db_id
stringclasses 69
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stringlengths 24
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|---|---|---|---|---|---|
works_cycles
|
Please list the top 3 discounts with the highest discount percentage and fall under the reseller category.
|
discount percentage refers to DiscountPct; highest discount percentage refers to MAX(DiscountPct);
|
SELECT Description, DiscountPct FROM SpecialOffer WHERE Category = 'Reseller' ORDER BY DiscountPct DESC LIMIT 0, 3
| 7,400 | |
works_cycles
|
Where can I get the demographic information about the Valley Bicycle Specialists store?
|
Valley Bicycle Specialists is a name of a store;
|
SELECT Demographics FROM Store WHERE Name = 'Valley Bicycle Specialists'
| 7,401 | |
works_cycles
|
Among all the products that are manufactured in-house, how many of them are salable?
|
product is mnanufactured in-house refers to MakeFlag = 1; salable product refers to FinishedGoodsFlag = 1;
|
SELECT SUM(FinishedGoodsFlag) FROM Product WHERE MakeFlag = 1
| 7,402 | |
works_cycles
|
What is the minimum inventory quantity of Chainring Bolts?
|
minimum inventory quantity refers to SafetyStockLevel; chainring bolts is a name of product;
|
SELECT SafetyStockLevel FROM Product WHERE Name = 'Chainring Bolts'
| 7,403 | |
works_cycles
|
Which product has the highest standard cost?
|
SELECT Name FROM Product ORDER BY StandardCost DESC LIMIT 1
| 7,404 | ||
works_cycles
|
What type of employee is David Bradley?
|
type of employee refers to PersonType;
|
SELECT PersonType FROM Person WHERE FirstName = 'David' AND LastName = 'Bradley'
| 7,405 | |
works_cycles
|
Among the employees who are store contacts, how many of them have a title of "Mr."?
|
store contact refers to PersonType = 'SC';
|
SELECT COUNT(BusinessEntityID) FROM Person WHERE PersonType = 'SC' AND Title = 'Mr.'
| 7,406 | |
works_cycles
|
Where can I find the Valley Bicycle Specialists store?
|
Valley Bicycle Specialists is a name of store; full address = AddressLine1+AddressLine2;
|
SELECT T2.AddressLine1, T2.AddressLine2 FROM BusinessEntityAddress AS T1 INNER JOIN Address AS T2 ON T1.AddressID = T2.AddressID INNER JOIN Store AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID WHERE T3.Name = 'Valley Bicycle Specialists'
| 7,407 | |
works_cycles
|
To which e-mail address should I write if I want to contact David Bradley?
|
SELECT T2.EmailAddress FROM Person AS T1 INNER JOIN EmailAddress AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,408 | ||
works_cycles
|
Please list the phone numbers of all the store contacts.
|
store contact refers to PersonType = 'SC';
|
SELECT T2.PhoneNumber FROM Person AS T1 INNER JOIN PersonPhone AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.PersonType = 'SC'
| 7,409 | |
works_cycles
|
What is the hashed password of David Bradley?
|
hashed password refers to PasswordHash;
|
SELECT T2.PasswordHash FROM Person AS T1 INNER JOIN Password AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,410 | |
works_cycles
|
Please list the e-mail addresses of all the employees who wish to receive e-mail promotions from Adventureworks and selected partners.
|
employees who wish to receive e-mail promotions from AdventureWorks and selected partners refers to EmailPromotion = 2;
|
SELECT T2.EmailAddress FROM Person AS T1 INNER JOIN EmailAddress AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.EmailPromotion = 2
| 7,411 | |
works_cycles
|
Please show the credit card number of David Bradley.
|
credit card number refers to CardNumber;
|
SELECT T3.CardNumber FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,412 | |
works_cycles
|
In which year will the David Bradley's credit card expire?
|
year of credit card expiration refers to ExpYear;
|
SELECT T3.ExpYear FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,413 | |
works_cycles
|
Please list the names of all the store contact employees whose credit cards expired in 2007.
|
year of credit card expiration refers to ExpYear; ExpYear = 2007; store contact refers to PersonType = 'SC';
|
SELECT T1.FirstName, T1.LastName FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T3.ExpYear = 2007 AND T1.PersonType = 'SC'
| 7,414 | |
works_cycles
|
Among the store contact employees, how many of them have a Vista credit card?
|
store contact refers to PersonType = 'SC'; type of credit card refers to CardType; CardType = 'vista';
|
SELECT COUNT(T1.FirstName) FROM Person AS T1 INNER JOIN PersonCreditCard AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN CreditCard AS T3 ON T2.CreditCardID = T3.CreditCardID WHERE T3.CardType = 'Vista' AND T1.PersonType = 'SC'
| 7,415 | |
works_cycles
|
How many departments have David Bradley been in?
|
SELECT COUNT(T3.DepartmentID) FROM Person AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,416 | ||
works_cycles
|
Please list the departments that David Bradley used to belong to.
