitial, LastName; most amount of products refers to MAX(MULTIPLY(Quantity, Price));
|
SELECT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID ORDER BY T2.Quantity * T1.Price DESC LIMIT 1
| 5,465 | |
sales
|
Of the employees who sold Blade, who has the most amount of sales?
|
Blade' is name of product; most amount of sales refers to MAX(MULTIPLY(Quantity, Price));
|
SELECT T1.FirstName, T1.MiddleInitial, T1.LastName FROM Employees AS T1 INNER JOIN Sales AS T2 ON T1.EmployeeID = T2.SalesPersonID INNER JOIN Products AS T3 ON T2.ProductID = T3.ProductID ORDER BY T2.Quantity * T3.Price DESC LIMIT 1
| 5,466 | |
sales
|
List the full name of customers who spend more than 50,000 in descending order the amount spend.
|
full name of the customer = FirstName, MiddleInitial, LastName; more than 50,000 in the amount refers to MULTIPLY(Quantity, Price) > 50000;
|
SELECT DISTINCT T3.FirstName, T3.MiddleInitial, T3.LastName FROM Products AS T1 INNER JOIN Sales AS T2 ON T1.ProductID = T2.ProductID INNER JOIN Customers AS T3 ON T2.CustomerID = T3.CustomerID WHERE T2.Quantity * T1.Price > 50000
| 5,467 | |
sales
|
Name the product that sold the most quantity.
|
most quantity refers to MAX(Quantity);
|
SELECT T2.Name FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID ORDER BY T1.Quantity DESC LIMIT 1
| 5,468 | |
sales
|
Find and list the products that sold below the average quantity.
|
below the average quantity refers to Quantity < AVG(Quantity);
|
SELECT DISTINCT T2.Name FROM Sales AS T1 INNER JOIN Products AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Quantity < ( SELECT AVG(Quantity) FROM Sales )
| 5,469 | |
menu
|
How many dishes do not have correct data for the year in which it appeared first?
|
do not have correct data refers to first_appeared < 1851 or first_appeared > 2012;
|
SELECT COUNT(*) FROM Dish WHERE first_appeared < 1851 OR first_appeared > 2012
| 5,470 | |
menu
|
Which dish lasted longer, Anchovies or Fresh lobsters in every style?
|
if (SUBTRACT(last_appeared, first_appeared) WHERE name = 'Anchovies') > (SUBTRACT(last_appeared, first_appeared) WHERE name = 'Fresh lobsters in every style'), it means 'Anchovies' lasted longer; if (SUBTRACT(last_appeared , first_appeared) WHERE name = 'Fresh lobsters in every style') > (SUBTRACT(last_appeared , first_appeared) WHERE name = 'Anchovies') it means 'Fresh lobsters in every style' last longer;
|
SELECT CASE WHEN SUM(CASE WHEN name = 'Anchovies' THEN last_appeared - first_appeared ELSE 0 END) - SUM(CASE WHEN name = 'Fresh lobsters in every style' THEN last_appeared - first_appeared ELSE 0 END) > 0 THEN 'Anchovies' ELSE 'Fresh lobsters in every style' END FROM Dish WHERE name IN ('Fresh lobsters in every style', 'Anchovies')
| 5,471 | |
menu
|
Among all the dishes that were once free, what is the name of the dish that had appeared on most menus?
|
dishes that were once free refers to lowest_price = 0; appeared on most menus refers to MAX(menus_appeared);
|
SELECT name FROM Dish WHERE lowest_price = 0 ORDER BY menus_appeared DESC LIMIT 1
| 5,472 | |
menu
|
How many menus with the name "Waldorf Astoria" have 4 pages?
|
4 pages refers to page_count = 4;
|
SELECT COUNT(*) FROM Menu WHERE name = 'Waldorf Astoria' AND page_count = 4
| 5,473 | |
menu
|
What is the name of the dish that appeared on the upper left corner on menu page no. 1389?
