Code Line
stringclasses 57
values | User Explanation
stringclasses 692
values | Line-Explanation in PCEX
stringclasses 131
values | Annotation Score
float64 1
5
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|---|---|---|---|
if (values[i] > maxValue) {
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Creating if condition which is fulfilled if the values[i] is greated than the maxValue variable.
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If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
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maxValue = values[i];
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If the if condition is fulfilled, the value of maxValue will be replaced by the value in values[i].
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This statement sets the maximum value to value of the element at index i of the array.
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System.out.println("Maximum value: " + maxValue);
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Statement to print the maximum value in the array values.
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This statement prints the maximum value of the array to the default standard output stream.
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Scanner scan = new Scanner(System.in);
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Instance of object Scanner
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To read the input value from the user, we need to define a Scanner object.
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Scanner scan = new Scanner(System.in);
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Instance of object Scanner
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We need to read and process the value that the user enters.
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System.out.println("Enter an integer for seconds: ");
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Print message on console
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We prompt the user to enter the seconds.
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int seconds = scan.nextInt();
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Get input from command line as integer
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We need to read the seconds that the user enters and store it in a variable.
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int seconds = scan.nextInt();
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Get input from command line as integer
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We read the seconds by calling the nextInt() method because this input is an integer.
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scan.close();
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Close scanner instance
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We close the scanner as we do not want to process any input from the user in the rest of the program.
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int minutes = seconds / 60;
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calculate minutes by dividing by 60
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To obtain the minutes in seconds, we divide the seconds by 60 because there are 60 seconds in a minute.
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int minutes = seconds / 60;
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calculate minutes by dividing by 60
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Note that since both operands of division operator are integer, the fractional part of the result is truncated, if there is any.
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int remainingSeconds = seconds % 60;
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calculate the seconds, making the modulus of the integer, to obtain the rest
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This is because there are 60 seconds in a minute.
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int remainingSeconds = seconds % 60;
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calculate the seconds, making the modulus of the integer, to obtain the rest
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Note that the % operator returns the remainder of the division.
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int remainingSeconds = seconds % 60;
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calculate the seconds, making the modulus of the integer, to obtain the rest
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To obtain the remaining seconds after taking away the minutes, we have to take the remainder of the seconds divided by 60.
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System.out.println("Enter an integer for seconds: ");
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Print message by console so that the user inserts an integer number
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We prompt the user to enter the seconds.
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System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
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Print message by console with the result separated by minutes and seconds
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This statement prints to the default standard output stream the minutes and remaining seconds from the input amount of time in seconds.
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System.out.println(seconds + " seconds is " + minutes + " minutes and " + remainingSeconds + " seconds.");
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Print message by console with the result separated by minutes and seconds
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The printed text is followed by the end-of-line character at the end.
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int num = 15;
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Integer variable declaration num
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We define variable num to store the number that we want to find its smallest divisor.
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int num = 15;
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Integer variable declaration num
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We could initialize it to any positive integer greater than 1.
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int num = 15;
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Integer variable declaration num
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In this program, we initialize variable num to 15.
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int divisor = 2;
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Integer variable declaration divisor
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We initialize variable divisor by 2 because we want to find the smallest divisor except 1.
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int divisor = 2;
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Integer variable declaration divisor
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We define variable divisor to store the smallest divisor of the number.
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divisor += 1;
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Fulfills the condition and we increase the divisor variable
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When the divisor is not a factor of the number, we increment the variable divisor by 1.
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while (num % divisor != 0) {
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Loop condition, modulus between num and divisor
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Since we don't know ahead of time how many times the loop will be repeated, we need to use a while loop.
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while (num % divisor != 0) {
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Loop condition, modulus between num and divisor
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We need to increment the divisor repeatedly as long as the divisor is not a factor of the number.
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while (num % divisor != 0) {
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Loop condition, modulus between num and divisor
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Therefore, we need to use a loop structure.
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while (num % divisor != 0) {
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Loop condition, modulus between num and divisor
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The condition in the while loop tests whether the body of the loop should be repeated, so it should test whether the divisor is not a factor of the number.
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while (num % divisor != 0) {
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Loop condition, modulus between num and divisor
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We could check whether the divisor is not a factor of the number by computing the remainder of the division of the number by the divisor.
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System.out.println("The smallest divisor of " + num + " is " + divisor);
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Print message by console with the result of the smallest divisor of the variable num
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This statement prints to the default standard output stream the smallest divisor of the number.
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String fullName = "John Smith"
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assign the value of John Smith to the string called fullName
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We define a string variable to hold the name.
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String firstInitial = fullName.substring(0, 1);
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Get the characters from position 0 to 1 of fullName and assign them to the firstInitial string
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We need to extract the first letter from the first name.
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String firstInitial = fullName.substring(0, 1);
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Get the characters from position 0 to 1 of fullName and assign them to the firstInitial string
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We do this by calling the substring(0,1) method.