|
SELECT T2.DepartmentID FROM Person AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T1.FirstName = 'David' AND T1.LastName = 'Bradley'
| 7,417 | ||
works_cycles
|
How many people were there in the Engineering Department in the year 2009?
|
year(EndDate)>2009 and year(StartDate)<2009;
|
SELECT COUNT(T1.BusinessEntityID) FROM Person AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T3.Name = 'Engineering' AND STRFTIME('%Y', T2.EndDate) > '2009' AND STRFTIME('%Y', T2.StartDate) < '2009'
| 7,418 | |
works_cycles
|
Which employee has been in the Engineering Department the longest? Please give his or her firstname and lastname.
|
length of stay in a department = SUBTRACT(EndDate, StartDate);
|
SELECT T1.FirstName, T1.LastName FROM Person AS T1 INNER JOIN EmployeeDepartmentHistory AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T2.DepartmentID = T3.DepartmentID WHERE T3.Name = 'Engineering' ORDER BY T2.EndDate - T2.StartDate DESC LIMIT 1
| 7,419 | |
works_cycles
|
Among the employees in the Manufacturing group in 2007, how many of them are store contacts?
|
store contact refers to PersonType = 'SC'; year(EndDate)>2007 and year(StartDate)<2007;
|
SELECT COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN Person AS T3 ON T1.BusinessEntityID WHERE T3.PersonType = 'SC' AND T2.GroupName = 'Manufacturing' AND STRFTIME('%Y', T1.EndDate) >= '2007' AND STRFTIME('%Y', T1.StartDate) <= '2007'
| 7,420 | |
works_cycles
|
Please list the credit card numbers of all the employees who have left the Finance Department.
|
credit card number refers to CardNumber; employees who left the department refers to EndDate NOT null; Engineering Department is a name of department;
|
SELECT T3.CardNumber FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN CreditCard AS T3 ON T1.ModifiedDate = T3.ModifiedDate INNER JOIN PersonCreditCard AS T4 ON T3.CreditCardID = T4.CreditCardID WHERE T2.Name = 'Finance' AND T1.EndDate IS NOT NULL
| 7,421 | |
works_cycles
|
How many employees working in the Engineering Department in 2007 would have their credit cards expired in the same year?
|
year(StartDate) 2007; year of credit card expiration refers to ExpYear; ExpYear = 2007;
|
SELECT COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN PersonCreditCard AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID INNER JOIN CreditCard AS T4 ON T3.CreditCardID = T4.CreditCardID WHERE T4.ExpYear = 2007 AND T2.Name = 'Engineering'
| 7,422 | |
works_cycles
|
What is the e-mail address of the employee who switched departments for the most times?
|
switched department the most refers to MAX(count(DepartmentID));
|
SELECT T2.EmailAddress FROM EmployeeDepartmentHistory AS T1 INNER JOIN EmailAddress AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID GROUP BY T2.BusinessEntityID ORDER BY COUNT(T1.DepartmentID) DESC LIMIT 1
| 7,423 | |
works_cycles
|
Among all the employees who don't wish to receive promotion e-mails, how many of them belong to or once belonged to the Engineering Department?
|
Employees who don't wish to receive e-mail promotions refers to EmailPromotion = 0;
|
SELECT COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID INNER JOIN Department AS T3 ON T1.DepartmentID = T3.DepartmentID WHERE T3.Name = 'Engineering' AND T2.EmailPromotion = 0
| 7,424 | |
works_cycles
|
How many employees came into the Quality Assurance Group in the year 2007?
|
Quality Assurance Group is a group name of department; came in 2007 refers to year(StartDate) = 2007;
|
SELECT COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID WHERE T2.GroupName = 'Quality Assurance' AND STRFTIME('%Y', T1.StartDate) = '2007'
| 7,425 | |
works_cycles
|
Please list the product names of all the products on the LL Road Frame Sale.
|
LL Road Frame Sale is a description of special offer
|
SELECT T3.Name FROM SpecialOffer AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID INNER JOIN Product AS T3 ON T2.ProductID = T3.ProductID WHERE T1.Description = 'LL Road Frame Sale'
| 7,426 | |
works_cycles
|
How many products were on the LL Road Frame Sale?
|
LL Road Frame Sale is a description of special offer
|
SELECT COUNT(DISTINCT ProductID) FROM SpecialOffer AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID WHERE T1.Description = 'LL Road Frame Sale'
| 7,427 | |
works_cycles
|
Has the product Chainring Bolts been on any of the sales?
|
a product that's been on sale refers to SellStartDate NOT null and vice versa;
|
SELECT CASE WHEN COUNT(T1.Description) >= 1 THEN 'Yes' ELSE 'No' END FROM SpecialOffer AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID INNER JOIN Product AS T3 ON T2.ProductID = T3.ProductID WHERE T3.Name = 'Chainring Bolts'
| 7,428 | |
works_cycles
|
How many products from the Clothing category were on the LL Road Frame Sale?