|
appeared on the upper left corner on menu refers to xpos < 0.25 AND ypos < 0.25; menu page no. refers to menu_page_id; menu_page_id = 1389;
|
SELECT T1.name FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T2.menu_page_id = 1389 AND T2.xpos < 0.25 AND T2.ypos < 0.25
| 5,474 | |
menu
|
Please list the prices of the dish "Clear green turtle" on every menu page it appeared on.
|
Clear green turtle is a name of dish;
|
SELECT T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.name = 'Clear green turtle'
| 5,475 | |
menu
|
Among all the menu pages with the appearance of the dish "Clear green turtle", how many of them have the dish at a stable price?
|
Clear green turtle is a name of dish; stable price refers to highest_price is null;
|
SELECT SUM(CASE WHEN T1.name = 'Clear green turtle' THEN 1 ELSE 0 END) FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.highest_price IS NULL
| 5,476 | |
menu
|
What is the highest price of the dish "Clear green turtle" on a menu page?
|
highest price refers to MAX(Price); Clear green turtle is a name of dish;
|
SELECT T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T1.name = 'Clear green turtle' ORDER BY T2.price DESC LIMIT 1
| 5,477 | |
menu
|
Please list the IDs of all the menus in which the dish "Clear green turtle" had appeared.
|
Clear green turtle is a name of dish;
|
SELECT T1.menu_id FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T3.name = 'Clear green turtle'
| 5,478 | |
menu
|
Among the menus in which the dish "Clear green turtle" had appeared, how many of them used the dollar as their currency?
|
Clear green turtle is a name of dish; dollar as currency refers to currency = 'Dollars';
|
SELECT SUM(CASE WHEN T3.currency = 'Dollars' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T4.name = 'Clear green turtle'
| 5,479 | |
menu
|
Among the menus in which the dish "Clear green turtle" had appeared, how many of them did not support taking out or booking in advance?
|
Clear green turtle is a name of dish; not support taking out or booking in advance refers to call_number is null;
|
SELECT SUM(CASE WHEN T4.name = 'Clear green turtle' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.call_number IS NULL
| 5,480 | |
menu
|
Please list the names of all the dishes that appeared on the menu "Zentral Theater Terrace".
|
Zentral Theater Terrace is a name of menu;
|
SELECT T4.name FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.name = 'Zentral Theater Terrace'
| 5,481 | |
menu
|
Which dish has the highest price on the menu "Zentral Theater Terrace"? Please give its name.
|
highest price refers to MAX(Price); Zentral Theater Terrace is a name of menu;
|
SELECT T4.name FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T3.name = 'Zentral Theater Terrace' ORDER BY T1.price DESC LIMIT 1
| 5,482 | |
menu
|
How many dishes are there on the menu "Zentral Theater Terrace"?
|
Zentral Theater Terrace is a name of menu;
|
SELECT SUM(CASE WHEN T3.name = 'Zentral Theater Terrace' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id
| 5,483 | |
menu
|
How many dishes are there in total in the menus with the name "Waldorf Astoria"?
|
FALSE;
|
SELECT SUM(CASE WHEN T3.name = 'Waldorf Astoria' THEN 1 ELSE 0 END) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id
| 5,484 | |
menu
|
Please list the IDs of the menus that are DIYs of the restaurant and have the dish "Clear green turtle".
|
IDs of the menus refers to menu_id; menus that are DIYs of the restaurant refers to sponsor is null; Clear green turtle is a name of dish;
|
SELECT T2.menu_id FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id INNER JOIN Dish AS T4 ON T1.dish_id = T4.id WHERE T4.name = 'Clear green turtle' AND T3.sponsor IS NULL
| 5,485 | |
menu
|
What is the average page number of the menus that have the dish "Clear green turtle"?
|
average page number = AVG(page_number); Clear green turtle is a name of dish;
|
SELECT AVG(T1.page_number) FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T3.name = 'Clear green turtle'
| 5,486 | |
menu
|
What is the average price of the dishes on the menu "Zentral Theater Terrace"?
|
average price = AVG(price); Zentral Theater Terrace refers to menu;
|
SELECT SUM(T1.price) / COUNT(T1.price) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id WHERE T3.name = 'Zentral Theater Terrace'
| 5,487 | |
menu
|
How many menu items were created on 28th March 2011?
