premise
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| hypothesis
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Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Nathalie is thoughtful. | entailment |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stephen is careful. | neutral |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stefan is brown. | self_contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Kingston is thoughtful. | entailment |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Claudia is not visible. | neutral |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Sabrina is not careful. | self_contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stephen is brown. | neutral |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Nathalie is not thoughtful. | contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stefan is thoughtful. | entailment |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Kingston is not fine. | entailment |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Kingston is brown. | contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stefan is homely. | self_contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stephen is visible. | neutral |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Sabrina is careful. | self_contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stefan is not brown. | self_contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Sabrina is not visible. | contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Kingston is not brown. | entailment |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Kingston is fine. | contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Hadwin is not careful. | contradiction |
Kingston is thoughtful.
Stephen is homely.
Nathalie is homely.
Nathalie is not visible.
Sabrina is visible.
Stefan is thoughtful.
Claudia is not thoughtful.
Stefan is not homely.
Stefan is not fine.
Kingston is not fine.
Sabrina is careful.
Hadwin is careful.Someone being both not careful and not visible is equivalent to being fine and homely.
If there is someone who is not fine, then Stefan is brown and Sabrina is not careful.
If someone is either not visible or not fine, then he is homely and thoughtful.
It can be concluded that Sabrina is not homely once knowing that Stefan is not thoughtful and Nathalie is visible.
Kingston is not thoughtful if and only if Hadwin is brown and Sabrina is not homely.
If Stefan is not careful, then Sabrina is not thoughtful, and vice versa.
If there is someone who is both homely and not careful, then Stefan is not thoughtful.
If there is at least one people who is both careful and fine, then Hadwin is not visible.
Someone being both thoughtful and not brown is equivalent to being not fine.
Someone is not thoughtful and brown if and only if he is not homely and careful.
If someone is fine, then he is brown.
Nathalie being not thoughtful implies that Hadwin is visible. | Stephen is thoughtful. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Aiken is beige. | contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Barclay is not latter. | self_contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Barclay is not lively. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Debra is lively. | entailment |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Claude is not obnoxious. | entailment |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Debra is obnoxious. | self_contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Debra is beige. | entailment |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Maddox is not beige. | contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Kingsley is sufficient. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Barclay is latter. | self_contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Aiken is not lively. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Debra is skinny. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Maddox is latter. | contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Maddox is not sufficient. | contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Aiken is obnoxious. | neutral |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Claude is not lively. | contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Claude is sufficient. | entailment |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Deborah is obnoxious. | entailment |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Barclay is beige. | self_contradiction |
Maddox is beige.
Deborah is skinny.
Debra is sufficient.
Debra is lively.
Barclay is latter.
Claude is lively.
Barclay is not beige.
Maddox is sufficient.
Deborah is not lively.
Kingsley is not obnoxious.
Deborah is latter.
Maddox is not latter.If there is at least one people who is latter, then Aiken is not beige.
If there is someone who is both sufficient and obnoxious, then Barclay is not latter.
Someone who is eithor not lively or not sufficient is always obnoxious.
If there is someone who is not beige, then Claude is sufficient.
If someone is not skinny, then he is both not sufficient and lively.
If someone is lively, then he is not obnoxious, and vice versa.
If everyone is not sufficient, then Claude is not skinny and Maddox is obnoxious.
If there is at least one people who is not latter, then Debra is beige and Debra is not sufficient.
If Barclay is lively, then Debra is not latter.
If there is someone who is both sufficient and lively, then Barclay is beige and Debra is not obnoxious.
If there is someone who is both beige and not skinny, then Debra is latter.
If Aiken is not skinny, then Claude is sufficient. | Debra is not obnoxious. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Rufus is not encouraging. | contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Albert is not informal. | entailment |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Olin is motionless. | entailment |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Albert is motionless. | neutral |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Todd is informal. | contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Jesse is not odd. | entailment |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Todd is not motionless. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Rufus is motionless. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Aiken is modern. | neutral |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Albert is informal. | contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Rufus is encouraging. | entailment |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Jesse is not motionless. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Todd is not modern. | contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Todd is motionless. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Olin is not breakable. | contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Rufus is not motionless. | self_contradiction |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Olin is not encouraging. | neutral |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Albert is not odd. | neutral |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Olin is informal. | neutral |
Aiken is encouraging.
Albert is encouraging.
Rufus is not motionless.
Todd is not motionless.
Jesse is not odd.
Todd is odd.
Jesse is not motionless.
Olin is motionless.
Rufus is modern.
Jesse is modern.
Rufus is encouraging.