|
LL Road Frame Sale is a description of special offer
|
SELECT COUNT(T2.ProductID) FROM SpecialOffer AS T1 INNER JOIN SpecialOfferProduct AS T2 ON T1.SpecialOfferID = T2.SpecialOfferID INNER JOIN Product AS T3 ON T2.ProductID = T3.ProductID INNER JOIN ProductSubcategory AS T4 ON T3.ProductSubcategoryID = T4.ProductSubcategoryID INNER JOIN ProductCategory AS T5 ON T4.ProductCategoryID = T5.ProductCategoryID WHERE T1.Description = 'LL Road Frame Sale' AND T4.Name = 'Clothing'
| 7,429 | |
works_cycles
|
Please list the products that are under the Clothing category that are manufactured in-house and salable.
|
product is manufactured in-house refers to MakeFlag = 1; salable product refers to FinishedGoodsFlag = 1;
|
SELECT CASE WHEN T1.MakeFlag = 1 THEN T1.Name END FROM Product AS T1 INNER JOIN ProductSubcategory AS T2 ON T1.ProductSubcategoryID = T2.ProductSubcategoryID INNER JOIN ProductCategory AS T3 ON T2.ProductCategoryID = T3.ProductCategoryID WHERE T2.ProductSubcategoryID = 3
| 7,430 | |
works_cycles
|
For all the employees that have left the Engineering Department, what is the average time of their stay?
|
employees who left a department refers to EndDate NOT null; average stay = AVG(SUBTRACT(year(EndDate)), (year(T1.StartDate)));
|
SELECT CAST(SUM(365 * (STRFTIME('%Y', T1.EndDate) - STRFTIME('%Y', T1.StartDate)) + 30 * (STRFTIME('%m', T1.EndDate) - STRFTIME('%m', T1.StartDate)) + STRFTIME('%d', T1.EndDate) - STRFTIME('%d', T1.StartDate)) AS REAL) / COUNT(T1.BusinessEntityID) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID WHERE T2.Name = 'Engineering' AND T1.EndDate IS NOT NULL
| 7,431 | |
works_cycles
|
What is the average pay rate of the employees who worked in the Engineering Departmentin 2007?
|
average pay rate = AVG(Rate); work in 2007 refers to year(StartDate)<2007 AND year(EndDate)>2007;
|
SELECT AVG(T3.Rate) FROM EmployeeDepartmentHistory AS T1 INNER JOIN Department AS T2 ON T1.DepartmentID = T2.DepartmentID INNER JOIN EmployeePayHistory AS T3 ON T1.BusinessEntityID = T3.BusinessEntityID WHERE T2.Name = 'Engineering' AND STRFTIME('%Y', EndDate) > '2007' AND STRFTIME('%Y', T1.StartDate) < '2007'
| 7,432 | |
works_cycles
|
How much more expensive in percentage is the product with the highest selling price from the product with the lowest selling price in the Clothing category?
|
selling price refers to ListPrice; highest selling price refers to MAX(ListPrice); lowest selling price refers to MIN(ListPrice);
|
SELECT (MAX(T1.ListPrice) - MIN(T1.ListPrice)) * 100 / MIN(T1.ListPrice) FROM Product AS T1 INNER JOIN ProductSubcategory AS T2 ON T1.ProductSubcategoryID = T2.ProductSubcategoryID INNER JOIN ProductCategory AS T3 ON T2.ProductCategoryID = T3.ProductCategoryID WHERE T3.Name = 'Clothing'
| 7,433 | |
works_cycles
|
What is the average profit of all the products from the Clothing category?
|
average profit = DIVIDE(SUM(SUBTRACT(ListPrice, StandardCost))), (COUNT(ProductSubcategoryID))));
|
SELECT SUM(T1.ListPrice - T1.StandardCost) / COUNT(T1.ProductID) FROM Product AS T1 INNER JOIN ProductSubcategory AS T2 ON T1.ProductSubcategoryID = T2.ProductSubcategoryID INNER JOIN ProductCategory AS T3 ON T2.ProductCategoryID = T3.ProductCategoryID WHERE T3.Name = 'Clothing'
| 7,434 | |
works_cycles
|
Which product cost the least in 2013?
|
cost refers to StandardCost; cost the least refers to MIN(StandardCost);
|
SELECT ProductID FROM ProductCostHistory WHERE StartDate LIKE '2013%' ORDER BY StandardCost LIMIT 1
| 7,435 | |
works_cycles
|
List all products with the color yellow.
|
SELECT ProductID FROM Product WHERE Color = 'Yellow'
| 7,436 | ||
works_cycles
|
What is the bussiness id for Mr. Hung-Fu Ting?
|
business id refers to BusinessEntityID;
|
SELECT BusinessEntityID FROM Person WHERE Title = 'Mr.' AND FirstName = 'Hung-Fu' AND LastName = 'Ting'
| 7,437 | |
works_cycles
|
What is the phone number of the person with id "12597"?