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String lastInitial = fullName.substring(5, 6);
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Get the characters from position 5 to 6 of fullName and assign them to the lastInitial string
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We need to extract the first letter from the last name.
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String lastInitial = fullName.substring(5, 6);
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Get the characters from position 5 to 6 of fullName and assign them to the lastInitial string
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We do this by calling the substring(5,6) method.
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String initials = firstInitial + lastInitial;
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Combine the first initial and the last initial and assign it to the initials string
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This statements concatenates the extracted initials and store the result in the string initials.
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System.out.println(initials);
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output the initials string
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This statement prints the initials to the default standard output stream.
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System.out.println(initials);
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output the initials string
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The printed value is followed by the end-of-line character at the end.
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int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
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create an array with the values in the brackets
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We define array values to hold the specified numbers.
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int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
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create an array with the values in the brackets
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We initialize the array by separating elements with a comma and enclosing the collection in braces { }.
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int maxValue = values[0];
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set the maxValue to the value at position 0 in the value array.
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We need variable maxValue to store the maximum value of the array.
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int maxValue = values[0];
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set the maxValue to the value at position 0 in the value array.
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We initialize this variable by the first value in the array because we initially assume that the first value is the maximum.
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for (int i = 1; i < values.length; i++) {
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Loop through the array, from position 1 to the length of the array, incrementing by 1 position each time
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We use a for loop to iterate over the remaining array indexes and search for the maximum value.
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for (int i = 1; i < values.length; i++) {
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Loop through the array, from position 1 to the length of the array, incrementing by 1 position each time
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We need the array indexes to start at 1 with every integer number up to but not including the array length.
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if (values[i] > maxValue) {
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check if the value at position i is greater than the maxValue
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We need to compare the value at the index i of the array with the maximum value stored in variable maxValue.
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if (values[i] > maxValue) {
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check if the value at position i is greater than the maxValue
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If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
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maxValue = values[i];
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if the value is greater than the maxValue, assign that value to the maxValue
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This statement sets the maximum value to value of the element at index i of the array.
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System.out.println("Maximum value: " + maxValue);
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output the maxValue variable.
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This statement prints the maximum value of the array to the default standard output stream.
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int num = 1234;
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to store integer type data. int helps in storing integer value into memory.
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We need variable num to store the integer that we want to print its digits.
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Scanner scan = new Scanner(System.in);
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for obtaining the input of the int
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To read the input values from the user, we need to define a Scanner object.
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Scanner scan = new Scanner(System.in);
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for obtaining the input of the int
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We need to read and process the values that the user enters.
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System.out.println("Enter the phone age in years:");
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to print the sentence enclosed in the brackets display in the output screen
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We prompt the user to enter the phone age in years.
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int phoneAge = scan.nextInt();
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to get the integer value and to store the int value in the integer memory
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We read the phone age by calling the nextInt() method because this input is an integer.
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int phoneAge = scan.nextInt();
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to get the integer value and to store the int value in the integer memory
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We need to read the phone age that the user enters and store it in a variable.
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System.out.println("Enter whether the phone is broken (true or false):");
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to print the the sentence enclosed in the quotation display on the output screen
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We prompt the user to enter whether the phone is broken.
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boolean isBroken = scan.nextBoolean();
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to boolean get the value 0 or 1 and store the value in the boolean memory
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We need to read whether the phone is broken and store it in a variable.
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boolean isBroken = scan.nextBoolean();
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to boolean get the value 0 or 1 and store the value in the boolean memory
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The variable isBroken is true when the phone is broken, and false otherwise.
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boolean isBroken = scan.nextBoolean();
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to boolean get the value 0 or 1 and store the value in the boolean memory
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We read whether the phone is broken by calling the nextBoolean() method because this input is a boolean.
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scan.close();
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to close the scanner
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We close the scanner as we do not want to process any input from the user in the rest of the program.
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boolean needPhone = isBroken || phoneAge >= 3;
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to test the boolean value is true or not and store that in the needPhone memory
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We use the || operator (called or) to combine the two conditions.
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boolean needPhone = isBroken || phoneAge >= 3;
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to test the boolean value is true or not and store that in the needPhone memory
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The first condition is to test if the phone is broken and the second condition is to test if the phone age is at least 3 years old.
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boolean needPhone = isBroken || phoneAge >= 3;
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to test the boolean value is true or not and store that in the needPhone memory
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We need two conditions to determine if it is the time for a new phone.
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System.out.println(needPhone);
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print the needPhone value in the output screen
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This statement prints true/false depending on whether it is time to buy a new phone.
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System.out.println(needPhone);
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print the needPhone value in the output screen
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The printed value is followed by an end-of-line character in the end.
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int num = 1234;
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to store integer type data.
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We need variable num to store the integer that we want to print its digits.
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int num = 1234;
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int helps in storing integer value into memory.
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We need variable num to store the integer that we want to print its digits.
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do {
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its a loop used to process the values
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We need to process the digits of the integer from right to left and print them.