|
created on 28th March 2011 refers to created_at like '2011-03-28%';
|
SELECT COUNT(*) FROM MenuItem WHERE created_at LIKE '2011-03-28%'
| 5,488 | |
menu
|
How many dishes are included in the menu page ID 144?
|
FALSE;
|
SELECT COUNT(*) FROM MenuItem WHERE menu_page_id = 144
| 5,489 | |
menu
|
How many menus were used in Dutcher House?
|
Dutcher House refers to location = 'Dutcher House';
|
SELECT COUNT(*) FROM Menu WHERE location = 'Dutcher House'
| 5,490 | |
menu
|
How many dishes appeared on a menu more than once?
|
appeared on a menu more than once refers to times_appeared > menus_appeared;
|
SELECT COUNT(*) FROM Dish WHERE times_appeared > menus_appeared
| 5,491 | |
menu
|
How many menus were created for steamship?
|
steamship refers to venue = 'STEAMSHIP';
|
SELECT COUNT(*) FROM Menu WHERE venue = 'STEAMSHIP'
| 5,492 | |
menu
|
How many pages were there on the menu created on 17th November 1898?
|
created on 17th November 1898 refers to date = '1898-11-17';
|
SELECT SUM(CASE WHEN T1.date = '1898-11-17' THEN 1 ELSE 0 END) FROM Menu AS T1 INNER JOIN MenuPage AS T2 ON T1.id = T2.menu_id
| 5,493 | |
menu
|
Name the dishes that were on the menu page ID 174.
|
FALSE;
|
SELECT T2.name FROM MenuItem AS T1 INNER JOIN Dish AS T2 ON T2.id = T1.dish_id WHERE T1.menu_page_id = 174
| 5,494 | |
menu
|
List the names and menu page IDs of the dishes that first appeared in 1861.
|
first appeared in 1861 refers to first_appeared = 1861;
|
SELECT T2.name, T1.dish_id FROM MenuItem AS T1 INNER JOIN Dish AS T2 ON T2.id = T1.dish_id WHERE T2.first_appeared = 1861
| 5,495 | |
menu
|
Among the dishes on menu page ID 7610, list the names and highest prices of the dishes in menu items that were created on 23rd May 2011.
|
highest prices of the dishes refers to MAX(price); created on 23rd May 2011 refers to created_at like '2011-05-23%';
|
SELECT T1.name, T2.price FROM Dish AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.dish_id WHERE T2.created_at LIKE '2011-05-23%' ORDER BY T2.price DESC LIMIT 1
| 5,496 | |
menu
|
List the dishes included on page number 30 with the least in full height.
|
least in full height refers to MIN(full_height);
|
SELECT T3.name FROM MenuPage AS T1 INNER JOIN MenuItem AS T2 ON T1.id = T2.menu_page_id INNER JOIN Dish AS T3 ON T2.dish_id = T3.id WHERE T1.page_number = 30 ORDER BY T1.full_height DESC, T1.full_height ASC LIMIT 1
| 5,497 | |
menu
|
Provide the page IDs and name of the menu which had the highest page count.
|
page IDs refers to page_number; highest page count refers to MAX(page_count);
|
SELECT T1.page_number, T2.name FROM MenuPage AS T1 INNER JOIN Menu AS T2 ON T2.id = T1.menu_id ORDER BY T2.page_count DESC LIMIT 1
| 5,498 | |
menu
|
On the menu with the most dishes, how many dishes were there on its second page?
|
menu with the most dishes refers to menu.id with MAX(dish_count); second page refers to page_number = 2;
|
SELECT COUNT(T1.dish_id) FROM MenuItem AS T1 INNER JOIN MenuPage AS T2 ON T1.menu_page_id = T2.id INNER JOIN Menu AS T3 ON T2.menu_id = T3.id WHERE T2.page_number = 2 GROUP BY T3.name ORDER BY T3.dish_count DESC LIMIT 1
| 5,499 |
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