|
person with id refers to BusinessEntityID;
|
SELECT PhoneNumber FROM PersonPhone WHERE BusinessEntityID = 12597
| 7,438 | |
works_cycles
|
What is the price for the product with the id "912"?
|
price refers to ListPrice;
|
SELECT ListPrice FROM ProductListPriceHistory WHERE ProductID = 912
| 7,439 | |
works_cycles
|
Is there a work order where the planned cost is different from the actual cost?
|
planned cost is different from actual cost refers to ActualCost ! = PlannedCost;
|
SELECT CASE WHEN ActualCost = PlannedCost THEN 'No' ELSE 'Yes' END FROM WorkOrderRouting
| 7,440 | |
works_cycles
|
What is the thumbnail photo file for the product with the id "979"?
|
thumbnail photo file refers to ThumbnailPhotoFileName;
|
SELECT T2.ThumbnailPhotoFileName FROM ProductProductPhoto AS T1 INNER JOIN ProductPhoto AS T2 ON T1.ProductPhotoID = T2.ProductPhotoID WHERE T1.ProductID = 979
| 7,441 | |
works_cycles
|
List all the names of the products with the price of more than 1000$.
|
ListPrice>1000;
|
SELECT DISTINCT T2.Name FROM ProductListPriceHistory AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T1.ListPrice > 1000
| 7,442 | |
works_cycles
|
What is the product with the most profit?
|
profit = SUBTRACT(ListPrice, StandardCost);
|
SELECT T1.ProductID FROM ProductListPriceHistory AS T1 INNER JOIN ProductCostHistory AS T2 ON T1.ProductID = T2.ProductID ORDER BY T1.ListPrice - T2.StandardCost DESC LIMIT 1
| 7,443 | |
works_cycles
|
What is the name of the product stored in location 1 compartment L container 6?
|
compartment refers to Shelf;
|
SELECT T2.Name FROM ProductInventory AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T1.LocationID = 1 AND T1.Shelf = 'L' AND T1.Bin = 6
| 7,444 | |
works_cycles
|
What are locations of the work order "35493"?
|
SELECT T2.Name FROM WorkOrderRouting AS T1 INNER JOIN Location AS T2 ON T1.LocationID = T2.LocationID WHERE T1.WorkOrderID = 35493
| 7,445 | ||
works_cycles
|
What are the products with a large photo?
|
product with large photo refers to LargePhoto NOT null;
|
SELECT T2.ProductID FROM ProductPhoto AS T1 INNER JOIN ProductProductPhoto AS T2 ON T1.ProductPhotoID = T2.ProductPhotoID WHERE T1.LargePhotoFileName LIKE '%large.gif'
| 7,446 | |
works_cycles
|
List all the socks products.
|
Socks is a name of product subcategory
|
SELECT T2.ProductID FROM ProductSubcategory AS T1 INNER JOIN Product AS T2 ON T1.ProductSubcategoryID = T2.ProductSubcategoryID WHERE T1.Name = 'Socks'
| 7,447 | |
works_cycles
|
With 100$, how many Cable Lock can you buy?
|
number of products a $100 can buy = DIVIDE(100, ListPrice);
|
SELECT 100 / T2.ListPrice FROM Product AS T1 INNER JOIN ProductListPriceHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Cable Lock'
| 7,448 | |
works_cycles
|
What is the scrap reason for work order "57788"?
|
SELECT T2.Name FROM WorkOrder AS T1 INNER JOIN ScrapReason AS T2 ON T1.ScrapReasonID = T2.ScrapReasonID WHERE T1.WorkOrderID = 57788
| 7,449 | ||
works_cycles
|
What is the cost for the sports?
|
cost refers to StandardCost;
|
SELECT T2.StandardCost FROM Product AS T1 INNER JOIN ProductCostHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE '%Sport%'
| 7,450 | |
works_cycles
|
How many products with the id "476" are stored in Metal Storage?
|
Metal Storage is name of location
|
SELECT T2.Quantity FROM Location AS T1 INNER JOIN ProductInventory AS T2 ON T1.LocationID = T2.LocationID WHERE T2.ProductID = 476 AND T1.Name = 'Metal Storage'
| 7,451 | |
works_cycles
|
List all the products with lower than average cost.
|
cost refers to StandardCost; lower than average cost = StandardCost<(AVG(StandardCost));
|
SELECT DISTINCT T2.ProductID FROM ProductCostHistory AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T1.StandardCost < ( SELECT SUM(StandardCost) / COUNT(ProductID) FROM Product )
| 7,452 | |
works_cycles
|
What is the the percentage of profit for the product "858"?
|
percentage of profit = DIVIDE(SUBTRACT(ListPrice, StandardCost), (StandardCost)) as percentage;
|
SELECT (T1.ListPrice - T2.StandardCost) * 100 / T2.StandardCost FROM ProductListPriceHistory AS T1 INNER JOIN ProductCostHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.ProductID = 858
| 7,453 | |
works_cycles
|
How many products with a thumpnail photo?