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do {
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its a loop used to process the values
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Therefore, we need to use a loop structure.
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do {
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its a loop used to process the values
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In this program, we do this by using a do loop.
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do {
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its a loop used to process the values
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The do loop is more appropriate than a while loop because a positive integer always has at least one digit which results in the body of the loop performing at least once.
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num = num / 10;
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formula to obtain the value of num
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Therefore, this division will remove the digit that we processed (lastDigit) and we can move on to the next digit.
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num = num / 10;
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formula to obtain the value of num
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We truncate the extracted digit that we processed from the original integer by dividing the integer by 10.
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num = num / 10;
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formula to obtain the value of num
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Note that this statement performs an integer division because both operand of the / operator are integer.
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} while (num > 0);
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end of the loop enclosed with condition
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We need to check for termination conditions to avoid infinite loops.
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} while (num > 0);
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end of the loop enclosed with condition
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The loop should terminate when we run out of digits to process.
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} while (num > 0);
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end of the loop enclosed with condition
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We could check whether the are more digits left by checking whether the variable num, which gets updated in the body of the do loop, is greater than zero.
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} while (num > 0);
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end of the loop enclosed with condition
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If variable num is greater than zero, then it must have at least one digit, and in that case, the body of the do loop will be repeated again.
| 1 |
} while (num > 0);
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end of the loop enclosed with condition
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The body of the while loop should repeat as long as there are more digits left that we have not processed yet.
| 1 |
System.out.println(num % 10);
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print the num % 10 value in the output screen
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Each printed digit is followed by the line separator (e.g. '\n') at the end.
| 1 |
System.out.println(num % 10);
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print the num % 10 value in the output screen
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We need to extract the last digit in the 1's position of the integer.
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System.out.println(num % 10);
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print the num % 10 value in the output screen
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For example, if the integer is 1234, we want to extract the digit 4 that is in 1's position of the integer.
| 1 |
System.out.println(num % 10);
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print the num % 10 value in the output screen
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We do this by calculating the remainder of the division of the integer by 10.
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System.out.println(num % 10);
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print the num % 10 value in the output screen
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Then, this statement prints the last digit of the integer to the standard output stream.
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System.out.println("Enter whether the phone is broken (true or false):");
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to print the sentence within the bracket opn oputput screen
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We prompt the user to enter whether the phone is broken.
| 1 |
System.out.println("Enter whether the phone is broken (true or false):");
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ti print
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We prompt the user to enter whether the phone is broken.
| 1 |
String fullName = "John Smith"
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to store the name John smith in the String memory
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We define a string variable to hold the name.
| 3 |
String firstInitial = fullName.substring(0, 1);
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getting the substring and store the data in firstInitial
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We need to extract the first letter from the first name.
| 3 |
String firstInitial = fullName.substring(0, 1);
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getting the substring and store the data in firstInitial
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We do this by calling the substring(0,1) method.
| 2 |
String initials = firstInitial + lastInitial;
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formula for join the firstInitial and lastInitial and store the answer in initials
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This statements concatenates the extracted initials and store the result in the string initials.
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String lastInitial = fullName.substring(5, 6);
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getting the substring and store the data in lastInitial
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We need to extract the first letter from the last name.
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String lastInitial = fullName.substring(5, 6);
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getting the substring and store the data in lastInitial
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We do this by calling the substring(5,6) method.
| 2 |
System.out.println(initials);
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print the initials in the output screen
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This statement prints the initials to the default standard output stream.
| 4 |
System.out.println(initials);
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print the initials in the output screen
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The printed value is followed by the end-of-line character at the end.
| 1 |
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
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store the array of integer values in the name values
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We define array values to hold the specified numbers.
| 4 |
int[] values = {5, 8, 4, 78, 95, 12, 1, 0, 6, 35, 46};
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store the array of integer values in the name values
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We initialize the array by separating elements with a comma and enclosing the collection in braces { }.
| 2 |
int maxValue = values[0];
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initialize the array
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We need variable maxValue to store the maximum value of the array.
| 1 |
int maxValue = values[0];
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initialize the array
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We initialize this variable by the first value in the array because we initially assume that the first value is the maximum.
| 1 |
for (int i = 1; i < values.length; i++) {
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condition enclosed in the for loop to obtain the maxValue in the array
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We use a for loop to iterate over the remaining array indexes and search for the maximum value.
| 3 |
for (int i = 1; i < values.length; i++) {
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condition enclosed in the for loop to obtain the maxValue in the array
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We need the array indexes to start at 1 with every integer number up to but not including the array length.
| 1 |
if (values[i] > maxValue) {
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check the condition whether it is true or not by finding the maxValue
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We need to compare the value at the index i of the array with the maximum value stored in variable maxValue.
| 2 |
if (values[i] > maxValue) {
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check the condition whether it is true or not by finding the maxValue
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If the value at that index is larger than the maximum value, then we need to set the maximum value to the value of the element at index i.
| 1 |
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