Todd is modern.It can be concluded that Rufus is not odd once knowing that Shawn is not encouraging.
Albert being not encouraging or Aiken being odd implies that Shawn is motionless.
If someone is not encouraging, then he is both breakable and motionless.
Aiken being modern and Shawn being not informal imply that Olin is not encouraging and Shawn is breakable.
If there is at least one people who is not informal or not modern, then Todd is motionless.
Someone being both motionless and not informal is equivalent to being modern.
If there is someone who is both not informal and odd, then Shawn is not encouraging.
Someone who is motionless is always breakable.
If there is at least one people who is both encouraging and not motionless, then Aiken is informal.
If Olin is motionless, then Jesse is not odd and Albert is not informal, and vice versa.
Aiken being not odd implies that Jesse is not encouraging.
If Olin is not odd or Shawn is not informal, then Shawn is not encouraging. | Todd is modern. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ambrose is foolish. | self_contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Gresham is not smart. | neutral |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Gresham is not foolish. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ambrose is not united. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ridley is useful. | neutral |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Gresham is expensive. | contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Hector is not expensive. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Bruce is not smart. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ambrose is not useful. | contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ambrose is united. | contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ridley is not smart. | entailment |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Bruce is not fair-minded. | self_contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Marion is not fair-minded. | contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Gresham is not united. | neutral |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Gresham is not fair-minded. | self_contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Bruce is smart. | contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ridley is united. | neutral |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Ambrose is not fair-minded. | self_contradiction |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Carl is not expensive. | neutral |
Gresham is not useful.
Hector is useful.
Marion is expensive.
Hector is fair-minded.
Ambrose is useful.
Ridley is not smart.
Hector is not expensive.
Marion is fair-minded.
Gresham is not foolish.
Bruce is useful.
Gresham is not fair-minded.
Ambrose is not fair-minded.If Marion is not united, then Marion is not smart, and vice versa.
It can be concluded that Gresham is fair-minded and Bruce is united once knowing that Ridley is smart.
Someone is not fair-minded and not smart if and only if he is foolish and useful.
Someone being fair-minded is equivalent to being not expensive.
If someone is not foolish, then he is both fair-minded and not expensive.
Someone is not foolish and not smart if and only if he is useful.
All useful people are not smart.
As long as someone is smart, he is not fair-minded and expensive.
If there is someone who is not fair-minded, then Bruce is foolish.
If Carl is smart and Ambrose is not foolish, then Marion is not fair-minded.
If Gresham is not expensive or Marion is useful, then Carl is foolish.
If there is someone who is expensive, then Hector is not foolish and Ambrose is not united. | Marion is not expensive. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Jarvis is entire. | contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gilroy is aggressive. | contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Sophie is entire. | entailment |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gilroy is helpful. | entailment |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Jarvis is aggressive. | entailment |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gloria is aggressive. | contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Sophie is adventurous. | neutral |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Albion is aggressive. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gilroy is not itchy. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Sabrina is aggressive. | contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Sophie is itchy. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Sophie is not itchy. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Lee is helpful. | neutral |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gilroy is not aggressive. | entailment |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Albion is not aggressive. | self_contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Jarvis is not entire. | entailment |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Albion is helpful. | neutral |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Gloria is entire. | contradiction |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Lee is not itchy. | neutral |
Jarvis is not entire.
Gilroy is helpful.
Sophie is entire.
Sophie is not itchy.
Lee is aggressive.
Gilroy is not aggressive.
Gloria is not aggressive.
Gloria is not entire.
Gilroy is not itchy.
Gilroy is entire.
Sabrina is not aggressive.
Albion is not aggressive.If someone is itchy, then he is entire, and vice versa.
If Gilroy is every, then Gloria is aggressive and Gloria is not helpful.
If there is someone who is both not every and adventurous, then Sabrina is not helpful.
It can be concluded that Jarvis is aggressive once knowing that Gloria is not helpful or Gilroy is adventurous.
Someone being both adventurous and every is equivalent to being aggressive and helpful.
If Gilroy is helpful or Sophie is adventurous, then Albion is aggressive.
If Albion is not every, then Sophie is adventurous and Sophie is not aggressive.
As long as someone is not itchy and not entire, he is not helpful and not aggressive.
Lee being not itchy implies that Jarvis is aggressive and Gilroy is adventurous.
Gloria being adventurous and Albion being entire are equivalent to Lee being not helpful and Sophie being aggressive.
If someone who is not adventurous is also every, then he is aggressive.
If there is someone who is either not entire or helpful, then Gilroy is adventurous. | Albion is not helpful. | neutral |
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