|
products with a thumbnail photo refers to ProductPhotoID ! = 1 ;
|
SELECT COUNT(ProductID) FROM ProductProductPhoto WHERE ProductPhotoID != 1
| 7,454 | |
works_cycles
|
How many days did it take to end the work order "425"?
|
days to end a work order = SUBTRACT(ActualEndDate, ActualStartDate);
|
SELECT 365 * (STRFTIME('%Y', ActualEndDate) - STRFTIME('%Y', ActualStartDate)) + 30 * (STRFTIME('%m', ActualEndDate) - STRFTIME('%m', ActualStartDate)) + STRFTIME('%d', ActualEndDate) - STRFTIME('%d', ActualStartDate) FROM WorkOrderRouting WHERE WorkOrderID = 425
| 7,455 | |
works_cycles
|
Which product has the highest price in 2012?
|
price refers to ListPrice; highest price refers to MAX(ListPrice);
|
SELECT ProductID FROM ProductListPriceHistory WHERE StartDate LIKE '2012%' ORDER BY ListPrice DESC LIMIT 1
| 7,456 | |
works_cycles
|
What is the cost for the product "847"?
|
cost refers to StandardCost;
|
SELECT StandardCost FROM ProductCostHistory WHERE ProductID = 847
| 7,457 | |
works_cycles
|
What is the organization level for Human Resources Manager?
|
Human Resources Manager is a job title
|
SELECT OrganizationLevel FROM Employee WHERE JobTitle = 'Human Resources Manager'
| 7,458 | |
works_cycles
|
How many of the work orders didn’t meet the due date?
|
workers who did not meet the due date refers to EndDate>DueDate;
|
SELECT COUNT(WorkOrderID) FROM WorkOrder WHERE EndDate > DueDate
| 7,459 | |
works_cycles
|
What is the cost and the product number of product with the id "888"?
|
cost refers to StandardCost;
|
SELECT T2.StandardCost, T2.ProductNumber FROM ProductCostHistory AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T1.ProductID = 888
| 7,460 | |
works_cycles
|
How many products using "roadster_black_small.gif" as the thumbnail photo?
|
products using roadster_black_small.gif as the thumbnail photo refers to ThumbnailPhotoFileName = 'roadster_black_small.gif';
|
SELECT COUNT(DISTINCT T2.ProductID) FROM ProductPhoto AS T1 INNER JOIN ProductProductPhoto AS T2 ON T1.ProductPhotoID = T2.ProductPhotoID WHERE T1.LargePhotoFileName = 'roadster_black_large.gif'
| 7,461 | |
works_cycles
|
List the locations ids, compartments and containers for the Lock Ring
|
compartment refers to Shelf; container refers to Bin; Lock Ring is a name of product
|
SELECT T2.LocationID, T2.Shelf, T2.Bin FROM Product AS T1 INNER JOIN ProductInventory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name LIKE 'Lock Ring'
| 7,462 | |
works_cycles
|
What category do Road Frames fall into?
|
Road Frames is a name of product subcategory
|
SELECT T2.Name FROM ProductSubcategory AS T1 INNER JOIN ProductCategory AS T2 ON T1.ProductCategoryID = T2.ProductCategoryID WHERE T1.Name = 'Road Frames'
| 7,463 | |
works_cycles
|
List all the scraped work orders for handling damage reason.
|
handling damage is descrription of manufacturing failure which refers to ScrapReason.Name
|
SELECT T2.WorkOrderID FROM ScrapReason AS T1 INNER JOIN WorkOrder AS T2 ON T1.ScrapReasonID = T2.ScrapReasonID WHERE T1.Name = 'Handling damage'
| 7,464 | |
works_cycles
|
What is the profit for the product "792"?
|
profit = SUBTRACT(ListPrice, StandardCost);
|
SELECT T1.ListPrice - T2.StandardCost FROM ProductListPriceHistory AS T1 INNER JOIN ProductCostHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.ProductID = 792
| 7,465 | |
works_cycles
|
Who owns the email address "[email protected]"?
|
SELECT T2.FirstName, T2.LastName FROM EmailAddress AS T1 INNER JOIN Person AS T2 ON T1.BusinessEntityID = T2.BusinessEntityID WHERE T1.EmailAddress = '[email protected]'
| 7,466 | ||
works_cycles
|
Where are the locations where the product "810" is stored?
|
SELECT T2.Name FROM ProductInventory AS T1 INNER JOIN Location AS T2 ON T1.LocationID = T2.LocationID WHERE T1.ProductID = 810
| 7,467 | ||
works_cycles
|
What is the name of the product the work order "2540" was making?
|
SELECT T2.Name FROM WorkOrder AS T1 INNER JOIN Product AS T2 ON T1.ProductID = T2.ProductID WHERE T1.WorkOrderID = 2540
| 7,468 | ||
works_cycles
|
What is the price for the AWC Logo Cap?
|
price refers to ListPrice; price of 3 products = MULTIPLY(ListPrice, 3); Lock Washer 6 is a name of a product;
|
SELECT T2.ListPrice FROM Product AS T1 INNER JOIN ProductListPriceHistory AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'AWC Logo Cap'
| 7,469 | |
works_cycles
|
List all the work orders that is related to the Down Tube.
|
Down Tube is a name of a product;
|
SELECT T2.WorkOrderID FROM Product AS T1 INNER JOIN WorkOrder AS T2 ON T1.ProductID = T2.ProductID WHERE T1.Name = 'Down Tube'
| 7,470 | |
works_cycles
|
What is the the average percentage of profit for the all the product?
|
average profit percentage = DIVIDE(SUBTRACT(ListPrice, StandardCost)), (StandardCost)));
|
SELECT AVG((T1.ListPrice - T2.StandardCost) * 100 / T2.StandardCost) FROM ProductListPriceHistory AS T1 INNER JOIN ProductCostHistory AS T2 ON T1.ProductID = T2.ProductID
| 7,471 | |
works_cycles
|
What proportion of work order is in Subassembly?
|
proportion = DIVIDE(SUM(Name = 'Subassembly'). (COUNT(WorkOrderID)));
|
SELECT 100.0 * SUM(CASE WHEN T1.Name = 'Subassembly' THEN 1 ELSE 0 END) / COUNT(T2.WorkOrderID) FROM Location AS T1 INNER JOIN WorkOrderRouting AS T2 ON T1.LocationID = T2.LocationID
| 7,472 | |
image_and_language
|
How many object samples are there in image no.1?
|
object samples refers to OBJ_SAMPLE_ID; image no.1 refers to IMG_ID = 1
|
SELECT COUNT(OBJ_SAMPLE_ID) FROM IMG_OBJ WHERE IMG_ID = 1
| 7,473 | |
image_and_language
|
How many images have over 20 object samples?
|
over 20 object samples refers to COUNT(OBJ_SAMPLE_ID) > 20
|
SELECT COUNT(T1.IMG_ID) FROM ( SELECT IMG_ID FROM IMG_OBJ GROUP BY IMG_ID HAVING COUNT(OBJ_SAMPLE_ID) > 20 ) T1
| 7,474 | |
image_and_language
|
What is the ID of the image with the most number of object samples?
|
ID of the image refers to IMG_ID; most number of object samples refers to max(count(OBJ_SAMPLE_ID))
|
SELECT IMG_ID FROM IMG_OBJ GROUP BY IMG_ID ORDER BY COUNT(OBJ_SAMPLE_ID) DESC LIMIT 1
| 7,475 | |
image_and_language
|
Please list the IDs of the object samples in class no. 297 in image no.1.
|
IDs of the object samples refers to OBJ_SAMPLE_ID; class no. 297 in image no.1 refers to IMG_ID = 1 and OBJ_CLASS_ID = 297
|
SELECT OBJ_SAMPLE_ID FROM IMG_OBJ WHERE IMG_ID = 1 AND OBJ_CLASS_ID = 297
| 7,476 | |
image_and_language
|
How many self-relations are there between the object samples in image no.5?
|
self-relations refers to OBJ1_SAMPLE_ID = OBJ2_SAMPLE_ID; image no.5 refers to IMG_ID = 5
|
SELECT SUM(CASE WHEN IMG_ID = 5 THEN 1 ELSE 0 END) FROM IMG_REL WHERE OBJ1_SAMPLE_ID = OBJ2_SAMPLE_ID
| 7,477 | |
image_and_language
|
What is the bounding box of the object sample in image no.5 that has a self-relation?
|
bounding box of the object sample refers to (x, y, W, H); image no.5 refers to IMG_ID = 5; has a self-relation refers to OBJ1_SAMPLE_ID = OBJ2_SAMPLE_ID
|
SELECT T2.X, T2.Y, T2.W, T2.H FROM IMG_REL AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.IMG_ID = T2.IMG_ID WHERE T1.IMG_ID = 5 AND T1.OBJ1_SAMPLE_ID = T1.OBJ2_SAMPLE_ID
| 7,478 | |
image_and_language
|
How many object samples in image no.1 are in the class of "man"?
|
object samples refers to OBJ_CLASS_ID; image no.1 refers to IMG_ID = 1; in the class of "man" refers to OBJ_CLASS = 'man'
|
SELECT SUM(CASE WHEN T1.OBJ_CLASS = 'man' THEN 1 ELSE 0 END) FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T2.IMG_ID = 1
| 7,479 | |
image_and_language
|
How many images have at least one object sample in the class of "man"?
|
have at least one object sample in the class of "man" refers to count(IMG_ID where OBJ_CLASS = 'man') > = 1
|
SELECT COUNT(T.IMG_ID) FROM ( SELECT T2.IMG_ID FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T1.OBJ_CLASS = 'man' GROUP BY T2.IMG_ID ) T
| 7,480 | |
image_and_language
|
Please list the classes of all the object samples in image no.1.
|
classes of all the object samples refers to OBJ_CLASS; image no.1 refers to IMG_ID = 1
|
SELECT T1.OBJ_CLASS FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T2.IMG_ID = 1 GROUP BY T1.OBJ_CLASS
| 7,481 | |
image_and_language
|
What is the relation between object sample no.8 and object sample no.4 in image no.1?
|
relation refers to PRED_CLASS; object sample no.8 and object sample no.4 refers to OBJ1_SAMPLE_ID = 8 AND OBJ2_SAMPLE_ID = 4; image no.1 refers to IMG_ID = 1
|
SELECT T1.PRED_CLASS FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.IMG_ID = 1 AND T2.OBJ1_SAMPLE_ID = 8 AND T2.OBJ2_SAMPLE_ID = 4
| 7,482 | |
image_and_language
|
How many pairs of object samples in image no.1 have the relation of "parked on"?
|
pairs of object samples refers to OBJ1_SAMPLE_ID and OBJ2_SAMPLE_ID; image no.1 refers to IMG_ID = 1; relation of "parked on" refers to PRED_CLASS = 'parked on'
|
SELECT SUM(CASE WHEN T1.PRED_CLASS = 'parked on' THEN 1 ELSE 0 END) FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.IMG_ID = 1 AND T2.OBJ1_SAMPLE_ID != OBJ2_SAMPLE_ID
| 7,483 | |
image_and_language
|
Please list all the predicted relation classes of object sample no.14 in image no.1.
|
predicted relation classes refers to PRED_CLASS; object sample no.14 in image no.1 refers to OBJ1_SAMPLE_ID = 14 AND OBJ2_SAMPLE_ID = 14 and IMG_ID = 1
|
SELECT T1.PRED_CLASS FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.OBJ1_SAMPLE_ID = 14 AND T2.OBJ2_SAMPLE_ID = 14
| 7,484 | |
image_and_language
|
How many images have at least one pair of object samples with the relation "parked on"?
|
How many images have at least one pair of object samples with the relation "parked on" refers to count(IMG_ID) where OBJ1_SAMPLE_ID ! = OBJ2_SAMPLE_ID and PRED_CLASS = 'parked on'
|
SELECT SUM(CASE WHEN T1.PRED_CLASS = 'parked on' THEN 1 ELSE 0 END) FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.OBJ1_SAMPLE_ID != T2.OBJ2_SAMPLE_ID
| 7,485 | |
image_and_language
|
Please list the IDs of all the images with more than 2 pairs of object samples with the relation "parked on".
|
IDs of all the images refers to IMG_ID; relation "parked on" refers to PRED_CLASS = 'parked on'; more than 2 pairs refers to count(IMG_ID) where OBJ1_SAMPLE_ID ! = OBJ2_SAMPLE_ID
|
SELECT T2.IMG_ID FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T1.PRED_CLASS = 'parked on' AND T2.OBJ1_SAMPLE_ID != T2.OBJ2_SAMPLE_ID GROUP BY T2.IMG_ID HAVING COUNT(T2.IMG_ID) > 2
| 7,486 | |
image_and_language
|
To which predicted relation class does the self-relation of the object sample in image no.5 belong?
|
predicted relation class refers to PRED_CLASS; self-relations refers to OBJ1_SAMPLE_ID = OBJ2_SAMPLE_ID; image no.5 refers to IMG_ID = 5
|
SELECT T1.PRED_CLASS FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.IMG_ID = 5 AND T2.OBJ1_SAMPLE_ID = T2.OBJ2_SAMPLE_ID
| 7,487 | |
image_and_language
|
What are the bounding boxes of the object samples with a predicted relation class of "by" in image no.1?
|
bounding boxes of the object samples refers to (x, y, W, H); predicted relation class of "by" refers to PRED_CLASS = 'by'; image no.1 refers to IMG_ID = 1
|
SELECT T3.X, T3.Y, T3.W, T3.H FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID INNER JOIN IMG_OBJ AS T3 ON T2.OBJ1_SAMPLE_ID = T3.OBJ_CLASS_ID WHERE T2.IMG_ID = 1 AND T1.PRED_CLASS = 'by'
| 7,488 | |
image_and_language
|
What is the average difference in the y coordinate of 2 object samples with the relation "parked on" in image no.1?
|
relation "parked on" refers to PRED_CLASS = 'parked on'; image no.1 refers to IMG_ID = 1; average difference in the y coordinate = divide(sum(Y), count(PRED_CLASS)) where OBJ1_SAMPLE_ID ! = OBJ2_SAMPLE_ID
|
SELECT CAST(SUM(T3.Y) AS REAL) / COUNT(CASE WHEN T1.PRED_CLASS = 'parked on' THEN 1 ELSE NULL END) FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID INNER JOIN IMG_OBJ AS T3 ON T2.OBJ1_SAMPLE_ID = T3.OBJ_CLASS_ID WHERE T2.IMG_ID = 1 AND T2.OBJ1_SAMPLE_ID != T2.OBJ2_SAMPLE_ID
| 7,489 | |
image_and_language
|
What is the percentage of the object samples in the class of "man" in image no.1?
|
object samples refers to OBJ_SAMPLE_ID; class of "man" refers to OBJ_CLASS = 'man'; image no.1 refers to IMG_ID = 1; percentage = divide(count(OBJ_SAMPLE_ID)when OBJ_CLASS = 'man', count(OBJ_SAMPLE_ID)) as percentage
|
SELECT CAST(COUNT(CASE WHEN T1.OBJ_CLASS = 'man' THEN 1 ELSE NULL END) AS REAL) * 100 / COUNT(T1.OBJ_CLASS_ID) FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T2.IMG_ID = 1
| 7,490 | |
image_and_language
|
State the total number of the attribute classes.
|
attribute classes refers to ATT_CLASS
|
SELECT COUNT(ATT_CLASS_ID) FROM ATT_CLASSES
| 7,491 | |
image_and_language
|
How many object classes are there in the database?
|
object classes refers to OBJ_CLASS
|
SELECT COUNT(OBJ_CLASS_ID) FROM OBJ_CLASSES
| 7,492 | |
image_and_language
|
Provide the number of predicted classes.
|
predicted classes refers to PRED_CLASS
|
SELECT COUNT(PRED_CLASS_ID) FROM PRED_CLASSES
| 7,493 | |
image_and_language
|
Give the bounding box of the kite in image no.2324765.
|
bounding box refers to (x, y, W, H); kite refers to OBJ_CLASS = 'kite'; image no.2324765 refers to IMG_ID = 2324765
|
SELECT T2.X, T2.Y, T2.W, T2.H FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T2.IMG_ID = 2324765 AND T1.OBJ_CLASS = 'kite'
| 7,494 | |
image_and_language
|
How many white objects are there in image no.2347915?
|
white objects refers to ATT_CLASS = 'white'; image no.2347915 refers to IMG_ID = 2347915
|
SELECT SUM(CASE WHEN T2.ATT_CLASS = 'white' THEN 1 ELSE 0 END) FROM IMG_OBJ_ATT AS T1 INNER JOIN ATT_CLASSES AS T2 ON T1.ATT_CLASS_ID = T2.ATT_CLASS_ID WHERE T1.IMG_ID = 2347915
| 7,495 | |
image_and_language
|
Give the number of samples in image no.2377985 whose attribute is electrical.
|
number of samples refers to OBJ_SAMPLE_ID; image no.2377985 refers to IMG_ID = 2377985; attribute is electrical refers to ATT_CLASS = 'electrical'
|
SELECT SUM(CASE WHEN T2.ATT_CLASS = 'white' THEN 1 ELSE 0 END) FROM IMG_OBJ_ATT AS T1 INNER JOIN ATT_CLASSES AS T2 ON T1.ATT_CLASS_ID = T2.ATT_CLASS_ID WHERE T1.IMG_ID = 2347915
| 7,496 | |
image_and_language
|
What is the relationship between object sample no.12 and no.8 of image no.2345511?
|
relationship refers to PRED_CLASS; object sample no.12 and no.8 of image no.2345511 refers to IMG_ID = 2345511 AND OBJ1_SAMPLE_ID = 12 AND OBJ2_SAMPLE_ID = 8
|
SELECT T1.PRED_CLASS FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.IMG_ID = 2345511 AND T2.OBJ1_SAMPLE_ID = 12 AND T2.OBJ2_SAMPLE_ID = 8
| 7,497 | |
image_and_language
|
Give the object number of the sample which has the relationship of "lying on" with object sample no.1 from image no.2345524.
|
object number of the sample refers to OBJ1_SAMPLE_ID; object sample no.1 from image no.2345524 refers to OBJ2_SAMPLE_ID = 1 and IMG_ID = 2345524
|
SELECT T2.OBJ1_SAMPLE_ID FROM PRED_CLASSES AS T1 INNER JOIN IMG_REL AS T2 ON T1.PRED_CLASS_ID = T2.PRED_CLASS_ID WHERE T2.IMG_ID = 2345524 AND T1.PRED_CLASS = 'lying on' AND T2.OBJ2_SAMPLE_ID = 1
| 7,498 | |
image_and_language
|
How many samples of food object are there in image no.6?
|
samples of food object refers to OBJ_CLASS = 'food'; image no.6 refers to IMG_ID = 6
|
SELECT COUNT(T2.OBJ_SAMPLE_ID) FROM OBJ_CLASSES AS T1 INNER JOIN IMG_OBJ AS T2 ON T1.OBJ_CLASS_ID = T2.OBJ_CLASS_ID WHERE T2.IMG_ID = 6 AND T1.OBJ_CLASS = 'food'
| 7,499 |
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